SQL and the Q Q string manipulation

I'm trying to find out if I can use the manipulation of SQL strings in a Q Q. Here is an example of what I'm trying to do:

< cfquery dbtype = "query" name = "supportstatements_order" >
Select *, right (SupportStatements.Name, 12) as short_name
Of SupportStatements
Order by name
< / cfquery >

I get an error in CF I have an incorrect select statement.

Is it possible to do with Q of Q?

Thank you very much.

Anyone know if I could use queryaddcolumn in this situation?

Gather your themes led to the next suggestion

Erratum edit: data type correct varchar added

Tags: ColdFusion

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Seems to me that you are wrong assuming that the binding can be done by name and no position when you use immediate enforcement.

Example:

SQL> create table foo_tab( c1 varchar2(10), n1 number );

Table created.

SQL>
SQL> begin
  2          for i in 1..10
  3          loop
  4                  execute immediate 'insert into foo_tab values( to_char(:1), :1 )' using i;
  5          end loop;
  6          commit;
  7  end;
  8  /
begin
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SQL>
SQL>
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  7  end;
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PL/SQL procedure successfully completed.

SQL>

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Strange thing in the SQL and PL/SQL

Hi all

I meet a very strange thing of the length of the string in SQL and PL/SQL.
I ran the length of the string SQL and PL/SQL. The output values do not match.
Can you please help me on how this happens?

SQL

select LENGTH ( '!w0n5hn:  0.1 qlpgz-P0h1txtn-tk68-..1tk81-!A_kh0nlw_P0hphn0ln kh0nlw P0hphn0ln
zyntwm qlpgz – P0h1txtn 0n1 B00n1n – T00xk-..2 pwqt50wmwntn zt0ttn Pwn15nl pwlw0nw
tk pwfw0wnxw1 Extwnn5hn hf: T00xk ..1 qlpgz-P0h1txtn-tk77-!A_P0hphn0ln_B0hwnw0
Annhx50tw1 tkpn 
P05m00y Axth0n 
zwxhn100y Axth0n 
gwnx05pt5hn  zx0wwn 1
 
 
 
 

zx0wwn 2
 
 
 
 
 
 
 
 

zx0wwn .
 
 
 
 
 
 
 
 

zx0wwn !
 
 
 
 
 
 
 
 

zx0wwn 5
 

P0w-khn15t5hnn ed Thw tnw0 m0y l0tnxh thw kh0nlw P0hphn0l f0x5l5t5wn hy nwlwxt5nl thw kh0nlw !0ltw ftnxt5hn hn thw p0hphn0ln h0hwnw0
Phnt khn15t5hnn ed Fhllhw5nl thw ntxxwnnftl kh0nlw hf 0 15xt5hn00y xh0nnwl p0hphn0l, thw nyntwm x0005wn htt fhllhw5nl 0xt5hnn:
eded Thw xh0nlw1 !0ltw 5n nh lhnlw0 0!05l0hlw fh0 nwlwxt5hn 1t05nl 5twm m05ntwn0nxw; thw nyntwm thw0why p0w!wntn thw !0ltw hw5nl 0nn5lnw1 th 0115t5hn0l 5twmn
edmq Thw xh0nlw1 !0ltw 5n 0wmh!w1 f0hm 0ll 5twmn hn wh5xh 5t 5n p0wnwnt 0n1 0wpl0xw1 hy thw tnw0 npwx5f5w1 0wpl0xwmwnt; whw0w th5n 5mp0xtn 1w05!w1, 5twm-lw!wl fl0ln, ntxh 0n “pwn15nl 0tthh05n0t5hn”, thw nyntwm 0lnh 0mwn1n thwnw fl0ln 
ed.. Thw xh0nlw1 !0ltw p0hphn0l 5n 011w1 th thw pwjwxtw1 P0hphn0ln l5h000y, 0lhnl w5th thw xh0nlw x0twlh0y 0n1 0w0nhn th0t 00w npwx5f5w1 hy thw tnw0 5n thw xh0nlw !0ltw 150lhl
ed!. An 0 0wntlt hf 0wmh!5nl thw xh0nlw1 !0ltw f0hm 0ll 5twmn, 0ll tn0lwn hf thw xh0nlw1 !0ltw 00w, hf xht0nw, 0wmh!wed  Th5n 5nw!5t0hly 0wntltn 5n thw 0wmh!0l hf 0ll p0hphn0ln 5n!hl!5nl thw xh0nlw1 !0ltw 5n 0ll hthw0 xh0nnwln.  Thw 0115t5hn hf 0 nww !0ltw th thwnw 5twmn m0y, hf xht0nw, x0w0tw 0 nww p0hphn0l.  Thwnw p0hphn0ln 00w nht 0tthm0t5x0lly 0tthh05nw1 0n 0 0wntlt hf thw xh0nlw !0ltw 0xt5hn; thwy mtnt hw 01m5n5ntw0w1 hy thw 0pp0hp050tw 0tthh05nw0 5n 0 nwp000tw 0xt5hn
ed5. An w-m05l nht5f5x0t5hn 5n 1wl5!w0w1 th thw tnw0 whh x0w0tw1 thw p0hphn0l 0n1 th 0ny 0tthh05nw0n whh h0!w 0l0w01y 0tthh05nw1 thw p0hphn0l 5n thw wh0kflhw
mq Fhllhw5nl thw ntxxwnnftl kh0nlw hf 0 mh1tlw, lhx0l Pk h0 !0ltw-p050 xh0nnwl p0hphn0l, thw nyntwm x0005wn htt fhllhw5nl 0xt5hnn:
mqed Thw xh0nlw1 !0ltw 5tnwlf 5n 0wt05nw1 5n thw 15xt5hn00y
mqmq Thw !0ltw 5n 0wmh!w1 f0hm 0ll 5twmn hn wh5xh thw p0hphn0l (NB. thw p0hphn0l, nht thw !0ltw) 5n p0wnwnt 0n1 0wpl0xw1 hy thw tnw0 npwx5f5w1 0wpl0xwmwnt; whw0w th5n 5mp0xtn 1w05!w1, 5twm-lw!wl fl0ln, ntxh 0n “pwn15nl 0tthh05n0t5hn”, thw nyntwm 0lnh 0mwn1n thwnw fl0ln.  In thw x0nw hf !0ltw-p050 p0hphn0ln, hnly thw p0hphn0l !0ltw th0t w0n nwlwxtw1 5n thw p0hphn0ln h0hwnw0 m0y hw xh0nlw1 (5f thw tnw0 w5nhwn th xh0nlw thw hthw0 !0ltw 5n thw p050, thwy mtnt 0xxwnn thw n0mw p050 p0hphn0l !50 th0t !0ltw 5n thw p0hphn0ln h0hwnw0)
mq.. Thw tn0lw p0hphn0l 5n 011w1 th thw pwjwxtw1 P0hphn0ln l5h000y, 0lhnl w5th thw 0wjwxt5hn x0twlh0y 0n1 0w0nhn th0t 00w npwx5f5w1 hy thw tnw0 5n thw 0wjwxt5hn 150lhl.  Thw 0wpl0xwmwnt !0ltw th0t w0n 0ppl5w1 5n thw xh0nlw 5n 0lnh 0wxh01w1 pw0m0nwntly, nh th0t th5n x0n hw 15npl0yw1 th tnw0n whw0w 0pp0hp050tw 1t05nl 5twm xh15nl 0xt5!5ty
mq!. An 0 0wntlt hf 0wmh!5nl thw xh0nlw1 !0ltw f0hm nhmw 5twmn, hthw0 tn0lwn hf thw !0ltw m0y 0lnh hw 0wmh!wed  If th5n 5n thw x0nw, 0n1 5f thwnw tn0lwn 00w 0lnh p0hphn0ln, th5n 0lnh 0wntltn 5n thw 0wmh!0l hf p0hphn0ln 5n!hl!5nl thw !0ltw 5n hthw0 tn0lw xh0nnwln (5t 5n w!wn 0 0wmhtw phnn5h5l5ty th0t xh0nl5nl 0 lhx0l Pk p0hphn0l m0y 0wmh!w 0 tn0lw 0n1 p0hphn0l fh0 thw n0mw !0ltw 5n 0nhthw0 lhx0l Pk; n5m5l00ly xh0nl5nl 0 !0ltw p050 m0y 0wmh!w hthw0 !0ltw-p050 tn0lwn/p0hphn0ln).  z5m5l00ly, thw 0115t5hn hf 0 nww !0ltw th 5twmn 0n 0 0wntlt hf thw xh0nlw 0xt5hn, m0y lwnw00tw nww p0hphn0ln 5n 0ny tn0lw xh0nnwl
mq5. An w-m05l nht5f5x0t5hn 5n 1wl5!w0w1 th thw tnw0 whh x0w0tw1 thw p0hphn0l 0n1 th 0ny 0tthh05nw0n whh h0!w 0l0w01y 0tthh05nw1 thw p0hphn0l 5n thw wh0kflhw
.. zww 5mplwmwnt0t5hn nhtwn hwlhw, tn1w0 “pwl0tw1 Infh0m0t5hn” 
B0n5x Flhw 
 fl1l1fl1fl;lj0n1khfh0njkfhzgJKkf xhy0w0ttj 0nwhtj5y0w0hlwfklj0w0lklt5h5hn1fhlj1fhljn1fhlj1fhljwj50w0ytlt5w0j0w5t5
ztfl!n1fllw0t!qww0wh00wwjh0f0n1jfhn1jkkwjhqw5t! tjt5w0yttwn1fln1ln1fn1') from dual;

Here, I got an error like

ORA-01704: string literal too long
01704. 00000 -  "string literal too long"
*Cause:    The string literal is longer than 4000 characters.
*Action:   Use a string literal of at most 4000 characters.
           Longer values may only be entered using bind variables.
Error at Line: 1 Column: 16

But in PL/SQL,.

BEGIN
     dbms_output.put_line(LENGTH ( '!w0n5hn:  0.1 qlpgz-P0h1txtn-tk68-..1tk81-!A_kh0nlw_P0hphn0ln kh0nlw P0hphn0ln
zyntwm qlpgz – P0h1txtn 0n1 B00n1n – T00xk-..2 pwqt50wmwntn zt0ttn Pwn15nl pwlw0nw
tk pwfw0wnxw1 Extwnn5hn hf: T00xk ..1 qlpgz-P0h1txtn-tk77-!A_P0hphn0ln_B0hwnw0
Annhx50tw1 tkpn 
P05m00y Axth0n 
zwxhn100y Axth0n 
gwnx05pt5hn  zx0wwn 1
 
 
 
 

zx0wwn 2
 
 
 
 
 
 
 
 

zx0wwn .
 
 
 
 
 
 
 
 

zx0wwn !
 
 
 
 
 
 
 
 

zx0wwn 5
 

P0w-khn15t5hnn ed Thw tnw0 m0y l0tnxh thw kh0nlw P0hphn0l f0x5l5t5wn hy nwlwxt5nl thw kh0nlw !0ltw ftnxt5hn hn thw p0hphn0ln h0hwnw0
Phnt khn15t5hnn ed Fhllhw5nl thw ntxxwnnftl kh0nlw hf 0 15xt5hn00y xh0nnwl p0hphn0l, thw nyntwm x0005wn htt fhllhw5nl 0xt5hnn:
eded Thw xh0nlw1 !0ltw 5n nh lhnlw0 0!05l0hlw fh0 nwlwxt5hn 1t05nl 5twm m05ntwn0nxw; thw nyntwm thw0why p0w!wntn thw !0ltw hw5nl 0nn5lnw1 th 0115t5hn0l 5twmn
edmq Thw xh0nlw1 !0ltw 5n 0wmh!w1 f0hm 0ll 5twmn hn wh5xh 5t 5n p0wnwnt 0n1 0wpl0xw1 hy thw tnw0 npwx5f5w1 0wpl0xwmwnt; whw0w th5n 5mp0xtn 1w05!w1, 5twm-lw!wl fl0ln, ntxh 0n “pwn15nl 0tthh05n0t5hn”, thw nyntwm 0lnh 0mwn1n thwnw fl0ln 
ed.. Thw xh0nlw1 !0ltw p0hphn0l 5n 011w1 th thw pwjwxtw1 P0hphn0ln l5h000y, 0lhnl w5th thw xh0nlw x0twlh0y 0n1 0w0nhn th0t 00w npwx5f5w1 hy thw tnw0 5n thw xh0nlw !0ltw 150lhl
ed!. An 0 0wntlt hf 0wmh!5nl thw xh0nlw1 !0ltw f0hm 0ll 5twmn, 0ll tn0lwn hf thw xh0nlw1 !0ltw 00w, hf xht0nw, 0wmh!wed  Th5n 5nw!5t0hly 0wntltn 5n thw 0wmh!0l hf 0ll p0hphn0ln 5n!hl!5nl thw xh0nlw1 !0ltw 5n 0ll hthw0 xh0nnwln.  Thw 0115t5hn hf 0 nww !0ltw th thwnw 5twmn m0y, hf xht0nw, x0w0tw 0 nww p0hphn0l.  Thwnw p0hphn0ln 00w nht 0tthm0t5x0lly 0tthh05nw1 0n 0 0wntlt hf thw xh0nlw !0ltw 0xt5hn; thwy mtnt hw 01m5n5ntw0w1 hy thw 0pp0hp050tw 0tthh05nw0 5n 0 nwp000tw 0xt5hn
ed5. An w-m05l nht5f5x0t5hn 5n 1wl5!w0w1 th thw tnw0 whh x0w0tw1 thw p0hphn0l 0n1 th 0ny 0tthh05nw0n whh h0!w 0l0w01y 0tthh05nw1 thw p0hphn0l 5n thw wh0kflhw
mq Fhllhw5nl thw ntxxwnnftl kh0nlw hf 0 mh1tlw, lhx0l Pk h0 !0ltw-p050 xh0nnwl p0hphn0l, thw nyntwm x0005wn htt fhllhw5nl 0xt5hnn:
mqed Thw xh0nlw1 !0ltw 5tnwlf 5n 0wt05nw1 5n thw 15xt5hn00y
mqmq Thw !0ltw 5n 0wmh!w1 f0hm 0ll 5twmn hn wh5xh thw p0hphn0l (NB. thw p0hphn0l, nht thw !0ltw) 5n p0wnwnt 0n1 0wpl0xw1 hy thw tnw0 npwx5f5w1 0wpl0xwmwnt; whw0w th5n 5mp0xtn 1w05!w1, 5twm-lw!wl fl0ln, ntxh 0n “pwn15nl 0tthh05n0t5hn”, thw nyntwm 0lnh 0mwn1n thwnw fl0ln.  In thw x0nw hf !0ltw-p050 p0hphn0ln, hnly thw p0hphn0l !0ltw th0t w0n nwlwxtw1 5n thw p0hphn0ln h0hwnw0 m0y hw xh0nlw1 (5f thw tnw0 w5nhwn th xh0nlw thw hthw0 !0ltw 5n thw p050, thwy mtnt 0xxwnn thw n0mw p050 p0hphn0l !50 th0t !0ltw 5n thw p0hphn0ln h0hwnw0)
mq.. Thw tn0lw p0hphn0l 5n 011w1 th thw pwjwxtw1 P0hphn0ln l5h000y, 0lhnl w5th thw 0wjwxt5hn x0twlh0y 0n1 0w0nhn th0t 00w npwx5f5w1 hy thw tnw0 5n thw 0wjwxt5hn 150lhl.  Thw 0wpl0xwmwnt !0ltw th0t w0n 0ppl5w1 5n thw xh0nlw 5n 0lnh 0wxh01w1 pw0m0nwntly, nh th0t th5n x0n hw 15npl0yw1 th tnw0n whw0w 0pp0hp050tw 1t05nl 5twm xh15nl 0xt5!5ty
mq!. An 0 0wntlt hf 0wmh!5nl thw xh0nlw1 !0ltw f0hm nhmw 5twmn, hthw0 tn0lwn hf thw !0ltw m0y 0lnh hw 0wmh!wed  If th5n 5n thw x0nw, 0n1 5f thwnw tn0lwn 00w 0lnh p0hphn0ln, th5n 0lnh 0wntltn 5n thw 0wmh!0l hf p0hphn0ln 5n!hl!5nl thw !0ltw 5n hthw0 tn0lw xh0nnwln (5t 5n w!wn 0 0wmhtw phnn5h5l5ty th0t xh0nl5nl 0 lhx0l Pk p0hphn0l m0y 0wmh!w 0 tn0lw 0n1 p0hphn0l fh0 thw n0mw !0ltw 5n 0nhthw0 lhx0l Pk; n5m5l00ly xh0nl5nl 0 !0ltw p050 m0y 0wmh!w hthw0 !0ltw-p050 tn0lwn/p0hphn0ln).  z5m5l00ly, thw 0115t5hn hf 0 nww !0ltw th 5twmn 0n 0 0wntlt hf thw xh0nlw 0xt5hn, m0y lwnw00tw nww p0hphn0ln 5n 0ny tn0lw xh0nnwl
mq5. An w-m05l nht5f5x0t5hn 5n 1wl5!w0w1 th thw tnw0 whh x0w0tw1 thw p0hphn0l 0n1 th 0ny 0tthh05nw0n whh h0!w 0l0w01y 0tthh05nw1 thw p0hphn0l 5n thw wh0kflhw
.. zww 5mplwmwnt0t5hn nhtwn hwlhw, tn1w0 “pwl0tw1 Infh0m0t5hn” 
B0n5x Flhw 
 fl1l1fl1fl;lj0n1khfh0njkfhzgJKkf xhy0w0ttj 0nwhtj5y0w0hlwfklj0w0lklt5h5hn1fhlj1fhljn1fhlj1fhljwj50w0ytlt5w0j0w5t5
ztfl!n1fllw0t!qww0wh00wwjh0f0n1jfhn1jkkwjhqw5t! tjt5w0yttwn1fln1ln1fn1') );
END;

I got the value as 3969.

I tried with the same string. I know that the maximum length of the SQL string is 4000 and PL/SQL is 32767. but the thing is when am a length of the string in PL/SQL as less than 4000, then iwhy must not be run alongside SQL?

Can you help me out on this issue?

DB: Oracle 11g Release 2

Thank you and best regards,
Suresh.

Suresh Mohan says:

Outside chr (256), are there other characters of white space available?

White space characters are listed on http://en.wikipedia.org/wiki/Whitespace_character.

From the point of view of the old MS-MS-BACK/ASCII characters, a white space character was #256 as the chariot of normal space was #32. He was also a space compared to a difficult space.

You need to look at the character set you use - ASCII is a set of characters in a single byte, and not the same thing.

You can use the SQL DUMP() function to watch the characters in a string. For example

select dump( my_string_column ) from my_table where ...

Get the bind variables name string SQL or the cursor

Hello

Is there way to get of the bind variables name string SQL or the cursor?

Example of

DECLARE
  l_sql VARCHAR2(2000);
  desctab DBMS_SQL.DESC_TAB;
  curid   PLS_INTEGER;
BEGIN

  l_sql := 'SELECT * FROM emp WHERE mgr = :X and deptno = :Y';

  curid := dbms_sql.open_cursor;
  dbms_sql.parse(curid, l_sql, dbms_sql.NATIVE);
  ....
END;

What I mean with the SQL string:
I love to get using some functions from above code variable l_sql all the bind variable.
In this case the function should return array where is for example: X and: Y

Back to bind the cursor variable names, I mean same but rather string I pass number of cursor.

Y at - it sucks ready function or some may share a code customized for this purpose?

Thanks

Kind regards
Jari

http://dbswh.webhop.NET/dbswh/f?p=blog:Home:0Regards,

Published by: jarola December 19, 2011 02:44

I found there are wwv_flow_utilities.get_binds of the function not documented in APEX packages that do what I want.
Usage example

set serveroutput on
DECLARE
  binds DBMS_SQL.varchar2_table;
BEGIN
  binds := wwv_flow_utilities.get_binds('select :P1_TEST from dual');
  FOR i IN 1 .. binds.count
  LOOP
    dbms_output.put_line(binds(i));
  END LOOP;
END;
/

anonymous block completed
:P1_TEST

But I would not use these functions without papers as those who can change or there is no future versions APEX.
Is there a documented function or the custom function that do the same thing as wwv_flow_utilities.get_binds?

Some old basic example code of my friends. Also the media getting the bind variable of PL/SQL code blocks anon.

SQL> create or replace function GetBindVariables( statement varchar2 ) return TStrings is
  2          --// bind variables names are terminated by one the following special chars
  3          SPECIAL_CHAR    constant TStrings := TStrings(' ',')','+','-','>','<','*',',','=',';',CHR(10),CHR(13));
  4
  5          --// max size of a bind var name
  6          MAX_VARSIZE     constant integer := 100;
  7
  8          pos     integer;
  9          pos1    integer;
 10          occur   integer;
 11          varName varchar2(100);
 12          varList TStrings;
 13  begin
 14          varList := new TStrings();
 15
 16          --// looking for the 1st occurance of a bind variable
 17          occur := 1;
 18
 19          loop
 20                  pos := InStr( statement, ':', 1, occur );
 21                  exit when pos = 0;
 22
 23                  varName := SubStr( statement, pos, 100 );
 24
 25                  --// find the terminating char trailing the
 26                  --// bind variable name
 27                  pos1 := Length( varName );
 28                  for i in 1..SPECIAL_CHAR.Count
 29                  loop
 30                          pos := InStr( varName, SPECIAL_CHAR(i) ) - 1;
 31                          if (pos > 0) and (pos < pos1) then
 32                                  pos1 := pos;
 33                          end if;
 34                  end loop;
 35
 36                  --// extract the actual bind var name (without
 37                  --// colon char prefix)
 38                  varName := SubStr( varName, 2, pos1-1 );
 39
 40                  --// maintain a unique list of var names
 41                  if not varName member of varList then
 42                          varList.Extend(1);
 43                          varList( varList.Count ) := varName;
 44                  end if;
 45
 46                  --// look for the next occurance
 47                  occur := occur + 1;
 48          end loop;
 49
 50          return( varList );
 51  end;
 52  /

Function created.

SQL>
SQL> select
  2          column_value as BIND_VAR
  3  from TABLE(
  4          GetBindVariables('select * from foo where col=:BIND1 and day = to_date(:B2,''yyyy/mm/dd'')')
  5  );

BIND_VAR
------------------------------
BIND1
B2

SQL>

PS. just realize this code is case-sensitive, while variable bind is not. Should throw a upper() or lower() by adding the name of the var to the list - never really a problem for me because I'm pretty tense when it use cases correctly in the code. ;-)

Published by: Billy Verreynne, December 19, 2011 06:19

String manipulation SQL query

Starting with the data for this example:

GET sampledata
WITH sampledata AS
     (SELECT 'THIS Information Collection GL Enquiry User' resp
        FROM DUAL
      UNION ALL
      SELECT 'THIS Information Collection PO Web Requisitioner and Receiver'
        FROM DUAL
      UNION ALL
      SELECT 'THIS Asset Management Team GL Enquiry User'
        FROM DUAL        
      UNION ALL
      SELECT 'THIS Asset Management Team PO Web Requisitioner and Receiver'
        FROM DUAL
      UNION ALL
      SELECT 'THIS Collections GL Enquiry User'
        FROM DUAL
      UNION ALL
      SELECT 'THIS Collections PO Web Requisitioner and Receiver'
        FROM DUAL)
SELECT *
  FROM sampledata;

I am trying to find a way to get the first section of chain BEFORE and also the little after that, including 2 letter string - for example I would like to extract:

BEFORE                          | AFTER
--------------------------------------------------------------------------------
THIS Information Collection     | GL Enquiry User
THIS Information Collection     | PO Web Requisitioner and Receiver
THIS Asset Management Team      | GL Enquiry User
THIS Asset Management Team      | PO Web Requisitioner and Receiver
THIS Collections                | GL Enquiry User
THIS Collections                | PO Web Requisitioner and Receiver

However, I am rather stuck - I think I will need to use a combination of INSTR() and SUBSTR(), but the problem is that the 2 letter string appears after a variable number of words, so there is no ordinary way to check where to appear the 2 letters - more the 2 letter string will be different each time - not only GL and PO as above , but one range of others, for example, AR, AP, etc. OM.

Any advice much appreciated.

Thank you!

Like this?

SQL> ed
Wrote file afiedt.buf

  1  WITH sampledata AS
  2       (SELECT 'THIS Information Collection GL Enquiry User' resp FROM DUAL UNION ALL
  3        SELECT 'THIS Information Collection PO Web Requisitioner and Receiver' FROM DUAL UNION ALL
  4        SELECT 'THIS Asset Management Team GL Enquiry User' FROM DUAL UNION ALL
  5        SELECT 'THIS Asset Management Team PO Web Requisitioner and Receiver' FROM DUAL UNION ALL
  6        SELECT 'THIS Collections GL Enquiry User' FROM DUAL UNION ALL
  7        SELECT 'THIS Collections PO Web Requisitioner and Receiver' FROM DUAL)
  8  SELECT regexp_replace(resp,'^(.*) [^ ]{2} .*$','\1') as resp1
  9        ,regexp_replace(resp,'^.* ([^ ]{2} .*)$','\1') as resp2
 10*   FROM sampledata
SQL> /

RESP1                                    RESP2
---------------------------------------- ----------------------------------------
THIS Information Collection              GL Enquiry User
THIS Information Collection              PO Web Requisitioner and Receiver
THIS Asset Management Team               GL Enquiry User
THIS Asset Management Team               PO Web Requisitioner and Receiver
THIS Collections                         GL Enquiry User
THIS Collections                         PO Web Requisitioner and Receiver

6 rows selected.

Help of query SQL - inner joins and the separate results
Hello

ASP VB, SQL Server

I have a structure of data base with 3 tables - users, albums and photos. each user has a identifier unique, each record has a unique albumid and also contains a column with the user name. each record in the photo has a unique id so that store the user name and the album in which the image belongs.

I'm writing a query that returns a list of the albums for a particular user (based on a user name query string) and who will also bring back the id of the first record in the table for each of these albums photo.

the closest I get is to run a query to select albumid albums where userid = varuserid with a join internal on the pictures table to remove the photo ID - problem I then it comes out all the photos from the photos table where userid = varuserid, so when I do a repeat region to display a list of albums for a certain user It produces a list of all the photos where userid = varuserid

I really want to return just a list of ID album based on the username variable, but also to return the first record in the table of photos for each of these albumids

I tried different combinations of inner joins, select distinct etc but no joy.

any suggestion would be appreciated as am floundering here...

First, you must define 'first' with regard to the photos. Is there a
timestamp? They are numbered inside the album? Do you really care who is
"first", or do you want simply a shot? You also neglected to indicate if they are
empty photo albums have been allowed. I assumed that the empty albums are not
allowed.

Whatever you decide, the answer will be similar.
SQL Server tends to get better results with joins with subqueries. You will have
See such a written request more often with subqueries, and there isn't
nothing wrong with that, but I'll use a join on a derived table. I have
have not all column names (hint, hint), so I made them, but the
Comments should help out you.

SELECT A.Title, P.PhotoID, P.Caption, A.AlbumID, P.ImagePath
FROM dbo. A albums
-build a table derived, consisting of photo ID lowest for each
album.
INNER JOIN (SELECT AlbumID, MIN (PhotoID) AS FirstPhoto FROM dbo. Photos
AlbumID GROUP) AS PM WE A.AlbumID = PM. AlbumID
-details of the photo for the photo shown in the table above
INNER JOIN dbo. Photos P on A.AlbumID = P.AlbumID AND
H. FirstPhoto = P.PhotoID
User A.UserID ='some WHERE '

"tedstar" wrote in message
News:ee4pfn$de$1@forums. Macromedia.com...
> I am writing a query that returns a list of the albums for a
> particular user (based on a user name query string) and also bring
> return
> the id of the first record in the table for each of these albums photo.

number of words and the release of n words in string
Hello. I use the following script to output n number of records of a description string "longdescription" - type varchar 8000chrs in sql server 2000

< cfset teaser = ">
< cfset temp longdescription = >
< CFLOOP from = "1" to = "26" index 'i' = >
< cfset teaser =
ListAppend (teaser, ListFirst (temp,' '),' ') >
< cfset temp = ListRest (temp,' ') >
< / CFLOOP >
#teaser #.

It works without problem until I want to display a large number of records on a page, it takes 10 seconds to display records with a fairly long description (2000 characters +) 60, (it's definitely the only factor during the long wait as eliminated all others) can anyone think that of any ways alternatives/functions to more effectively , keeping in mind, I don't want to put an end to the chain on a split Word

Thank you very much

Oli
Hi Dan, thanks for the reply, the 'left' function works a treat, and thanks to your pointers on this one, I did a bit of googleing and found some info on sql do all the work, goes it the word count/dear one loop and comes the number of intelligent characters space, while sql and fast v - soft!

SELECT LEFT (longdescription, CHARINDEX (' ', longdescription, 280)) as shorterdescription, table

see you soon

How do I in the sql and pl/sql?
I have the following data in a table:

Cust_Id Relation_ID
1 2
1 3
2 3
1 v
5 7
6 7
7 8
8 9

for customer 1 is connected to client 2 somehow (could be the husband, for example) and is also linked to the customer 3. Client 2 is related to the customer, 3 3 client is then linked to the customer 4. Similarly, visitors 5,6,7,8 and 9 are all connected, but they are in no way related to customers 1,2,3 and 4.

I need to divide these data into related groups. So clients 1,2,3 and 4 in 1 (say Group 1), and customers 5,6,7,8 and 9 would be in another (say Group 2). Of course, this is a simple example, but my real data are more than that!
In theory, client 1 might also be in another 'group', say with the customers, 10, 11 and 12, that would not be associated with anyone in the Group 1. This would then form another group (say 3).

How I did it and communicate the results in sql/pl sql?
Hello

Tracey.Sheppard wrote:
My apologies - I'm one of these groups a little bit, which would have confused the issue further.

Groups must be:

Customer 195229 (father) Group: (father is 195229 no 195226!)
195229
195224
201147
195228
195226

Son, daughter, and mother of group
195224
195228
195229
195226

Group of friends of 11807
11807
201147

A group of friend of 201147
201147
195229
11807

For each customer, the group is their cust_id more people that they are directly related.

If a group consists of a node and all other nodes connected directly.
That is, x and are in the same group if (and only if) at least one of the following is true:
(1) cust_id = x and reln_id = y for a relationship line.
(2) reln_id = x and cust_id = y for a relationship line, or
(3) x = y
Is this fair?

If I do:

Select distinct (decode(cust_id,'195226',reln_id,cust_id))
in the relationship where (cust_id = ' 195226 'or reln_id = ' 195226')

I get:

DECODE (C
--------
195224
195228
195229

so 195226 group is foregoing plus 195226.

I don't think it's useful to think of "the 195226 group." Haven't you said that an id can be member of groups of two or more systematically? Aren't say you, below, that "195226 group' is equivalent to 'of 195224 group', and that the two are the same as"195228 group?

The same query, but with 295228 gives:

DECODE (C
--------
195224
195226
195229

so when 195228 is added, the group is the same. Here in a single group.

You are on the right track. Associate each node with all nodes connected directly to it, as well as to himself. It's that the subquery in the query below got_memebers. Note the similarity between got_members and the definition I gave to a group above.
```
WITH     got_members     AS
(
     SELECT     cust_id  AS id1,   reln_id  AS id2     FROM relation     UNION
     SELECT     reln_id  AS id1,   cust_id  AS id2     FROM relation     UNION
     SELECT     cust_id  AS id1,   cust_id  AS id2     FROM relation     UNION
     SELECT     reln_id  AS id1,   reln_id  AS id2     FROM relation
)
,     got_r_num     AS
(
     SELECT     id1
     ,     id2
     ,     ROW_NUMBER () OVER ( PARTITION BY  id1
                               ORDER BY          id2
                       )  AS r_num
     FROM     got_members
)
SELECT DISTINCT      SUBSTR ( SYS_CONNECT_BY_PATH (id2, ',')
                       , 2
               ) AS grp
FROM           got_r_num
WHERE           CONNECT_BY_ISLEAF     = 1
START WITH      r_num          = 1
CONNECT BY      r_num          = PRIOR r_num + 1
     AND      id1          = PRIOR id1
;
```
The main query uses String aggregation to obtain a unique identifier for each group. (The unique ID used above is the list separated by commas of the members in alphabetical order.) Got_r_num of the subquery is useful for making string using CONNECT BY aggregation. If you use another method of aggregation of the chain, you shouldn't have this subquery. (On my system, I would use the STRAGG function defined by the user, that is found in)
http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:2196162600402
.)

Please test (and correct, if necessary) any code before you post.
INSERT statements you posted all contain errors: the word "INSERT INTO * TABLE * relationship...» ». Reln_to and reln_of are each defined as VARCHAR2 (4), but almost all the values you are trying to use more than 4 characters.

With the data for this example:
```
CREATE TABLE relation (
cust_id varchar2(8),
reln_to varchar2(8),
reln_id varchar2(8),
reln_of varchar2(8) );

INSERT INTO relation(cust_id, reln_to, reln_id, reln_of) VALUES('195228', 'MOTHER',   '195226', 'SON');
INSERT INTO relation(cust_id, reln_to, reln_id, reln_of) VALUES('195229', 'FATHER',   '195226', 'SON');
INSERT INTO relation(cust_id, reln_to, reln_id, reln_of) VALUES('195229', 'FATHER',   '195224', 'DAUGHTER');
INSERT INTO relation(cust_id, reln_to, reln_id, reln_of) VALUES('195226', 'BROTHER',  '195224', 'SISTER');
INSERT INTO relation(cust_id, reln_to, reln_id, reln_of) VALUES('195228', 'WIFE',     '195229', 'HUSBAND');
INSERT INTO relation(cust_id, reln_to, reln_id, reln_of) VALUES('195228', 'DAUGHTER', '195224', 'MOTHER');
INSERT INTO relation(cust_id, reln_to, reln_id, reln_of) VALUES('11807',  'FRIEND',   '201147', 'FRIEND');
INSERT INTO relation(cust_id, reln_to, reln_id, reln_of) VALUES('201147', 'FRIEND',   '195229', 'FRIEND');
```
the above query gives these results:
```
GRP
-----------------------------------------------------
11807,195229,201147
195224,195226,195228,195229
11807,201147
195224,195226,195228,195229,201147
```
This assumes that the output will only contain related items. What happens if you have some entitiy which is not linked to another entity in your application? If you want to include "Islands" like this in your output, you must include them in the data somehow. The best way is probably to have a separate table that had a line per node, if not he was connected to all other nodes. Another way would be to have a line in the relationship that binds each otherwise node not connected to itself.

SQL in pl/sql and create the duplicate RMAN script.
Hello

I'm new to pl/sql and I am trying to write a script that will generate RMAN commands to make a clone of database.

I want to be able to run the script, and he invited me to the variables to be used in the script.

I did some research but I have been unable to find examples of how to proceed.

Basic script is (it would be obviously a lot more to the final script):

declare

dbname varchar2 (9): = & dbname;

BEGIN
DBMS_OUTPUT. ENABLE (2000);
DBMS_OUTPUT. Put_line (' DUPLICATE TARGET DATABASE to ' | dbname |) ';') ;
end;
/

Makes me:

Enter the value of dbname: ORCL4
old 3: dbname varchar2 (9): = & dbname;
new 3: dbname varchar2 (9): = ORCL4;
dbname varchar2 (9): = ORCL4;
*
ERROR at line 3:
ORA-06550: line 3, column 24:
PLS-00201: identifier 'ORCL4' must be declared.
ORA-06550: line 3, column 9:
PL/SQL: Ignored Element
ORA-06550: line 7, column 66:
PLS-00320: the declaration of the type of the expression is incomplete or incorrect
ORA-06550: line 7, column 9:
PL/SQL: Statement ignored

Thank you
Tom.
Hi, Tom.

When SQL * more variable substitution resolves, it puts the string you gave as value (ORCL4 for example) instead of the string representing the name (& dbname, for example). East exaclty what you could do using the Replace function in a text editor: nothing more.
After SQL * more substituted for these channels, it send s the text changed the database to be compiled. So, where you coded:
```
dbname varchar2(9) := &dbname;
```
is that it sends to compile
```
dbname varchar2(9) := ORCL4;
```
in other words, it looks like a variable on the side right of the: = sign.

You must provide quotes:
```
dbname varchar2(9) := '&dbname';
```

SQL and the Q Q string manipulation

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