sqlldr: using RTRIM date format conversion

Similar Questions

• varchar2 to the date format conversion

  I have converted the formats of date several times, but for some reason, I get an error invalid number when you try to convert a varchar2 column. I tried the to_char and to_date function and I get the same result. The column is a date and it is formatted like ME-DD-YYYY, but I want to change it to DD/MM/YYYY. My query is below:
  
  Select to_date('fccpdate','MM/DD/YYYY')
  of cc_class_scmast_v
  
  When I try to_date I get this:
  
  Error from the 1 in the command line:
  Select TO_DATE ('fccpdate ',' MON-DD-YYYY "") of cc_class_scmast_v, where fccpdate IS NOT NULL
  Error report:
  SQL error: ORA-01858: a non-digit character was found here where was waiting for a digital
  01858 00000 - "a non-digit character found here where was waiting for a digital".
  * Cause: Input data to convert using a date format model has been
  incorrect answer. The input data did not contain a number where is a number
  required by the format model.
  * Action: Fix the input data or the date format model to ensure that the
  elements correspond to the number and the type. And then try the operation again.
  
  
  
  When I try to_char I get this:
  
  Error from the 1 in the command line:
  Select TO_char ('fccpdate ',' MON-DD-YYYY "") of cc_class_scmast_v, where fccpdate IS NOT NULL
  Error report:
  SQL error: ORA-01722: invalid number
  01722 00000 - "invalid number."
  * Cause:
  * Action:
  
  
  I tried to remove the single quotes of my column and that does make a difference. Any help is appreciated.

  Hello

  housetiger77 wrote:
  I have converted the formats of date several times, but for some reason, I get an error invalid number when you try to convert a varchar2 column. I tried the to_char and to_date function and I get the same result. The column is a date and it is formatted like ME-DD-YYYY,

  If the column is a DATE, then it has the same format that all DATEs, which is nothing like 'DD-MON-YYYY '. Formats like which apply only to chains.
  Conversely, if it is in the format "DD-MON-YYY", then it is a string, not a DATE.

  but I want to change to DD/MM/YYYY. My query is below:

  Select to_date('fccpdate','MM/DD/YYYY')
  of cc_class_scmast_v

  To_date (x, "MM/DD/YYYY") tries to convert the string x in a DATE. Let's say it starts by taking the first 2 characters of x, for the month. The first 2 characters of 'fccpdate' are "fc", which is not a valid number (at least not in base 10), not to mention a number from 1 to 12, TO_DATE so will raise an error.

  When I try to_date I get this:

  Error from the 1 in the command line:
  Select TO_DATE ('fccpdate ',' MON-DD-YYYY "") of cc_class_scmast_v, where fccpdate IS NOT NULL
  Error report:
  SQL error: ORA-01858: a non-digit character was found here where was waiting for a digital
  01858 00000 - "a non-digit character found here where was waiting for a digital".
  * Cause: Input data to convert using a date format model has been
  incorrect answer. The input data did not contain a number where is a number
  required by the format model.
  * Action: Fix the input data or the date format model to ensure that the
  elements correspond to the number and the type. And then try the operation again.

  When I try to_char I get this:

  Error from the 1 in the command line:
  Select TO_char ('fccpdate ',' MON-DD-YYYY "") of cc_class_scmast_v, where fccpdate IS NOT NULL
  Error report:
  SQL error: ORA-01722: invalid number
  01722 00000 - "invalid number."
  * Cause:
  * Action:

  I tried to remove the single quotes of my column and that does make a difference. Any help is appreciated.

  It's a good first step. Literals are enclosed in single quotes are not identifiers (including the column names). "fccpdate" is the literal string of 8 characters containing 'f', ' c; Another 'c', 'p' 'd', 'a', 't' and 'e'. " fccpdate (without the single quotes) can be the name of a column.

  If fccpdate is a string, as July 18, 2012', then you can convert it to a DATE using TO_DATE.

  TO_DATE (fccpdate, 'DD-MON-YYYY')
  

  If you want to display a DATE in a particular format, use

  TO_CHAR ( d
          , f
          )
  

  where d is a DATE, and f is the format string. In this case, d is perhaps the TO_DATE expression above

  TO_CHAR ( TO_DATE (fccpdate, 'DD-MON-YYYY')
          , 'MM/DD/YYYY'
          )
  

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• Date format conversion - am/pm

  I want to insert below in a table, the column is type 'DATE '.
  
  but in the following case which is at 12:00, it removes the time part and returns ony the part date how he converted with a portion of time. (without using 24-hour format)
  See the queries
  
  SELECT to_date('01/11/2011 11:59:00 am','dd/MM/yyyy hh:mi:ss am')
  OF the double
  Back: 11/01/2011 11:59
  
  SELECT to_date('01/11/2011 12:00:00 am','dd/MM/yyyy hh:mi:ss am')
  OF the double
  Back: 11/01/2011
  
  SELECT to_date('01/11/2011 12:01:00 am','dd/MM/yyyy hh:mi:ss am')
  OF the double
  Back: 11/01/2011 12:01:00 AM
  
  I can get it at the TO_CHAR conversion but there is a problem when inserting a DATE column type?
  
  SELECT to_char (to_date('01/11/2011 12:00:00 am','dd/MM/yyyy hh:mi:ss am'),' dd/MM/YYYY HH: mi: ss am')
  OF the double

  user483578 wrote:
  Thanks everyone... It was like that... and worked well

  DECLARE
  x varchar2 (50);

  BEGIN

  SELECT to_char (to_date (11 January 2011 12:00 ',' dd/MM/yyyy hh), ' dd/MM/yyyy HH')
  X
  DOUBLE;

  INSERT INTO my VALUES (to_date (x,' dd/MM/yyyy hh));

  END;

  ?

  It's the same what do I do...

  BEGIN
    INSERT INTO ma VALUES(to_date('01/11/2011 12:00:00','dd/MM/yyyy hh:mi:ss'));
  END;
  

  There is no need to convert a string date and then back to a string and then insert this string by converting it back to a date once again.

• date format conversion

  Hello

  I have the date format in the table as below and now I need to convert the date format YYYY-MM-DD hh: mm :)

  data type of column is varchar2 (20)

  1993-06-24 - 14.15.06.785408 (note: hours, minutes, seconds, milliseconds are separated by.) (dot)

  1991-11-05 - 11.32.17.045702

  Can someone help me please.

  Thank you!

  Hello

  3058870 wrote:

  Hello

  I have the date format in the table as below and now I need to convert the date format YYYY-MM-DD hh: mm :)

  data type of column is varchar2 (20)

  1993-06-24 - 14.15.06.785408 (note: hours, minutes, seconds, milliseconds are separated by.) (dot)

  1991-11-05 - 11.32.17.045702

  Can someone help me please.

  Thank you!

  Do not store information on dates in a VARCHAR2 column. It's simply to request data not valid, complicated, inefficient code and runtime errors.  The columns DATE, or, if necessary, fractions of a second TIMESTAMP.

  To convert strings from one format to another, you can always use TO_DATE to convert any format they are dates and then use TO_CHAR to generate a new string, in any desired output format.

  In this case, it seems that you just want to lose the split second, change the 3rd indent to a space and change points to colons.  You can do the following:

  SUBSTR (datatype, 1, 10).

  ' '                      ||

  REPLACE (SUBSTR (datatype, 12, 8)

  , '.'

  , ':'

  )

  If you would care to post CREATE TABLE and INSERT statements for some sample data and accurate results, you want from these data, then I could test this.

  Check out the Forum FAQ: Re: 2. How can I ask a question on the forums?

  You could do all the work in a single call REGEXP_REPLACE, but it is probably more complicated and less effective.

• Use the date Format

  Hi all

  I have question,

  "If I get the data of an input parameter 10 December 2013 08:41:53.

  How can I convert the format of date,-> "DD-MM-YYYY".

  Thanks for the help of You ' r

  Hello

  If you have a string str = 10 December 2013 08:41:53 ', you can call TO_DATE to create a DATE from it:

  To_date (str, "MM/DD/YYYY HH24:MI:SS")

  (Assuming that "12" is the month and '10' is the day).

  Once you have a DATE (let's call it dt), you can view it in any format you want using TO_CHAR:

  To_char (dt, "DD-MM-YYYY")

  If you wish, you can nest one of these functions inside each other, like this:

  SELECT TO_CHAR (TO_DATE (' DECEMBER 10, 2013 08:41:53 '))

  , "MM/DD/YYYY HH24:MI:SS.

  )

  'DD-MM-YYYY ".

  ), Exit

  DOUBLE;

  Output:

  OUTPUT

  ----------

  10/12/2013

• Date format Conversion MM/DD/YYYY month day, year

  Hi all
  
  Is there a BEEP function that converts the DD/MM/YYYY month day, year?
  
  for example.
  
  08/10/2010 convert to 8 October 2010
  
  Thank you very much!

  Since your date is not in canonical format, you cannot format dates directly.
  You will have to do with workarounds.
  Try to use
  ,

  Here, I assume that your date is delivered in the format MM/DD/YYYY

• How to use the date with the report parameter format

  Hi all
  
  How to use the date format with this tag function,
  
  <? param@begin:P_FROM_DATE? > <? $P_FROM_DATE? >
  
  This date of form source of report and setting is coming as this 2012/11/01 00:00:00.
  
  So now I need this in MY-DD-YYYY marker. I tried like this..? param@begin:P_FROM_DATE? > <? $format - date: P_FROM_DATE; ' DD-MON-YYYY '? >
  
  but its giving error. Can someone pls how to convert to the format of date custom.
  
  Thanks and greetings
  Srikkanth.M

  Problem solved.

  REF this link

  Date Format of XML

• Date of issue - conversion to date and the date of conversion in months

  I have some data in a text file for SQLLDR from a SQL SERVER.
  
  In date columns are YYYY-MM-DD format eg-2011-01-03 00:00:00
  
  but in oracle, we use DD-MM-RRRR.
  
  Don't know why the SD and MM are get interchanged. Help, please.
  
  It's my for sqlldr control file:
  

  LOAD DATA 
  INFILE 'F:\NV\Permits\SQLLDR\permits.txt'
  REPLACE 
  INTO TABLE lot.p_permit
  FIELDS Terminated by "~" TRAILING NULLCOLS
  (
   CP_PermitID  "TRIM (:CP_PermitID)",
   CP_SubmitDate "to_date(to_date(substr(:CP_SubmitDate, 1,19),'RRRR-MM-DD HH24:MI:SS'),'DD-MM-RRRR')",
   CP_IssueDate "to_date(to_date(substr(:CP_IssueDate, 1,19),'RRRR-MM-DD HH24:MI:SS'),'DD-MM-RRRR')")

  You convert date to date. First TO_DATE

  TO_DATE (substr (: CP_IssueDate, 1.19), "DD-MM-RRRR HH24:MI:SS")

  Converts correctly 19 characters of the CP_IssueDate string to date. Now, look at what is happening with the other. To_date first argument is string. Since to_date (substr (: CP_IssueDate, 1.19), "DD-MM-RRRR HH24:MI:SS") are dates:

  TO_DATE (to_date (substr (: CP_SubmitDate, 1.19), 'DD-MM-RRRR HH24:MI:SS'), "DD-MM-RRRR")

  implicitly converts the to_date (substr (: CP_IssueDate, 1.19), "DD-MM-RRRR HH24:MI:SS") to a string using default date format, then converts it back to the date using the format "DD-MM-RRRR. Of course if the default date format is not "DD-MM-RRRR" you can either get an incorrect date or a mistake. In any case, use:

  LOAD DATA
  INFILE 'F:\NV\Permits\SQLLDR\permits.txt'
  REPLACE
  INTO TABLE lot.p_permit
  FIELDS Terminated by "~" TRAILING NULLCOLS
  (
   CP_PermitID  "TRIM (:CP_PermitID)",
   CP_SubmitDate "to_date(substr(:CP_SubmitDate,1,10),'YYYY-MM-DD')",
   CP_IssueDate "to_date(substr(:CP_IssueDate,1,10),'YYYY-MM-DD')"
  )
  

  SY.

  Published by: Solomon Yakobson August 1, 2011 16:45

• How do I change the date format in the section of the United States to the United Kingdom

  As in the question.

  Hello

  I had a glance in this and have found that Thunderbird uses the date format of your computer system. If you change it, it should be reflected in Thunderbird.

  I hope this helps, but if not, please come back here and we can look at another solution for you.

• convert date format period

  Hi all

  Here are my existing query which I run another tool to extract data from oracle-

  Select * from transactionTbl

  WHERE

  DATE > = TO_DATE (' $(vAppStartDate)', "DD/MM/YYYY")

  AND DATE < = TO_DATE (' $(vAppEndDate)', "DD/MM/YYYY")

  variables-

  -vAppStartDate = 06/01/2014

  -vAppEndDate = 30/06/2015

  Rather than use the Date column in the WHERE condition, I want to use PeriodID of column existing in the same table, to make the query faster.

  The period column is in below format.

  PeriodID format-> 201294 //means 2012Q 4. So 9 means Q

  Since I'm on variables, the values are always to the date format, so my requirement is first change variable date from periods of format.

  I wrote the pseudo-code, because I of course know how to convert date format periodID. Q also means in the periodID 9.

  Select * from transactionTbl

  WHERE

  PeriodID > = period_function (TO_DATE (July 1, 14 ',' DD/MM/YYYY '), 'YYYYxx')

  AND PeriodID > = period_function (TO_DATE (July 1, 15 ',' DD/MM/YYYY '), 'YYYYxx')

  Please help me with the query.

  Thank you!

  Calling a user-defined function is likely to slow down your query.

  What's the problem with just using regular date formatting strings for example

  SQL > select to_char (to_date('15/09/2014','DD/MM/YYYY'), 'YYYY "9" Q') of double;
  TO_CHA
  ------
  201493

  1 selected line.

• Date formatting to_char - truncate issue zeros

  Hello

  I have used this date formatting in an APEX application, but I noticed that the problem also occurs when you run a simple script in the database.

  The query is:

  Select

  TO_CHAR (sysdate, 'fmDay, GFMD fmMonth AAAA HH:MIPM'),

  TO_CHAR (sysdate, ' HH:MIPM of MON-DD-YYYY "")

  of the double

  The problem occurs when the minutes have a zero in it, in the example that I have attached, it was 14:05, and it shows as 14:05

  https://plus.Google.com/u/0/photos/104459804528712563956/albums/5958573459391223345/5958573462256341170?PID=595857346225...

  Is there a reason that this is happening? I am unable to use the combination I've used? I really want the full date with month and day names.

  Version of DB: Oracle Database 11g Enterprise Edition Release 11.2.0.3.0

  Amanda.

  Just add fm with the time format:

  SQL > select

  2 to_char (sysdate, 'fmDay, GFMD fmMonth AAAA fmHH:MIPM')

  3 double;

  TO_CHAR (SYSDATE,'FMDAY, FMDDFMMONTHYY)

  ------------------------------------

  Wednesday, December 18, 2013 09:03

  Concerning

  Girish Sharma

• Java date format

  Hello world
  
  I have a piece of code like below for date format conversion.
  

  DateFormat formatter1 ; 
  DateFormat formatter2 ; 
  Date date = new Date(); 
  
  formatter1 = new SimpleDateFormat("yyyy-mm-dd");
  date = formatter1.parse("1952-12-10"); 
  System.out.println("before format, date is " + date);
  
  formatter2 = new SimpleDateFormat("dd-MMM-yy");
  formatter2.format(date);
  System.out.println("after format, date is " +formatter2.format(date));

  I would change from 1952-12-10 became 10 December 52, however, I get the below output:
  
  before the format, the date is Thu Jan 10 00:12:00 MYT 1952
  After format, date is January 10, 52

  AAAA-MM-JJ is probably meant for formatter1.

• Date formats and rawValue

  Hello

  Is there a way to change the default rawValue of a date field. It seems that my default locale (Australia) D/MM/YY. I would like to make it appear as DD MMM YYYY.

  I'm also trying to add it to a text field, for inclusion in mid-sentence, once a date has been selected, using the datefield.rawValue. The text field seems to show only in the form YYYY-MM-DD.

  Thanks in advance for any help or discussion of this problem.

  See you soon,.

  Greig

  Hello

  You can use a model to display the date format in the way that you want.

  date{DD-MMMM-YYYY}
  

  To use the date formatting in another area see the formattedValue instead of the rawValue.

  var d = datefield.formattedValue;
  

• Data format of hyperlink

  I want to be in a position of the column in the query to access a certain URL, for example, suppose I have a column in the database containing data from URL in there, and I want the user to be able to access the URL for the report. I know I can use the data format 'Hyperlink', but I don't want the URL is displayed in this column, I want, for example, the value of 'Visit website' to appear and when the user clicks on this link, the underlying URL would be open in a separate window.

  somehow, I'm not able to view code... just text

  Replace "visit our Web site.

  '|| Cast (DealHeader.AnotherColumntobeshown as varchar (50)). »

  How your url is stored in the database column? Mine is stored as
  http://server/...

• Is there a way to use data formats i.e. Go Mo Ko in numbers?

  Is there a way to use data formats i.e. Go Mo Ko in numbers?

  I am trying to add the size of the library files to estimate the needs of the HD. If I had the files on my system I could just put them in a folder and the operating system would be to calculate them for me, but I don't have them yet. I have a list of files and their size in GB.

  Someone has it worked?

  I suggest the following:

  

  Create a second table called "convert".

  In this table, enter the first column as show (pasted here so you can copy)

  Value	Divide by	suffix
  0	1	b
  400	1024	Ko
  1000000	1048576	MB
  1000000000	1073741824	GB
  1000000000000	1099511627776	TB

  Appropriate now in the table 1 use the conversion table to change the size of the files in the format:

  

  "C2 = ROUND (B2÷VLOOKUP (B2, Convert::A:C, 2, 1), 2) &" "& VLOOKUP(B2,Convert::A:C,3,1)".

  It's shorthand dethrone select cell C2, then type (or copy and paste it here) the formula:

  "= ROUND (B2÷VLOOKUP (B2, Convert::A:C, 2, 1), 2) &" "& VLOOKUP(B2,Convert::A:C,3,1)".

  Select cell C2, copy

  Select cells C2 at the end of the C column, paste