String to number conversion problem

Similar Questions

• The decimal string to number Conversion, cutting necessary zeros

  I'm new to the forum, but have been using labview for awhile. Finally found something that really puzzled me, hope I can find someone who is smarter than me! It may be something obvious too, but here goes. The attached vi is the cause of the error. I have a serial number I need to convert a decimal string into a number, I use later the number of "math" so he need as a number. The system always receives a serial number of 6 characters (ie. 123456), but today the system has received a serial number with two leading figures of the scale (ie. 003456) zeros. This compensation of all the bells of alarm stream (sent 4 digits), but the error found that started the 'intelligence' at the beginning of the monitoring program. I would like to know if there is a way to force the zeros in the decimal number in string to not shave off the coast of the 6-digit value above.

  File is located in LabVIEW 2014

  Ideas or comments, thank you!

  The problem is not the string functions.  This is the display format for your digital indicator.  Change the properties on that.

  

• Varchar2 to the number conversion problem

  I have some difficulty conversion strings to numbers. On my Oracle 9.2 server, it gives me an error ORA-1722:
  SELECT TO_NUMBER ('1.2') OF DOUBLE
  Apparently, this is because my server is configured to use the Greek number format (comma instead of decimal point) and substitute "1.2' above with '1.2' will work correctly."
  Is it possible for me to convert strings with decimal number type, independent of the culture so that my application will not have to depends on the locale setting of the server?
  
  Thank you.

  Hello

  Welcome to the forum!

  If you don't want to change the NLS settings for your session, you can specify what settings to use for a particular call to TO_NUMBER (and other features), like this:

  ALTER SESSION     SET NLS_TERRITORY = GREECE;
  
  SELECT     TO_NUMBER ('1.2')     AS wont_work
  FROM     dual;
  
  SELECT     TO_NUMBER ( '1.2'
              , '999999999.999999'
              , 'NLS_NUMERIC_CHARACTERS = '',.'''
              )          AS n
  FROM     dual;
  

  The output below shows the TO_NUMBER 1-argument fails, but the 3-argument TO_NUMBER works:

  Session altered.
  
  SELECT  TO_NUMBER ('1.2')       AS wont_work
                     *
  ERROR at line 1:
  ORA-01722: invalid number
  
           N
  ----------
         1,2
  

  The actual format of the string (the first argument) should not match precisely the format mask (the second argument). You can include signs, or omit the decimal points, so '3', ' '-1,2. '-3', ' + 1.2 ' and ' + 3' will be all converted correctly.»»» "

• Basic question on the string-to-number conversion

  Hello
  
  I have a string, for example '23,2445,45'
  I want to extract the numbers of this string and put it in an array of numbers.
  
  Any keyword SQL is available. What is the best way to do it.
  
  Thank you
  MD

  Try this

  declare
  
  type vnum is varray(20)  of number;
  
  vnum1 vnum :=vnum();
  
  j number;
  
  begin
  
  j:= 1;
     for i in (
     with t as (
     select '23,2445,45' product_string from dual
     )
     SELECT   *
         FROM (SELECT
                      RTRIM(LTRIM(SUBSTR(product_string,
                                         INSTR(',' || product_string||',', ',', 1, n),
                                           INSTR(',' || product_string||',', ',', 1, n + 1)
                                         - INSTR(',' || product_string||',', ',', 1, n))),
                            ' ,') AS prod
                 FROM t,
                      (SELECT     ROWNUM n
                             FROM DUAL
                       CONNECT BY LEVEL < 10))
       WHERE prod IS NOT NULL)
       loop
  
       vnum1.extend;
       vnum1(j):= to_number(i.prod);
  
       dbms_output.put_line(vnum1(j));
  
       j:=j+1;
  
       end loop;
  
       end;
    
  

  vnum1 vnum: = vnum (0,0,0,0,0,0,0,0,0);

  I did it because I don't know how to initialize the array. Need to read more about it.

  This will put the values in the vnum1 table.

  If you need to do something with the numbers in the string

  so you can do the following without using a table.

  declare
  begin
     for i in (
     with t as (
     select '23,2445,45' product_string from dual
     )
     SELECT   *
         FROM (SELECT
                      RTRIM(LTRIM(SUBSTR(product_string,
                                         INSTR(',' || product_string||',', ',', 1, n),
                                           INSTR(',' || product_string||',', ',', 1, n + 1)
                                         - INSTR(',' || product_string||',', ',', 1, n))),
                            ' ,') AS prod
                 FROM t,
                      (SELECT     ROWNUM n
                             FROM DUAL
                       CONNECT BY LEVEL < 10))
       WHERE prod IS NOT NULL)
       loop
  
  -----Do what ever you want with the number.
  
       dbms_output.put_line(i.prod);
  
       end loop;
       end;
    
  

  Published by: alvinder on March 11, 2009 15:18

  Discovered how to initialize the array.

• Problem with string to Int conversion

  Dear friends,
  
  Problem with string to Int conversion
  
  I'll have a column where most of the values is digital. Only 4 values are not numeric.
  
  I have replaced the non-numeric values to numeric in order to maintain the data type.
  
  Grade.Grade DEAL WHEN "E4" THEN "24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' Grade.Grade OTHER END"
  
  This is the result as inactive
  
  Grade
  
  _0_
  
  _1_
  
  _10_
  
  _11_
  
  _12_
  
  _13_
  
  _14_
  
  15
  
  _16_
  
  _17_
  
  _18_
  
  _19_
  
  _2_
  
  _20_
  
  _21_
  
  _22_
  
  _23_
  
  _24_
  
  _3_
  
  _4_
  
  _5_
  
  _6_
  
  _7_
  
  _8_
  
  _9_
  
  Discount
  -            -            -
  
  Now I want to convert this value in digital and do some math
  
  So I changed the formula as below
  
  Cast (CASE Grade.Grade WHEN "E4" THEN "24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' Grade.Grade END as an INT. ELSE")
  
  
  Now I get the following error
  View display error
  Driver Odbc _ returned an error (SQLExecDirectW). _
  Error details
  Error codes: OPR4ONWY:U9IM8TAC:OI2DL65P
  _State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error occurred. [nQSError: 17001] Oracle error code: 1722, message: ORA-01722: invalid number in the OIC calling OCIStmtFetch. [nQSError: 17012] In bulk fetch failed. _ (HY000)
  SQL issued: SELECT cast (CASE Grade.Grade WHEN "E4" THEN "24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' Grade.Grade END as an int. ELSE") seen'Human Capital' 0 - Costing Manpower WHERE LENGTH (Grade.Grade CASE WHEN 'E1' THEN '20' WHEN 'E2' THEN '21' WHEN 'E3' THEN '22' WHEN "E4" THEN "23 ' ELSE Grade.Grade END) > 0 ORDER BY saw_0_
  
  Discount
  
  
  
  
  
  Could someone help me
  
  Concerning
  
  Mustafa
  
  Published by: Musnet on June 29, 2010 05:42
  
  Published by: Musnet on June 29, 2010 06:48

  Are you sure you don't have another non-digital value in your column. I want to get this filter temporarily just to check if your plaster works or not. If it works, then you can remove this filter.

• Sub - VI with the entry as a string og number

  At this small Subvi. I wonder if I could make it more flexible and be able to take the string and number as a value ('value dbl' market) entry.  Is there some sort of variable of variant type that could be used?

  

  Michael.Koppelgaard wrote:

  At this small Subvi. I wonder if I could make it more flexible and be able to take the string and number as a value ('value dbl' market) entry.  Is there some sort of variable of variant type that could be used?

  It is possible with the key to write OpenG (varying) _ogtk.vi. But the problem is that when you want to read this back, you need to know what type it is. If you write to a different section of the config file each with a specific type, the TI will work. With this solution, you must use the key to reading OpenG (varying) _ogtk.vi to read and convert the value to LV

  Another way is to use Get Type Information.vi of the Variant Data Type palette. The trick here is to convert double or string before saving it in the config file (wire structure dealing with the output type of the vi and do conversions in the case of type dbl and string). Here, too, you must use a different section, one for dbl for string. Here, you use the standard Read button live file configutaion palette.

  Ben64

• Is the locale-specific number conversion chain?

  I would like to know what effect the computer's regional settings may have on the string number conversion in AS3. Specifically, in locales that use a comma as the decimal separator instead of a period, different conversion methods (Number() function, parseNumber(), Builder of the Number() class) they treat the comma as decimal separator? None of the documents I've read resolves this problem and all the examples use periods as a decimal separator. I suspect periods in strings will always be handled as decimal separators (and this is the behavior I want), but I would like to know for sure.

  FTR, an Adobe employee comes to informs me on programmers list that the answer to this question is no. period is always interpreted as a decimal separator, regardless of the location of the BONE.

• "Decimal string to Number.vi" bug in LabVIEW 2009 SP1

  The "decimal string to Number.vi' seems to be the conversion of the input data in the type int32 internally even when the input tape in vi data is expanded floating point (no points of constraint).  This is causing me grief.  See attached vi

  This bug is still present in LabVIEW 2010?

  Thank you

  Richard Ballantyne

  There is no bug. You use the wrong function (see Help) If you want a floating point output. Use Fract/Exp string to a number.

• How convert string to number

  How convert string to number
  
  
  my character
  
  
  Select form double to_number ('1,6,9,4'); my putting here 1,6,9,4
  
  get the character of number conversion error.
  
  concerning
  
  Published by: vr on March 31, 2011 23:59
  
  Published by: vr on March 31, 2011 23:59

  VR says:
  Getting error while the conversion of character to the number in instring is possible to get the position of the channels at one time

  I have the following table, called pack

  Acct_No pack2 pack3 pack1
  1000 10101011 111111101 01010101111

  Select * Pack
  where instr (pack2, ' 1') and * (to_number (replace('1,6,9,4',','))); * - getting values of function as string '1,6,9,4'

  If you want to retrieve lines where the position of the first "1" in the pack2 chain is one of the positions in your list number e.g. position 1, 6, 9, or 4?

  Something with regexp_like can help...

  SQL> ed
  Wrote file afiedt.buf
  
    1  with pack as (select '1000' as acct_no, '10101011' as pack1, '111111101' as pack2, '01010101111' as pack3 from dual union all
    2                select '1001', '10101011', '000011111', '10101010110' from dual union all
    3                select '1001', '10101011', '000000001', '10101010110' from dual)
    4  --
    5  -- end of test data
    6  --
    7  select pack.*, case when regexp_like('1,6,9,4','(^|,)'||to_char(instr(pack2,'1'),'fm9999')||'(,|$)') then 'Yes' else 'No' end as x
    8* from pack
  SQL> /
  
  ACCT PACK1    PACK2     PACK3       X
  ---- -------- --------- ----------- ---
  1000 10101011 111111101 01010101111 Yes
  1001 10101011 000011111 10101010110 No
  1001 10101011 000000001 10101010110 Yes
  

• PL/SQL: digital or value error: character number conversion in the TRG error

  Hello
  I have a strange problem with a trigger that, during the update of the table of reports (DB is 9.2.0.8):

  ORA-06502: PL/SQL: numeric or value error: character to number conversion error
  ORA-06512: at "UDR_LOG", line 345
  ORA-04088: error during execution of trigger 'UDR_LOG'

  but the 345 line is:
  END IF;
  
  This kind of strange

  the code looks like
  
  343 IF nvl(to_char(:old.PKD_ID),'''') <> nvl(to_char(:new.PKD_ID),'''') THEN
  344     v_zmn := v_zmn || 'PKD_ID''' || to_char(:old.PKD_ID) || '''' || to_char(:new.PKD_ID) || '''';
  345    END IF;
  
  so its concatenation not to_number usage .

  error is raised by the update on a column.
  
  I'm sorry that I can't provide you with the code in the trigger everything.
  So, if you could recommend only whole method of inquiry that would be great.
  Concerning
  Greg

  Hi, Greg.

  When there is an error in a trigger, the line numbers in error messages are compared to the first statement DECLARE or BEGIN; often, it is a few lines after CREATE OR REPLACE TRIGGER. Post a few lines after what you have already posted.

  If you do not find the error, then create another table to test this and create a small trigger on that table, who did just enough to cause the error. Then, you will be able to post the complete relaxation, and the code needed to recreate the problem.

• I have 22 SPSS for Mac.  Since I upgraded to El Capitan, I have a number of problems.  I checked the Web sites of IBM, but they only mention fixes for SPSS 23.  Any thoughts would be greatly appreciated.  Thank you.

  I have 22 SPSS for Mac.  Since I upgraded to El Capitan, I have a number of problems.  I checked the Web sites of IBM, but they only mention fixes for SPSS 23.  Any thoughts would be greatly appreciated.  Thank you.

  I am running SPSS 23.0

  You can upgrade to 23.0?

  Also, have you looked here

  http://www-933.IBM.com/support/fixcentral/SWG/selectFixes?parent=SPSS & Product = IB m / + Information Management / SPSS + statistical...

• How to convert string to number in TS?

  Hello

  Anyone know how to convert string to number in TS?

  I couldn't find the Num() function.

  Thank you

  Val()

• Whole singed to hexadecimal string to number converter

  HI guys...

  I want to convert the number to hex string to number converter but when I connect integer, otherwise it does not change the value (as if you write 'EC78' you should get "-5000", but I get the value in the range of 60 thousand ")...

  Any ideas?

  Thanks in advance...

  MADO...

  Hi Eric,.

  clearly, the OP asked for signed integers!

  Use this approach:

  ,

  It will mean by '-' 5000 for your example EC78h...

• string to double conversion table

  Hello

  I try to convert the string in the array in DBL, but I can't find the function

  Someone can help me. my program is attached

  Thank you

  Use "fact/Exp string to number. http://zone.NI.com/reference/en-XX/help/371361H-01/Glang/fract_exp_string_to_number/

• Number del problema evento: BEX application number: devenv.exe

  I can't launch the application by all means, I have tried almost everything

  This error whenever I try to start the application

  Number del problema evento: BEX
  The application number: devenv.exe
  Application version: 12.0.21005.1
  Marca of tiempo of the application: 524fcb34
  Number del modulo con errores: StackHash_4150
  Version del modulo con errores: 0.0.0.0
  Tiempo del modulo Marca con errores: 00000000
  Exception offset: d4aa3de8
  Exception code: c0000005
  Exception data: 00000008
  Led operating system version: 6.1.7601.2.1.0.256.48
  ID of regional config: 8202
  Additional 1:4150 information
  Additional information 2: 415033a9f1ae6fcc5aebaf4daaa5684d
  3: 86 additional information has 0
  Additional information 4: 86a011b887b8da0d2c7df6b38f9d7e04

  This error seems to be related to Visual Studio.  If you explain what you do to cause this error to appear, it is possible that someone here may be able to help, but I suspect that you would be more likely to get help by asking in the appropriate MSDN (developer) or TechNet forums (technical):

  https://social.msdn.Microsoft.com/forums/vstudio/en-us/home?Forum=visualstudiogeneral

  https://social.technet.Microsoft.com/forums/en-us/home?Forum=whatforum