split the data on each colon

Hello

I have some data in a column in my table, it is stored as 1:2:3. When I have this query with the following query:

SELECT
'SRR_SERVICES '. "" SHR_ID_FROM ".
Of
'SRR_SERVICES '.

The output will be:

SHR_ID_FROM
1:2:3

I have woul like the output to be:

SHR_ID_FROM
1
2
3

How can I achieve this?

For example in 10g using settlers...

SQL> ed
Wrote file afiedt.buf

  1  select regexp_substr('1:2:3','[0-9]+',1,level) vals from dual
  2* connect by level<=length(regexp_replace('1:2:3','[^:]'))+1
SQL> /

VALS
-----
1
2
3

SQL>

Tags: Database

Similar Questions

Windows Media Player 11 Date added function - please stop repeating the date for EACH file.

I have been using Media Player 9, decided to upgrade to Windows Media Player 11, and the only thing I can not stand on Player 11 is how it sorts Date added media files. In Player 9 when I chose the column Date added, the program would list all the files on a given under a SINGLE date. With Windows Media Player 11 it lists EACH file with a date so that instead of see Tuesday, December 14, 2010 once and then listing all of the files under it, I see Tuesday, December 14, 2010 about twenty times. I download podcasts once a week and dump it on my phone, but it's a worry now. Is it possible to stop Windows Media Player 11 to repeat the date again and again and force him to the date that the list only once? Think back to Player 9. Alex

Hi Alex103,

It's design in Windows media player 11 and it is also included in Windows Media player 12.

However, you can uncheck this option, follow the steps below:

a. open windows Media player

b. right-click on one of the sorted column

c. click Choose column

d. uncheck data added

With regard to:

Samhrutha G S - Microsoft technical support.

Visit our Microsoft answers feedback Forum and let us know what you think.

Split the data

Hi all

The Oracle worm: 10 gr 2.

Requriment is from the below query am getting the output as below, 

_*Query*_

with dates
as
(select to_date('2005 05', 'YYYY MM') start_date, to_date('2006 07', 'YYYY MM') end_date 
 from dual)
select substr(max(sys_connect_by_path(to_char(ADD_MONTHS(start_date, level - 1),'YYYY MM'),',')),2)
from dates
connect by ADD_MONTHS(start_date,level) <= end_date

_*Output*_

2005 05,2005 06,2005 07,2005 08,2005 09,2005 10,2005 11,2005 12,2006 01,2006 02,2006 03,2006 04,2006 05,2006 06

But is there any way that i can split the output as below 

_*Expected Output*_

2005 05,
2005 06,
2005 07,
.....
....
...
2006 05,
2006 06

Iam trying with decode, level and connect by level but the query is wrong hoping am making some logic issues. Can someone
help me out to get the desired output. Thanks in advance.

WITH t AS
     (SELECT '2005 05,2005 06,2005 07,2005 08,2005 09,2005 10,2005 11,2005 12,2006 01,2006 02,2006 03,2006 04,2006 05,2006 06'
                                                                          col
        FROM DUAL)
SELECT     LEVEL, LENGTH (REGEXP_REPLACE (col, '[^,]')),
           LTRIM (REGEXP_SUBSTR (col, '[^,]+', 1, LEVEL), ',')
      FROM t
CONNECT BY LEVEL <= LENGTH (REGEXP_REPLACE (col, '[^,]'))

From your query:

SELECT     LEVEL, LENGTH (REGEXP_REPLACE (col, '[^,]')),
           LTRIM (REGEXP_SUBSTR (col, '[^,]+', 1, LEVEL), ',')
      FROM (
WITH dates AS
     (SELECT TO_DATE ('2005 05', 'YYYY MM') start_date,
             TO_DATE ('2006 07', 'YYYY MM') end_date
        FROM DUAL)
SELECT     SUBSTR
                (MAX (SYS_CONNECT_BY_PATH (TO_CHAR (ADD_MONTHS (start_date,
                                                                LEVEL - 1
                                                               ),
                                                    'YYYY MM'
                                                   ),
                                           ','
                                          )
                     ),
                 2
                ) col
      FROM dates
CONNECT BY ADD_MONTHS (start_date, LEVEL) <= end_date)
CONNECT BY LEVEL <= LENGTH (REGEXP_REPLACE (col, '[^,]'))

Published by: user2361373 on Sep 8, 2011 06:36

Get the date of each month in the last year

Hi all

I need to find the last date of the month for the year.

Example:

I used to spend the date or such year 2012 or 01-01-2012(DD-MM-YYYY)

SQL query should return the last date of the month as

31/01/2012

28/02/2012

31/03/2012

30/04/2012

12/31/2012

For more top the requirement that I wrote the SQL code following

select rownum as row_count,
case when rownum=1 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as Jan_month,
case when rownum=2 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as Feb_month,
case when rownum=3 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as mar_month,
case when rownum=4 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as apr_month,
case when rownum=5 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as may_month,
case when rownum=6 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as jun_month,
case when rownum=7 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as jul_month,
case when rownum=8 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as aug_month,
case when rownum=9 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as sep_month,
case when rownum=10 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as oct_month,
case when rownum=11 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as nov_month,
case when rownum=12 then last_day(to_date(add_months(trunc(to_date('01-01-2012','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as dec_month


from dual connect by level <= 12 order by rownum;

Result

Jan_Month

Feb_Month

Mar_Month

Apr_Month

may_month

jun_month

jul_month

aug_month

sep_month

oct_month

nov_month

dec_month

31/01/2014

28/02/2014

31/03/2014

30/04/2014

31/05/2014

30/06/2014

31/07/2014

31/08/2014

30/09/2014

31/10/2014

30/11/2014

12/31/2012

Except the result:

am result except as single line such as

Jan_Month	Feb_Month	Mar_Month	Apr_Month	may_month	jun_month	jul_month	aug_month	sep_month	oct_month	nov_month	dec_month
31/01/2012	28/02/2012	31/03/2012	30/04/2012	31/05/2012	30/06/2012	31/07/2012	31/08/2012	30/09/2012	10/31/2012	30/11/2012	12/31/2012

Kindly give me suggestion to archive more high result.

Thanks and greetings

Saami

I agree with Marcus Pivot is the way to go on this subject... But on the other hand you almost solved yourself... it was just a max function for your results:

---------

select
max(case  when rownum=1 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as Jan_month,
max(case  when rownum=2 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as Feb_month,
max(case  when rownum=3 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as mar_month,
max(case  when rownum=4 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as apr_month,
max(case  when rownum=5 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as may_month,
max(case  when rownum=6 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as jun_month,
max(case  when rownum=7 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as jul_month,
max(case  when rownum=8 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as aug_month,
max(case  when rownum=9 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as sep_month,
max(case  when rownum=10 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as oct_month,
max(case  when rownum=11 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as nov_month,
max(case  when rownum=12 then last_day(to_date(add_months(trunc(to_date('01-01-2012','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as dec_month
from dual connect by level <= 12 order by rownum;

AND to avoid hard-coding, you can also modify your query in the form:

select
max(case  when rownum=1 then last_day(to_date(to_char(rownum),'MM')) end) as Jan_month,
max(case  when rownum=2 then last_day(to_date(to_char(rownum),'MM')) end) as Feb_month,
max(case  when rownum=3 then last_day(to_date(to_char(rownum),'MM')) end) as mar_month,
max(case  when rownum=4 then last_day(to_date(to_char(rownum),'MM')) end) as apr_month,
max(case  when rownum=5 then last_day(to_date(to_char(rownum),'MM')) end) as may_month,
max(case  when rownum=6 then last_day(to_date(to_char(rownum),'MM')) end) as jun_month,
max(case  when rownum=7 then last_day(to_date(to_char(rownum),'MM')) end) as jul_month,
max(case  when rownum=8 then last_day(to_date(to_char(rownum),'MM')) end) as aug_month,
max(case  when rownum=9 then last_day(to_date(to_char(rownum),'MM')) end) as sep_month,
max(case  when rownum=10 then last_day(to_date(to_char(rownum),'MM')) end) as oct_month,
max(case  when rownum=11 then last_day(to_date(to_char(rownum),'MM')) end) as nov_month,
max(case  when rownum=12 then last_day(to_date(to_char(rownum),'MM')) end) as dec_month
from dual connect by level <= 12 order by rownum;

Easy way: (without login)

SELECT LAST_DAY (TO_DATE (ROWNUM, 'MM')) AS Jan_month,
       LAST_DAY (TO_DATE (ROWNUM + 1, 'MM')) AS Feb_month,
       LAST_DAY (TO_DATE (ROWNUM + 2, 'MM')) AS Mar_month,
       LAST_DAY (TO_DATE (ROWNUM + 3, 'MM')) AS Apr_month,
       LAST_DAY (TO_DATE (ROWNUM + 4, 'MM')) AS May_month,
       LAST_DAY (TO_DATE (ROWNUM + 5, 'MM')) AS Jun_month,
       LAST_DAY (TO_DATE (ROWNUM + 6, 'MM')) AS Jul_month,
       LAST_DAY (TO_DATE (ROWNUM + 7, 'MM')) AS Aug_month,
       LAST_DAY (TO_DATE (ROWNUM + 8, 'MM')) AS Sep_month,
       LAST_DAY (TO_DATE (ROWNUM + 9, 'MM')) AS Oct_month,
       LAST_DAY (TO_DATE (ROWNUM + 10, 'MM')) AS Nov_month,
       LAST_DAY (TO_DATE (ROWNUM + 11, 'MM')) AS Dec_month
  FROM DUAL

See you soon,.

Manik.

The data of each virtual machine in the list store

We would like to know where to find Datastore (MON) our VMs and integrate in our weekly report.
Someone has an idea, how we could do that?
Any help would be appreciated!

The data in the report are in the $report variable.

Now it depends on where and in what format, you want your state.

If you want a CSV file, you could do
```
$report = @()
Get-VM | Get-View | % {
     $row = "" | select Name, Datastore, Path
     $row.Name = $_.Name
     $row.Datastore = (Get-View $_.Datastore[0]).Summary.Name
     $current = Get-View $_.Parent
     $path = $_.Name
     do {
          $parent = $current
          if($parent.Name -ne "vm"){$path = $parent.Name + "\" + $path}
          $current = Get-View $current.Parent
     } while ($current.Parent -ne $null)
     $row.Path = $path
     $report += $row
}
$report | Export-Csv "C:\VM-ds-report.csv" -noTypeInformation
```
If you want to get a report to HTML format, you can replace the last line to
```
$report | ConvertTo-Html | Set-Content "c:\VM-ds-report.html"
```
Note that it comes to the ConvertTo-Html cmdlet in its simplest form, you can use the parameters (- title, - head - body) to improve the output.

There are a number of samples of these two methods in this community to quit smoking.

For outlook HTML for example have a peek at the Script to the list of Annotations.

And there are several scripts for reporting have been entered in the script of last year competition.

Those that you can find in the community Community Sample Code .

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Post edited by: LucD

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Hello

Please give me brief idea or document for this concept:

I need to create id, date, update id, updated for each record inserted or updated in the database (multiple tables).

(1) how the user id can be obtained?
(2) is it better if I use views instead of tables for this?
(3) is it possible for each record?

Please show me the full scenario. a piece of code can also be useful.

Thanks in advance.
http://psoug.org/reference/table_trigger.html

Concerning
Biju

split the data belonging to the same group at two different levels
Hello

I have data in the same group I want to split into two levels.

For example: If the XML is:

< data >
Taxable < Type > < / type >
< value1 > one < / value1 >
b < value2 > < / value2 >
< / data >
< data >
Taxable < Type > < / type >
e < value1 > < / 1 >
f < value2 > < / value2 >
< / data >
< data >
Taxable < Type > < / type >
g < value1 > < / 1 >
h < value2 > < / value2 >
< / data >
< data >
Taxable < Type > < / type >
u < value1 > < / 1 >
v < value2 > < / value2 >
< / data >
< data >
Taxable < Type > < / type >
o < value1 > < / 1 >
< value2 > x < / value2 >
< / data >

The output using the RTF model should be:

Taxable
a and b
e f
g h

Not taxable
u v
l x

I can't change the query to add a group.

Kindly, if anyone can help

Published by: user10606061 on 25/06/2012 01:05

delete a table with 2 columns and two rows. In the second column of row 1

in column 2

table below

PS: your must be within a root element

How to extract the data from each row
Hello

I wrote a CQL query with lines 3 records. Is it possible in this query to fetch the first record and last present specific field values.

for example,.
Column: c1, c2, c3
Record1: id1, 2,3, 3.5
Record2: id2, 2.3, 3.6
record Record3: id21, 2.3, 3.7
record Record3: id25, 2.3, 3.9

I need to get the average of three rows of c3 and get the first record id and last record ID.

Output 1: id1 id1, avg (c3) = 3.5
output2: id1, id2, avg (c3) = 3.55
Output3: id1, id21, avg (c3) = 3.6
output4: id2, id25, avg (c3) = 3.733

Please help on above.

Thank you
Sri
Hello

Not quite sure that understand what is the problem that you see.

Here's what I got when I ran the query:

Input data:

C1, c2, c3
ID1, 2,3, 3.5
ID2, 2.3, 3.6
id21, 2.3, 3.7
ID25, 2.3, 3.9
DELAYED26, 2.3, 4.0
ID27, 2.3, 4.1

Query:

Select T.firstC1, T.lastC1, S1 T.avgC3
() match_recognize
measures
First (M1. C1) as firstC1,
M2. C1 as lastC1,
AVG (C3) as avgC3
all matches
model (A B? C ? | D + C)
subset m1 m2 = (A, B, C) =(A,D)
define
At as prev (A.c1) is null.
B as (count (*) = 2),
C as (count (*) = 3),
D like ((prev (D.c1) is not null) and (count (*))<>
) t

Output:

firstc1, lastC1, avgC3
ID1, id1, 3.5 - avg only trace
ID1, id2, 3.55 - avg from two records
ID1, id21, 3.6000001 - avg from three recent reviews
Id2, id25, 3.7333336 - avg from three recent reviews
id21, delayed26, 3.8666668 - avg from three recent reviews
ID25, id27, 4.0 - average last three book reviews

This output confirms with you that mentioned the expected results?
Can you please run this query as it is on the above mentioned input data and check by yourself?
If you don't get the desired result, please paste the input data provided, complete the text of the query and the outputs.

Concerning

Distribute the data in a column and update new column with data of split
Hi all

I'm working on Oracle 10 g. One of my table of the column stores the data, sampled below.

1722999340KK000200000
1444210829AB1001EX003
1444300000CD0148EX003
1722999340KL 000200000

I want to split the data in the report between the numbers (4; 6; 6; 5), as shown below and store it in different columns (A1 |) A2 | A3 | A4).
1444 | 210829 | AB1001 | EX003

Grateful if someone can give me some advice on how to achieve the same in the SQL database.

See you soon,.

novice
```
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Query SQL to split the lines based on the amount

I have the data in the following format in the table.

ORDER_ID PRODUCT_ID QUANTITY

O1 A1 3

I need to write the sql query to divide the data in following format:

ORDER_ID PRODUCT_ID QUANTITY

O1 A1 1

Query must split the data based on the value in the quantity column.

Thank you

Developer

Hello

create table order_items (
  order_id varchar2(2),
  product_id varchar2(2),
  quantity number
)
;
insert into order_items values ('O1', 'A1', 3)
;
-- Recursive Subquery Factoring
with item(order_id, product_id, quantity) as (
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)
select
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from item
order by order_id
;
drop table order_items purge
;

Table ORDER_ITEMS created.

1 row inserted.

OR PR   QUANTITY
-- -- ----------
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O1 A1          1
O1 A1          1

Table ORDER_ITEMS dropped.

How to split the PHONE NUMBER in the column of database?

Hello - how to split the telephone within the same column number?
Existing column PHONE data
3711943
8744723
8487928
3349262
I want to split the data in the same
371-1943
874-4723
etc...

Is this possible? I need to do this only through SQL query not PL/SQL.

SUBSTR (your_col, 1, 3). » -'|| SUBSTR(your_col,4)

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I am trying to learn Oracle DB at home. I installed Oracle DB Express 11.2 and Developer SQL 4.0.3. I can connect to the database, the communication between SQL and Oracle DB Express Developer works well.
It is probably a problem with Oracle database, but since I see it in SQL Developer, I'll ask it anyway.
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RANK NAME
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Periods are used to separate components of object names so that they are not valid in the names.

for example

Schema.table

table. Column

Schema.table.Column

Package.PROCEDURE

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