Subtracting SYSDATE

Similar Questions

• Simple subtraction of Dates

  Hello, GUI, I'm new here. I am a student certification iz0-051 exam and I would be really grateful if you can help me with this doubt I have...
  
  I know that a character literal can be implicitly converted to a date if she follows the mask "[dd, DD] separator [mm, MM, Lun] separator [yy, rr, YYYY] etc...". etc...
  then... Why this simple subtraction will not through (the number of days between a given date and the current sysdate)?
  
  Select sysdate - ' double' 01-jan-2012.
  
  It gives the error 'ora-01722 invalid number', should - not implicitly convert the literal date and then subtracting sysdate? what I am doing wrong?
  
  Thanks for your help,
  
  Paolo

  955202 wrote:
  Still in doubt, I hate the implicit conversion...
  Well, let's see, following your suggestions, sysdate-"2" should not work too, but it does.
  My nls_date_fornat is dd-MON-rr, but even if I try to replace the literal with 1 January 12 ' it stil does not work, why?

  When two possibilities are there, ORACLE will make implicit conevrsion to the default NUMBER. That's why '2' sysdate - works. SYSDATE-'01-Jan-12' does not work for the same reason.

  But him below will work (based on nls_date_format), coz ORACLE knows, the string should be converted to DATE for sure.

  select  add_months('01-Jan-12',3) tst
  from dual;
  

• SYSTIMESTAMP, sysdate and subtraction

  Hello Experts!

  Everything that happens is really me stumping

  Version database - Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

  Select sessiontimezone dbtimezone, systimestamp, double sysdate

  SessionTimeZone	DBTIMEZONE	SYSTIMESTAMP	SYSDATE
  America/Phoenix	-04:00	17 MARCH 15 04.09.27.894994000 PM - 04:00	17 MARCH 15

  the column of sample_table

  updated_ts timestamp (6)

  When I run the following question

  Select sysdate - updated_ts,.

  SYSTIMESTAMP - updated_ts SUB_SYSTIMESTAMP,

  updated_ts,

  SYSDATE,

  SYSTIMESTAMP

  of sample_table

  

  I try very hard get any explanation on this.

  Thank you in advance!

  Everything that happens is really me stumping

  Probably because it lacks you some basics on arithmetic datetime and time zones.

  See the first row of data:

  (1) SYSDATE = 17 March 15 16:37:16 (Yes, SYSDATE there part of the time but your just sample does not display it)

  (2) UPDATED_TS = 17 MARCH 15 16:37:15.863983

  Thus (1) - (2) 0.136017 = (second)

  OK so far?

  (1) SYSTIMESTAMP = 17 March 15 16:37:16.516080 -04:00 = 17 March 15 20:37:16.516080 UTC

  (2) UPDATED_TS = 17 March 15 16:37:15.863983 America/Phoenix = 17 March 15 23:37:15.863983 UTC

  Since there is a time zone, the two operands are compared to UTC format.

  This column UPDATED_TS (which holds no information TZ) is first converted to the TIMESTAMP WITH time ZONE SCHEDULE using the session TZ "America/Phoenix" (= UTC - 07:00).

  So (1)-(2) = - 2:59:59.347903 (h: min: sec)

• How to calculate the date from sysdate

  
  I try to get 12/09/2009-12:51:30 by subtracting the current date to sysdate.

  I can get with this year, but I don't know how I can get to the date and the month preceding.

  () Choose add_months (sysdate-36() of double) = 12/09/2010

  Planned result 12/09/2010 13:23:30

  Thank you for the help

  I'm assuming that time is fixed if it is to see the example below.

  SQL > select add_months (to_date (to_char(sysdate,'dd-mon-yyy') |)) (("" 12:51:30 ',' dd-MON-yyy hh: mi: ss AM "), - 36) prior_date
  2 double;

  PRIOR_DATE
  -----------------------
  12 - Oct - 2010 12:51:30

  SQL >

• subtracting hours to date

  Hello
  
  I have the date format mm:dd:yyyy hh: mi: ss am .
  I have to subtract 10 for hh this format field. I mean that I have to convert as
  09/mm/yyyy hh24 - 10:mi: ss in oracle by Toad
  
  PL tell me how...
  
  
  waiting for m?
  
  regarding
  Vishal amine

  Hello

  Remove an hour:

  Select sysdate, sysdate-(1/24) from dual;
  

  François

• How to get the time in hours minutes and seconds subtraction between two varchar t

  Hi all
  
  I have two variable varchar that has a value like this
  
  v_outpunch1: = 17: 50:00'
  and v_Shifttime: = 18:00:00 '
  
  
  This time I'm subtracting here and in another varchar variable
  who's like that.
  
  
  
  v_EarlyLeaverstimeformat: = ((extrait extrait de (heure de TO_TIMESTAMP (v_ShiftTime, 'HH24:mi:ss'))-(heure de TO_TIMESTAMP (v_OutPunch1, 'HH24:mi:ss') LPAD)), 2, '0'): ': ' |)) LPAD ((extrait (minute de TO_TIMESTAMP (v_ShiftTime, 'HH24:mi:ss'))-extrait (minute de TO_TIMESTAMP (v_OutPunch1, 'HH24:mi:ss'))), 2, '0'): ': ' |)) LPAD ((extrait (seconde de TO_TIMESTAMP (v_ShiftTime, 'HH24:mi:ss'))-extrait (seconde de TO_TIMESTAMP (v_OutPunch1, 'HH24:mi:ss'))), 2, '0');))
  
  
  
  It is not properly subtracting value.
  
  Thank you

  This works for me...

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as(select to_date('17:50:00','HH24:MI:SS') as out, to_date('18:00:00','HH24:MI:SS') as shft from dual)
    2  --
    3  select to_char(trunc(sysdate)+(shft-out),'HH24:MI:SS') as diff
    4* from t
  SQL> /
  
  DIFF
  --------
  00:10:00
  

  If you want something different, please report the details according to the FAQ: {message identifier: = 9360002}

• Helps the subtraction of two different lines

  Hi all... Beginner here... :)
  I have a table in which I have to subtract two different dates for the idle time.
  I need to subtract the evnt_end to evnt_start to get the difference concerning the duration of inactivity...
  Thanks for your help...
  
  Here is an example of the table:
  
  EVNT_ID... * EVNT_START *... * EVNT_END *.
  ..... 12:34:30 1...6/22/2010... 2010-06-22 18:36:06
  ..... 21:58:38 2...6/22/2010... 2010-06-23 04:02:11
  ..... 05:10:43 3...6/23/2010... 2010-06-23 11:08:13
  ..... 4...6/23/2010 12:22:24... 2010-06-23 18:21:17
  ..... 22:29:03 5...6/23/2010... 2010-06-24 04:28:11

  I have another question, is there a function that can still give me the result in which it is in the format hh: mm:?

  select
  evt_id, evt_start, evt_end,
  to_char( trunc(sysdate) + (evt_start - lag(evt_end) over (order by evt_id)),'HH24:MI:SS') idle_time
  from yourtable
  order by evt_id;
  

• Subtracting Dates

  Hello
  
  I'm subtracting two dates for the number of days in the service:
  
  trunc(((86400*(SYSDATE-p.effective_start_date))/60)/60)/24) "none of the days of Service."
  
  I would do the same and to calculate the number of years more?
  
  Can anyone help with SQL?
  
  Thank you

  Hello

  For years, MONTHS_BETWEEN is simpler than the arithmetic mean of the dates

  MONTHS_BETWEEN (SYSDATE, p.effective_start_date)
          / 12        AS years_in_service
  

  Furthermore, simply subtracting one date from another gives you the number of days between them.

  SYSDATE - p.effective_start_date
  

  There is no need to convert this number of seconds and then back to days.

  SELECT     ename
  ,     hiredate
  ,     TRUNC (SYSDATE - hiredate)     AS days_in_service
  ,     TRUNC ( MONTHS_BETWEEN (SYSDATE, hiredate)
             / 12
             )                    AS years_in_service
  FROM     scott.emp;
  

  Released (October 1, 2010):

  ENAME      HIREDATE    DAYS_IN_SERVICE YEARS_IN_SERVICE
  ---------- ----------- --------------- ----------------
  SMITH      17-Dec-1980           10880               29
  ALLEN      20-Feb-1981           10815               29
  WARD       22-Feb-1981           10813               29
  JONES      02-Apr-1981           10774               29
  MARTIN     28-Sep-1981           10595               29
  BLAKE      01-May-1981           10745               29
  CLARK      09-Jun-1981           10706               29
  SCOTT      19-Apr-1987            8566               23
  KING       17-Nov-1981           10545               28
  TURNER     08-Sep-1981           10615               29
  ADAMS      23-May-1987            8532               23
  JAMES      03-Dec-1981           10529               28
  FORD       03-Dec-1981           10529               28
  MILLER     23-Jan-1982           10478               28
  

• Subtracting two timestamps

  Hi all
  
  Thanks for looking
  
  I'm subtracting (systimestamp - "TIME_IN") as "HOURS_WORKED".
  (30/08/2010 16:42-30/08/2010 04:00) = "HOURS_WORKED".
  
  the column called hours, the columns hours 'worked' shows '000000000 12:42:58.9881'
  
  I understand that the hours are 12 hours and 42 minutes and 58 seconds.
  
  is it possible that I can format this column to just show me hours and minutes?
  
  of '000000000 12:42:58.9881' 12:42?
  
  is there an easier way?
  
  Thanks in advance
  
  Published by: jo3y2 on August 30, 2010 17:19

  Select double to_char(sysdate,'hh24:mi:ss')

  or

  SELECT TO_CHAR(date1,'MMDDYYYY:HH24:MI:SS') date1,
  To_char(date2,'MMDDYYYY:HH24:mi:SS') date2,
  trunc (86400 *(date2-date1))-60 * (trunc ((86400 *(date2-date1)) / 60)) seconds.
  trunc ((86400 *(date2-date1)) / 60)-60 * (trunc (((86400 *(date2-date1)) / 60) / 60)) minutes,.
  trunc (((86400 *(date2-date1)) / 60) / 60)-24 * (trunc (((86400 *(date2-date1)) / 60) / 60) / 24)) hours.
  trunc (((86400 *(date2-date1)) / 60) / 60) / 24) days.
  trunc (((86400 *(date2-date1)) / 60) / 60) / 24) / 7) weeks
  OF date_table

  See this post
  http://www.databasejournal.com/features/Oracle/article.php/2234501/A-comparison-of-oracles-date-and-timestamp-datatypes.htm

• I get a null on the subtraction of 2 dates...

  I'm trying to subtract 2 dates
  by using the following query
  
  Select
  To_date (TO_CHAR (TRUNC(SYSDATE-1), ' mm/dd/yyyy') |) (' 07:35:33 ',' DD/MM/YYYY HH: MI: SS AM') + 10/1440
  -
  (TO_DATE (TO_CHAR (TRUNC(SYSDATE-1), ' mm/dd/yyyy') |)) ((' 08:35:33 ',' DD/MM/YYYY HH: MI: SS AM') + 10/1440)
  of the double
  
  
  but the result is null.
  Why?
  
  
  I want to get the subtraction of the 2. how to get it?

  I copied and pasted your code... not NULL values for me.

  select
  TO_DATE( TO_CHAR(TRUNC(SYSDATE-1),'mm/dd/yyyy')||' 07:35:33 AM','MM/DD/YYYY HH:MI:SS AM')+10/1440
  -
  (TO_DATE( TO_CHAR(TRUNC(SYSDATE-1),'mm/dd/yyyy')||' 08:35:33 AM', 'MM/DD/YYYY HH:MI:SS AM')+10/1440)
    5  from dual;
  
  TO_DATE(TO_CHAR(TRUNC(SYSDATE-1),'MM/DD/YYYY')||'07:35:33AM','MM/DD/YYYYHH:MI:SSAM')+10/1440-(TO_DATE(TO_CHAR(TRUNC(SYSDATE-1),'MM/DD/YYYY')||'08:35:33AM','MM/DD/YYYYHH:MI:SSAM')+10/1440)
  -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
                                                                                                                                                                           -.0416666666666667
  
  1 row selected.
  
  Elapsed: 00:00:00.03
  TUBBY_TUBBZ?
  
  TUBBY_TUBBZ?select * from v$version;
  
  BANNER
  --------------------------------------------------------------------------------
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
  PL/SQL Release 11.2.0.1.0 - Production
  CORE     11.2.0.1.0     Production
  TNS for Linux: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  
  5 rows selected.
  
  Elapsed: 00:00:00.02
  TUBBY_TUBBZ?
  

• Cannot add or subtract from the choice of backup discs

  I can't find how to add or subtract from the disks to use for storing upOne of my disks (3) is complete and I want to use new selecta. the preferences window is not resized

  IN aid, he said:
  «If you already set up Time Machine, your backup disks are listed, and information on each disc of the backup is displayed.» To select, add, or remove backup disks, click Select Disk or add or remove the backup disc. »

  I don't see this option in preferences:

  

  

  Simon,

  Scroll down in the window pane to display the add/remove disk backup option:

  

  

• With the help of check box in number to add/subtract a value of 0.5

  Hello

  I use a formula that calculates working hours daily and then subtract a half hour for lunch if a check box is selected. The formula applies with the exception of the time 0.5 being added or subtracted. Any ideas? The box strives to subtract the Boolean value (0 or 1), I just need this value to be represented as 0.5 If you get my drift...

  Thanks in advance!

  Tender Hello,

  

  Formula in D2 (fill down)

  = B2−a2−if(C2,"0.5H","0h")

  Kind regards

  Ian.

• Hi, I recently bought numbers in order to create a commercial newspaper. I'm the pen and paper. I need help to create a formula. A purchase column determines if the entry price column is subtracted from the price of output column or output subtracted

  Hi, I recently bought numbers in order to create a commercial newspaper. I'm the pen and paper. I need help to create a formula. A purchase column; Determines if the entry price column is subtracted from the price of output column (buy) or subtracted from (Sell) entry exit. Thank you for your help

  Hi B',.

  Buying and selling in column B

  Price of entry in column c.

  Exit in column D price

  Formula (and outcome) in column E

  If the column will B always contained 'Buy' or 'Sell', it works. It is default to a calculation of 'sell' if sale or has been specified.

  E2: = IF (B = "Buy", D - C, C - D)

  If you want to delay the calculation until the amounts entered in C and D, use this version:

  E2: = IF (OR (LEN (C) < 1, LEN (D) < 1,"", IF (B = "Buy", D - C, C - D) ")

  If you want to delay the calculation until all three ducks are on a line (B contains buy or sell, C and D contain both data), use this version:

  E2: = IF (OR (LEN (C) < 1, LEN (D) < 1,"", IF (B = "Buy", D - C, IF(B="Sell",C-D,) "" ")))

  Third version used in this table.

  

  Kind regards

  Barry

• The computer crashes: something to do with the minidump and sysdata.xml?

  My computer broke down twice now and restart an error message pops up saying "your computer has recovered from a serious error". It is said that two files in the error report will be sent to microsoft. the first complete mini103106 - 01.dmp and the second sysdata.xml

  I could find these files and delete them but have no idea if this would solve the problem and do not want to do the wrong thing...

  Hello

  Not easy to say why this is happening, but for me it s definitely something wrong with the software.
  Well, in this case we can only speculate. You know, it s Microsoft Windows and sometimes things happens without any reason :(

  I have heard from probably the system restore function could be corrupted and no have deleted the folder with the minidump and disabled the system restore feature in the control panel-> system.

  But in my opinion, the system restore function is important and necessary if you want to restore the operating system to the beginning.
  That's why I put t recommend disabling this feature.

• Why numbers cannot subtract correctly?

  I put together a spreadsheet earlier with a very simple formula and I got a very unexpected result. I tried the same calculation in many ways on several computers and short to force the precision (in the formatting of the cell resulting as currency or by setting turn instead of hundredths), I have the unexpected answer. The formula is simply '= 5.52 to 5.49' which for some reason in the response results "0.0299999999999994". "» Initially I was referencing more than one cell, but I boiled in as simple an equation as possible for discussion. Please do not hesitate to try and let me know if your results vary.

  

  Hi TheTubbyOne,

  Welcome to the communities of Apple Support!

  Welcome also to the way computers operate floating arithmetic. This isn't a bug in numbers, just a fact of life. This is how computers convert 'human' (decimal characters) to binary and back to decimal.

  A screenshot of a decimal subtraction and subtraction of integers:

  

  Use the ROUND in the final formula function (don't keep 'rounding' at each stage). Let the numbers to deal with arithmetic in the Middle rounds.

  

  Compare that to the subtraction of whole number in row 3.

  Tested in numbers 3 and with a pencil and paper.

  Kind regards

  Ian.