sum of column that contains the values in the time format

Hi all

I give you a piece of my code below

SELECT  dif.EMPLOYEE_NUMBER Employee#, dif.FULL_name EmployeeName,
 TO_CHAR(START_DATE,'dd-Mon-rrrr') DOJ ,dif.DEPT_NAME,POSITION , DATE_ENTRAY AttendanceDate,

 to_char(DATE_ENTRAY,'DY') day, TO_CHAR(LNE1,'hh24:mi')TimeIn1 ,TO_CHAR(LNE2,'hh24:mi')TimeOut1,
 
 TO_CHAR(LNE3,'hh24:mi')TimeIn2 ,TO_CHAR(LNE4,'hh24:mi')TimeOut2, TO_CHAR(LNE5,'hh24:mi')TimeIn3 ,

 TO_CHAR(LNE6,'hh24:mi')TimeOut3, to_char(decode(LNE8,null ,

 decode(LNE7,null, decode(LNE6,null, decode(LNE5,null, decode(LNE4,null, decode(LNE3,null,

 decode(LNE2,null,LNE2 ,LNE2 ),LNE3 ),LNE4 ),LNE5 ),LNE6 ),LNE7 ),LNE8 ),'hh24:mi')TimeOuts ,
 
 ACT_HOUR Work_Hrs, 

decode(DLY_ABSENT_TYPE,'Late',DED_ABS ,'Late (Deduction)',DED_ABS,'00:00') Late_Hrs,ACT_OVT Over_Time
 FROM jjj_PUNCH_DATA_EMP_LIST trn , 
 jjj_emp_def dif,jjj_PUNCH_CARD_ELEG ele WHERE trn.EMPLOYEE_NUMBER =dif.EMPLOYEE_NUMBER and   
 ele.EMPLOYEE_NUMBER =trn.EMPLOYEE_NUMBER  and   DATE_ENTRAY between '23-Aug-2009' and  '24-Aug-2009' 

I require to find the sum of column  wrk_hrs
Act_hour or wrk_hrs belongs to table  jjj_PUNCH_DATA_EMP_LIST trn , and the datatype of act_hour is varchar(10 byte)
the values of column act_hrs, (i require the sum of this column)
08:00
07:22
06:08

kindly help
thanking in advance

concerning
Oracle user

Hello

Thanks for posting the CREATE TABLE and INSERT. That really helps.

Do you want 19:33 ' as the output? Which makes it look like 19 hours and 33 minutes. Most people would represent 19.33 hours (i.e. 19 more than 1/3 hours) as 19:20 '. Should not the sum of
' x: 00 ' and
'y: 20' be
"z: 20?

If you really want 19:33 ', see the solution of Hoek.

If you really want 19:20 ', then you were on the right track.
I think that you were trying to do:

WITH  got_total_hours     AS
(
     SELECT SUM (   TO_NUMBER (SUBSTR (act_hour, 1, 2))
                + ( TO_NUMBER (SUBSTR (act_hour, 4, 2))
                  / 60
                  )
                ) AS total_hours
     from      p
)
SELECT        TO_CHAR (FLOOR (total_hours))
       || ':'
       || TO_CHAR ( MOD (total_hours, 1) * 60
               , 'fm00'
               )     AS hh_mm
FROM     got_total_hours
;

Looks like you were trying calculate total_hours in a subquery, then use the total_hour alias in a query Super, which is quite accurate. You're just confused on how to write a subquery.
There are two basic ways to write subqueries:

(1) WITH clause:

WITH  sub_query  AS
(
     SELECT  ...
)
SELECT  ...
FROM      sub_query
;

(2) online review

SELECT     ...
FROM     (     -- Begin sub_query
     SELECT     ...
     )     -- End sub-query
;

Looks like you tried a bit of each method.

In most cases (this included problem) either one will work.
Other problems are much easier by using a WITH clause and WITH clauses are usually easier to read and understand, I recommend that you always use a WITH clause rather than views online.

You can also change the Hoek solution to get the result 19:20 ' without a subquery (or without using any expression complicated, more than once, which is the only reason why I have proposed a subquery). Since date arithmetic Oracle comes from the days, not hours, when the solution of Hoek has calculated the number of hours, you'll have to divide by 24 to get the number of days. If you are using TO_CHAR to fit the time, however, the results can be confusing if the total is 24 hours or more. You might be better off using NUMTODSINTERVAL.

Tags: Database

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North America                                                                       312.19                            148.92
Oceana                       456.96
South America                                                                                                                                 662.41
Europe                                              848.5                                                 832.58
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