Simplification
Hello
I do the simplification of code now, it a pretty big Chuck of the codes.
I was wondering how can I track my memory usage to see that my work is effcienc or not?
Also, I am trying to speed up my code run time so how can I tell how long it will take for all of the code?
Thank you
The easiest way is to go to tools-> profile-> Performance and memory.
Another way to compare (good for subVIs) code is to use two functions of the number of cycles with your code in the middle. Subtract the last of the first to get your code how long taken.
Tags: NI Software
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I know what I'm trying to do, don't know how to get there. I provided do it table and inserts as well as the query is not working.
What I need is all RECORD_ID and STEP_DATE where/*table*/ CREATE TABLE claims_step_table ( table_id INTEGER PRIMARY KEY, record_id NUMBER, step_code VARCHAR2(20 Byte), date_completed DATE, step_date DATE ) /*inserts*/ INSERT INTO claims_step_table VALUES (1, 123456,'P96','10-JAN-09','05-JAN-09'); INSERT INTO claims_step_table VALUES (2, 123456,'L61',null,'05-JAN-09'); INSERT INTO claims_step_table VALUES (3, 67,'P96','10-MAR-08','05-MAR-08'); INSERT INTO claims_step_table VALUES (4, 67,'L61',null,'05-MAR-08'); INSERT INTO claims_step_table VALUES (5, 67,'U18',null,'05-MAR-08'); INSERT INTO claims_step_table VALUES (6, 67,'429',null,'05-MAR-08'); INSERT INTO claims_step_table VALUES (7, 9876,'L61',null,'05-FEB-08'); INSERT INTO claims_step_table VALUES (8, 9876,'429',null,'05-FEB-08'); INSERT INTO claims_step_table VALUES (9, 123456,'P96','10-AUG-07','05-JUN-07'); INSERT INTO claims_step_table VALUES (10, 123456,'L61',null,'05-JUN-07'); INSERT INTO claims_step_table VALUES (11, 123456,'U18',null,'05-JUN-07'); INSERT INTO claims_step_table VALUES (12, 123456,'429',null,'05-JUN-07'); INSERT INTO claims_step_table VALUES (13, 67555,'L61',null,'07-NOV-08'); INSERT INTO claims_step_table VALUES (14, 67555,'P96','08-NOV-08','07-NOV-08'); INSERT INTO claims_step_table VALUES (15, 67555,'429','15-NOV-08','07-NOV-08'); COMMIT; /*query*/ SELECT RECORD_ID, max(STEP_DATE) from( select RECORD_ID, STEP_DATE, case when STEP_CODE = 'L61' then DATE_COMPLETED end as STEP_L61, case when STEP_CODE = 'P96' then DATE_COMPLETED end as STEP_P96, case when STEP_CODE = 'U18' then DATE_COMPLETED end as STEP_U18, case when STEP_CODE = '429' then DATE_COMPLETED end as STEP_429 from CLAIMS_STEP_TABLE where STEP_CODE in('L61','P96','U18','429') ) where STEP_L61 is null and STEP_P96 is not null and STEP_U18 is null and STEP_429 is null group by RECORD_ID, STEP_DATE order by RECORD_ID, STEP_DATE DESC
• STEP_CODE L61, U18 and 429 the null value AND STEP_CODE P96 is over
• Only the more recent recordings based on the STEP_DATE (so the step_date max), if of multiple RECORD_ID.
The query should return * 2 * n - tuples
I am currently getting the followingRECORD_ID MAX(STEP_DATE) 67 03/05/2008 123456 01/05/2009
It is a much more simplified than the original query as it has several joins of tables. There are 100 records of k + in the real CLAIMS_STEP_TABLE with more than 1 different k STEP_CODE. (it is a fictitious table for this example). BTW on the real DB, I have only read access.RECORD_ID MAX(STEP_DATE) 67 03/05/2008 67555 11/07/2008 <= step 429 not null 123456 01/05/2009 123456 06/05/2007 <= old record need newest
Thank you for your patience and understanding with a noob, hope this attempt is more clear.The reason why it is failing because your pivot (inner query) is return few results:
RECORD_ID STEP_DATE STEP_L61 STEP_P96 STEP_U18 STEP_429 ---------- --------- --------- --------- --------- --------- 123456 05-JAN-09 10-JAN-09 123456 05-JAN-09 67 05-MAR-08 10-MAR-08 67 05-MAR-08 67 05-MAR-08 67 05-MAR-08 9876 05-FEB-08 9876 05-FEB-08 123456 05-JUN-07 10-AUG-07 123456 05-JUN-07 123456 05-JUN-07 123456 05-JUN-07 67555 07-NOV-08 67555 07-NOV-08 08-NOV-08 67555 07-NOV-08 15-NOV-08
So in the case of 67555, there is a situation where all the outer query conditions are met. What you need to do is to remove the extra NULL values as follows:
SELECT RECORD_ID , STEP_DATE , MAX(CASE WHEN STEP_CODE = 'L61' THEN DATE_COMPLETED END) AS STEP_L61, MAX(CASE WHEN STEP_CODE = 'P96' THEN DATE_COMPLETED END) AS STEP_P96, MAX(CASE WHEN STEP_CODE = 'U18' THEN DATE_COMPLETED END) AS STEP_U18, MAX(CASE WHEN STEP_CODE = '429' THEN DATE_COMPLETED END) AS STEP_429 FROM CLAIMS_STEP_TABLE WHERE STEP_CODE IN ('L61','P96','U18','429') GROUP BY RECORD_ID , STEP_DATE
To achieve this result:
RECORD_ID STEP_DATE STEP_L61 STEP_P96 STEP_U18 STEP_429 ---------- --------- --------- --------- --------- --------- 67555 07-NOV-08 08-NOV-08 15-NOV-08 9876 05-FEB-08 123456 05-JUN-07 10-AUG-07 67 05-MAR-08 10-MAR-08 123456 05-JAN-09 10-JAN-09
Then your entire query returns the following:
SQL> SELECT RECORD_ID 2 , MAX(STEP_DATE) 3 FROM 4 ( 5 SELECT RECORD_ID 6 , STEP_DATE 7 , MAX(CASE 8 WHEN STEP_CODE = 'L61' THEN DATE_COMPLETED 9 END) AS STEP_L61, 10 MAX(CASE 11 WHEN STEP_CODE = 'P96' THEN DATE_COMPLETED 12 END) AS STEP_P96, 13 MAX(CASE 14 WHEN STEP_CODE = 'U18' THEN DATE_COMPLETED 15 END) AS STEP_U18, 16 MAX(CASE 17 WHEN STEP_CODE = '429' THEN DATE_COMPLETED 18 END) AS STEP_429 19 FROM CLAIMS_STEP_TABLE 20 WHERE STEP_CODE IN ('L61','P96','U18','429') 21 GROUP BY RECORD_ID 22 , STEP_DATE 23 ) 24 WHERE STEP_L61 IS NULL 25 AND STEP_P96 IS NOT NULL 26 AND STEP_U18 IS NULL 27 AND STEP_429 IS NULL 28 GROUP BY RECORD_ID 29 / RECORD_ID MAX(STEP_ ---------- --------- 123456 05-JAN-09 67 05-MAR-08 SQL>
HTH!
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Viruses, Trojans, Malware - and other aspects of Internet Security
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https://discussions.Apple.com/docs/doc-8841
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