Swap partition

Similar Questions

• VCP exam question - the difference between the file exchange and the swap partition?

  I am currently a student at my VCP and stumbled upon a question and was hoping someone could explain the answer offered.  Essentially the question is asking why you must manually create a local VMFS volume.  The possible answers were: files of storage for the service console log, decentralized storage for all the vmkernel vmkernel swap activity Exchange files for virtual machines that are configured locally and swap files from service console for the console service RAM overcommitment.

  It is my understanding that the swap partition has its own format.  When you create the necessary partitions for installing ESX format the swap partition is 'swap', not vmfs or ext - 3.  Then, because the last three options are to swap/activity files, I chose the first choice, storage for the service console logs.  This study guide says I'm wrong and the answer is VMKernel swap files for virtual machines that are configured locally.   Of course, Miss me something here...

  How you store Exchange files on VMFS partition?  I thought that the swap partition is the only place to have to Exchange files, and then it is on its own partition.  You cannot store a partition on a partition.

  Maybe it's the difference between a swap file and a swap partition which is tripping me?

  Search for, swap space as it is usually is a place to store a replica of memory the system for the purpose of managing memory better (usually data that are accessed most often).

  SWAP PARTITION is now, for the ESX SWAP space.

  And the EXCHANGE FILE is for some particular VM swap space that can be used by the guest operating system. The use of this file is managed by VMkernel. Now, this swap file has some different features from the windows of i.e normal swap, linux or ESX swap space space.

  NUTZ

  VCP 3.5

  (Preparation for VCP 4)

• Swap Partition - best practices

  Hi all

  What is considered a best practice to create the swap partition?

  ESX 4 is based on Red Hat Enterprise Linux Server version 5.1,

  I searched their knowledge base and found the following article:

  Q. If I add several hundred GB of RAM for a system should I really more

  hundreds of GB of swap space? (kbase.redhat.com/faq/docs/DOC-15252)

  A. short answer:

  • Systems with 4 GB of ram or less require a minimum of 2 GB of swap space

  • Systems with 4 GB to 16 GB of ram require a minimum of 4 GB of swap space

  • Systems with 16 GB to 64 GB of ram require a minimum of 8 GB of swap space

  • Systems with 64 GB, 256 GB of ram require a minimum of 16 GB of swap space

  Thanks in advance,

  Ronen.

  1.6 GB as the Service Console is limited to 800 MB of memory.

  Duncan

  VMware communities user moderator | VCP | VCDX

  -

• Multiple Swap Partitions?

  Anyone know if ESX 3.5 is able to use several swap partitions? I asked this question of my Install and Config. instructor, but he didn't.

  Thanks in advance

  Hello

  Swap partition by default ESX service console will be alone, you do not require more than one swap partition as each VM will have its own page file (.vswp).

  Thank you

  Samir

  PS: If you think the answer is useful please consider rewarding points.

• With parallel option swap partition

  Hi all
  
  I do a swap with parallel option partition, but his giving is not not an option valid.
  
  ALTER TABLE table_1
  P_name SWAP PARTITION
  WITH TABLE table_2
  WITHOUT VALIDATION
  PARALLEL (level 12);
  
  ERROR on line 5:
  ORA-14094: invalid ALTER TABLE EXCHANGE PARTITION option
  
  Please advice.
  
  Thank you and best regards,
  Rakesh
  
  Published by: user12003321 on March 5, 2010 17:43

  This means that we cannot run with parallel option swap partition when we do not include the index of update?

  FIX!

  cannot use PARALLEL with EXCHANGE

• Resize the SWAP Partition.

  I want to resize my partition for swap of 1.4 GB GB 7.

  Some data from system below:

  Welcome to SUSE Linux Enterprise Server 11 for VMware (x86_64) - Kernel \r (\l) SP3.

  # uname - a

  Platinium2 3.0.76 - 0.11 - default #1 SMP Linux kill Jun 14 08:21:43 UTC 2013 (ccab990) x86_64 x86_64 x86_64 GNU/Linux

  # swapon s

  Size of the characters in filename used priority

  / dev/sda1 partition 1532924 0-1

  # fdisk-l

  Disk/dev/sda: 591,6 GB, 591631745024 bytes
  255 heads, 63 sectors/track, 71928 cylinders, total of 1155530752 areas
  Units is 1 * 512 sectors is 512 bytes
  Sector size (logical or physical): 512 bytes / 512 bytes
  Size of the e/s (minimum/maximum): 512 bytes / 512 bytes
  Disk identifier: 0x00033b0e

  Device boot start end blocks Id system
  / dev/sda1 2048 3067903 1532928 82 Linux swap / Solaris
  / dev/sda2 * 3067904 471859199 234395648 83 Linux
  / dev/sda3 471859200 1155530751 341835776 83 Linux

  # cat/etc/fstab

  / dev/sda1, swap swap defaults 0 0

  / dev/sda2 / ext3 acl, user_xattr 1 1

  proc/proc proc defaults 0 0

  Sysfs/sys sysfs noauto 0 0

  debugfs/sys/kernel/debug debugfs noauto 0 0

  devpts/dev/pts devpts mode = 0620, gid = 5 0 0

  / dev/sda3/local/apps ext3 noatime, acl, user_xattr 1 2

  # free k

  total used free shared buffers cached

  MEM: 16392148 1273944 15118204 0 149864 760472

  -/ + buffers/cache: 363608 16028540

  Swap: 1532924 0 1532924

  Thank you

  Paul

  If using ESXi 5.x, please check its: http://rickardnobel.se/esxi-5-0-partitions/

  If you use an earlier version of ESX, you can do the Linux systems.

• Try to convert the partitioned Table of interval in the range... Swap partition...

  Requirement:
  
  Interval of replacement partitioned Table by range partitioned Table
  

  DROP TABLE A;
  
  CREATE TABLE A
  (
     a              NUMBER,
     CreationDate   DATE
  )
  PARTITION BY RANGE (CreationDate)
     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
     (PARTITION P_FIRST
         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  
  INSERT INTO A
       VALUES (1, SYSDATE);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 30);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 60);

  I need to change this partitioned Table apart to a partitioned range Table. I can do using the EXCHANGE PARTITION. Like if I use the classic method to create another table range partitioned, then:
  
  

  DROP TABLE A_Range
  CREATE TABLE A_Range
  (
  a NUMBER,
  CreationDate DATE
  )
  PARTITION BY RANGE (CreationDate)
     (partition MAX values less than (MAXVALUE));
  
  Insert  /*+ append */  into A_Range Select * from A; --This Step takes very very long..Trying to cut it short using Exchange Partition.

  Problems:
  
  I can't do
  

   ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A
    WITHOUT VALIDATION;
   

  ORA-14095: ALTER TABLE CHANGE requires a not partitioned table nonclustered
  This is because the tables are partitioned. So it does not allow me.
  
  If I instead:
  
  
  Create a table that is not partitioned for exchanging data by partition.
  

    Create Table A_Temp as Select * from A;
    
     ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A_TEMP
    WITHOUT VALIDATION;
     
    select count(*) from A_Range partition(MAX);
   

  -The problem is that all the data is in MAX Partition.
  Even after the creation of a large number of partitions by walls of separation, the data is still in MAX Partition only.
  
  So:
  
  -What we cannot replace a partitioned Table to the Table partitioned using the EXCHANGE PARTITION range interval. that is, we have to insert in...
  -We can do it, but I'm missing something here.
  -If all the data is in MAX Partition due to "WITHOUT VALIDATION", can say us be redistributed in the right type of range partitions.

  You must pre-create the partitions in a_range and then swap one for one for a tmp, and then to arange. With the help of your sample (thanks to proviing code, incidentally).

  SQL> CREATE TABLE A
    2  (
    3     a              NUMBER,
    4     CreationDate   DATE
    5  )
    6  PARTITION BY RANGE (CreationDate)
    7     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
    8     (PARTITION P_FIRST
    9         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  Table created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 30);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 60);
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  

  You can find the form of existing partitions assistance:

  SQL> select table_name, partition_name, high_value
    2  from user_tab_partitions
    3  where table_name = 'A';
  
  TABLE_NAME PARTITION_NAME HIGH_VALUE
  ---------- -------------- --------------------------------------------------------------------------------
  A          P_FIRST        TO_DATE(' 2001-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P44        TO_DATE(' 2013-01-28 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P45        TO_DATE(' 2012-12-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P46        TO_DATE(' 2012-11-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  

  You can then create the table a_range with apporopriate partitions. Note that you may need to create additional in a_range partitions because the partitioning interval does not create the partitions has no data for, even if that leaves 'holes' in the partitioning scheme. So, on that basis:

  SQL> CREATE TABLE A_Range (
    2     a NUMBER,
    3     CreationDate DATE)
    4  PARTITION BY RANGE (CreationDate)
    5     (partition Nov_2012 values less than (to_date('30-nov-2012', 'dd-mon-yyyy')),
    6      partition Dec_2012 values less than (to_date('31-dec-2012', 'dd-mon-yyyy')),
    7      partition Jan_2013 values less than (to_date('31-jan-2013', 'dd-mon-yyyy')),
    8      partition MAX values less than (MAXVALUE));
  
  Table created.
  

  Now, create a regular table to use in the constituencies:

  SQL> CREATE TABLE A_tmp (
    2     a              NUMBER,
    3     CreationDate   DATE);
  
  Table created.
  

  and all partitions in Exchange:

  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p44
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION jan_2013
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p45
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION dec_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p46
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION nov_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> select * from a;
  
  no rows selected
  
  SQL> select * from a_range;
  
           A CREATIOND
  ---------- ---------
           1 23-NOV-12
           1 23-DEC-12
           1 22-JAN-13
  

  John

• Swap partition after the derivation of a field value

  Hello gurus

  There is a table that currently contains records 4billion. In this table, there is an obligation to fill a new column that is currently empty. The logic to fill the column based on the value of another column and using substr/instr, we can calculate the value to be entered in the new column. Meaningful to shoot is not a problem. This existing table in which I want to fill the new field is partitioned. Now, since its seen record 4billion and its partitioned and Yes its compressed as a result, I don't mean to update the table of origin rather go for Exchange of partitioning.

  One would be a pseudo-code or flow for the same. I think so

  1. create a temporary table that held all the records of 4 b of the table in its population and origin derive the logic of the new field.

  2. once the temporary table is populated, use exchange notion of partitioning to transfer the data from the temporary table to the original table.

  Please confirm my understanding and if possible any pseduocode to reproduce this scenario will be very useful.

  Thank you very much

  To use the exchange concept, you do partitioning wise partition (a bit like the pseudocode below):

  create the table exchange_table as

  Select c_1, c_2,... out

  Since the partition of big_table (some_partition)

  where 1 = 2;

  for x in (select nom_partition from user_tab_partitions where table_name = "BIG_TABLE")

  loop

  
  

  run immediately "insert into exchange_table" |

  "Select c_1, c_2,..., c_k,..., substr (c_k, instr (c_k,...),...). René,... out ' |

  «partition big_table (' |)» x.partition_name | ') ';

  
  

  run immediately 'alter partition change table big_table' | x. nom_partition | "with table exchange_table;

  
  

  run immediately 'truncate table exchange_table;

  
  

  end loop;

  Concerning

  Etbin

• View swap partition?

  Hello

  Using oracle 11.2.0.3

  Used with the table Exchange partition.

  We have a table with 4 weeks into it.

  Ideally, we would charge each week in a separate table partitioned by week.

  However, we need to split the source into 4 separate tables table first before loading in the partitioned table?

  Prefer partition excahnge with read seuledes this table

  ALTER TABLE EXCHANGE PARTITION bird dest_table "|" TO_CHAR (v_start_fwk_num) | ' WITH table (select * from insert_table where week = 1) WITHOUT VALIDATION'

  ALTER TABLE EXCHANGE PARTITION bird dest_table "|" TO_CHAR (v_start_fwk_num) | ' WITH table (select * from insert_table where week = 2) WITHOUT VALIDATION'

  ALTER TABLE EXCHANGE PARTITION bird dest_table "|" TO_CHAR (v_start_fwk_num) | ' WITH table (select * from insert_table where week = 3) WITHOUT VALIDATION'

  ALTER TABLE EXCHANGE PARTITION bird dest_table "|" TO_CHAR (v_start_fwk_num) | ' WITH table (select * from insert_table where week = 4) WITHOUT VALIDATION'

  instead of creating 4 sep temporary tables - 1 for each week.

  Get invalid table name when trying this. (ora-00903)

  Thank you

  No, you cannot partition exchange a partition with a view

  Exchange partition exchange of segments - views is not a segment.

• Follow-up change partition and swap partition

  Hello

  Using oracle 11.2.0.3.

  We have a summary table which has replaced entire partitions every night by an exchange of partition whenever data is modified. for us to have a compression.

  This table is composite date range / hash-partitioned

  We are consideruing either to build a summary table or mview on this summary with the same strategy partitionin table.

  A read partition the track changes to refresh this second mview since requires no newspapers mview but was wondering if would work in our scneario.

  Anyone know if it would work - make some conditiosn must be met for 'updating fast/incremenatl' take place.

  Now second summary table/mview would be simple counties + sum of data in the first table aggregated measures but high in order to reduce the amount of data.

  Achieve couldn't track the separate use if wanted to use partition change.

  Thank you

  What you have said I think you could make this work.

  On the other hand, if you do not have 'normal' mview updates via a mview diary and only refreshing the mview as a side effect of the exchange of partition I consider simply write the code to make your table a partitioned table, write 'create in select' / 'Exchange' in order to keep the summary table.  It would be probably more effective than the generic approach of Oracle.

  Concerning

  Jonathan Lewis

• STALE after SWAP PARTITION stats

  Version Oracle 11.2.0.1 and 11.2.0.2
  
  Can someone explain why statistics on indexes and the table show as STALE after completing an operation of the EXCHANGE PARTITION?
  
  Thanks in advance!
  

  SQL> CREATE TABLE testpart
    2    ( a1    number,
    3      a2    date,
    4      a3    varchar2(5),
    5      a4    number
    6    )
    7    PARTITION BY RANGE (a2)
    8    (
    9    PARTITION testpart_2011 VALUES LESS THAN(to_date('01-jan-2012','dd-mon-yyyy')),
   10    PARTITION testpart_2012 VALUES LESS THAN(to_date('01-jan-2013','dd-mon-yyyy'))
   11    )
   12  /
  
  Table created.
  
  SQL>
  SQL> insert into testpart values ( 1, '15-jun-2011', 'ONE', 100 );
  
  1 row created.
  
  SQL> insert into testpart values ( 2, '15-feb-2012', 'TWO', 200 );
  
  1 row created.
  
  
  SQL> create index idx_testpart_a3 on testpart (a3) local;
  
  Index created.
  
  SQL> create index idx_testpart_a4 on testpart (a4);
  
  Index created.
  
  SQL>
  SQL> select * from user_tab_modifications
    2  where table_name = 'TESTPART';
  
  no rows selected
  
  SQL>
  SQL> exec DBMS_STATS.FLUSH_DATABASE_MONITORING_INFO;
  
  PL/SQL procedure successfully completed.
  
  SQL>
  SQL>
  SQL> select * from user_tab_modifications
    2  where table_name = 'TESTPART';
  
  TABLE_NAME      PARTITION_NAME     INSERTS    UPDATES    DELETES TIMESTAMP TRU DROP_SEGMENTS
  --------------- --------------- ---------- ---------- ---------- --------- --- -------------
  TESTPART                                 2          0          0 18-MAY-12 NO              0
  TESTPART        TESTPART_2011            1          0          0 18-MAY-12 NO              0
  TESTPART        TESTPART_2012            1          0          0 18-MAY-12 NO              0
  
  SQL>
  SQL> exec dbms_stats.gather_table_stats(user, 'testpart');
  
  PL/SQL procedure successfully completed.
  
  SQL>
  SQL> select * from user_tab_modifications
    2  where table_name = 'TESTPART';
  
  no rows selected
  
  SQL>
  SQL>
  SQL> select table_name, partition_name, last_analyzed, stale_stats
    2  from dba_tab_statistics
    3  where table_name = 'TESTPART';
  
  TABLE_NAME      PARTITION_NAME  LAST_ANAL STA
  --------------- --------------- --------- ---
  TESTPART                        18-MAY-12 NO
  TESTPART        TESTPART_2011   18-MAY-12 NO
  TESTPART        TESTPART_2012   18-MAY-12 NO
  
  SQL>
  SQL>
  SQL> select index_name, partition_name, last_analyzed, stale_stats
    2  from dba_ind_statistics
    3  where table_name = 'TESTPART';
  
  INDEX_NAME                     PARTITION_NAME  LAST_ANAL STA
  ------------------------------ --------------- --------- ---
  IDX_TESTPART_A3                                18-MAY-12 NO
  IDX_TESTPART_A4                                18-MAY-12 NO
  IDX_TESTPART_A3                TESTPART_2011   18-MAY-12 NO
  IDX_TESTPART_A3                TESTPART_2012   18-MAY-12 NO
  
  SQL>
  SQL>  -- create staging table
  SQL>
  SQL> create table testpart_temp as select * from testpart where 1=2;
  
  Table created.
  
  SQL>
  SQL> insert /*+ append */ into testpart_temp select * from testpart partition (testpart_2012);
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL>
  SQL> create index idx_testpart_temp_a3 on testpart_temp (a3);
  
  Index created.
  
  SQL>
  SQL> exec dbms_stats.gather_table_stats(user, 'testpart_temp');
  
  PL/SQL procedure successfully completed.
  
  SQL>
  SQL> select table_name, partition_name, last_analyzed, stale_stats
    2  from dba_tab_statistics
    3  where table_name = 'TESTPART_TEMP';
  
  TABLE_NAME      PARTITION_NAME  LAST_ANAL STA
  --------------- --------------- --------- ---
  TESTPART_TEMP                   18-MAY-12 NO
  
  SQL>
  SQL>
  SQL> select index_name, partition_name, last_analyzed, stale_stats
    2  from dba_ind_statistics
    3  where table_name = 'TESTPART_TEMP';
  
  INDEX_NAME                     PARTITION_NAME  LAST_ANAL STA
  ------------------------------ --------------- --------- ---
  IDX_TESTPART_TEMP_A3                           18-MAY-12 NO
  
  
  SQL>
  SQL> alter table testpart
    2    exchange partition testpart_2012
    3    with table testpart_temp
    4    including indexes without validation
    5    update global indexes;
  
  Table altered.
  
  SQL>
  SQL> select table_name, partition_name, last_analyzed, stale_stats
    2  from dba_tab_statistics
    3  where table_name = 'TESTPART';
  
  TABLE_NAME      PARTITION_NAME  LAST_ANAL STA
  --------------- --------------- --------- ---
  TESTPART                        18-MAY-12 NO
  TESTPART        TESTPART_2011   18-MAY-12 NO
  TESTPART        TESTPART_2012   18-MAY-12 NO
  
  SQL>
  SQL> select index_name, partition_name, last_analyzed, stale_stats
    2  from dba_ind_statistics
    3  where table_name = 'TESTPART';
  
  INDEX_NAME                     PARTITION_NAME  LAST_ANAL STA
  ------------------------------ --------------- --------- ---
  IDX_TESTPART_A3                                18-MAY-12 NO
  IDX_TESTPART_A4                                18-MAY-12 NO
  IDX_TESTPART_A3                TESTPART_2011   18-MAY-12 NO
  IDX_TESTPART_A3                TESTPART_2012   18-MAY-12 NO
  
  SQL>
  SQL> select * from user_tab_modifications
    2  where table_name = 'TESTPART';
  
  no rows selected
  
  SQL>
  SQL> exec DBMS_STATS.FLUSH_DATABASE_MONITORING_INFO;
  
  PL/SQL procedure successfully completed.
  
  SQL>
  SQL>
  SQL> select * from user_tab_modifications
    2  where table_name = 'TESTPART';
  
  TABLE_NAME      PARTITION_NAME     INSERTS    UPDATES    DELETES TIMESTAMP TRU DROP_SEGMENTS
  --------------- --------------- ---------- ---------- ---------- --------- --- -------------
  TESTPART                                 1          0          1 18-MAY-12 NO              1
  
  SQL>
  SQL> select table_name, partition_name, last_analyzed, stale_stats
    2  from dba_tab_statistics
    3  where table_name = 'TESTPART';
  
  TABLE_NAME      PARTITION_NAME  LAST_ANAL STA
  --------------- --------------- --------- ---
  TESTPART                        18-MAY-12 YES
  TESTPART        TESTPART_2011   18-MAY-12 NO
  TESTPART        TESTPART_2012   18-MAY-12 NO
  
  SQL>
  SQL> select index_name, partition_name, last_analyzed, stale_stats
    2  from dba_ind_statistics
    3  where table_name = 'TESTPART';
  
  INDEX_NAME                     PARTITION_NAME  LAST_ANAL STA
  ------------------------------ --------------- --------- ---
  IDX_TESTPART_A3                                18-MAY-12 YES
  IDX_TESTPART_A4                                18-MAY-12 YES
  IDX_TESTPART_A3                TESTPART_2011   18-MAY-12 NO
  IDX_TESTPART_A3                TESTPART_2012   18-MAY-12 NO
  
  SQL>
  SQL>

  Its because you modify the table, with the partition definition and OVERALL stats becomes obsolete.
  IDX_TESTPART_A4 index is GLOBAL, so if you move and partition this will become stale (I guess). I have however you suggest to check the status of the global index, isn't - this can be USED? Because if you don't MOVE a partition, all index overall would be UNUSABLE.

• swap partition valid lines

  Hello
  
  I am trying to Exchange data between a table and a partition with the following syntax
  

  alter table dw_owner.fw_auth_dtl_new
     exchange partition "2008_07" with table "DW_OWNER"."FW_AUTH_DTL_2008_07"
     without validation
     update indexes;

  I was expecting the process to carry out relatively quickly but was surprised when the operation has taken a lot of time.
  

  WWRIGHT@dtrdw 20-JAN-09> alter table dw_owner.fw_auth_dtl_new
    2       exchange partition "2008_07" with table "DW_OWNER"."FW_AUTH_DTL_2008_07"
    3       without validation
    4       update indexes;
  
  Table altered.
  
  Elapsed: 00:55:47.67

  I made trace the Exchange using track 10046 and found this statement seems to be burning as much time.
  

  select /*+ first_rows(1) ordered */ 1 
  from
   "DW_OWNER"."FW_AUTH_DTL_2008_07" A ,"DW_OWNER"."FW_AUTH_DTL_NEW" B where 
    "A"."FW_AUTH_DTL_KEY" = "B"."FW_AUTH_DTL_KEY" and ( 
    tbl$or$idx$part$num("DW_OWNER"."FW_AUTH_DTL_NEW",0,0,0 ,B .LOCAL_TRANS_DT ) 
     <  42 or  tbl$or$idx$part$num("DW_OWNER"."FW_AUTH_DTL_NEW",0,0,0 ,B 
    .LOCAL_TRANS_DT )  >  42 ) and rownum < 2

  Want to book seems to indicate that this sql performed the validation of the lines in the Exchange.
  
  Can someone help me understand why, even after the specification WITHOUT VALIDATION, I am online as part of the Exchange partition validation? Is there something I can do to prevent this?
  
  Version of database is 10.1.0.5 on 64-bit solaris. If that helps.
  
  
  Thanks in advance

  Check out this link. I think you have a PK or UK enabled on the table.

  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14231/partiti.htm#i1107555

  Concerning

  REDA

• Find the right Partition for swap Partiton when there are PARTITION and SUBPARTITION

  Hi all

  I have a small problem:

  I want to find the right cause of partitions of the partition key.  I have a partition and a Subpartition (sample - table in annex).

  I leave the database to generate the partition (and name), the name is generated. I need to find for the exchange of partition

  the right of Partition has cause of a given value of the partition key (in this case EVOD_PART_DATE and 20141101 value).

  When I try to find the right partiton name, I would use generally not:

  SELECT DISTINCT dbms_rowid.rowid_object(ROWID) data_object_id
     FROM F_CONTRACT_EVENT
     WHERE  EVOD_PART_DATE = TO_DATE ('20141101','YYYYMMDD')
  

  Okay, I get 2 rows, I'm expecting one, but cause the result are the subpartions, I get this:

    SELECT *  FROM ALL_OBJECTS WHERE DATA_OBJECT_ID IN ( 155159,155154);
  

  I see:

  EVO_DM    F_CONTRACT_EVENT    SYS_SUBP4292    155159    155159    TABLE SUBPARTITION
  EVO_DM    F_CONTRACT_EVENT    SYS_SUBP4287    155154    155154    TABLE SUBPARTITION
  

  But I don't want the subparts, I want the PARTITON!

  The table:

  CREATE TABLE "EVO_DM"."A0_F_CONTRACT_EVENT" 
     ( "EVOD_DDATE_ID_VALID_FROM" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDATE_ID_VALID_TO" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DTIME_ID_START" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DSUST_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCHAN_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DARTI_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCAMP_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DUSAG_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOPSY_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDEVI_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DSHOP_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DPLFO_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DACCO_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDECL_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOBJT_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOFFR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCNTR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCURR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCONT_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DIVWC_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "DD_SUBSCRIPTION_ID" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "SINGLE_ISSUE" NUMBER(8,0) DEFAULT 0, 
      "SUBSCRIPTION" NUMBER(8,0) DEFAULT 0, 
      "RENEWAL" NUMBER(8,0) DEFAULT 0, 
      "CONVERSION" NUMBER(8,0) DEFAULT 0, 
      "DOWNLOAD" NUMBER(8,0) DEFAULT 0, 
      "UPDATES" NUMBER(8,0) DEFAULT 0, 
      "NET_VALUE_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "GROSS_VALUE_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "COMMISSION_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "TAX_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "POSITION_NR" NUMBER(3,0) DEFAULT -1, 
      "DD_ORDER_NR" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "EVOD_SOURCE_CD" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "FLAG_STOCK_RELEVANT" NUMBER(1,0) DEFAULT '0' NOT NULL ENABLE, 
      "RENEWAL_NR" NUMBER(3,0) DEFAULT -1, 
      "EVOD_DDATE_ID_SUBSCRIPTION" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DPRCG_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
    
     EVOD_PART_DATE DATE  GENERATED ALWAYS AS ( TRUNC(TO_DATE(TO_CHAR(EVOD_DDATE_ID_VALID_FROM),'YYYYMMDD'),'MM')) VIRTUAL)
  PARTITION BY RANGE(EVOD_PART_DATE)
  interval(NUMTOYMINTERVAL (1,'MONTH'))
  SUBPARTITION BY LIST(EVOD_SOURCE_CD)
  SUBPARTITION TEMPLATE(
  SUBPARTITION "P_ITUNES"  VALUES ('ITUNES') ,
  SUBPARTITION    "P_WSP"  VALUES ('WSP'),
  SUBPARTITION   "P_GOOGLE"  VALUES ('PLAYSTORE'),
  SUBPARTITION   "P_DEFAULT"  VALUES ('~') ,
  SUBPARTITION   "P_AMAZON"  VALUES ('AMAZON_EREADER', 'AMAZON_MANUELL', 'AMAZON_TABLET') ,
  SUBPARTITION    "P_MSD"  VALUES ('MSD')
  )
  (
   PARTITION P01 VALUES LESS THAN (TO_DATE('200310','YYYYMM')) SEGMENT CREATION DEFERRED
  )
  PARALLEL 10  ;
  

  Any ideas?

  Thanks for Berlin

  First of all - the DOF you posted is INVALID - you do not specify a delayed segment creation for partitions. Specify you for the table.

  Also, you must remove the DEFAULT value - 1 for the partitioning column. The value '-1' cannot be converted to a valid date for the virtual partitioning column value.» The default value is useless and will give confusion around the year exception err when the exception should actually provide a NULL value for a column not null.

  The documentation explains how to use the EXCHANGE PARTITION and has the code example

  Maintenance of Partitions

  Exchange a Partition of a partitioned Table interval

  You can exchange of range partitions in a partitioned table interval. However, you must make sure that the partition of the interval was created before that you can swap partition. You can leave the database create the partition in the partition of the interval of locking.

  The following example shows an Exchange partition for the interval_sales table, range-partitioned using the monthly from partitions of 1 January 2004. This example shows how to add data to the table using charge Exchange partition for June 2007. Assume there is only a local index on the interval_sales table and equivalent index have been created on the interval_sales_june_2007 table.

  LOCK TABLE interval_sales  PARTITION FOR (TO_DATE('01-JUN-2007','dd-MON-yyyy'))  IN SHARE MODE;    ALTER TABLE interval_sales  EXCHANGE PARTITION FOR (TO_DATE('01-JUN-2007','dd-MON-yyyy'))  WITH TABLE interval_sales_jun_2007  INCLUDING INDEXES;
  

  Note the use of the FOR syntax to identify a partition that has been generated by the system. The name of the partition can be used by querying the *_TAB_PARTITIONS view of data dictionary to find the partition system-generated name.

  Given that the last paragraph? That's what showed Solomon.

  NOTE:-special attention to the FIRST paragraph. If you use segment carried OVER creating the partition you want to Exchange could NOT have been created yet.

  Make SURE that you lock the partition as the example shows, or you will get an exception if it has not been created.

  Also - we know NOT what PROBLEM you're trying to solve.

  If you exchange a PARTITION of a table subpartitioned your working table should actually be partitioned using the SAME parttioning as the subparts in the source table:

  See my response in this thread:

  https://forums.Oracle.com/forums/thread.jspa?threadID=2482090&TSTART=30

  In this thread I have provide the code example illustrating how the table should be created and made Exchange.

• Swap file UUID partition

  We had to resize our partition root on one of our 3.0.2 ESX host. In the process, our over Linux swap partition corrupted. We have restored the partition and then was re - activate the partition with the kswap command. We get always the no error of swap partition at the start of the host. I think the problem is that the specification of the UUID in the fstab file is incorrect. However, I can't find a way into ESX to list the UUID for the partitions of the host. Linux command like sudo blkid and ls-l commande┬a identifiant_volume do not work. What is the process to find the UUID in ESX swap partition, so I can correct in fstab?

  Thank you for any input,

  Greg

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  I have a laptop Toshiba TE2100, divided into three partitions: a partition of Windows XP (sda1), a Linux swap partition and a Kubuntu partition. I would like to use the Toshiba recovery CD for the installation of Windows (which doesn't work), but it doesn't seem to be an option on the CD to install in a single partition and not to reformat the entire disk (I really don't want reinstall my Linux).

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  Hello

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