Split a string using regexp_substr with consecutive delimiter

I split a string with tubes as a delimiter. A string like this for example:

"THIS |" EAST | ONE | EXAMPLE '

If I do something like this:

SELECT REGEXP_SUBSTR('THIS|IS|AN|EXAMPLE', '[^|]+', 1, 4) FROM DUAL

I would get the word EXAMPLE

But if the string is like this:

"THIS |" EAST | ONE | EXAMPLE '

With the above query, I always get EXAMPLE, but the word should be in the next position (5) because after IS, there should be an empty element

Is it possible to change the regular expression to also get the empty element?

Thanks in advance

Well, the way I understand it, you get this behavior, because there is 'nothing' between the delimiters. so there is a field, so it does not display it don't think the regular expression.

Try it with a space between the delimiters - works fine.

So, with this in mind, the simplest solution might be something like that?

regexp_substr (replace(c,'||','| |'), "[^ |]") +' 1, 4)

[edited to avoid having a partial answer marked "correct"]

As mentioned below by a few others, there are other solutions using regular expressions.

The solution above does not work if more than 2 consecutive fields are empty, or if the first or last is empty.

A simple tweak to the logic would help with this:

RTrim (regexp_substr (replace (c,'|))) ',' |'), ' [^ |] +', 1, level))

However, even if it has still some limitations compared to the solution of the full regular expression mentioned by Frank, below.

[/ Edit]

Tags: Database

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