How to split a string into columns

Similar Questions

• How to split a string into several substrings parent using a delimiter

  Hello

  I am forced to split a string into several substrings parent using a delimiter.

  And insert these substrings in variuou of the columns of a table in a row.

  For example. The sting is: ABC * DEF * GHI * JKH *.

  where ' *' is the separator.

  Desired output:

  Col1 Col2 Col3 Col4 Col5

  -------     --------     --------     -------     ---------

  JKH GHI ABC DEF (null)

  Could you please guide me how can I achieve this.

  Thank you

  Bogoss

  Hello Salim,

  Leave the thread for reference... got this excerpt:

  with t as

  (

  Select "c: its: hgfd:1:23" Str

  )

  Select

  REGEXP_SUBSTR (str, ' ([^:] *)(:|$)', 1, 1, null, 1) col1

  , REGEXP_SUBSTR (str, ' ([^:] *)(:|$)', 1, 2, null, 1) col2

  , REGEXP_SUBSTR (str, ' ([^:] *)(:|$)', 1, 3, null, 1) col3

  , REGEXP_SUBSTR (str, ' ([^:] *)(:|$)', 1, 4, null, 1) col4

  , REGEXP_SUBSTR (str, ' ([^:] *)(:|$)', 1, 5, null, 1) col5

  t;

  This code snippet works well, but for the fixed columns. Here are 5 predefined columns.

  But I need to have a logic that I can browse the string any No.. sometimes.

  For example. If I get 3 secondary channels of the parent chain... I need to insert into 3 columns.

  And if I get 6 strings under... I need to insert into 6 columns.

  Could you please help me develop a logic like that.

  I use Oracle database 10g.

  And the data are currently being collected on external table... but I can store in a variable or a column of a database table.

  Thank you

  Bogoss

• Split a string into lines {< string1 >} | {< string2 >}

  I implemented the Oracle text search in my database. Now I have this query

  Select ctx_thes.syn ('RED', 'MY_THESAURUS') of double;

  the output is displayed as

  {RED} | {MIXTURE OF RED} | {TABLE RED} | {RED}

  and I want to get the words in separate lines, i.e.

  Red

  Mixture of Red

  Red table

  Red wine

  How to split the string into lines?

  SELECT *
    FROM (    SELECT DISTINCT
                     REGEXP_SUBSTR ('{RED}|{RED BLEND}|{RED TABLE}|{RED WINE}',
                                    '({)([A-Z]+ *[A-Z]*)(})',
                                    1,
                                    LEVEL,
                                    'i',
                                    2)
                        val
                FROM DUAL
          CONNECT BY LEVEL <=
                          REGEXP_COUNT (
                             '{RED}|{RED BLEND}|{RED TABLE}|{RED WINE}',
                             '|')
                        + 1)
   WHERE val IS NOT NULL;
  

• splits the string into 3 parts

  Hello

  I have a requirement to split the string into 3 different room example inf.ethz.ch should be subdivided into inf ethz ch in 3 different column

  We have table called email within this column contains all identification of email we need to divide email with dot (.) in different columns and display please suggest how to implement in the query

  Thank you

  Sudhir

  Use REGEXP_SUBSTR:

  SQL > with t as (select ' inf.ethz.ch' double txt)
  2 Select regexp_substr (txt,'[^.] +') part_1,.
  3 regexp_substr (txt,'[^.] +', 1, 2) part_2,.
  4 regexp_substr (txt,'[^.] +' 1, 3) part_3
  5 t
  6.

  BY PARTY PA
  --- ---- --
  INF ethz ch

  SQL >

  Or you can use SUBSTR + Instr.

  SY.

• Oracle regular expressions - splits the string into words for

  Hello

  Nice day!

  My requirement is to split the string into words.

  So I need to identify the new line character and the semicolon (;), comma and space like terminator for string entry.

  Please note that I am currently embedded blank and the comma as separator, as shown below.

  Select regexp_substr('test)
  TO
  string in words, "([^, [: blanc:]] +) (', 1, 1) double;"

  How to integrate the semicolons and line break characters in regular expression Oracle?

  Please notify.

  Thanks and greetings

  Sree

  This has nothing to do with REGEXP. Is SQL * more parser does not not a semicolon at the end of the line:

  SQL > select ' testto, mm\;
  ERROR:
  ORA-01756: city not properly finished chain

  SQL >

  Just break the chain:

  SQL > select regexp_substr ('testto, mm\;' |) '
  2 string into words
  3 \w+',1,level ',') of double
  4. connect by level<= regexp_count('testto,mm\;'="" ||="">
  5 string in words
  6      ','\w+')
  7.

  REGEXP_SUBSTR ('TESTTO, MM\;' |') STRINGIN
  --------------------------------------
  Testto
  mm
  string
  in
  Words

  SQL >

  Or modify SQL * more the character of endpoints:

  SQL > set sqlterm.
  SQL > select regexp_substr ('testto, mm\;)
  2 string into words
  3 \w+',1,level ',') of double
  4. connect by level<=>
  5 string in words
  6      ','\w+')
  7.

  REGEXP_SUBSTR ('TESTTO, MM\;) STRINGINTOWO
  --------------------------------------
  Testto
  mm
  string
  in
  Words

  SQL >

  SY.

• split a string into pl/sql

  Hello
  
  How to split a string and store in an associative array in pl/sql.function
  
  My string like this
  
  '1102,1101,1012,1011,1010,1009,1008,1007,1006,10005,1004,1003,1002,1001'
  and assign it to the array list. According to
  can someone please help
  
  concerning
  r

  You can try the following. Although I recommend, it would be better to write the function code php as a java stored procedure parser and use the result. We have a class defined in Java String Tokenizer.

  -- Define function to split string into tokens
  FUNCTION get_token(
      p_input_string IN VARCHAR2,            -- input string
      p_token_number IN PLS_INTEGER,         -- token number
      p_delimiter    IN VARCHAR2 DEFAULT ',' -- separator character
    )
    RETURN VARCHAR2
  IS
    v_temp_string VARCHAR2(32767) := p_delimiter || p_input_string ;
    v_pos1 PLS_INTEGER ;
    v_pos2 PLS_INTEGER ;
  BEGIN
    v_pos1     := INSTR( v_temp_string, p_delimiter, 1, p_token_number ) ;
    IF v_pos1   > 0 THEN
      v_pos2   := INSTR( v_temp_string, p_delimiter, 1, p_token_number + 1) ;
      IF v_pos2 = 0 THEN
        v_pos2 := LENGTH( v_temp_string ) + 1 ;
      END IF ;
      RETURN( SUBSTR( v_temp_string, v_pos1+1, v_pos2 - v_pos1-1 ) ) ;
    ELSE
      RETURN NULL ;
    END IF ;
  EXCEPTION
    WHEN OTHERS THEN
      RAISE;
  END get_token;
  
  -- Call the above function in loop for a string with N tokens
  DECLARE
        TYPE assoc_arr_str_typ IS TABLE OF VARCHAR2(100) INDEX BY PLS_INTEGER;
        str_arr assoc_arr_str_typ;
  
        v_str VARCHAR2(200) := '1102,1101,1012,1011,1010,1009,1008,1007,1006,10005,1004,1003,1002,1001' ;
        v_token   VARCHAR2(4) ;
        i          PLS_INTEGER := 1 ;
      BEGIN
        LOOP
          v_token := get_token( v_str, i , ',') ;
          EXIT WHEN v_token IS NULL ;
          dbms_output.put_line( v_token ) ;
          str_arr(i) := v_token;
          i := i + 1 ;
       END LOOP ;
    END ;
   /
  

  Published by: GG 24 March 2011 09:51

• Simple question: how to divide the string into multiple lines concatenated?

  Hi people,
  
  Maybe it's an easy question.
  
  How to split a string that is concatenated into multiple lines by using the SQL query?
  
  ENTRY:

  select 'AAA,BBB,CC,DDDD' as data from dual

  Delimiter = ', '.
  
  Expected results:

  data
  ------------
  AAA
  BBB
  CCC
  DDDD

  I'm looking for something nice to feature "an opposite to «sys_connect_by_path»»
  
  Thank you
  Tomas

  with t as (select 'aaaa,,bbbb,cccc,dddd,eeee,ffff' as txt from dual)
  -- end of sample data
  select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
  from t
  connect by level <= length(regexp_replace(txt,'[^,]*'))+1
  
  REGEXP_SUBSTR(TXT,'[^,]+',1,LE
  ------------------------------
  aaaa
  bbbb
  cccc
  dddd
  eeee
  ffff
  

• split a string into separate variables

  Suppose I have a procedure that returns the following for the parameter,

  V_STR: = ' 10077500733 | 10077500733 | 14/04/2015 | Τ | AJ240557 | 2012 | GREECE | GR | MAN | 00108337640 | CLARKSON | DAVID"

  How to cut this string into separate variables?

  for example v1 = 10077500733

  v3 = 14/04/2015

  v4 = null;

  Thank you

  with qry (STR) as)

  Select ' 10077500733 | 10077500733 | 14/04/2015 | T | AJ240557 | 2012 | GREECE | GR | MAN | 00108337640 | CLARKSON | DAVID' the double

  )

  Select the level,

  RTrim (regexp_substr (str, ' [^ |] *(.| $) ', 1, level), ' |') ASPLIT

  of qry

  connect by level<= length="" (regexp_replace="" (str,="" '[^|]+'))="" +="">

  LEVEL	ASPLIT
  1	'10077500733'
  2	'10077500733'
  3	April 14, 2015"
  4
  5	' T '
  6	'AJ240557 '.
  7	'2012 '.
  8	"GREECE".
  9	"GR".
  10	"THE MAN".
  11	'00108337640'
  12	"CLARKSON."
  13	"DAVID."

• How to split a PDF into smaller files using Acrobat XI

  How to split a PDF into smaller files using Acrobat XI?

  Hi laforcej

  Open the PDF in Acrobat...

  Go to tools-> Pages-> extract

  Now, select the Page number, you want to extract and save

• splits the string into documents

  Hello
  
  I did a query (see regexp) that split a string into records. The problem with the query is the separate in the subquery. Otherwise, it returns millions of records where I expect less than a thousand.
  Meanwhile, I found an other solution (see xmlsequence), but this statement returns the message "ORA-03113: end of file on the communication channel.
  
  Please advice.
  
  regexp:

      SELECT smp.sample_id
      FROM
      (
          SELECT sa.sample_id, sau.u_box_code, sau.u_box_position
          FROM lims_sys.sdg sd, lims_sys.sdg_user sdu, lims_sys.sample sa, lims_sys.sample_user sau
          WHERE sd.sdg_id = sdu.sdg_id
          AND sd.sdg_id = sa.sdg_id
          AND sa.sample_id = sau.sample_id
          AND sau.u_padded_out = 'F'
          AND sdu.u_client_type =  decode('#Client#','-1',sdu.u_client_type,'#Client#')
          AND sdu.u_crop_group = decode('#Crop#','-1',sdu.u_crop_group,'#Crop#')
          AND sdu.u_year_of_sample_delivery = decode('#Year#',-1,sdu.u_year_of_sample_delivery,'#Year#')
          AND sdu.u_week_of_processing = decode('#Week#',-1,sdu.u_week_of_processing,'#Week#')
          AND sd.status IN ('V','P','C')
      ) smp,
      (
          SELECT distinct box_code, regexp_substr(box_pos,'[^,]+',1,level) box_pos 
          FROM
          (
               SELECT p.name box_code, substr(p.description,instr(p.description, 'NP=') + 3) box_pos
               FROM lims_sys.plate_template pt, lims_sys.plate p, lims_sys.plate_user pu
               WHERE pt.plate_template_id = p.plate_template_id
               AND p.plate_id = pu.plate_id
               AND pt.name = 'Box96'
               AND p.status IN ('V','P','C')
               AND p.description like '%NP=%'
               AND pu.u_client_type = decode('#Client#','-1',pu.u_client_type,'#Client#')
               AND pu.u_crop_group = decode('#Crop#','-1',pu.u_crop_group,'#Crop#')
               AND pu.u_year = decode('#Year#',-1,pu.u_year,'#Year#')
               AND pu.u_week = decode('#Week#',-1,pu.u_week,'#Week#')
           )
           connect by level <= length(box_pos) - length(replace(box_pos,',')) + 1
      ) box
      WHERE smp.u_box_code = box.box_code
      AND smp.u_box_position = box.box_pos

  xmlsequence:

      SELECT smp.sample_id
      FROM
      (
          SELECT sa.sample_id, sau.u_box_code, sau.u_box_position
          FROM lims_sys.sdg sd, lims_sys.sdg_user sdu, lims_sys.sample sa, lims_sys.sample_user sau
          WHERE sd.sdg_id = sdu.sdg_id
          AND sd.sdg_id = sa.sdg_id
          AND sa.sample_id = sau.sample_id
          AND sau.u_padded_out = 'F'
          AND sdu.u_client_type =  decode('#Client#','-1',sdu.u_client_type,'#Client#')
          AND sdu.u_crop_group = decode('#Crop#','-1',sdu.u_crop_group,'#Crop#')
          AND sdu.u_year_of_sample_delivery = decode('#Year#',-1,sdu.u_year_of_sample_delivery,'#Year#')
          AND sdu.u_week_of_processing = decode('#Week#',-1,sdu.u_week_of_processing,'#Week#')
          AND sd.status IN ('V','P','C')
      ) smp,
      (
          SELECT  box_code, trim(x.column_value.extract('e/text()')) box_pos 
          FROM
          (
               SELECT p.name box_code, substr(p.description,instr(p.description, 'NP=') + 3) box_pos
               FROM lims_sys.plate_template pt, lims_sys.plate p, lims_sys.plate_user pu
               WHERE pt.plate_template_id = p.plate_template_id
               AND p.plate_id = pu.plate_id
               AND pt.name = 'Box96'
               AND p.status IN ('V','P','C')
               AND p.description like '%NP=%'
               AND pu.u_client_type = decode('#Client#','-1',pu.u_client_type,'#Client#')
               AND pu.u_crop_group = decode('#Crop#','-1',pu.u_crop_group,'#Crop#')
               AND pu.u_year = decode('#Year#',-1,pu.u_year,'#Year#')
               AND pu.u_week = decode('#Week#',-1,pu.u_week,'#Week#')
           ) t, table (xmlsequence(xmltype('<e><e>' || replace(t.box_pos,',','</e><e>')|| '</e></e>').extract('e/e'))) x
      ) box
      WHERE smp.u_box_code = box.box_code

  Hello

  When 'LEVEL '.<= x"="" is="" the="" only="" connect="" by="" condition,="" then="" you="" should="" be="" using="" a="" table="" that="" has="" only="" one="" row,="" like="">

  You can generate a Table of counters (a result set, in fact) who has all the integers that you need and then join one.
  The next thread is an example:
  I don't don't want to mark in plsql

• SQL / PLSQL to split the string into pieces

  Hi all
  
  I have a problem of data conversion from the name of one table to another structure.
  
  for example
  
  SQL > desc names
  Name Null? Type
  ----------------------------------------- -------- ----------------------------
  TITLE VARCHAR2 (5)
  FNAME VARCHAR2 (20)
  LNAME VARCHAR2 (20)
  
  SQL > Data desc
  Name Null? Type
  ----------------------------------------- -------- ----------------------------
  FULLNAME VARCHAR2 (50)
  
  
  Insert in data values ("SIR I HAVE ONE NAME PARTICULARLY LONG INDEED");
  Insert in the data values ("MINE IS EVEN MORE, ENOUGH RIDICULEMENT so IN FACT");
  
  Essentially, I need to divide these names long, stored in the 1 field, in the above 3 fields. The trickiest part is however I want to do it in such a way so that if the 1st part of the name fits the 1 5 char field I want to do, otherwise I would divide between 2 fields - once again without splitting a string. The reason behind this is that application will automatically put a space between each field when they appear and I would avoid gaps in the names if possible.
  
  This baffled me a little if any help would be seriously great... it might not even be a go-er, as it might be too uneconomic with the amount of available space, but I would give it a shot.
  
  Thank you!
  Adam

  Hi, Adam.

  Use regular expressions:

  INSERT INTO names (title, fname, lname)
  SELECT  RTRIM (REGEXP_SUBSTR ( fullname
                            , '^.{1,5} '
                      )
             )
  ,     REGEXP_REPLACE ( fullname
                   , '(^.{1,5} )?'       ||     -- \1      = optional 1-5-letter word(s)
                         '(.{1,20})'       ||     -- \2       = 1-20 letters
                  '(( .*)|$)'          -- \3-\4 = space (plus anything) or end
                   , '\2'
                   )
  ,     REGEXP_REPLACE ( fullname
                   , '(^.{1,5} )?'       ||     -- \1      = optional 1-5-letter word(s)
                         '(.{1,20}( |$))' ||     -- \2-\3 = 1-20 letters and space or end
                         '(.{1,20})?'       ||     -- \4       = 0-20 letters
                  '(( .*)|$)'          -- \5       = space (plus anything) or end
                   , '\4'
                   )
  FROM     data_table          -- data is not a good name
  ;
  

  Published by: Frank Kulash, August 18, 2009 11:13
  Revised to manage long single word fullname

• split a string into a single alpha character

  Hello
  
  I would like to know how to divide this string "ABC123XYZ! "@ > ' unique and don't get as 'ABCXYZ' alphabets as an output using pl/sql.
  
  Any suggestions please.
  
  Thank you.

  SQL:

  SQL> select  regexp_replace(' ABC123XYZ!@> ','[^[:alpha:]]') from dual
    2  /
  
  REGEXP
  ------
  ABCXYZ
  
  SQL> 
  

  PL/SQL:

  SQL> set serveroutput on
  SQL> exec dbms_output.put_line(regexp_replace(' ABC123XYZ!@> ','[^[:alpha:]]'));
  ABCXYZ
  
  PL/SQL procedure successfully completed.
  
  SQL> 
  

  SY.

• How to parse this string into an array

  Someone sees an easy way to parse this string into an array of type

  [Street 1, 2, city, zip code]

  the string:

  '

  [

  [address = "Paris Ltd, 5 North Street, Athens, SW1X 9the"]

  [address = "Paris Ltd, 5 North Street, Athens, SW1X 9the"]

  ]

  '

  THX

  If you want just the address as a single entry as myArray [1] = 'Paris Ltd, 5 North, Athens, SW1X 9A Street', then try this:

  If you really want the different elements had a blast, you would need a picture of structures, so you get .street1 myArray [1] = 'Paris Ltd ':

  Note: As Steve has pointed out, you may need to test for listLen() on the addressList object to determine whether or not there is a street.2 entry in any given row.

• Splits the string into two columns

  Can someone please help me the following
  
  I want to divide into two columns URL and ID /cfd/abc.html,/night/aaa/Page1,/can/MLP/Page2|107
  
  Result must be
  
  Temporary table
  < font color = "red" > URL < / police > < font color = 'blue' > ID < / make >
  
  < font color = "red" > /cfd/abc.html < / police > < font color = "blue" > 107 < / make >
  
  < font color = "red" > / night/aaa/page 1 < / police > < font color = "blue" > 107 < / make >
  
  < font color = "red" > / can/MLP/Page2 < / police > < font color = "blue" > 107 < / make >
  
  
  There can be N number of comma separated URLs, but there will be only 1 separate ID which is the vertical bar (|)

  Try this,

  SQL> WITH T
    2       AS (SELECT  '/cfd/abc.html,/night/aaa/Page1,/can/MLP/Page2|107 ' str FROM DUAL UNION ALL
    3           SELECT  '/cfd/def.html,/bbbb/bbbb/Page1,/lll/MLP/Page3|108 ' str FROM DUAL)
    4  SELECT REGEXP_SUBSTR ( str, '[^,|]+', 1, lvl) URL,
    5         REGEXP_SUBSTR ( str, '[^|]+', 1, 2) ID
    6    FROM T,
    7         (SELECT LEVEL lvl
    8            FROM (SELECT MAX (LENGTH (REGEXP_REPLACE ( str, '[^,]'))) mx FROM T)
    9          CONNECT BY LEVEL <= mx + 1)
   10   WHERE Lvl - 1 <= LENGTH (REGEXP_REPLACE ( str, '[^,]+'))
   11   order by id,lvl;
  
  URL                                                ID
  -------------------------------------------------- -------------------------------------------------
  /cfd/abc.html                                      107
  /night/aaa/Page1                                   107
  /can/MLP/Page2                                     107
  /cfd/def.html                                      108
  /bbbb/bbbb/Page1                                   108
  /lll/MLP/Page3                                     108
  
  6 rows selected.
  
  SQL> 
  

  G.

• Splits the string into two columns to dashboard

  Hi all
  
  I got thisworking
  
  decode (SUBSTR (ADDR2_ATTR_1, 1, INSTR(ADDR2_ATTR_1,'-')-1), '9999', NULL, (SUBSTR (ADDR2_ATTR_1, 1, INSTR(ADDR2_ATTR_1,'-')-1))),
  
  decode (SUBSTR (ADDR2_ATTR_1, INSTR (ADDR2_ATTR_1,'-') + 1), '9999', NULL, (SUBSTR (ADDR2_ATTR_1, INSTR(ADDR2_ATTR_1,'-') + 1)))
  
  but the results were a little different.
  
  It came as
  
  Col1 for 8-10 have come beauiful... .but however Col2 data should be in K1 and transferred to Col2
  
  Col1 Col2
  < null > 10
  < null > 33
  8 10
  
  Any guidance is appreciated.

  Personally, I like the cases, but another way using the DECODE method...

  WITH t AS
          (SELECT '8-10' str FROM DUAL
           UNION ALL
           SELECT '163' FROM DUAL
           UNION ALL
           SELECT '789' FROM DUAL)
  SELECT str col1,
         DECODE (NVL2 (NULLIF (INSTR (str, '-'), 0), 99999, 0),99999, SUBSTR (str, 1, INSTR (str, '-', 1) - 1),str) col2,
         DECODE (NVL2 (NULLIF (INSTR (str, '-'), 0), 99999, 0),99999, SUBSTR (str, INSTR (str, '-', 1) + 1),NULL) col3
    FROM t;
  

  Simplified:
  ------

  WITH t AS
          (SELECT '8-10' str FROM DUAL
           UNION ALL
           SELECT '163' FROM DUAL
           UNION ALL
           SELECT '789' FROM DUAL)
  SELECT str col1,
         DECODE (SIGN (INSTR (str, '-')),1, SUBSTR (str, 1, INSTR (str, '-', 1) - 1),str)  col2,
         DECODE (SIGN (INSTR (str, '-')),1, SUBSTR (str, INSTR (str, '-', 1) + 1), NULL) col3
    FROM t;
  

  OUTPUT:

  COL1     COL2     COL3
  8-10     8     10
  163     163
  789     789     
  

  See you soon,.
  Manik.

  Published by: adding a simplified version