SQL syntax recordset IF THEN ELSE
Here's what I'm trying to do: I am trying to display two different levels of content based on a user is profitable or not. for example, if the field xyz_paying = 'Yes' then select *, otherwise only display some fields, so I will try to use a mysql statement to create a SELECT query. I tried to do that IF, THEN, ELSE, but I'm getting syntax error messages. could someone show me a simple example please. or suggest a good resource. Thank you.I can't seem to get the sql to do what I want, so I changed gears and I use a conditional region to display only when my paid domain == works y. very well.
I guess it's as good as force sql to do what you want. I'm now pulling all the data in the tables but it displays in a selective way.
Tags: Dreamweaver
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Error in SQL syntax when creating record insertion form
Nice day
I was hoping that someone could help me. I am creating a form of registration on a website to insert data into a database table. When you try to create the form, I get the following error:
You have an error in your SQL syntax; consult the manual for your version of the MySQL server for the right syntax to use near ' organization, office, phone, EmailAddress, JobTitle, 'OfficialMaili' at line 1
Do not know what is happening. I am running windows 8 and cs5 DW w / MYSQL. I'm testing on a local server before pushing to the remote server.
I thank you for your help and please indicate any code you want to send me.
M.I.,
"OfficialMailing address".
The table names, column names, etc. must not contain punctuation, space or special characters. Difficulty of these column names, and then try again.
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How to validate SQL syntax in Application Engine Peoplecode
Hello
Can someone help me to find out How to validate SQL in Application Engine Peoplecode. I just need to validate SQL syntax. If the syntax is wrong, it should save the exception in the log file but engine Apllication should not go WITHOUT success. App Engine should continue with other SQL validation to check the correct syntax and to retrieve values.
Here is given is peoplecode, which is that I currently use.
Thanks in advance.
String local CSG_SQL_ID & sqltext;
Local date & effdt;
Local Boolean & sql_flag = True;
& CSG_SQL_ID = CSG_REP_DIS_AET. CSG_SQL_ID. value;
SQLExec ("SELECT DEV. CST PS_CSG_SQL_TMP, CRAD PS_CSG_REP_AUT_DST SQLTEXT WHERE CSE. CSG_SQL_ID = DEV. CSG_SQL_ID AND CST. EFFDT = DEV. EFFDT AND CST. CSG_SQL_ID =: 1 ", CSG_SQL_ID, & sqltext);
Try
& sql_flag = SQLExec (& sqltext);
If & sql_flag = True Then
& sql = CreateSQL (& sqltext);
Local string SqlString = & sql. Value;
Logger (String (ExtractTablesJob (& SqlString)));
Logger (String (ExtractTablesDept (& SqlString)));
End - If;
catch Exception & sqlerror
MessageBox (0, "", 0, 0, "found Exception");
end - try;Ludi,
I apologize: I remembered wrong. The Select Type must be reselect. I opened a ticket with Oracle on this problem. I hope that maybe they will build better error messaging tools, but we'll see. The real result of the ticket, it is that evolution to select Type of reselect solved my problem.
Remember that when you Reselect it, you need to follow wherever you are. Reselect him running the DoSelect SQL statement every time until it returns no rows. So, you will need a flag turned on the table. You're DoSelect should select only the rows where the transformed flag is N. Then, you must update the line you are dealing with to set the flag turned on Y. In this way, you will pass through the processing of each lines.
Also, just to be clear, I don't think that App Designer will ever "validate" your SQL. It allows the database to do that when you run it. It can be frustrating because up to now it is not telling you that you are developing, but the advantage is that App Designer does not limit you. You can place some SQL you want in your program, and it will transmit to the database. Stored procedures, functions, all work because the App Designer do not validate things specific special platform.
If you wish, you can copy your SQL in the SQLExec to a SQL definition:
SELECT THE DEV. SQLTEXT
OF PS_CSG_SQL_TMP CST.
PS_CSG_REP_AUT_DST SLAG
WHERE CSE. CSG_SQL_ID = DEV. CSG_SQL_ID
AND CSE. EFFDT = DEV. EFFDT
AND CSE. CSG_SQL_ID =: 1You could name MY_AE_SQL.
Then, in your App Engine PeopleCode, you can change the SQLExec in:
SQLExec (SQL. MY_AE_SQL, & CSG_SQL_ID, & sqltext);This will place your SQL in a place that teaches better, but I don't think that it will validate it no more. In my opinion, it makes your code more difficult to read. Someone coming along behind you must open several pieces of code to see what your program does.
The more I watch your program, you want probably to validate and protect the SQL code that is in & sqltext, rather than the SQLExec. If you want it to be dynamic, I don't see what you can do.
You could possibly launch an other App Engine as another process. You can use the object API ProcessRequest to plan the program through the process scheduler. You must pass your dynamic SQL code to the other program through a sort of serial control. In this way each SQL would go as a separate instance in process monitor and would go to success or no success individually. I still think it's too complicated.
I hope these thoughts help. It looks like a difficult task.
Stephen
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Help to fic my if-then-else logic in Forms 6i
Hello world
I have the following if-then-else in a when-validate-point called trigger where I'm trying to make it work the way I want to, but only works if I have 3 numeric values for each item. If put a letter in one of them, then I get the following error:
FRM-40735: WHEN-VALIDATE-ITEM trigger raised unhandled exception ORA-06502.
Can someone please help me fix my logic?
Published by: user626836 on September 28, 2011 08:42Begin If (:BLOCK1.ITEM1 BETWEEN 0 AND 100) and (:BLOCK2.ITEM2 BETWEEN 0 AND 100) and (:BLOCK3.ITEM3 BETWEEN 0 AND 100) Then :BLOCK1.ITEM4 := (:BLOCK1.ITEM1*0.40) + (:BLOCK1.ITEM2*0.40) + (:BLOCK1.ITEM3*0.20); Elsif (:BLOCK1.ITEM1 IN ('F', 'P', 'NA')) and (:BLOCK1.ITEM2 BETWEEN 0 AND 100) and (:BLOCK1.ITEM3 BETWEEN 0 AND 100) Then :BLOCK1.ITEM4 := (:BLOCK1.ITEM2 + :BLOCK1.ITEM3)/2; Elsif (:BLOCK1.ITEM2 IN ('F', 'P', 'NA')) and (:BLOCK1.ITEM1 BETWEEN 0 AND 100) and (:BLOCK1.ITEM3 BETWEEN 0 AND 100) Then :BLOCK1.ITEM4 := (:BLOCK1.ITEM1 + :BLOCK1.ITEM3)/2; Elsif (:BLOCK1.ITEM1 IN ('F')) AND :BLOCK1.ITEM2 IN ('F')) AND (:BLOCK1.ITEM3 IN ('F')) Then :BLOCK1.ITEM4 := 'F'; Elsif (:BLOCK1.ITEM1 IN ('P')) AND (:BLOCK1.ITEM2 IN ('P')) AND (:BLOCK1.ITEM3 IN ('P')) Then :BLOCK1.ITEM4 := 'P'; Elsif (:BLOCK1.ITEM1 IN ('NA')) AND (:BLOCK1.ITEM2 IN ('NA')) AND (:BLOCK1.ITEM3 IN ('NA')) Then :BLOCK1.ITEM4 := 'NA'; Else Null; End if; End;
Published by: user626836 on September 28, 2011 08:54Yes, everywhere, wherever you want to see the numerical score or Alpha you will use this code. Depending on your version of the database of the stated CASE may not work, but all versions support DECODING.
Craig...
Published by: Silvere Sep 29, 2011 07:18
I need to clarify... the DECODING is a SQL function. If you can't use it in SQL queries. You will get a compiler error if you try to use the DECODE function in PL/SQL.
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How to get if THEN ELSE another condition table
Hi eveybody,.
I have a situation and I need your advice guys.
I apply if THEN ELSE condition in PL/SQL from another table. I do the merger in tableA that will run IF Column1 in tableC = Y.
Ex: Tablec has three columns: source, dest, condition. Condition IF = Y in tableC, then merge into tableA use (Sql query in table C source selection) B.
Please let me know how to get the condition = Y of table C.
Condition IF = Y for each source in C, then fusion will happen for this source.
Please provide your comments and your responses.
I'd really appreciate your comments and your responses.
Thank you very much.user13426784 wrote:
DB link is passed as parameter in MS and we need to check the status for this link db to TableC.select status into v_status from tableC where db_link = v_source; if v_status = 'Y' then EXECUTE IMMEDIATE 'MERGE INTO tableA A USING (select
from tableA@' || v_source || ')B when matched insert when not matched update'; end if; SY.
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Req SQL syntax. to extract the value XML [CLOB]
Hello
I'll have the XML column in my table.
I have XML value in CLOB data type. I had an experience using extract XML from SQL syntax.
But I am unable to extract this file. I need to meet tagname value XML who gave example below.
For example, the name of the Table is A
Column name is A1
The value of column given below here.
<? XML version = "1.0" encoding = "ISO-8859-1? > < tags > < tag > < tagname > {docval} < / tagname > < tagvalue > ESPRefNotice < / tagvalue > < / tag > < tag > < tagname > {: inputvalue} < / tagname > < tagvalue > 3216 < / tagvalue > < / tag > < tag > < tagname > {officename} < / tagname > < tagvalue > ssvofficename < / tagvalue > < / tag > < / tags >
Kindly help me on this to extract the value 'tagname' or 'tagvalue' according to the above xml data.
Thank youSELECT warehouse_name warehouse, warehouse2."Water", warehouse2."Rail" FROM warehouses, XMLTABLE('/Warehouse' PASSING warehouses.warehouse_spec COLUMNS "Water" varchar2(6) PATH '/Warehouse/WaterAccess', "Rail" varchar2(6) PATH '/Warehouse/RailAccess') warehouse2;
check this exp in the documentation
http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/functions228.htm#CIHGGHFBthe warehouse_spec is of type xmltype. So in your case it is clob then you need to add like what I did in the query...
XmlType ()... Hope that explains everything...
Ravi Kumar
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Hello I have an email in outlook express I need to open a pdf file to, whenever I try to open the pdf file, told me that I have a SQL syntax error, how can I fix this problem
Hello
I suggest you to follow the steps in this link and check if it helps:
It will be useful.
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Original title: how to solve this problem:
System error
You have an error in your SQL syntax; consult the manual for your version of the MySQL server for the right syntax to use near ')' at line 5
Hi Roger,
It seems that you have problems with the SQL syntax. The question you have posted is related to encoding and it would be better suited to the MSDN Community. Please report it in the community below.
http://social.msdn.Microsoft.com/forums/SQLServer/en-us/home
Hope this is useful.
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Here's the test with values from the table and insert.
create table students ( name varchar2(25 BYTE), joined_date DATE, exam_type VARCHAR2(25 BYTE), SCORE NUMBER(2,1), CUT_OFF_DATE DATE ); insert into students values('john','26-mar-14','SCREEN',7.6,'10-apr-14'); insert into students values('john','10-Apr-14','RETEST',8.0,'10-apr-14');
I try to return the single folder with the score of the same name of the student. I use CASES, but he really do not act as "IF-THEN-else" as the use of a control statement.
select name, joined_date, case ---something like IF statment if below[b] statement 1[/b] --is true then it --should return below statement when exam_type ='SCREEN' and score between 8.0 and 10.0 then score ----[b]statement 2[/b] --if above expr fails, the below to be executed when exam_type ='RETEST' and score between 8.0 and 10.0 and joined_date >= cut_off_date then score else null end result from students;
output-
Name joined_date Result John 26/03/14 John 04/10/14 8 in the game of results above, I need only the score of '8' and 'John' and the unique records only? like this, there are more then millions of records must be calculated.
Please help me with logic
Thank you
Jason
Well,.
in this case, you will need to use something like ROW_NUMBER to keep only the "first" instance:
SELECT name,
joined_date,
exam_type,
score
FROM (select s.*,
ROW_NUMBER() over (partition by order of name of joined_date) rn
s students
where 1 = case when (exam_type = "SCREEN" and score between 8 and 10)
or (exam_type = "RETEST" and the score between 8 and 10 and joined_date > = cut_off_date)
then 1
end
)
WHERE rn = 1;
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I have a purchase order where my buyers can add to my form. I use a loop that adds an extra line when they add a new product. I'm storing the information in two tables different mySQL. The first is alll of my personal, the second is the elements. My personal records correctly. However, I get the following error when you save the items:
You have an error in your SQL syntax; consult the manual for your version of the MySQL server for the right syntax to use near 1, 'wer 2345', 1, 1)' on line 9
The error occurred in E:\webs\clarkwebhosting.com\SSL\esrc\order_add.cfm on line 74
++ After storage of the personal information, I take the command ID to populate the table of Articles
< cflock timeout = "5" >
< name cfquery = "qGetorderID" datasource = "#application.dsn #" >
Select max (orderID) as oid of orders
< / cfquery >
< / cflock >
< cfoutput > < cfset getoid = #qGetorderID.oid # > < / cfoutput >
++ Is the loop that I use to fill the table items ++
< cfloop to = "#form.numba # '1' = ' index 'idx' = >"
< cfset getqty = evaluate ("form.qty" & idx) >
< cfset getitem = evaluate ("form.item" & idx) >
< cfset getunit = evaluate ("form.unit" & idx) >
< cfset gettotal = evaluate ("form.total" & idx) >
< name cfquery = "insertItems" datasource = "#application.dsn #" >
INSERT in Articles
(orderID,
quantity,
agenda,
Unit,
total
)
VALUES)
< cfqueryparam value = "" #getoid # "CFSQLType ="CF_SQL_INTEGER">"
< cfqueryparam value = "" #getqty # "CFSQLType ="CF_SQL_INTEGER">,"
< cfqueryparam value = "" #getitem # "CFSQLType ="CF_SQL_VARCHAR">,"
< cfqueryparam value = "" #getunit # "CFSQLType ="CF_SQL_INTEGER">,"
< cfqueryparam value = "" #gettotal # "CFSQLType ="CF_SQL_INTEGER">"
)
< / cfquery >
< / cfloop >
This line: 1, 'wer' 2345, 1, 1 is the first element of the command line. Any ideas as to why it doesn't work? I use 5.5.9 - log CF9 and mySQL
My apologies... that should have been (note the quotes)...
In addition, it would be...
On another note... You should probably avoid using cfinput and simply use the standard form tags.
-
start end in if then else.
Hello
I've seen people to help
If 1 = 1 then
HOMELESS: = 9;
on the other
HOMELESS: = 10;
end if;
or
If 1 = 1 then
Start
HOMELESS: = 9;
end
on the other
Start
HOMELESS: = 10;
end;
end if;
(1) which is good. (good coding practices)
(2) is it wrong by removing start end if then else.
what I show begin end can be used for the management of exceptions, if it can be used for any other things please tel me.
Yours sincerely944768 wrote:
what I show begin end can be used for the management of exceptions, if it can be used for any other things please tel me.The previous poster gave you good links.
In your example, I think that putting BEGIN/END in each IF/ELSE condition is rare and would not be useful, so I'd omit them.
Nested BEGIN/END blocks can be useful If you want to:
(a) put a label, or
(b) DECLARE a variable that will be used only within that block, and/or
(c) write a specific EXCEPTION handler.Since your example only none of that above, I don't see the use of these nested blocks. When something is useless, do not.
P.S. If the goal is to write modular code, anonymous blocks can declare functions and procedures that can be called from the main block.
set serveroutput on DECLARE PROCEDURE proc_inside(p_msg in varchar2) IS BEGIN dbms_output.put_line( 'Message from procedure within an anonymous block: '||p_msg ); END proc_inside; BEGIN proc_inside('Message A.'); proc_inside('Message B.'); END; / anonymous block completed Message from procedure within an anonymous block: Message A. Message from procedure within an anonymous block: Message B.
Published by: Ashton stew on March 10, 2013 16:46
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How an action can test if (if-then-else) a symbol is visible?
I have a symbol that can be hidden or display depends on a number of previous actions. I need a new action that tests the visibility of this symbol, so I can run a new action if-then-else. How this can be done? I speak not the pictures hidden behind others, just the actions/hide.
Thank you. I'll work with it.
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Error in SQL syntax when inserting data to the table in the form of values using insert record
Hello
I was hoping that someone could help me. I am creating a form of registration on a website to insert data into a database table. When you try to create the form, I get the following error:
You have an error in your SQL syntax; consult the manual for your version of the MySQL server for the right syntax to use near ' VALUES (name, regno, reason) leave (has ', 1, 'dddd')' at line 1
I checked the syntax, but you don't know what's wrong.
I am running Windows 7 with Dw cs6 and wamp server.
Leave with the names of column (name, regno, reason) is the name of the table.
Thank you for your help and please help me.
The code is as below:
<? php require_once('Connections/connect.php');? >
<? PHP
If (! function_exists ("GetSQLValueString")) {}
function GetSQLValueString ($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
If (via PHP_VERSION < 6) {}
$theValue = get_magic_quotes_gpc()? stripslashes ($TheValue): $theValue;
}
$theValue = function_exists ("mysql_real_escape_string")? mysql_real_escape_string ($TheValue): mysql_escape_string ($theValue);
Switch ($theType) {}
case 'text ':
$theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";
break;
case "long":
case "int":
$theValue = ($theValue! = "")? intval ($TheValue): 'NULL ';
break;
case "double":
$theValue = ($theValue! = "")? doubleVal ($TheValue): 'NULL ';
break;
case "date":
$theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";
break;
case "set":
$theValue = ($theValue! = "")? $theDefinedValue: $theNotDefinedValue;
break;
}
Return $theValue;
}
}
$editFormAction = $_SERVER ['PHP_SELF'];
If (isset {}
$editFormAction. = « ? ». htmlentities($_SERVER['QUERY_STRING']);
}
If ((isset($_POST["MM_insert"])) & & ($_POST ["MM_insert"] == "form1")) {}
$insertSQL = sprintf ("INSERT INTO leave (name, regno, reason) VALUES (%s, %s, %s)',
GetSQLValueString ($_POST ['name'], "text").
GetSQLValueString ($_POST ['reg'], "int").
GetSQLValueString ($_POST ['reason'], "text"));
@mysql_select_db ($database_connect, $connect);
$Result1 = mysql_query ($insertSQL, $connect) or die (mysql_error ());
}
? >
< ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd" > ""
" < html xmlns =" http://www.w3.org/1999/xhtml ">
< head >
< meta http-equiv = "content-type" content = text/html"; charset = utf-8 "/ >"
< title > online form let < /title >
< name meta = "keywords" content = "" / > "
< name meta = "description" content = "" / > "
< link href = "styless.css" rel = "stylesheet" type = "text/css" media = "screen" / > "
< / head >
< body >
< div id = 'wrapper' >
< div id = "header" >
< div id = 'menu' >
< ul >
< class li = "current_page_item" > < a href = "#" > home < /a > < /li >
< li > < /li >
< li > < /li >
< li > < a href = "#" > on < /a > < /li >
< li > < /li >
< li > < a href = "#" > Contact < /a > < /li >
< /ul >
< / div >
<!-end #menu->
< div id = "Search" >
< / div >
<!-end #search->
< / div >
<!-end #header->
< div id = "logo" >
E - SCHOOL of CHRIST < h1 > < / h1 >
< p > < / p >
< / div >
< hr / >
<!-end #logo->
<! - end #header - wrapper->
< div id = "page" >
< div id = "content" >
< div class = "post" >
< h2 class = "title" > leave application online < / h2 >
< div class = "entry" > < / div >
< / div >
< do action = "<?" PHP echo $editFormAction;? ">" method = "POST" name = "form1" id = "form1" >
< table width = "200" border = "2" cellspacing = "5" cellpadding = "5" >
< b >
< scope th 'row' = > name < /th >
< td > < label for = "name" > < / label >
< input type = "text" name = "name" id = "name" / > < table >
< /tr >
< b >
< scope = "row" th > Reg No. < /th >
< td > < label for = "reg" > < / label >
< input type = "text" name = "reg" id = "reg" / > < table >
< /tr >
< b >
< scope = "row" th > why < /th >
< td > < label for = "reason" > < / label >
< name textarea = 'reason' id = cols 'reason' = "45" rows = "5" > < / textarea > < table >
< /tr >
< b >
< scope = "row" th > < /th >
< td > < input type = "submit" name = "b1" id = "b1" value = "Submit" / > < table >
< /tr >
< /table >
< input type = "hidden" name = "MM_insert" value = "form1" / >
< / make >
< / div >
<!-end #content->
< div id = "sidebar" >
< ul >
< li >
Notice of < h2 > < / h2 >
< p > students must present the appropriate documents supporting the reason for leave within 3 working days. < /p >
< /li >
< li id = "calendar" >
Calendar < h2 > < / h2 >
< div id = "calendar_wrap" >
< table summary = "Calendar" >
< caption >
March 2014
< / legend >
< thead >
< b >
< th abbr = "Monday" scope = "col" title = "Monday" > M < /th >
< th abbr = "Tuesday" scope = "col" title = "Tuesday" > T < /th >
< th abbr = "Wednesday" scope = "col" title = "Wednesday" > W < /th >
< th abbr = "Thursday" scope = "col" title = 'Thursday' > T < /th >
< th abbr = "Friday" scope = "col" title = 'Friday' > F < /th >
< th abbr = "Saturday" scope = "col" title = 'Saturday' > S < /th >
< th abbr = "Sunday" scope = "col" title = 'Sunday' > S < /th >
< /tr >
< / thead >
< tfoot >
< b >
< td abbr = "February" colspan = "3" id = "prev" > < a href = "#" title = "" > & laquo; Feb < /a > < table >
< class td = "pad" > < table >
< td abbr = "April" colspan = "3" id = "next" > < a href = "#" title = "" > Apr & raquo; < /a > < table >
< /tr >
< / tfoot >
< tbody >
< b >
< td colspan = "5" class = "pad" > < table >
< td > < table > 1
< td > < table > 2
< /tr >
< b >
< td > 3 < table >
< td > < table > 4
< td > 5 < table >
< td > < table > 6
< td > < table > 7
< td > < table > 8
< td > < table > 9
< /tr >
< b >
< td > < table > 10
< td id = 'today' > < table > 11
< td > < table > 12
< td > < table > 13
< td > < table > 14
< td > < table > 15
< td > < table > 16
< /tr >
< b >
< td > < table > 17
< td > < table > 18
< td > < table > 19
< td > < table > 20
< td > < table > 21
< td > < table > 22
< td > < table > 23
< /tr >
< b >
< td > < table > 24
< td > < table > 25
< td > < table > 26
< td > < table > 27
< td > < table > 28
< td > < table > 29
< td > < table > 30
< /tr >
< b >
< td > < table > 31
< class td = "pad" colspan = "6" > < table >
< /tr >
< / tbody >
< /table >
< / div >
< /li >
< li > < /li >
< /ul >
< / div >
<!-end #sidebar->
< div style = "" clear: both; "> < / div >"
< / div >
<!-end #page->
< div id = "footer" >
< p > Copyright (c) University of Christ. All rights reserved. < /p >
< / div >
<!-end #footer->
< / div >
< div align = center > < / div > < / body >
< / html >
The LEAVE is a reserved word in MySQL. You can try to quote, but you are better to rename it.
-
You have an error in your SQL syntax
ColdFusion 7 and mySQL
I get syntax error or access violation: you have an error in your SQL syntax; check the manual that corresponds to your version of the MySQL server for the right syntax to use
It's a job application, and I want that managers are able to enter and modify any part of this.
It says error near 'unique =' I can cook food. I have the power. ', excellent = "Someone asked me w" on line 33
1. What is the error could she talk to?
2. are there limits to this method? It's just too many fields?
3. is there a better way to do it?
Quote:
< cfquery datasource = "afgdb" >
UPDATE extranetJobApp
SET
location = "#Trim (FORM.location), #
month = ' #FORM.month # ',.
day = ' #FORM.day # ',.
year = ' #FORM.year # ',.
nameFirst = "#Trim (FORM.nameFirst), #
nameLast = "#Trim (FORM.nameLast), #
address = "#Trim (FORM.address), #
apt = "#Trim (FORM.apt), #
City = "#Trim (FORM.city), #
State = ' #Trim (FORM.state), #
zip = ' #Trim (FORM.zip), #
phoneHome = "#Trim (FORM.phoneHome), #
phoneCell = "#Trim (FORM.phoneCell), #
18 = "#FORM.eighteen #"
license = "#Trim (FORM.license), #
position = "#Trim (FORM.position), #
hours = "#Trim (FORM.hours), #
travel = "#Trim (FORM.travel), #
dayOnly = ' #Trim (FORM.dayOnly), #
industry = "#Trim (FORM.industry), #
industryLoc = ' #Trim (FORM.industryLoc), #
whySeek = ' #Trim (FORM.whySeek), #
currentEmploy = ' #Trim (FORM.currentEmploy), #
currentContact = "#Trim (FORM.currentContact), #
Felony = "#Trim (FORM.felony), #
felonyExplanation = ' #Trim (FORM.felonyExplanation), #
workRefusal = ' #Trim (FORM.workRefusal), #
workRefusalExplanation = ' #Trim (FORM.workRefusalExplanation), #
knowledge = "#Trim (FORM.know), #
knowWho = "#Trim (FORM.knowWho), #
unique = "#Trim (FORM.unique), #
excellent = "#Trim (FORM.excellent), #
discharge = "#Trim (FORM.discharge), #
dischargeExplanation = ' #Trim (FORM.dischargeExplanation), #
fastPace = "#Trim (FORM.fastPace), #
armedForces = "#Trim (FORM.armedForces), #
armedPosition = ' #Trim (FORM.armedPosition), #
nationalGuard = "#Trim (FORM.nationalGuard), #
socialDL = ' #Trim (FORM.socialDL), #
E1 = "#Trim (FORM.emp1), #
emp1From = ' #Trim (FORM.emp1From), #
emp1To = ' #Trim (FORM.emp1To), #
emp1Position = ' #Trim (FORM.emp1Position), #
emp1Phone = ' #Trim (FORM.emp1Phone), #
emp1Wage = ' #Trim (FORM.emp1Wage), #
emp1From = ' #Trim (FORM.emp1Super), #
emp1Reason = ' #Trim (FORM.emp1Reason), #
EMP2 = "#Trim (FORM.emp2), #
emp2From = ' #Trim (FORM.emp2From), #
emp2To = ' #Trim (FORM.emp2To), #
emp2Position = ' #Trim (FORM.emp2Position), #
emp2Phone = ' #Trim (FORM.emp2Phone), #
emp2Wage = ' #Trim (FORM.emp2Wage), #
emp2Super = ' #Trim (FORM.emp2Super), #
emp2Reason = ' #Trim (FORM.emp2Reason), #
Emp3 = "#Trim (FORM.emp3), #
emp3From = ' #Trim (FORM.emp3From), #
emp3To = ' #Trim (FORM.emp3To), #
emp3Position = ' #Trim (FORM.emp3Position), #
emp3Phone = ' #Trim (FORM.emp3Phone), #
emp3Wage = ' #Trim (FORM.emp3Wage), #
emp3Super = ' #Trim (FORM.emp3Super), #
emp3Reason = ' #Trim (FORM.emp3Reason), #
High school = ' #Trim (FORM.highSchool), #
highSchoolComplete = ' #Trim (FORM.highSchoolComplete), #
highSchoolGrad = ' #Trim (FORM.highSchoolGrad), #
College = "#Trim (FORM.college), #
collegeComplete = ' #Trim (FORM.collegeComplete), #
collegeGrad = "#Trim (FORM.collegeGrad), #
Ref1 = "#Trim (FORM.ref1), #
ref1Relationship = ' #Trim (FORM.ref1Relationship), #
ref1Address = ' #Trim (FORM.ref1Address), #
ref1Phone = ' #Trim (FORM.ref1Phone), #
ref2 = "#Trim (FORM.ref2), #
ref2Relationship = ' #Trim (FORM.ref2Relationship), #
ref2Address = ' #Trim (FORM.ref2Address), #
ref2Phone = ' #Trim (FORM.ref2Phone), #
include = "#Trim (FORM.understand), #
GIS = "#Trim (FORM.sig), #
sigDate = ' #Trim (FORM.sigDate) #
WHERE
jobID = #FORM.jobID #.
< / cfquery > -
Get this error when you use DW CS3 Registration Wizard insert
with CF8 and MySql 5
Quote:
Run database query error.
You have an error in your SQL syntax; check the manual that corresponds to your MySQL Server version for the syntax to use near right "'description') VALUES ('no')' at line 1"
The error occurred in C:\ColdFusion8\wwwroot\mysqltest\untitled1.cfm: line 7
5: VALUES (< cfif IsDefined ("FORM.description") AND #FORM.description # NEQ "" > "")
6: < cfqueryparam value = "" #FORM.description # "cfsqltype ="cf_sql_clob"maxlength ="2147483647">"
7: < cfelse >
8:
9: < / cfif >
--------------------------------------------------------------------------------
SQLSTATE 42000
SQL INSERT INTO testedmemo ('description') VALUES ((param 1))
VENDORERRORCODE 1064
Test DATASOURCE
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