String::view - how to convert to wchar_t

Similar Questions

• How to convert string to number in TS?

  Hello

  Anyone know how to convert string to number in TS?

  I couldn't find the Num() function.

  Thank you

  Val()

• How to convert a string to a number?

  How to convert a numeric string to a number of TestStand?

  Use Val().

  Example Val (Locals.myString)

• How to convert a single byte String?

  Purpose:

  Show a result byte on the BB 9900 screen.

  Question:

  How to convert a single byte String?

  Part of the code:

  byte value = con.cpu_config.elementAt (i)

  stop here

  String valuestring = new String (value);

  _rtf. SetText (valueString);

  If you know how to fix it, please share your idea.

  Thank you for your attention,

  String valuestring = new String (new byte [] {value}};)

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• How to convert int to String

  How to convert int to String. I get the error 'cannot convert integer to int.

  Dim str As String = "abc";

  int NB = Integer.valueOf (str);

  Use Integar.parseInt (). But make sure your str contains the integer value (like str = '123') otherwise you will get the exception.

  String str = "123"; int num = Integer.parseInt(str);
  

  Concerning

  Bika

• How to convert string to datetime in the transformation of the Ombudsman

  Hello

  I am getting error below when inserting the data in the database using the database.

  Exception occurred when the link was invoked. Exception occurred during invocation of the JCA binding: "JCA binding run reference"insert"operations have to: DBWriteInteractionSpec Execute Failed Exception." insertion failed. The descriptor name: [InsertPayload.XxohInsertStgTable]. Created by Exception [EclipseLink-3001] (Eclipse - 2.3.1.v20111018 persistence Services - r10243): org.eclipse.persistence.exceptions.ConversionException Description of the Exception: object [2015-09-14 15:19:51], class [class java.lang.String], couldn't be converted [class java.sql.Timestamp]. Inner exception: LINK. JCA-11636 couldn't convert Timestamp Exception. Cannot convert a string value in the xml file to a java.sql.Timestamp. Although the databases accept strings representing the timestamps in a variety of formats, the adapter only accepts strings that represent xml ISO dateTime format. The input value must be in the format XS: DateTime to iso 8601, i.e. YYYY-MM - DDTHH:MM:SS.sss - 07:00. Please see the logs

  In the transformation of the mediator, the Source element is a string

  < xs: element name = "CREATED_DATE" type = "xs: String" > < / xs: element >

  Target is of type dateTime

  < xs: element name = "Creation_Date" type = "xs: DateTime" minOccurs = "0" nillable = "true" / >

  To avoid the above error, I used < xsl: value-of select ='xp20:format - dateTime (/CREATED_DATE, "[Y0001]-[M01]-[D01] [H01]: [m01]: [s01]")'/ > in the transformation, but its does not work. The value is blank display after processing.

  Please suggest me how to solve this problem.

  Thank you

  Sunita

  Unfortunately, the format required by the dateTime format is YYYY-MM - DDTHH:MM:SS.sss

  You can use the substring, and on the entry's concat function to create YYYY-MM - DDTHH:MM:SS.sss

  See formatting string to date in BPEL

• How to convert string input streams

  Can someone tell me how to convert string input streams...

  There are multiple ways. I will list down few of them.

  With the help of the old solution and standard java.
  

  publicstaticString fromStream(InputStream in)throwsIOException {    BufferedReader reader =newBufferedReader(newInputStreamReader(in));    StringBuilder out =newStringBuilder();    String line;    while((line = reader.readLine()) !=null) {        out.append(line);    }    returnout.toString(); } returnsb.toString();

  If you use Google-Collections/guava-

  InputStream stream = ... String content = CharStreams.toString(newInputStreamReader(stream, Charsets.UTF_8)); Closeables.closeQuietly(stream);

  If you use the common Apache library... then it is worthwhile.

  StringWriter writer =newStringWriter(); IOUtils.copy(inputStream, writer, encoding); String theString = writer.toString();

  Quick way but only work during deserialization.

  String result = (String)newObjectInputStream( inputStream ).readObject();

  Note: ObjectInputStream is on deserialization and the flow of data must respect the Protocol of serialization to work, which may not always true in all cases.

  Ultimately, the most effective solution and only in two lines using java class Scanner.

  Tricky is to remember the \A regex that matches the beginning of the entry. It actually indicates Scanner to mark all of the flow, from start to beginning next (illogical).

  publicstaticString convertToString(InputStream in) {    java.util.Scanner s =newjava.util.Scanner(in).useDelimiter("\\A");             returns.hasNext() ? s.next() :""; }

  Read more: http://www.techartifact.com/blogs/2013/11/how-to-readconvert-an-inputstream-to-a-string.html#ixzz2lvy5muix

• OpenScript/Bank of data/how to convert string to int

  Hello
  
  As far as I know, the values read from the database is a type of Sting. Now, I want to convert a character number stored in the database of type int.
  For example, in "Test.csv" I stored the '9' in the column 'Number' character, then I use the following code to read the character and convert an int in one:
  getDatabank("Test").getNextDatabankRecord ();
  String Testnumber = "{{db." Test.Numberr}} '; Info (Testnumber);
  int number = Integer.parseInt (Testnumber);
  
  However, it seems this does not work, because he says "basic unexpected failure caused by: NumberFormatException occurred." For the input string: «{{db.» Test.Numberr}}.
  I think that this error can be caused by the conversion of character '9' int 9.
  Can someone tell me how to convert a character to be read from database in an int?
  
  Thank you very much!
  
  Kind regards
  Angyoung

  Hello

  You can use the same approach. Use eval()

  getDatabank("Test").getNextDatabankRecord();
  String Testnumber =eval("{{db.Test.Numberr}}") ;
  info(Testnumber);
  int number = Integer.parseInt(Testnumber);
  

  Kind regards
  Dembélé M

• How to convert a Blob to String? Hi all

  How to convert a Blob to String? Hi all
  
  currentRow.getAttribute ("TemplateFile"); TemplateFile is file blob...
  
  I want to convert...

  What is the data type of the TemplateFile in the VO... or VORowImpl... is - this String?... If so it changes of type Blob...

• How to convert String to Date

  hell there everyone,

  I have a question which is:

  How to convert a string that we get by reading an XML in the instance of date value type?

  So there is a XML that modifiedDate as an attribute on a node of the XML and how I put this value in an instance variable date?

  the timeformat in the XML file is: mm/dd/yyyy hh: mm: = > 31/12/2010 23:57:46

  I chose this time format because I want to use the method . parse() which always causes an error, but that's another topic...,.

  hope I was clear on the issue,

  Thanks in advance for the help.

  First of all, you should watch the Date object constructor to find out how to specify different parameters.

  public void Date (yearOrTimevalue:Object, month:number, date:number = 1, hour:number = 0, minute:number = 0, second:number = 0, millisecond:number = 0)

  Then you need to determne how to break the string by using the String.Split method.  The first split() should be the space between the date and time, the second for the slashes in the date and the third for the colon in time.

  Then you come to take each of these paintings of substrings and feed them in the constructor as the Number() values.

  If you remain unsure how to do this, look at the different terms that I have identified in the help documents and you will find them all explained with examples.

• How to convert a string and use a rope as a property?

  I have an array in the following format:

  {ownsCar: 'true', ownsBike: 'true', ownsHouse: 'true'}

  {ownsCar: ownsBike 'false',: 'true', ownsHouse: 'true'}

  {ownsCar: 'true', ownsBike: ownsHouse 'false',: 'true'}

  etc ............

  And I need to test against each element, for example

  If...

  myDataGrid ["myItem"] .ownsCar is object (myCheckbox) .label

  ... then

  If...

  myDataGrid ["myItem"] .ownsBike is object (myCheckbox) .label

  ... then

  If...

  myDataGrid ["myItem"] .ownsHouse is object (myCheckbox) .label

  ... then

  But I have to build my application where the property (for example 'ownsCar', 'ownsBike', 'ownsHouse') is a variable such as:

  If...

  myDataGrid ["myItem"] .myProperty is object (myCheckbox) .label

  ... then

  I would like to browse my table, by counting the number of items and then use each element as a property.

  How to convert the string (for example, "ownsCar") in a property "myProperty"?

  Thanks in advance

  Chris

  OK, if I got this right what you need to do is introspection.

  The easiest way to do this would be:

  for ( var propertyName:String in myObject ) {
       // Do what you need with this here:
       myObject[ propertyName ];
  }
  

• [Oracle 8i] How to convert a string (timestamp) in a date?

  I find it difficult to know how to convert a string to a date time stamp (or possibly several).
  
  The timestamp is 20 positions, character (NOT NULL, CHAR (20))
  in the format: YYYYMMDDHHMMSSUUUUUU
  where Y = year, M = month, D = day, M = Minutes, S = seconds and U = microseconds
  
  The reason why I want to convert it is so that I can compare a timestamp to each other (that is, I want to be able to find the MIN (timestamp), MAX (timestamp) and make comparisons of inequality).
  
  Is this possible?
  
  Thanks in advance for the help on this!

  Hello

  As Damorgan said, if all you want to do is find which is the earlier or later, then you can just compare the strings: they are in a format where it works.

  If you need to do other things, such as compare to today date or see the difference between two of your lines of days, you will need to convert it to date. (He has no reason to convert them to numbers).

  A new TIMESTAMP data type, which manages the fractions of a second, was introduced in Oracle 9.
  Since you use Oracle 8 (depending on your subject line), or it must be
  (1) ignores the microseconds, or
  (2) use a separate column for microseconds.

  Whatever it is, use TO_DATE to convert the first 14 characters in DATE:

  TO_DATE ( SUBSTR (txt, 1, 14)
          , 'YYYYMMDDHH24MISS'
          )
  

  where txt is your column of type CHAR.
  To convert microseconds to a number (between 0 and 999999):

  TO_NUMBER (SUBSTR (txt, 15))
  

• How to convert an analog signal into digital signal

  Hello

  How to convert an analog signal into digital signal, such that each sample of the analogue signal corresponding to 1.2V will be represented as '1' digital signal and other samples of the analog signal (which are not 1.2V) will be represented (converted) ' 0' in the digital signal.

  And how to view the wavefroms or graphical indicators signals.

  Thank you.

  If you have 1000 samples and you want to convert to digital, you get 1000 digital values.  Attached, that's what I mean.

• How to convert hex 8 bytes floating point double?

  Hello

  I want to know how to convert a string of 8 bytes of data double floating-point.

  data (HEX): 40 02 70 40 00 00 00 4F

  Thank you.

  DP

  This string of 8 bytes of data is actually a string? Are the characters in the string of letters or you have hex values? Ultimately you want to use the Type Cast:

• How to convert times from second to hh with CVI

  How to convert times from second to hh with CVI?

  Can anyone advice?

  It's here. As I told you, it's very simple:

  //----------------------------------------------------------------------
  // Function secToHMSstring ()
  //----------------------------------------------------------------------
  /// HIFN secToHMSstring ()
  /// HIFN The function takes an amount of seconds and returns a string with
  /// HIFN the corresponding value in H:M:S format
  /// HIPAR sec/Value in seconds to convert
  /// HIPAR verbose/If True use "hms" separators; if not, use ":" separator
  /// HIPAR string/The output string. It is responsibility of the programmer
  /// HIPAR string/that the string is large enough to keep the resulting text
  /// OUT string
  void secToHMSstring (int sec, int verbose, char *string)
  
  {
      int     hh = 0, mm = 0, ss = 0;
  
      if (sec >= 3600) {
          hh = sec / 3600;
          sec -= hh * 3600;
      }
      if (sec >= 60)
          mm = sec / 60;
      ss = sec - mm * 60;
  
      strcpy (string, "");
      if (verbose) {
          if (hh > 0) sprintf (string, "%s%dh", string, hh);
          if (mm > 0) { if (strlen (string)) strcat (string, " "); sprintf (string, "%s%dm", string, mm); }
          if (ss > 0) { if (strlen (string)) strcat (string, " "); sprintf (string, "%s%ds", string, ss); }
      }
      else {
          if (hh > 0) sprintf (string, "%s%d:", string, hh);
          if (mm > 0) {
              if (strlen (string)) sprintf (string, "%s%02d:", string, mm); else sprintf (string, "%d:", mm);
          }
          else if (strlen (string))
              strcat (string, "00:");
          if (strlen (string)) sprintf (string, "%s%02d",  string, ss); else sprintf (string, "%d", ss);
      }
  
      return;
  }