Sum function

Similar Questions

• Sum function does not work in the group clause current 'function not found SUM'

  Hi all

  Im working on one. Model RTF to use with EBS R12, I use the version 10.1.3.2.1 on Windows 7.

  I'm reports on invoices for a customer with a subtotal for each customer, but the subtotal does not work

  It worked with a later version of BI publisher model generator, but it was not the right version for EBS.

  The code is shown below, patterns valid OK it's just that when I try to preview the outout I get the error ' caused by: oracle.xdo.parser.v2.XpathException: not found "SUM" function.

  <? for each: G_CUSTOMER? > <? sort: client_name: "growing." data-type = "text"? >

  <? Client_name? >

  <? for-each: G_MAIN? >

  <? ADJUSTMENT_NUMBER? >

  <? NAME? >

  <? ADJUSTMENT_AMOUNT? >

  <? end foreach? >

  <? Sum (Currrent - Group () / ADJUSTMENT_AMOUNT)? >

  <? end foreach? >

  Pointers much appreciated.

  Thank you

  Guy

  Just should be fine, I guess.

  If you still get the error, try to remove this feature and see if the error occurs. Another error is caused by something else.

• How does the sum function in the element tag?

  Hello!
  
  I am new to XML Publisher and I need help to understand how my definition of data.
  
  In my xml file, I have this piece of code

  <group name="G_ACCOUNT" source="Q_REGISTER">
       <element name="COST_ACCOUNT" value="COST_ACCOUNT"/>
       <element name="ACC_DESC" value="ACC_DESC"/>
       <element name="YEAR" value="YEAR"/>
       <group name="G_COST" source="Q_REGISTER">
            <element name="COST_CENTER" value="COST_CENTER"/>
            <group name="G_TAG_NUMBER" source="Q_REGISTER">
                 <element name="TAG_NUMBER" value="TAG_NUMBER"/>
                 <element name="ASSET_NUMBER" value="ASSET_NUMBER"/>
                 <element name="DESCRIPTION" value="DESCRIPTION"/>
                 <element name="ASSET_ID" value="ASSET_ID"/>
                 <element name="ASSET_NUMBER" value="ASSET_NUMBER"/>
                 <element name="COST" value="COST" dataType="number"/>
                 <element name="YTD_DEPRN" value="YTD_DEPRN" dataType="number"/>
                 <element name="DEPRN_RESERVE" value="DEPRN_RESERVE" dataType="number"/>
                 <element name="DEPRN_RESERVE_BY" value="DEPRN_RESERVE_BY" dataType="number"/>
                 <element name="NET_VALUE" value="NET_VALUE" dataType="number"/>
                 <element name="DPIS" value="DPIS"/>
            </group>
            <element name="SUM_ACCOUNT_COST" function="sum" dataType="number" value="G_TAG_NUMBER.COST"/>
            <element name="SUM_ACCOUNT_YTD_DEPRN" function="sum" dataType="number" value="G_TAG_NUMBER.YTD_DEPRN"/>
            <element name="SUM_ACCOUNT_DEPRN_RESERVE" function="sum" dataType="number" value="G_TAG_NUMBER.DEPRN_RESERVE"/>
            <element name="SUM_ACCOUNT_DEPRN_RESERVE_BY" function="sum" dataType="number" value="G_TAG_NUMBER.DEPRN_RESERVE_BY"/>
            <element name="SUM_ACCOUNT_NET_VALUE" function="sum" dataType="number" value="G_TAG_NUMBER.NET_VALUE"/>
       </group>
  </group>

  and now, I have problem with element with functions sum, because it returns like for example. 21356,15. all other components (COST, YTD_DEPRN, DEPRN_RESERVE, DEPRN_RESERVE_BY, NET_VALUE) return values such as 21356.15.
  
  Can you tell me why sum function does not return to the same value?
  
  Kind regards
  drama9346

  As I expected wrong since this isn't a RAW number his tent for formatting. You can change this value and format or just go for the sum of RTF, or the SUM of your SQL query.

  Sum in RTF: for SUM_ACCOUNT_COST
  

  I have given how you use grouping in this case, based on what you might change the code slightly.

  Published by: amri on 9 April 2013 14:28

• Sum function is not displayed total

  Hello
  I have to calculate the sum in the report. When I use the sum function is not the total addition display. Please let me know. How to calculate sum?
  
  Thank you
  Lax

  Hello

  In your model if there is no group logic can simply give the syntax below.
  (Cloumn_name must be your xml of the column name)

  If you're using any function group
  

  Thank you
  Ananth v

• How can I use the SUM function to calculate the number of employees in the comp. &amp; deptnt?

  I have two tables: employees and their departments. I'm figuring the total employees by the Department and the total employees of the entire society. I know I have to use the SUM function, but I can only calculate total employees by Department and company separately. I need to get this result:
  
  

  DEPT_NAME     DEPT_TOTAL_SALARY         COMPANY_TOTAL_SALARY
  RESEARCH                  10875                        29025
  SALES                      9400                        29025    
  ACCOUNTING                 8750                        29025      
  
  
  This is my code:
  
  SELECT department_name, SUM(salary) as total_salary
  FROM employee, department
  WHERE employee.department_id = department.department_id
  GROUP BY department_name;
  
  SELECT SUM(salary)
  FROM employee;
  
  
  
  
  
  
  Can somebody help please?
  Thank you in advance.

  Published by: user13675672 on January 30, 2011 14:29
  
  Published by: user13675672 on January 30, 2011 14:31

  Hello

  Something like:

  SELECT dname,
         dept_tot_sal,
         SUM (dept_tot_sal) OVER () comp_tot_sal
  FROM   (SELECT   dname,
                   SUM (sal) dept_tot_sal
          FROM     dept, emp
          WHERE    dept.deptno = emp.deptno
          GROUP BY dname);
  

  There might be a smarter way, with no re - select.

  Concerning
  Peter

  Analytical functions:
  http://download.Oracle.com/docs/CD/E11882_01/server.112/e17118/functions004.htm

• Is there in front of the SUM function?

  Hi all

  I'm trying to subtract to the current line and 1 previous row, what analytical function should I choose? (In front of the sum)

  Select a.*, SUBTRACT(endpoint_number) (endpoint_number order lines between 1 and previous current line)

  from user_histograms where table_name = 't' and column_name = 'YENI ";

  Concerning

  Charlie

  Subtract from what? Prior to the current rank? If so:

  Select a.*, endpoint_number - lag (endpoint_number, 1, 0) (endpoint_number order)

  from user_histograms where table_name = 't' and column_name = 'YENI ";

  SY.

• SUM function in a calculation

  Hi all
  
  Hope everything goes well. I'm a beginner level initially with the discoverer/Oracle
  
  (a) have a calc to determine how many weeks it took from when the end of the course the instructor handed in rank.
  
  
  Calc_DateDiff
  ROUND ((TRUNC(Final Grade Date)-TRUNC(Meeting Time.End Date)) / 7)
  
  
  (b) if (a) is less than 7 weeks, then it is TIME of WE , otherwise it is LATE
  So I created these 2 Calc:
  
  
  1) calc_ontime BOX WHEN Calc_DateDiff < 7 THEN 1 END ELSE 0
  
  2) calc_late BOX WHEN Calc_DateDiff < 7 THEN 0 1 ELSE END
  
  (c) would like to sum up by id, total submitted on time, total handed end course
  but the following calc creates a histogram with nothing in it:
  Sum(*calc_ontime*) MORE (Student Course.Course PARTITION)
  
  so, I tried to replace the calc with the code behind the scenes of calc_ontime, and Moreover, the calc column is empty:
  
  SUM (CASE WHEN Calc_DateDiff < 7 THEN 1 0 if NOT END) ON (Student Course.Course PARTITION)
  
  so I tried to replace the calc_datediff, with it of formula and make me a syntax error that I can not solve:
  
  SUM (CASE WHEN ROUND ((TRUNC(Final Grade Date)-TRUNC(Meeting Time.End Date)) / 7) < 7 THEN 1 0 if NOT END) ON (Student Course.Course PARTITION)
  
  and it's not like the Ending Date field, even if I put in the folder...
  
  ====
  
  You have any ideas how I can ADD the field calc_ontime and calc_diff, bec once I have are
  I need to divide the total class pop to reach a percentage of how many students given time
  and how many students handed delay.
  
  or do I have to create a function for dba save the discoverer who would do this, I would feed in the course id
  as a parameter?
  
  SELECT SUM (CASE WHEN ROUND ((TRUNC(Final Grade Date)-TRUNC(Meeting Time.End Date)) / 7) < 7 THEN 1 0 OTHERWISE END)
  The student COURSE
  MEETING TIME
  Student course WHERE = parm_course
  GROUP BY ON (Student Course.Course PARTITION)
  
  
  pls advise, tx for your help, sandra

  Hi, Sandra
  You're safe by changing the name of an item in the admin of discoverer. Behind the scenes, discoverer uses the ID of the element for navigation purposes.

  If you are not sure to try it on a single field and see what happens. You will see that it is very good.

  Michael

• In PIF Sum function

  Hi all
  
  Anyone know how to use the function sum beep without using the running totals?
  
  It's the xml structure
  
  < DetailRate >
  rate < 1 > 2 < / rate1 >
  < naturel2 > 3 < / naturel2 >
  < revenu3 > 4 < / revenu3 >
  < mensuel4 > 5 < / revenues4 >
  < Rate5 > 6 < / Rate5 >
  < Rate6 > 7 < / Rate6 >
  < / DetailRate >
  < DetailRate >
  < Rate1 > 5 < / rate1 >
  < naturel2 > 5 < / naturel2 >
  < revenu3 > 5 < / revenu3 >
  < mensuel4 > 5 < / revenues4 >
  < Rate5 > 5 < / Rate5 >
  < Rate6 > 5 < / Rate6 >
  < / DetailRate >
  
  output would be
  
  
  Total rate1 naturel2 revenu3 revenues4 Rate5 Rate6
  
  real would be:
  
  7 8 9 10 11 12 total
  
  
  Thanks in advance!

  I mean on the outside for each.

  You are going to have something like

  
  Total

• How to only the totals using the native summary column (= "SUM () function

  Hi all, this is my data model:
  
  < name of dataTemplate 'Employees' description = 'Simple Dept - Emp' = >
  < dataQuery >
  < SQLStatement instance name = "Q1" >
  <! [CDATA]
  Select SERVICES. DEPTNO as DEPTNO,
  DEPARTMENTS. DNAME as a DNAME
  Scott. MINISTRIES DEPT order by DEPTNO]] >
  < / sqlStatement >
  < SQLStatement instance name = "Q2" >
  <! [CDATA [Select
  EMPLOYEES. ENAME like EMP_NAME,
  EMPLOYEES. EMPNO as EMPNO,
  EMPLOYEES. Hiring as HIREDATE date,
  EMPLOYEES. SAL as WAGES,
  EMPLOYEES. DEPTNO as EMP_DEPTNO
  Scott. EMPLOYEES OF THE EMP
  where EMPLOYED. [[DEPTNO =: DEPTNO]] >
  < / sqlStatement >
  < / dataQuery >
  < dataStructure >
  < name of group = "G_DEPT" source = "Q1" >
  < element name = "DEPTNO" value = "DEPTNO" / >
  < element name = "DNAME" value = "DNAME" / >
  < element name = "TOTAL_EMPS" value = "G_EMP. EMPNO"function ="COUNT ()"/ >
  < element name = "TOTAL_SALARY" value = "G_EMP. SALARY"function ="SUM ()"/ >
  < element name = "AVG_SALARY" value = "G_EMP. SALARY"function ="AVG ()"/ >
  < element name = "MAX_SALARY' value = 'G_EMP. SALARY"function ="MAX ()"/ >
  < element name = "MIN_SALARY" value = "G_EMP. SALARY"function ="MIN ()"/ >
  < name of group = "G_EMP" source = "Q2" >
  < feature name = 'EMPNO' value = 'EMPNO' / >
  < element name = "EMP_NAME" value = "EMP_NAME" / >
  < element name = "HIREDATE" value = "HIREDATE" / >
  < element name = "SALARY" value = "SALARY" / >
  < / Group >
  < / Group >
  < / dataStructure >
  < / dataTemplate >
  
  This datatemplate works very well with the TOTAL_EMPS, TOTAL_SALARY, AVG_SALARY, MAX_SALARY MIN_SALARY split for all departments; So these are subtotals.
  
  Now, I need to have the totals at the end of my report to the following:
  
  TOTAL_ALL_EMPS
  TOTAL_ALL_SALARY
  TOTAL_ALL_AVG_SALARY
  TOTAL_ALL_MAX_SALARY
  TOTAL_ALL_MIN_SALARY
  
  Add a new query (Q1) with all the totals, now the data model is the following:
  
  < name of dataTemplate 'Employees' description = 'Simple Dept - Emp' = >
  < dataQuery >
  < SQLStatement instance name = "Q1" >
  <! [CDATA]
  Select COUNT (empno) TOTAL_ALL_EMPS, SUM (sal) TOTAL_ALL_SALARY, AVG (sal) TOTAL_ALL_AVG_SALARY, MAX (sal) TOTAL_ALL_MAX_SALARY MIN (sal) scott TOTAL_ALL_MIN_SALARY. EMPLOYEES EMP]] >
  < / sqlStatement >
  < SQLStatement instance name = "Q2" >
  <! [CDATA]
  Select SERVICES. DEPTNO as DEPTNO,
  DEPARTMENTS. DNAME as a DNAME
  Scott. MINISTRIES DEPT order by DEPTNO]] >
  < / sqlStatement >
  < SQLStatement instance name = "Q3" >
  <! [CDATA [Select
  EMPLOYEES. ENAME like EMP_NAME,
  EMPLOYEES. EMPNO as EMPNO,
  EMPLOYEES. Hiring as HIREDATE date,
  EMPLOYEES. SAL as WAGES,
  EMPLOYEES. DEPTNO as EMP_DEPTNO
  Scott. EMPLOYEES OF THE EMP
  where EMPLOYED. [[DEPTNO =: DEPTNO]] >
  < / sqlStatement >
  < / dataQuery >
  < dataStructure >
  < name of group = "G_TOT" source = "Q1" >
  < element name = "TOTAL_ALL_EMPS" value = "TOTAL_ALL_EMPS" / >
  < element name = "TOTAL_ALL_SALARY" value = "TOTAL_ALL_SALARY" / >
  < element name = "TOTAL_ALL_AVG_SALARY" value = "TOTAL_ALL_AVG_SALARY" / >
  < element name = "TOTAL_ALL_MAX_SALARY" value = "TOTAL_ALL_MAX_SALARY" / >
  < element name = "TOTAL_ALL_MIN_SALARY" value = "TOTAL_ALL_MIN_SALARY" / >
  < / Group >
  < name of group = "G_DEPT" source = "Q2" >
  < element name = "DEPTNO" value = "DEPTNO" / >
  < element name = "DNAME" value = "DNAME" / >
  < element name = "TOTAL_EMPS" value = "G_EMP. EMPNO"function ="COUNT ()"/ >
  < element name = "TOTAL_SALARY" value = "G_EMP. SALARY"function ="SUM ()"/ >
  < element name = "AVG_SALARY" value = "G_EMP. SALARY"function ="AVG ()"/ >
  < element name = "MAX_SALARY' value = 'G_EMP. SALARY"function ="MAX ()"/ >
  < element name = "MIN_SALARY" value = "G_EMP. SALARY"function ="MIN ()"/ >
  < name of group = "G_EMP" source = "Q3" >
  < feature name = 'EMPNO' value = 'EMPNO' / >
  < element name = "EMP_NAME" value = "EMP_NAME" / >
  < element name = "HIREDATE" value = "HIREDATE" / >
  < element name = "SALARY" value = "SALARY" / >
  < / Group >
  < / Group >
  < / dataStructure >
  < / dataTemplate >
  
  It works fine, but my question is this:
  
  How can I change the data model and use the native summary column (function = "SUM (), for example) to collect data that I mentioned above (TOTAL_ALL_EMPS, TOTAL_ALL_SALARY, etc.), in order to avoid a third query SQL (Q1)?
  In a few words, I would only use the query Q2 and Q3 and have overall totals and subtotals.
  
  Thanks in advance for any help
  
  Alex

  
  
  
  Select 1 double DUMMY_FIELD]] >
  
  
  Select SERVICES. DEPTNO as DEPTNO,
  DEPARTMENTS. DNAME as a DNAME
  Scott. MINISTRIES DEPT order by DEPTNO]] >
  
  
  EMPLOYEES. ENAME like EMP_NAME,
  EMPLOYEES. EMPNO as EMPNO,
  EMPLOYEES. Hiring as HIREDATE date,
  EMPLOYEES. SAL as WAGES,
  EMPLOYEES. DEPTNO as EMP_DEPTNO
  Scott. EMPLOYEES OF THE EMP
  where EMPLOYED. [[DEPTNO =: DEPTNO]] >
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  

  Try this

  Concerning
  Charlotte

• XML data model. Using the SUM() function

  Hello
  
  I have a data model where I want to create a column of synthesis based on the Group of children.
  
  * < name of group = "G_RO_ESTIMATES" source = "Q_RO_ESTIMATES" >
  < element name = "ESTIMATE_TOTAL" value = "G_RO_ESTIMATE_LINES. "CHARGE of" function = "SUM ()" / > "
  
  < name of group = "G_RO_ESTIMATE_LINES" source = "Q_RO_ESTIMATE_LINES" >
  < element name = "LOAD" value = "LOAD" / >
  < / Group >
  < / Group > *.
  
  ESTIMATE_TOTAL returns 0
  even if the value of the column LOAD is 760.
  
  I got the function SUM() to work on another group further in my model data, but for some reason, it won't work.
  
  Does anyone have an idea on what is wrong?
  
  Thank you in advance.
  
  Kenneth BR

  give the name of the element diff CHARGE_TEST

  *
  

  
  
  
  *

  Sometimes the name overlap which results in zero... keep unique names
  (I guess I already logged a bug for this return sometimes)

• You attempt to add a column with a SUM function

  Hello

  I am new to Oracle (using 11 g) and I try to add a new column in my table with one facility amount.

  Currently, I have a weekly Chronicle of salary, but I would like to add an annual salary that uses the data of the week.

  Example I tried was:

  change the emp table add)

  yearly_wage SUM(WEEK_WAGE*52));

  Is it possible to do this please?

  Thank you

  Create a virtual column.

  http://www.Oracle-base.com/articles/11g/virtual-columns-11gr1.php

• SUM function in the select statement

  Hi I have a table like this
  
  EmpNo, ndahrs, swipedate
  101, 00:01, 01-apr-2013
  101, 01:03, 02-apr-2013
  102, 02:00, 01-apr-2013
  102, 03:00, 03-apr-2013
  104, 01:00, 04-apr-2013
  104, 00:30, 03-apr-2013
  
  now, I want to SELECT the EMPNO, NDAHRS, SWIPEDATE, SUM (NDAHRS) OF the TABLE;
  
  How can I get what I've written request is to show message not a group by clause even when I added group that does not

  Hello

  Here's one way:

  WITH  got_tot_mins  AS
  (
       SELECT    empno, nda_hrs, swipedate
       ,       SUM ( (60 * TO_NUMBER (SUBSTR (nda_hrs, 1, 2)))
                  +       TO_NUMBER (SUBSTR (nda_hrs, 4))
                  )  OVER ( PARTITION BY  empno
                       )    AS tot_mins
       FROM       staffndamuster
  --     WHERE        swipedate  BETWEEN :p_startdate
  --                           AND     :p_enddate
  )
  SELECT    empno, nda_hrs, swipedate
  ,       TO_CHAR ( TRUNC ( tot_mins / 60)) || ':'
                                           || TO_CHAR ( MOD (tot_mins, 60)
                                       , 'FM00'
                                       ) AS tot_hrs
  FROM      got_tot_mins
  ORDER BY  empno, swipedate
  ;
  

  You post p_startdate and p_enddate, so I can't test with them.

  Published by: Frank Kulash on 10 April 2013 12:52
  Just saw your desired results

• How to make a SUM function on table with TI-auto

  Hi all
  I created a table with column 2:

        CREATE TABLE Suppliers
  
        (
  
            Id                     NUMBER(10)              PRIMARY KEY,
  
            ProductNum       NUMBER(10)              NOT NULL,
  
            Amount             NUMBER(10)              NOT NULL
  
       );

  Example: I have these data in the table

  ----------------------------------
  
  Id|ProductNum|Amount|
  
  ----------------------------------
  
  1|      4A        |    50   |
  
  ----------------------------------
  
  2|      10Q      |     3    |
  
  ---------------------------------
  
  1|      4A        |    40   |
  
  ---------------------------------
  
  3|      Q9       |     32  |
  
  ---------------------------------
  
  2|      10Q      |     60 |
  
  .          .                .
  
  .          .                .
  
  .          .                .

  And I want a query to get the sum of the amount of each product, that is if I run this query o the previous table, I expect the following result

  ------------------------------
  
  ProductNum|Amount|
  
  ------------------------------
  
  4A            |     90    |
  
  10Q          |      63   |
  
  Q9            |      32   |
  
  .               |       .    |
  
  .               |        .   |

  Thanks in advance

  Something like this->

  select ProductNum, sum(Amount)
  from Suppliers
  group by ProductNum;
  

  Kind regards.

  LOULOU.

• Function of the missing sum in list dropdown metric value in config FMS dashboard portlet

  In the FMS dashboard, click "Edit property" right to the top corner of each section of the dashboard, we opened 'Config Portlet. Click the tab 'Option' find 'of the metric values. In the document 5.6.3 and 5.6.5, metric drop-down list value must includes the following options:

  None

  Average

  Minimum

  Maximum

  Minimum/Maximum

  Sum

  But in my FMS 5.6.5, I don't see "Sum" function from the drop-down list.

  Guru can tell me it's a bug or my configuration error?

  Thank you

  I'm pretty sure.  I do a lot of work from Dashboard and have notice that went.

• Function Sum() in GROUP BY for return null if all lines aggregate is NULL

  Consider the following FOO table:

  COL_A	VAL_A	VAL_B
  A	1	2
  A	NULL VALUE	2

  and the sql code:

  SELECT COL_A, SUM (VAL_A) VAL_A

  FOO

  COL_A GROUP;

  Returns

  COL_A	VAL_A
  A	1

  Is there a way to make the SUM() values if and only if all of the aggregated lines are not NULL?

  I want to return is:

  COL_A	VAL_A
  A	NULL VALUE

  If all of the aggregated rows are not null, the normal SUM() function is made.

  SELECT COL_A, SUM (VAL_B) VAL_B

  FOO

  COL_A GROUP;

  Returns

  COL_A	VAL_B
  A	4

  WITH (FOO AS

  SELECT COL_A, VAL_A 1, 2 VAL_B OF THE DOUBLE ' A'

  UNION ALL SELECT 'A' COL_A, VAL_A, 2 VAL_B OF THE DOUBLE NULL

  )

  SELECT NULLIF (0, MAX (DECODE(VAL_A,,0))) + SUM (VAL_A) IN FOO GROUP OF COL_A;