Single line ink = unique uniform drawn line in the trace function? Nope.

Similar Questions

• Graphics problems with a single line at the top.

  During bootup until I perfect video resolution, but after starting windows I have a single line of the video of the ideas would be useful. I already checked the wiring, video card and the BIOS settings. Anyone had this problem? This had beat me my head against the wall for a week now.

  I'm just guessing that you have a problem with
  your video driver. Maybe the info will be
  be useful...

  Good luck...

  What happens if you start in Mode safe?

  (315222) a Description of the Safe Mode
  Boot into Windows XP options
  http://support.Microsoft.com/?kbid=315222

  How to start safe mode in Windows XP
  http://bertk.MVPs.org/html/SafeMode.html

  If you start correctly in safe mode... it can
  be worth a try to roll back your video driver.

  (306546) HOW to: use the driver to restore roll back feature
  a previous Version of a device in Windows XP driver
  http://support.Microsoft.com/default.aspx?scid=kb;en-us;306546

• Reading single line of the text file

  I use the following code to read a .txt file

  private String readTextFile (String fName) {}
  String result = null;
  FileConnection fconn = null;
  DataInputStream is = null;
  try {}
  fconn = (FileConnection) Connector.open (fName, Connector.READ);
  is = fconn.openDataInputStream ();
  Byte [] = IOUtilities.streamToBytes (is) data;
  result = new String (data);
  } catch (IOException e) {}
  System.out.println (e.getMessage ());
  } {Finally
  try {}
  If (null! = is)

  is. Close();
  If (null! = fconn)
  fconn. Close();
  } catch (IOException e) {}
  System.out.println (e.getMessage ());
  }
  }
  return the result;
  }

  I want to print a single line instead of the file around so I read that I need to store the contents of the file into an array and then get the index of the line. Problem is that I couldn't find any information on how to do it. Can someone give me a shot. Thanks in advance.

  This isn't a problem with encoding. You just need to do a little extra accounting and adjust start and end indices to remove these characters. To treat the "\r\n" of line termination style, you can maintain a flag (initially false) to indicate that the previous line ended with a \r; If a line begins with \n, it should be treated as the end of a line (empty) if the flag is true (in which case it should be ignored).

  If you want to extract all lines (not just the first), then it may be easier to do this accounting while avoiding a separate function. Something like this (untested):

  // read the file into a byte array 'data'; then:
  Vector lines = new Vector();
  boolean endCR = false;
  int start = 0;
  for (i = start; i < data.length; ++i) {
    if (data[i] = 0xD) {
      lines.addElement(new String(data, start, i - start));
      endCR = true;
      start = i + 1;
    } else if (data[i] = 0xA) {
      if (endCR && i == start) {
        start++;
        endCR = false;
      } else {
        lines.addElement(new String(data, start, i - start));
        start = i + 1;
      }
      endCR = false;
    }
  }
  String[] results = new String[lines.size()];
  lines.copyInto(results);
  

• You can disable a single line within the ACL?

  We have 881g on 15.1 code with a ZBFW.

  In an ACL, ip access list extra blah, with several lines, 10,20,30, etc... is there a way to disable a single line or make it inactive any leaving it in the config? He can't see in there, don't know if it is not possible or I'm not looking for the good things.

  Thank you!

  There is no "inactive" as on the ASA. An entire book would be to do something like

  Note allowed tcp any any smtp log set EQ

  It keeps things in the config, but it does nothing since it is a comment.

• Help me.subquery belonging to a person on a single line on the lines of the Display.

  CREATE TABLE STUDENTS
  (
  NUMBER OF OPPORTUNITY,
  NAME VARCHAR2 (30 BYTE),
  STUDENT_ID);
  INSERT INTO STUDENT (LANGUAGE_ID, STUDENT_ID, NAME) VALUES)
  1, "Carol Haan", 1);
  INSERT INTO STUDENT (LANGUAGE_ID, STUDENT_ID, NAME) VALUES)
  3, "Saskia Tune", 2);
  INSERT INTO STUDENT (LANGUAGE_ID, STUDENT_ID, NAME) VALUES)
  1, "Saskia Tune", 2);
  INSERT INTO STUDENT (LANGUAGE_ID, STUDENT_ID, NAME) VALUES)
  2, "Saskia Tune", 2);
  INSERT INTO STUDENT (LANGUAGE_ID, STUDENT_ID, NAME) VALUES)
  3, "Mark Quin', 1);
  INSERT INTO STUDENT (LANGUAGE_ID, STUDENT_ID, NAME) VALUES)
  4, 'Aretha June', 3);
  INSERT INTO STUDENT (LANGUAGE_ID, STUDENT_ID, NAME) VALUES)
  1, 'Aretha June', 3);
  COMMIT;
  
  
  
  CREATE TABLE STUDENTS_JOBS
  (
  JOB_ID NUMBER,
  JOBNAME VARCHAR2 (20 BYTE),
  LANGUAGE_I);
  INSERT INTO STUDENTS_JOBS (JOB_ID, JOBNAME, LANGUAGE_ID) VALUES)
  1, "Registrar", 1);
  INSERT INTO STUDENTS_JOBS (JOB_ID, JOBNAME, LANGUAGE_ID) VALUES)
  2, 'reception clerck', 2);
  INSERT INTO STUDENTS_JOBS (JOB_ID, JOBNAME, LANGUAGE_ID) VALUES)
  2, 'reception clerck', 1);
  INSERT INTO STUDENTS_JOBS (JOB_ID, JOBNAME, LANGUAGE_ID) VALUES)
  2, 'reception clerck', 3);
  INSERT INTO STUDENTS_JOBS (JOB_ID, JOBNAME, LANGUAGE_ID) VALUES)
  3, 'manager', 1);
  INSERT INTO STUDENTS_JOBS (JOB_ID, JOBNAME, LANGUAGE_ID) VALUES)
  3, 'manager', 4);
  COMMIT;
  
  
  CREATE TABLE STUDENT_LANGUAGES
  (
  NUMBER OF OPPORTUNITY,
  LANGUAGE VARCHAR2 (30 BYTE)
  );
  INSERT INTO STUDENT_LANGUAGES (LANGUAGE_ID, LANGUAGE) VALUES)
  1, 'English');
  INSERT INTO STUDENT_LANGUAGES (LANGUAGE_ID, LANGUAGE) VALUES)
  2, "Dutch");
  INSERT INTO STUDENT_LANGUAGES (LANGUAGE_ID, LANGUAGE) VALUES)
  3, 'Spanish');
  INSERT INTO STUDENT_LANGUAGES (LANGUAGE_ID, LANGUAGE) VALUES)
  4, "Japanese");
  INSERT INTO STUDENT_LANGUAGES (LANGUAGE_ID, LANGUAGE) VALUES)
  5, 'German');
  COMMIT;
  I, ve worked with languages_id. the aiming languages_id students and students_jobs at the same
  opportunity in the student_languages. In the subquerie following students who speak the
  the languages that are required in the student_jobs are derived.
  In the example, the used job_id argument is 1, it's just in the example but it could be any job_id.
  
  SELECT DISTINCT
  $m.name
  m.student_id
  s.language
  students m, student_languages s
  Where s.language_id = m.language_id
  and not EXISTS
  ((select opportunity
  of students_jobs
  where job_id = 1) less (select opportunity
  students
  where student_id = m.student_id));
  
  The result is as follows:
  STUDENT_ID LANGUAGE NAME
  English Aretha June 3
  Japanese Aretha June 3
  Carol Haan 1 English
  Saskia Tune 2 Dutch
  Saskia Tune 2 English
  Saskia Tune 2 Spanish
  
  
  The problem is that I need a query that can put the languages in addition to the person (a line), with the language of a person in a line and not separately in different lines.
  the result should be as follows:
  student_id language name
  3 June Aretha English, Japanese
  Carol Haan 1 English
  Saskia Tune 2 Dutch, English, Spanish
  
  I don't know if this can be done with prior agreement. I really need help.
  Can someone help me pleasse. Don't mind English mine.
  
  Greetings,
  Caroline

  Hi, Caroline.

  What you want is called "Aggregation of String": make a long list, delimited containing any number of individual elements (language names, in this case).
  This page:
  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:2196162600402
  has several techniques.
  I use (and recommend) one, a user-defined function called STRAGG which can be copied directly from the above site.
  When you have installed STRAGG, you can get the results you want like this:

  SELECT    m.name
  ,         m.student_id
  ,         STRAGG (s.language)   AS all_languages
  from      students m
  ,         student_languages s
  Where     s.language_id = m.language_id
  and       not EXISTS
            (       ( select  language_id
                      from    students_jobs
                      where   job_id = 1
                    )
            minus   ( select language_id
                      from   students
                      where   student_id = m.student_id
                    )
            )
  GROUP BY  m.name
  ,         m.student_id;
  

  In Oracle 10 (and more) you can have a function like STAGG, called WM_CONCAT, that is already available.

  The site referenced above also shows how string aggregation using the "CONNECT BY...» BEFORE... ", as you said.

  Thank you for including CREATE TABLE and INSERT!

• Combine in a single line: check the box Case() and Group BY

  Hello
  
  I have a little problem and it seems my knowledge and possession is simply not enough good to slove it.
  
  To better understand my question here an example (the actual query is too large):
  Data:
  NAME, CASE_NO, GO_TAG
  Tom 10 GB
  Tom 15 GB
  Tom 20
  30 Tim
  Tim 40
  
  My query looks like this:
  SELECT NAME,
  CASE
  WHEN (GO_TAG IS NOT NULL) THEN wm_concat (CASE_NO)
  ANOTHER NULL
  END WITH_GO_TAG
  CASE
  When wm_concat (CASE_NO) (GO_TAG IS NULL) THEN
  ANOTHER NULL
  END WITHOUT_GO_TAG
  GROUP BY NAME, GO_TAG;
  
  
  Now what I get output:
  NAME, WITH_GO_TAG, WITHOUT_GO_TAG
  Tom, 10, 15', "
  Tom, ", '20'
  Tom, 10, 15', "
  Tom, cm, 30, 40'
  
  Here's my problem: I want a line instead of two lines for "Tom."
  It looks like: Tom, 10 ', 15', 20'
  
  Is this possible?
  
  You should know that I coded those SQL things to right directly in this forum to show you my problem... hope you can understand it :-)
  
  Hope someone can help me in this case.
  
  Oh, almost forgot, I (or better: my company) use Oracle Version: 10g
  
  See you soon,.
  Phil

  Hello

  Thank you. It's clearer.

  Did you count 5 lines of sample data, or 10?
  In SQL * Plus, when you finish an order with one; and then have a /, the / means "repeat the last command. So, when I run

  INSERT INTO EXAMPLE VALUES
  ('Tom', 10, 'go');
  / 
  

  I get 2 identical rows. I suppose you want only 1.

  When you say ' GROUP BY name, go_tag ', the output contains a line for each distinct combination of name and go_tag.
  If you want just one row for each distinct value of the name, just say 'GROUP BY name. If we are not group by go_tag, we must be careful that any reference to go_tag in the SELECT clause is like an aggregation function argument, like this:

  SELECT     NAME,
             STRAGG (NVL2 (go_tag, case_no, NULL))     AS with_go_tag,
             STRAGG (NVL2 (go_tag, NULL,    case_no))     AS without_go_tag
      FROM   EXAMPLE
  GROUP BY   NAME;
  

  NVL2 (a, x, y) is equivalent to
  CASES WHERE an IS NOT NULL THEN x ELSE y END to this problem, I found NVL2 easier than CASES to read and understand, but I don't maintain your code, then you should use your way of thinking is the best.

• Print the values to increment on a single line in the dynamic instruction

  How to print an increment of values in a single statement using dynamic sql?
  
  

  create table test_table (file_id number, start_id number, no_of_id number);
  
  insert into test_table(1, 1000, 3);
  insert into test_table (2, 1500, 4);
  commit;

  I want output like suite to be printed using the dynamic instructions:
  

  redo id 1 bases 1000,1001,1002,1003 ;
  redo id 2 bases 1500,1501,1502,1503,1504 ;

  I can able to print only to start the number with the following help:
  

  select 'redo id '||file_id||' bases '||start_id||';' from test_table;
  
  o/p is not what i wanted though
  redo id 1 bases 1000 ;
  redo id 2 bases 1500 ;

  Thanks for any help here!

  Hello

  You can do with plain old SQL static:

  WITH     all_ids     AS
  (
       SELECT     file_id
       ,     start_id + LEVEL - 1     AS an_id
       FROM     test_table
       CONNECT BY      PRIOR file_id        = file_id
            AND     PRIOR SYS_GUID ()  IS NOT NULL
            AND     LEVEL              <= no_of_id + 1
  )
  SELECT       'redo id '
         || file_id
         || ' BASES '
         || LISTAGG (an_id, ',') WITHIN GROUP (ORDER BY an_id)
         || ';'       AS out_txt
  FROM       all_ids
  GROUP BY  file_id
  ;
  

• Merge two lines & show to a single line in the table results

  Hi, I need to merge 2 rows with 3 columns in a single row in a table view
  
  The passes are currently displayed in form:
  
  
  Revenue-Revenue (Prior_Month) project No.-(Current_Month)
  123123 10000
  20000
  
  
  Recipes are a single column with recipes for diffreent period.
  10000 is for may
  20000 is for April
  
  Project NOT because both are the same, just the periods are different. If I'm not display period I need to merge the 2 rows & show as
  
  Revenue-Revenue (Prior_Month) project No.-(Current_Month)
  123123-10000-20000
  
  
  Please let me know how we can achieve this?
  
  thanx
  Pankaj

  .

• How to get the values in a single line, without the help of the union

  Hello
  
  I have a table with the structure and the following data
  
  EmpID address phoneno emailid
  1001 xyz
  1001 1234234
  1001 [email protected]
  1002 23434
  1002 [email protected]
  1003 abcd
  1003 [email protected]
  1004 [email protected]
  
  
  
  I need to get a result in this format.
  
  
  EMP id address phoneno emailid
  1001 xyz 1234234 [email protected]
  1002 23434 [email protected]
  1003 abcd [email protected]
  1004 [email protected]
  
  
  I can do this by using the union, but who gives a performance of questions with a large table. I want to do it using any other way using lead or something, but with the relative to data complexity, I couldn't do it.
  
  Can someone help me please?
  
  
  Natarajan
  
  Published by: Nikita on December 3, 2009 15:50

  Select employee_id, max(address), max(phone), max(email)
  from emp
  group by employee_id;
  

  Max

• How to merge data from the table with a single line

  Hello

  I have three tables subscription_type, the address and the person. Here are the details of the table

  Person Subscription_type Address                                           

  Person_Id AdressType_id Address_id

  Person_name Description Address_type_id

  Person_id

  Address details

  
  

  There are three types of different address - home, postal and previous.

  Each person can have these three different addresses.

  I want to create a view that displays all addresses of three of each person in the table of the person in a single line.

  Any help please

  In your example, there are 2 rows of columns street1, TOWN, SUBURB etc for a single person. To convert this into a single line, with the new columns we could simply use CASES or DECODE in the select as the SQL below. To understand why consolidation function THAT MAX is used - remove the MAX and GROUP BY in SQL keyword and try.

  Select full_name

  , max (case when description = "Home" then end street1) Home_Street

  , max (case when description = "Home" then end suburb) home_suburb

  , max (case when description = end of the "Home" then City) home_city

  , max (case when description = "Home" then postal code end) home_postcode

  , max (case when description = "Home" then end state_name) home_state

  , max (case when description = 'Postal' then end street1) Postal_Street

  , max (case when description = 'Postal' and then end of suburb) Postal_suburb

  , max (case when description = 'Postal' then the city) Postal_city

  , max (case when description = 'Postal' and then end of CP) Postal_postcode

  , max (case when description = 'Postal' then state_name end) Postal_state

  , max (case when description = "Back" then end street1) Prev_Street

  , max (case when description = "Back" then end suburb) Prev_suburb

  , max (case when description = "Back" then city end) Prev_city

  , max (case when description = "Back" then postal code end) Prev_postcode

  address a

  S State

  No p

  Subscription_type att

  where a.person_id = p.person_id

  and a.state_id = s.state_id

  and a.address_type_id = att.address_type_id

  Full_name group

• AF board display a single line

  I use jdev 11.1.1.5
  
  I dropped a table af... I want on UI for it to display a single row (a first)... I don't want that it displays all the lines
  
  What property should change... I remember in 11.1.1.3 there was a building known as lines, but do we have nothing in 11.1.1.5

  Or add the VO even for the modules of applications data model using a different name, click on the edit button on the top of the face of data model and change the knot tuning to return a single line for the VO. Then you have a VO which returns all the lines you use for the tables and which returns a single row.

  Timo

• Data in multiple lines concatenated into a single line to separate id

  Hello
  
  I have a t1 like this table:
  
  create table t1
  (number of c1,
  number of C2,
  C3 number (4.2)
  );
  
  Data in the table are such as:
  
  ----------------------------------------
  C1 | C2 | C3 |
  -----------------------------------------
  102. 1. 1.1 |
  102. 1. 1.2 |
  102. 2. 2.1 |
  103. 2. 2.1 |
  103. 2. 2.2 |
  -----------------------------------------
  
  How to display data by using a query above?
  
  ------------------------------------------------------
  C1 | C2 | C3 |
  -------------------------------------------------------
  102. 1, 2 | 1.1, 1.2, 2.1 |
  103. 2. 2.1, 2.2.
  ------------------------------------------------------
  
  Thank you

  So you're after what we call 'Aggregation in the chain.'

  Check this link as it highlights several techniques:

  Aggregation of string techniques

  A Re: Concat ranks of the values in a single column Michael

  At Re: multiple lines in a single line in the 'single column Table' followed by reason of Billy on the conduct of a stragg first.

  In addition, 11 GR 2 has the LISTAGG function.

• How to return to the line in the text field

  I created a form with a text field, but by filling out the form, the words don't word wrap, but just go in a single line across the field to text box.

  When can I format the text box for the return to the line?

  TKS

  Under the Options tab of the Properties dialog box, you can set the Multiline field.

• Adding code to each line at the same time?

  Is it possible to do this? Instead of having to select 400 separate lines and put the list around them item code, is it possible to make it to each line individual all at once? I really hope that nothing. I'm sitting here thinking, "there must be an easier way." Please, tell me there!
  
  Thank you!
  -Alyse

  Is the problem that you have plain text of 400 lines, and you are wanting
  to wrap

• Tags around each line automatically? If so, try to stick a
  copy all the text in a separate empty file, then go in Edition > search
  and replace.

  Just a heads-up - I'm on a Mac, so if you're on a Windows computer, the
  keyboard shortcuts may vary a little.

  For the search field, enter the character of CR - on my Mac, I have to
  Hold down the command (probably the control in Windows) key while hitting
  Check back for it leaves the input field. That should put a line break
  in the search field.

  For the replacement field, enter this:
  

• ... and then, place the cursor between 2 tags and it shift-return (or
  -have to insert a line break).

  If you run find/replace, should replace all line breaks, so
  you will need too just add the opening:
  

  
  
  • 
    .. .and closing...
    
  
  

  There may be a better GUI or regex how to do in DW, but how is it
  I know what to do (if it is still what you ask).

  CuteAlyse wrote:
  > Is it possible to do this? Instead of having to select 400 separate lines and
  > put around them, list item code is possible to do in each
  > single-line at the same time? I really hope that nothing. I'm sitting here to make
  > this, thinking, "there must be an easier way." Please, tell me there!
  >
  > Thank you!
  > - Alyse
  >

• How can I get data from each associated XMLnode in movieclips separated when you click a line in the combobox

  How can I get data from each associated XMLnode in movieclips separated when you click a line in the combobox?

  A sample of XML is like this:

  <>planter

  < Lauvtre >

  < Botanisk_navn > Acer campestre < / Botanisk_navn >

  < Norsk_navn > Naverlonn < / Norsk_navn >

  Gronn < Farge > < / fan >

  H4 < Herdighet > < / Herdighet >

  < Hoyde > 10-15 m < / Hoyde >

  < / Lauvtre >

  I have a combobox where it shows the botanical name and the Norwegian name. But the rest of the info in movieclips seem separate.

  Someone has an idea how to do this? Can I use the trace function maybe? Here is my AS3 code so far:

  var loader: URLLoader = new URLLoader();

  loader.addEventListener (Event.COMPLETE, onLoaded);

  list.addEventListener (Event.CHANGE, itemChange);

  function itemChange(e:Event):void

  {

  your. Text = list.selectedItem.data;

  TB. Text = list.selectedItem.label;

  }

  var xml;

  function onLoaded(e:Event):void

  {

  XML = new XML (e.target.data);

  var it: XMLList = xml. Planter.Lauvtre;

  for (var i: uint = 0; i < il.length (); i ++)

  {

  list.addItem ({data: it.}) Farge.Text ([i]) + "\n"+ it.» Herdighet.Text ([i]) + "\n" + it. Hoyde.text ([i]),

  label: it. Botanisk_navn. Text() [i] + "\n"+ it.» Norsk_navn. Text() [i]});

  }

  }

  Loader.Load (new URLRequest ("lauvtre.xml"));

  Thank you!

  Rheus.

  I don't know what you're trying to do.  but, if you want to fill one combobox with the botanical names and when one is chosen, the other use of logins:

  var loader: URLLoader = new URLLoader();

  loader.addEventListener (Event.COMPLETE, onLoaded);

  list.addEventListener (Event.CHANGE, itemChange);

  function itemChange(e:Event):void {}

  var selectedObj:Object = a [list.selectedIndex]

  trace (selectedObj ['fan'], selectedObj ['Botanisk'], etc);

  }

  var xml;

  var a: Array = [];

  function onLoaded(e:Event):void {}

  XML = new XML (e.target.data);

  var it: XMLList = xml. Lauvtre;

  for (var i: uint = 0; i

  list.addItem({label:il[i].child('Botanisk_navn').toString()});)

  a [i] = {'Fan': it [i].child('Farge').toString (), 'Herdighet': it [i].child('Herdighet').toString (), "Hoyde": he [i].child('Hoyde').toString (), 'Botanisk':il[i].child('Botanisk_navn').toString(),'Norsk_navn':il[i].child('Norsk_navn').toString()};}

  }

  }

  Loader.Load (new URLRequest ("test.xml"));