String to double conversion

Similar Questions

• string to double conversion table

  Hello

  I try to convert the string in the array in DBL, but I can't find the function

  Someone can help me. my program is attached

  Thank you

  Use "fact/Exp string to number. http://zone.NI.com/reference/en-XX/help/371361H-01/Glang/fract_exp_string_to_number/

• LV RT - string double conversion

  Hello

  I want to convert a string to double on my camera in time real (PXI-8101. When I use the 'scan value' or "String Fract/Exp to function of number" VI the digits after the decimal point disappear. This does not happen on the host (PC).

  So, for example on the host vi, the string "2121,3" gives the number 2121,3. If I do the same thing on real time, the string "2121,3" returns the number 2121.

  How can I fix?

  Thanks in advance,

  Kind regards
  Dries

  I changed to the '%, %f' format string and now it works. Thanks for the help.

  Best regards
  Dries

• Problem with string to Int conversion

  Dear friends,
  
  Problem with string to Int conversion
  
  I'll have a column where most of the values is digital. Only 4 values are not numeric.
  
  I have replaced the non-numeric values to numeric in order to maintain the data type.
  
  Grade.Grade DEAL WHEN "E4" THEN "24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' Grade.Grade OTHER END"
  
  This is the result as inactive
  
  Grade
  
  _0_
  
  _1_
  
  _10_
  
  _11_
  
  _12_
  
  _13_
  
  _14_
  
  15
  
  _16_
  
  _17_
  
  _18_
  
  _19_
  
  _2_
  
  _20_
  
  _21_
  
  _22_
  
  _23_
  
  _24_
  
  _3_
  
  _4_
  
  _5_
  
  _6_
  
  _7_
  
  _8_
  
  _9_
  
  Discount
  -            -            -
  
  Now I want to convert this value in digital and do some math
  
  So I changed the formula as below
  
  Cast (CASE Grade.Grade WHEN "E4" THEN "24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' Grade.Grade END as an INT. ELSE")
  
  
  Now I get the following error
  View display error
  Driver Odbc _ returned an error (SQLExecDirectW). _
  Error details
  Error codes: OPR4ONWY:U9IM8TAC:OI2DL65P
  _State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error occurred. [nQSError: 17001] Oracle error code: 1722, message: ORA-01722: invalid number in the OIC calling OCIStmtFetch. [nQSError: 17012] In bulk fetch failed. _ (HY000)
  SQL issued: SELECT cast (CASE Grade.Grade WHEN "E4" THEN "24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' Grade.Grade END as an int. ELSE") seen'Human Capital' 0 - Costing Manpower WHERE LENGTH (Grade.Grade CASE WHEN 'E1' THEN '20' WHEN 'E2' THEN '21' WHEN 'E3' THEN '22' WHEN "E4" THEN "23 ' ELSE Grade.Grade END) > 0 ORDER BY saw_0_
  
  Discount
  
  
  
  
  
  Could someone help me
  
  Concerning
  
  Mustafa
  
  Published by: Musnet on June 29, 2010 05:42
  
  Published by: Musnet on June 29, 2010 06:48

  Are you sure you don't have another non-digital value in your column. I want to get this filter temporarily just to check if your plaster works or not. If it works, then you can remove this filter.

• String to number conversion problem

  I have a VI that pulls in data from a device using VISA, and I got it on another computer to work a few weeks back. I had to transfer the VI to a laptop computer to run a few tests, and now I can't make it work. I am unable to put my VI because the laptop on it's is unable to access the network companies, I will do my best to explain it all, I apologize for the inconvenience! My problem is not however with VISA, it's with an exit VISA number conversion chain.

  I have attached a painting drawing of VI to better explain it.

  I use the block series Visa football match in baud rate and all that many good things to the unit and port settings set of device management. Then, a while loop is entered. The loop will run until you press the stop"" button. The next block of visa is the writing block, he asks for a reading of the device. The next block of visa is the first block of reading, he returns playback in the form of "NA-XXX. X' where x are numbers. The next block of visa is the second reading block, this block just echoes back the command sent to the device. Playback of the first visa read block, "NA-XXX. X' is going exponential/fractional chain to digital converter.

  When you perform a run/debug to highlight run, the release of visa reports the correct value, is the value of the device reading - however the string to number converter generates a 0,000, no matter what channel number is. I am at a loss as to what may be wrong because it's the EXACT set up I had to work very well a few weeks ago!

  I'm using Labview 10 on the laptop, the old computer was labview 7. I'm guessing that this is perhaps the rub... I Redid the VI from scratch, although I have not opened the old VI in labview 10.

  Any help would be appreciated. Again, sorry I am unable to attach the VI.

  DARB wrote:

  I have attached a painting drawing of VI to better explain it.

  Would it not have been easier to just post a screenshot? You might also have used the Tool of Capture of Code. (Which reminds me that I need to install it to my previous versions of LabVIEW, as evidenced by the screenshot I took. )

  As to the question: you probably either:

  • employee analysis of chain initially and when you rewrote the VI you used the regular string conversion functions.
  • Wired an offset value in the string to the number function.

  

• Converting a string to Double

  Let's say, I had the string "123", how can I convert a number to floating point double?

  Thank you

  parseFloat("123");

  Kyle

• CHD: the string is used as an index of change in data type? String to double?

  Hello

  I'm new to the tiara. I'm reading the line of a channel number and then to read the data of a channel which is in the same line of another channel.

  That's why I use the SMC function but my index seems not to fit. What I need to change in the code?

  error:

  CHD (2, NOVALUE): = 785 wird die Textvariable «...» CHD (2, > N)

  Code:

   

  DIM intloop, zeilenwerte
  
  Line DIM, aktwert, index
  
  Call ChnAlloc ("zeilenwerte", lang, 1, DataTypeFloat64)          ' Create channel,  'lang' is the size of a channel
  
  index = 0
  
  index = 1 to lang
  
     index = index + 1
  
     aktwert zeit (index) =                         ' get the value that will be compared to the SOPS in the following line of code
  
     Line = PNo (myChannel, aktwert)        ' it returns the line only by comparing aktwert valued myChannel
  
     CHD (line, zeilenwerte) = intloop           '  <--->here the error. try to get the value in a line @index do String data types does not match? what do I do then?
  
  Next

  Thank you very much for your help!

  Buddhist salvation,

  It seems to me that you would be better to use "Linear Mapping" in the palette of ANALYSIS "Suitable curve", but you should be able to get your code works by passing the name of the channel in this second parameter instead of an empty string variable.  You would have noticed that if you had OPTION EXPLICIT the first line of your code - always a good idea.

  Brad Turpin

  Tiara Product Support Engineer
  National Instruments

• The decimal string to number Conversion, cutting necessary zeros

  I'm new to the forum, but have been using labview for awhile. Finally found something that really puzzled me, hope I can find someone who is smarter than me! It may be something obvious too, but here goes. The attached vi is the cause of the error. I have a serial number I need to convert a decimal string into a number, I use later the number of "math" so he need as a number. The system always receives a serial number of 6 characters (ie. 123456), but today the system has received a serial number with two leading figures of the scale (ie. 003456) zeros. This compensation of all the bells of alarm stream (sent 4 digits), but the error found that started the 'intelligence' at the beginning of the monitoring program. I would like to know if there is a way to force the zeros in the decimal number in string to not shave off the coast of the 6-digit value above.

  File is located in LabVIEW 2014

  Ideas or comments, thank you!

  The problem is not the string functions.  This is the display format for your digital indicator.  Change the properties on that.

  

• Hexadecimal string of digital conversion

  I have the following string returned by a MODBUS instrument:

  

  My embedded data are 0104, 7530, 7530, 7530 that appears inside the Green brackets.

  I want to convert them into digital data relevant to 260, 30000, 30000 30000.

  Tried to do it with an attached VI. Do not do good. Any help would help!

  (The attached VI tries to convert only the first data that is 0104)

  
  

• remove the string in double paragraph

  Hi, I wandered if someone had the best way to search for a string and delete the repeated subsections.

  For example, the input string may look like:

  T2, T2, T3, T6

  but I want to delete one of the T2 repeated, so the output would be:

  T2, T3, T6

  Note that the input string can be any length and a multiple of 4. I went through all the string functions and find nothing to match what I'm asking. I tried to use "String subset" in a wired loop in an output table.

  Any help in the right direction would be appreciated!

  Here's a handy dandy little tool that does just that.  The strings must be delimited by commas.  It is in LV2009.  If you do not, save the file and send it to the thread Downconvert VI ask.

• string floating-point conversion issues

  Dear reader,

  System:
  Windows 2000 with Labview 8.0 update 8.0.1

  I'm having problems converting a string to a variable number to decimal. The string I want to convert is "+ 000.41". If I feed this string to a string for the object Number Fract/Exp the result is 0. I found it a little strange so I check to another computer and the result was 0.41. The only differentses between systems was version 8.0 and 8.0.1 and the opperating system windows 2000 and Xp. So I run an update to update the version of 8.0.1, but that didn't work.
  Now I am stuck and don't know where to look for a solution. So can you help me?

  Kind regards

  K. Zwetsloot

  
  

• Analysis of string to double unit 'French '.

  Maybe I am not forum pretty hard, but here is a strange problem.

  When I run this line:

  double dValue = Double.parseDouble(str);
  

  on a device with the English language, everything is OK.

  But when I change the language to French , he throws NumberFormatException !

  No explanation?

  OS 6/7

  Sorry, that was actually no analysis but memory corraption another place that caused this issue.

• Extract the given string a String between double quotes

  Hey guys,.

  I am doing a project open source to help lovers of ADS - B to store data on Oracle Database XE (11.2.0.2)

  I need to retrieve a string, but I didn't know how, please can someone help me.

  Chain: [{'id': 'PR - GIG', 'label': "PR-CONCERT - E47EB2 - BS Airlines - Boeing 737 - 73 S (29077)", "value": 'PR - GIG' "}]

  KeyString: "label".
  

  Output: ' PR-CONCERT - E47EB2 - BS Airlines - Boeing 737 - 73 S (29077) '

  
  

  And if possible put this string in multiple strings

  String1: PR-GIG

  Channel 2: E47EB2

  String3: BS Airlines

  String4: Boeing 737 - 73 S

  String5: 29077
  

  Thanks for the help.

  Select x.*

  t,.

  XMLTable)

  "ora: tokenize($s,"-").

  from regexp_substr (str,'"label": "([^"]+) "', 1,1,null, 1) as"s ".

  ) x

  /

  COLUMN_VALUE
  -------------------------
  PR - GIG
  E47EB2
  BS Airlines
  Boeing 737 - 73S (29077)

  SQL >

  SY.

• Time to string to Numeric conversion

  Oracle: 10g
  
  
  I have a column in the table which is a time calculated and stored as follows
  
  t_resp
  
  4h59m38s
  1d8h36m
  37m29s
  0 s
  1 m
  3: 00
  
  Like this
  
  How can I convert the string which consists of d-> day-> time: m-> Min minutes for comparisons and additional calculations.
  
  Is there any direct sql statement, we can write another to write a plsql to collect for this.
  
  Thanks in advance.

  Like this

  with t
  as
  (
  select '4h59m38s' str from dual union all
  select '1d8h36m' str from dual union all
  select '37m29s' str from dual union all
  select '0s' str from dual union all
  select '1m' str from dual union all
  select '3h' str from dual
  )
  select str,
         nvl(replace(regexp_substr(str,'[[:digit:]]*d'),'d'),0)*24*60*60 +
         nvl(replace(regexp_substr(str,'[[:digit:]]*h'),'h'),0)*60*60 +
         nvl(replace(regexp_substr(str,'[[:digit:]]*m'),'m'),0)*60 +
         nvl(replace(regexp_substr(str,'[[:digit:]]*s'),'s'),0) seconds
    from t
  

• String to date Conversion inside XSLT

  Hi all
  
  I want to convert a string of (Eg: 2009-12-06 00:00:00) to a type of format date yyyy-mm-dd Vice versa.
  
  I managed to convert the Date to a string
  
  < element name = "input" type = "date" / > (schema)
  
  < element name = "result" type = "string" / > (schema)
  
  
  < ns1:SIDtoCRMProcessResponse >
  < ns1:result >
  < xsl: value-of select = "xp20:format - dateTime (/ ns1:SIDtoCRMProcessRequest / ns1:input,)" [M01] / [D01] / [Y0001] [H01]: [m01]: [s01] ")" / > "
  < / ns1:result >
  < / ns1:SIDtoCRMProcessResponse >
  
  
  but when try to String in Date
  
  < element name = "input" type = "string" / > (schema)
  
  < element name = "result" type = "date" / > (schema)
  
  < ns1:CRMToSIDProcessResponse >
  < ns1:result >
  < xsl: value - of select = "xp20:format - dateTime(/ns1:CRMToSIDProcessRequest/ns1:input,"[Y0001]-[M01]-[D01]")" / > "
  < / ns1:result >
  < / ns1:CRMToSIDProcessResponse >
  
  his failure
  
  I think the format dateTime function expects the entry date. Can someone kindly help me how to convert String to Date inside a xsl without using the external java function.
  Thank you

  you could use some dirty concatination to build the format yourself.

  not going to win the beauty contest but