Table of the Union
Hi allI have 2 tables TableA and TableB
TableA
Name, amount, Date
TableB
Name, Amt, BusinessDate
How to get all records in TableA, TableB (Union)
Join TableA.Date = TableB.BusinessDate
Note: above the table column name was different. (TableA. Amount and TableB.Amt)
Result:
Name, amount, Date
I should show all (Union records) in above the column name.
How to do this in OBIEE could you please me step by step
Thank you
Hi reda,.
Defined a level of aggregation (Sum) to the RPD for amount columns?
Thank you
Daan Bakboord
http://obibb.WordPress.com
Tags: Business Intelligence
Similar Questions
-
How can find data in a colum prj_no in all the table of the same schema
Hi all
I find the list of tables with data that has prj_no = "Axis_11" for all tables in the same schema.
Thank you
NrPNR wrote:
I find the list of tables with data that has prj_no = "Axis_11" for all tables in the same schema.1. find the tables with a column of PRJ_NO name. You can find it in USER_TAB_COLUMNS
2 write a query to read the data in each table, using the UNION/UNION ALL operators to merge the results for each table -
Values in the list by the order of table in SELECT Union
Version: 11.2
Apparently a very basic thing. But I couldn't do it :)
In the UNION example below automatic sorting in is based on alphabetical order. I want to get rid of this sort and list the values according to the order of the table in the SELECT.
Test data
In the above example, I want the values in the first array SELECT listed first, then all the values of the second table in SELECT it and so on.create table test1 (name1 varchar2(10)); create table test2 (name2 varchar2(10)); create table test3 (name3 varchar2(10)); insert into test1 values ('EARTH'); insert into test1 values ('TAURUS'); insert into test2 values ('YELLOW'); insert into test2 values ('ALPHA'); insert into test2 values ('TANGO'); insert into test3 values ('BRAVO'); select name1 from test1 union select name2 from test2 union select name3 from test3; NAME1 ---------- ALPHA BRAVO EARTH TANGO TAURUS YELLOW 6 rows selected.
Basically my requirement will be
Expected results:Return all values from test1 (alphabetically sorted) then Return all values from test2 (alphabetically sorted) then Return all values from test3 (alphabetically sorted)
NAME1 ---------- EARTH ------------> from the first table in the SELECT TAURUS ------------> from the first table in the SELECT ALPHA ----------------------> from the second table in the SELECT TANGO ----------------------> from the second table in the SELECT YELLOW ----------------------> from the second table in the SELECT BRAVO ------------------------------> from the third table in the SELECT
Hello
Union made a distinct in terms of the line. From the line "ALPHA", 2 and the line 'ALPHA', 3 are different, they both show in the result set.
Further, you are all just lucky, that you get the results you want with the order clause:
order by 2
This performs a sort on the second column (1,2,3)
Also, you want to sort on the first column (name1, name2 and Name3). The order clause should be (as already shown correctly abbove):order by 2, 1
Kind regards
Peter
-
How to find the Union between the column in the table
Hello
I have the followin table and I want to find the union between the lines as below,
I need the result to be as below.create table test5 (tidset varchar2(200)); insert into test5 values('1;2;3;4;5;6;7;8;9;10;11;12;13;15;16;17;18;19;20'); insert into test5 values('1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20'); insert into test5 values('1;2;3;4;6;7;8;9;11;12;13;15;16;19;20'); insert into test5 values('1;4;6;10;6;11;12;13;14;15;16;17;18;19;20');
any help please,.1;4;6;11;12;13;15;16;19;20
Published by: user11309581 on November 17, 2011 21:32Always mention what version of oracle you are using.
The following query will give you the desired result oracle version 11g release 2.
Connected to Oracle Database 11g Release 11.2.0.2.0 SQL> SQL> with test5 as 2 ( 3 select '1;2;3;4;5;6;7;8;9;10;11;12;13;15;16;17;18;19;20' tidset from dual union all 4 select '1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20' from dual union all 5 select '1;2;3;4;6;7;8;9;11;12;13;15;16;19;20' from dual union all 6 select '1;4;6;10;6;11;12;13;14;15;16;17;18;19;20' from dual -- "END OF SAMPLE DATA" 7 ), all_items as 8 ( 9 SELECT regexp_substr(t.tidset, '[^;]+', 1, column_value) item 10 ,t.tidset 11 FROM test5 t 12 ,TABLE(CAST(MULTISET 13 (SELECT LEVEL 14 FROM dual 15 CONNECT BY LEVEL <= 16 length(regexp_replace(t.tidset, '[^;]')) + 1) AS 17 sys.odcinumberlist)) 18 ),item_counts as 19 ( 20 SELECT DISTINCT a.item 21 ,COUNT(DISTINCT a.tidset) over() total_tidset 22 ,COUNT(a.item) over(PARTITION BY a.item) item_occurance_count 23 FROM (SELECT DISTINCT item 24 ,tidset 25 FROM all_items) a 26 ) 27 SELECT listagg(item, ';') within GROUP(ORDER BY to_number(item)) common_items 28 FROM item_counts 29 WHERE total_tidset = item_occurance_count 30 ; COMMON_ITEMS -------------------------------------------------------------------------------- 1;4;6;11;12;13;15;16;19;20 SQL>
OR if you have any version of oracle less than 11g release 2 then replace below mentioned line
SELECT listagg(item, ';') within GROUP(ORDER BY to_number(item)) common_items
with this one
select xmlagg(xmlelement(c,item||';').extract('//text()') order by (to_number(item))) common_items
It is because the listagg function used in above query is not supported in versions of oracle 11.2 below.
I hope this helps.
-Gregory
Published by: Mohamed Diarra on November 18, 2011 01:05
Extra line to be changed for the oracle version lower than 11.2 -
Update a table using the clause
Hello
I want to update a table using the selected values.
Cases in the sample:
create table as empsalary)
Select 1 as empid, 0 in the wages of all the double union
Select option 2, the double 0);
Data update are as follows
with saldata as
(
Select 1 as empid, 5000 as wages, 500 as double pf
Union of all the
Select option 2, 10000,1000 like double pf
)
Select empid, salary saldata
I tried the following query but does not work
updated set of empsalary table (empid, salary) =
(
Select * from)
with saldata as
(
Select 1 as empid, salary, 500 5000 as pf Union double all the
Select option 2, 10000,1000 like double pf
)
Select empid, salary saldata
) sl
where sl.empid = empsalary.empid
)
I use oracle 10g.
Help, please.
Krishna Devi wrote:
Hello
I want to update a table using the selected values.
Cases in the sample:
create table as empsalary)
Select 1 as empid, 0 in the wages of all the double union
Select option 2, the double 0);
Data update are as follows
with saldata as
(
Select 1 as empid, 5000 as wages, 500 as double pf
Union of all the
Select option 2, 10000,1000 like double pf
)
Select empid, salary saldata
I tried the following query but does not work
updated set of empsalary table (empid, salary) =
(
Select * from)
with saldata as
(
Select 1 as empid, salary, 500 5000 as pf Union double all the
Select option 2, 10000,1000 like double pf
)
Select empid, salary saldata
) sl
where sl.empid = empsalary.empid
)
I use oracle 10g.
Help, please.
Thanks for posting creates table and test data.
The error message would have helped because it's pretty obvious that this is the problem:
Update table empsalary
*
ERROR on line 1:
ORA-00903: invalid table name
Just remove the word "table".
-
Please help me with the Alternative of queries to replace the UNION ALL for two queries
Hi all
I have the query to retrieve assets employees salary count and in so far as below:
Select ename, emp_no, sum (sal_till_2010), sum (sal_till_2014) of
(select emp_no, ename, salary as sal_till_2010, 0 as sal_till_2014 of employee e1
where effective_date < = 1 January 2010 ' and not exists (select 1 from e2 employee_deletion where e2.emp_no = e1.emp_no and e2.deletion_date < = January 1, 2010 "")
UNION ALL
Select ename, emp_no, 0 as sal_till_2010, salary as employee e1 sal_till_2014 - here is a dummy 0 salary until 2010 for the union of all the
where effective_date < = 1 January 2014 "and not exists (select 1 from e2 employee_deletion where e2.emp_no = e1.emp_no and e2.deletion_date < = 1 January 2014") "
Group of emp_no, ename;
In this query, I get the total salary until 2010 and until 2014 in the employee table, dates are dynamically passed to the procedure, and this can change.
But assume the date above and let me know the alternative of queries to improve performance because I use Union ALL and read the same table twice in the above query.
Advice me with request to read the table once to fetch the same data as the above query.
Thanks in advance.
Hello
Thanks for the display of the data of the sample; It's very useful!
I think OP wants something like this:
WITH cutoff_dates AS
(
SELECT TO_DATE (January 1, 2010 ', ' DD/MM/YYYY') AS cutoff_date, 2010 UNDER the label OF dual UNION ALL
SELECT TO_DATE (1 January 2014 ', "DD/MM/YYYY"), double 2014
)
SELECT e.emp_no, e.ename
, NVL (SUM (CASE WHEN c.label = 2010 THEN e.salary END), 0) AS sal_till_2010
, NVL (SUM (CASE WHEN c.label = 2014 THEN e.salary END), 0) AS sal_till_2014
E employee
JOIN cutoff_dates c ON e.effective_date<=>=>
WHERE DOES NOT EXIST)
SELECT 1
Of employee_deletion ed
WHERE ed.emp_no = e.emp_no
AND ed.deletion_date<=>=>
)
E.emp_no GROUP, e.ename
ORDER BY e.emp_no
;
Output of your sample data:
EMP_NO ENAME SAL_TILL_2010 SAL_TILL_2014
---------- ------ ------------- -------------
1 Mickey 450 0
2 Donald 750 0
-
Hello everyone, have a look at the statements below and let me know what wrong with my approach.
CREATE TABLE test (column1 CLOB); INSERT INTO test SELECT to_clob('This is test') FROM dual;
When I run the query below, I get data types incompatible error (ORA-00932). Help, please.
SELECT to_clob('This is test two') FROM dual UNION SELECT column1 FROM test;
Kind regards
Shiva.
Hey Shiva,
Copied from documentation
http://docs.Oracle.com/CD/B19306_01/server.102/b14200/queries004.htm
Restrictions on operators define the set operators are subject to the following restrictions:
- Set operators are not valid on columns of type
BLOB
,CLOB
,BFILE
,VARRAY
, or a nested table. - The
UNION
,INTERSECT
, andMINUS
operators are not valid onLONG
columns. - If the selection list prior the operator set contains an expression, you must provide an alias for the expression column to refer in the
order_by_clause
. - You cannot specify also the
for_update_clause
with the set operators. - You cannot specify the
order_by_clause
in thesubquery
of these operators. - You cannot use these operators in
SELECT
statements containing theTABLE
expressions collection.
- Set operators are not valid on columns of type
-
Hi everyone, yet once landed upward with a problem.
After trying many things to myself, finally decided to post here...
I created a form in form builder 6i in which clicking on a button, the data gets exported to the excel sheet.
It works very well with a single table. The problem now is that I cannot do the same with 2 tables.
Because the tables have the same number of columns and the columns names.
Here are the 2 tables with column names:
Table-1 (MONTHLY_PART_1) Table-2 (MONTHLY_PART_2) SL_NO SL_NO MODEL MODEL END_DATE END_DATE U-1 U-1 U-2 U-2 U-4 U-4 .......... ........ .......... ........ U-20 U-20 U-25 U-25 Given that the tables have the same column names, I get the following error :
402 error at line 103, column 4
required aliases in the SELECT list of the slider to avoid duplicate column names.
So how to export data to excel that has 2 tables with the same number of columns and the column names?
Should I paste the code? Should I publish this query in 'SQL and PL/SQL ' Forum?
Help me with this please.
Thank you.
Wait a second... is this a kind of House of partitioning? Shouldn't it is a union of two tables instead a join?
see you soon
-
I'm trying to get this result,
EQPID EVENTVAL 20120501 20120502 20120503 201204 201205
-------------------------------------------------------------------------------------------------------------------
MS - A1 21528 28386 18288 821295 908602 TKINQTY
MS - A1 21510 28359 18270 820470 907321 TKOUTQTY
MS - B1 21090 17990 15750 467922 557239 TKINQTY
MS - B1 21080 17982 15735 467495 556730 TKOUTQTY
MS - C1 35548 23848 26082 914351 1013655 TKINQTY
MS - C1 35533 23826 26058 913727 1012888 TKOUTQTY
MS - D1 22680 17568 15030 514467 494510 TKINQTY
MS - D1 22660 17565 15021 513955 493857 TKOUTQTY
MS - E1 18450 20916 20754 429057 490732 TKINQTY
MS - E1 18436 20912 20739 428564 490188 TKOUTQTY
MS - F1 13968 14436 14670 440760 517343 TKINQTY
MS - F1 13949 14409 14657 440364 516870 TKOUTQTY
MS - G1 21060 21600 25240 573409 460286 TKINQTY
MS - G1 21057 21595 25237 573317 459888 TKOUTQTY
MS - H1 16452 19278 21456 510192 545201 TKINQTY
MS - H1 16452 19278 21456 510174 545174 TKOUTQTY
170776 164022 157270 4671453 4987568 TKINQTY
170677 163926 157173 4668066 4982916 TKOUTQTY
341453 327948 314443 9339519 9970484
in this table
CUTOFF_DATE EQPID TKINQTY TKOUTQTY
-------------------------------------------------------------------------
20120401 MS - A1 46566 46524
20120401 MS - B1 13734 13720
and so on...
Here is my code,
SELECT EQPID, «EVENTVAL' AS «EVENTVAL', SUM("20120501") AS '20120501', SUM("20120502") AS '20120502', SUM("20120503") AS '20120503', SUM("201204") "201204" AS, SUM("201205") "201205" AS
Of
(
SELECT EQPID, «EVENTVAL' AS «EVENTVAL', SUM("20120501") AS '20120501', SUM("20120502") AS '20120502', SUM("20120503") AS '20120503', SUM("201204") "201204" AS, SUM("201205") "201205" AS
Of
(
SELECT EQPID,
CASE
WHEN EQPID LIKE 'MS-% '.
THEN "TKINQTY".
END, LIKE "EVENTVAL."
CASE
WHEN CUTOFF_DATE = '20120501'
THEN SUM (QTY)
END, LIKE "20120501."
CASE
WHEN CUTOFF_DATE = '20120502'
THEN SUM (QTY)
END, LIKE "20120502."
CASE
WHEN CUTOFF_DATE = '20120503'
THEN SUM (QTY)
END, LIKE "20120503."
CASE
WHEN CUTOFF_DATE BETWEEN '20120401' AND '20120430'
THEN SUM (QTY)
END AS "201204."
CASE
WHEN CUTOFF_DATE BETWEEN '20120501' AND '20120530'
THEN SUM (QTY)
END AS "201205.
Of
(
SELECT CUTOFF_DATE, EQPID, SUM (TKINQTY) QTY.
OF DAILY_DATA
WHERE CUTOFF_DATE BETWEEN '20120401' AND '20120530'
AND EQPID LIKE 'MS-%'
CUTOFF_DATE GROUP, EQPID
ORDER BY CUTOFF_DATE, EQPID
)
EQPID GROUP, CUTOFF_DATE
)
EVENTVAL GROUP, EQPID
UNION
SELECT EQPID, 'EVENTVAL' AS 'EVENTVAL', SUM("20120501") AS '20120501', SUM("20120502") AS '20120502', SUM("20120503") AS "20120503", SUM("201204") AS "201204', SUM("201205") AS"201205 '"
Of
(
SELECT EQPID,
CASE
WHEN EQPID LIKE 'MS-% '.
THEN "TKOUTQTY".
END, LIKE "EVENTVAL."
CASE
WHEN CUTOFF_DATE = '20120501'
THEN SUM (QTYO)
END, LIKE "20120501."
CASE
WHEN CUTOFF_DATE = '20120502'
THEN SUM (QTYO)
END, LIKE "20120502."
CASE
WHEN CUTOFF_DATE = '20120503'
THEN SUM (QTYO)
END, LIKE "20120503."
CASE
WHEN CUTOFF_DATE BETWEEN '20120401' AND '20120430'
THEN SUM (QTYO)
END AS "201204."
CASE
WHEN CUTOFF_DATE BETWEEN '20120501' AND '20120530'
THEN SUM (QTYO)
END AS "201205.
Of
(
SELECT CUTOFF_DATE, EQPID, SUM (TKOUTQTY) QTYO
OF DAILY_DATA
WHERE CUTOFF_DATE BETWEEN '20120401' AND '20120530'
AND EQPID LIKE 'MS-%'
CUTOFF_DATE GROUP, EQPID
ORDER BY CUTOFF_DATE, EQPID
)
EQPID GROUP, CUTOFF_DATE
)
EVENTVAL GROUP, EQPID
)
GROUP BY ROLLUP (EVENTVAL, EQPID)
ORDER OF EQPID, EVENTVAL
It seems to be so long, and I try to avoid the UNION...
Is there an alternative way to achieve the same result without the help of the union?
Thank you
Estelle =)
Published by: 1004902 on May 8, 2013 17:52
Published by: 1004902 on May 8, 2013 17:59Hello
Welcome to the forum!
1004902 wrote:
I'm trying to get this result,EQPID EVENTVAL 20120501 20120502 20120503 201204 201205
-------------------------------------------------------------------------------------------------------------------
MS - A1 21528 28386 18288 821295 908602 TKINQTY
MS - A1 21510 28359 18270 820470 907321 TKOUTQTY
...
in this tableCUTOFF_DATE EQPID TKINQTY TKOUTQTY
-------------------------------------------------------------------------
20120401 MS - A1 46566 46524
20120401 MS - B1 13734 13720
and so on...Every time you ave a problem, CREATE TABLE post and instructions INSERT for your sample data and the results you want from this data.
Explain how you get these results from these data.
Always say what Oracle version you have (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002}It seems that the UNION may be replaced by a cross join, or SELECT... UNPIVOT depending on what version of Oracle you are running.
Published by: Frank Kulash on May 8, 2013 21:52
You may want something like this:
WITH cntr AS ( SELECT LEVEL AS n FROM dual CONNECT BY LEVEL <= 2 ) , got_eventval AS ( SELECT d.cutoff_date , d.eqpid , CASE WHEN c.n = 1 THEN 'TKINQTY' ELSE 'TKOUTQTY' END AS eventval , CASE WHEN c.n = 1 THEN d.tkinqty ELSE d.tkoutqty END AS qty FROM daily_data d CROSS JOIN cntr c WHERE cutoff_date BETWEEN '20120401' AND '20120530' AND eqpid LIKE 'MS-%' ) SELECT eqpid, eventval , SUM (CASE WHEN cutoff_date = '20120501' THEN qty END) AS "20120501" , SUM (CASE WHEN cutoff_date = '20120502' THEN qty END) AS "20120502" , SUM (CASE WHEN cutoff_date = '20120503' THEN qty END) AS "20120503" , SUM (CASE WHEN cutoff_date LIKE '201204' THEN qty END) AS "201204" , SUM (CASE WHEN cutoff_date LIKE '201205' THEN qty END) AS "201205" FROM got_eventval GROUP BY eqpid, eventval ORDER BY eqpid, eventval ;
Of coursel, I can't test it until you post the sample data.
Storage of the information on the dates in a column VARCHAR2 is a very bad idea. The columns DATE to the date information.
-
Combine the results of the UNION
I have little experience with the UNION or UNION ALL, so I don't know what I'm doing wrong. I would like to get the lines in the 2nd statement that is to be United to be grouped with the lines of the first statement, that they must also be included in the total of the column. Here is my SQL and the results I get. Any help is appreciated.
Select
TRUNC (phy_pay_date, 'MONTH') MONTH.
MNTH NULL,
Count (distinct (decode (phy_prn_code, 'WEEK', phy_emp_no))) WEEK,.
Count (distinct (decode (phy_prn_code, 'SEMI', phy_emp_no))) SEMI.
Count (distinct (decode (phy_prn_code, 'MONTH', phy_emp_no))) +.
Count (distinct (decode (phy_prn_code, 'SEMI', phy_emp_no))) +.
Count (distinct (decode (phy_prn_code, 'WEEK', phy_emp_no))) TOTAL
of da.pyemppayhist
da.pyworkloc
da.pycompayprd
where wrl_code = phy_work_location
and phy_prn_code = ppr_prn_code
and phy_comp_code = ppr_comp_code
and phy_ppr_period = ppr_period
and phy_ppr_year = ppr_year
and phy_ppr_year = '2012'
and 12 between extract (ppr_start_date days) and (ppr_end_date days)
Trunc Group (phy_pay_date, 'MONTH')
UNION ALL
Select
MONTHS OF NULL,
Count (distinct (decode (phy_prn_code, 'MONTH', phy_emp_no))) MONTHS.
WEEK NULL,.
NULL SEMI,
TOTAL NULL VALUE
of da.pyemppayhist
da.pyworkloc
da.pycompayprd
where wrl_code = phy_work_location
and phy_prn_code = ppr_prn_code
and phy_comp_code = ppr_comp_code
and phy_ppr_period = ppr_period
and phy_ppr_year = ppr_year
and phy_ppr_year = '2012'
Trunc Group (phy_pay_date, 'MONTH')
order by MONTH
MONTH MNTH WEEK SEMI TOTAL --------- ---- ---- ---- ----- 01-JAN-12 112 235 347 01-FEB-12 109 233 342 01-MAR-12 101 230 331 01-APR-12 107 226 333 01-MAY-12 107 224 331 01-JUN-12 109 221 330 01-JUL-12 108 223 331 20 24 23 29 31 34 45
I don't think you need the Union, all at all - I think that you can do in a single query, if I understand your needs:
select TRUNC (phy_pay_date, 'MONTH') MONTH, count(distinct(decode(phy_prn_code, 'MNTH', phy_emp_no))) MNTH MNTH, count(distinct(case when 12 between extract(day from ppr_start_date) and extract(day from ppr_end_date) and phy_prn_code = 'WEEK' then phy_emp_no end)) WEEK, count(distinct(case when 12 between extract(day from ppr_start_date) and extract(day from ppr_end_date) and phy_prn_code = 'SEMI' then phy_emp_no end)) SEMI, count(distinct(case when 12 between extract(day from ppr_start_date) and extract(day from ppr_end_date) and phy_prn_code = 'MNTH' then phy_emp_no end)) + count(distinct(case when 12 between extract(day from ppr_start_date) and extract(day from ppr_end_date) and phy_prn_code = 'SEMI' then phy_emp_no end)) + count(distinct(case when 12 between extract(day from ppr_start_date) and extract(day from ppr_end_date) and phy_prn_code = 'WEEK' then phy_emp_no end)) TOTAL from da.pyemppayhist ,da.pyworkloc ,da.pycompayprd where wrl_code = phy_work_location and phy_prn_code = ppr_prn_code and phy_comp_code = ppr_comp_code and phy_ppr_period = ppr_period and phy_ppr_year = ppr_year and phy_ppr_year = '2012' group by trunc (phy_pay_date, 'MONTH') order by MONTH;
One thing - you don't are not explicitly indicating which column is from which table, which is something that is vital (IMO) when working with 2 or more tables being joined. Not only does that help you to work if you missed a join condition, it is easier for other people to see what you've done. I highly recommend you rewrite your query with table aliases and then use these aliases for your column names - for example:
select t1.col1, t2.col3, t3.col2 from table1 t1, table2 t2, table3 t3 where t1.col1 = t2.col1 and t3.col1 = t2.col2;
-
Several physical Tables in the single context
I have a scenario and need your input in how to solve this problem.
Let's say I have the schema from source database 2 S1 and S2 (on various Oracle Instances or a single instance). Both have the EMPLOYEE table. Now, I need to create a logical schema that maps to S1. EMPLOYEE and S2. USED, which is I should have access to the data of these two tables in the schema.
Is this possible. Maybe they both have different sets of records of EMPLOYEES for my warehouse I need a UNION of all the data. If I use the context then at any time I can only connect to 1 of these tables. What I want is that in 1 context both have access.
How can achieve us in ODI?>
If the topology would be something like:
Assuming that these are 2 scheme on a single database server
1 / I 1 physical database serverfix
2 / 2 physical diagrams (S1 and S2)
fix
3 / context? How many?
1
Figure 4 / logic? How many?
2
-
By comparing the two tables for the integrity of the data
Hi all
I need to compare two tables for the integrity of the data through the SQL query.If you need to compare all the columns of t1 to t2:
(SELECT * FROM t1 MINUS SELECT * FROM t2) UNION ALL (SELECT * FROM t2 MINUS SELECT * FROM t1);
Kind regards
Ankit Rouault
http://theoraclelog.blogspot.in -
query MySQL (search multiple tables in the database)
I have 12 tables in a database - January to December.
I need to find all the tables 'keyworrd' 12 phrases submitted by the user via a search form.
Need to create a simpler way to do as below with 'UNION '. I have incorporated 2 tables in the query below, but I need a query more "condensed" for all tables of 12?
$sql = (' SELECT * FROM January WHERE tourTitle = "'.") $keyword. "' UNION SELECT * FROM February WHERE tourTitle = ' '. '" $keyword.' » ") ;
See you soon
Operating system
Booth wrote:
> That's what I did last year, but thought I would break down this year in 12 easier to work with tables.
No, Ben is correct. 1 using table for each month is absolutely the wrong way. It violates the basic rules of standardization and causes all sorts of problems.
> Breaking down appealed to be more so I can keep all these months
> together instead of potentially become scattered across a table.
That's what you use the Order By clause for.
> If by chance the customer says they want to update x, y or z, I can go
> straight for the month in question, without the need to browse
> dozens of pages in phpMyAdmin, because there are no real management CMS in place for this process.
Don't know what you're saying. Performing inserts, updates and queries is much easier using a single table.
Whenever someone asks for a way to search through more than one table, he told me that the data structure is not well designed.
When I did this job last year there were about 60 pages created in phpMyAdmin. Records of January could be anywhere on these 60 pages I might add on additional folders much later in the process.
My thought behind this was to combine all entries of the month so I could view them easily in phpMyAdmin.
Now, due to my lack of knowledge on phpMyAdmin, it would be possible to create a query to show only entries from January, I suspect that she can do.
I agree it is much simpler using 1 table to select and browse BUT I need if the opportunity presents itself to be able to view all entries January or February etc. one after another, not 10 on page 2 and 3 on page 7 and 5 more to page 47 of phpMyAdmin.
So I quess what I really need, it is write a select query in phpMyAdmin that shows only the entries selected for the requested month. I did not much research into what phpMyAdmin can do... so I guess I have to.
PUBLISHED:
Arrgh, you see it WAS so SIMPLE:
SELECT * FROM 'towers' months WHERE = "March".
It's because I'm afraid of the bloody thing in case I mess up something!
-
How to eliminate the union clause
I have a requirement where I need to get some recording (say 5 records) of the table and the sum (TOTAL) of some columns in these 5 folders that should be displayed as the last record. Im trying it work with union all clause
Select cd
pid
dt
number
type
sum (iamt) iamt
sum (ALMPs) ALMPs
sum (oamt) oamt
idt
from t1
where code = 'NAQ.
Group by cd, pid, dt, idt
Union of all the
Select 'TOTAL '.
null
null
null
null
sum (iamt) iamt
sum (ALMPs) ALMPs
sum (oamt) oamt
null
from t1
where code = 'NAQ;
is there a way I can avoid using the UNION clause and achieve the same...? Kindly share your thoughts...Hello
Try below:
SELECT cd,
nest,
DT,
NUMBER,
TYPE,
Sum (iAMT) iamt,
Sum (ALMPS) ALMPs,
Sum (OAMT) oamt,
IDT
FROM t1
WHERE code = 'NAQ.
GROUP BY GROUPING SETS ((dt, cd, pid, NUMBER, idt), NULL)Kind regards
Karine -
How to find the data in two tables are the same?
Hi people,
Suppose we have table emp01, have 10 records and create another emp02 as table
create the table emp02 in select * from emp01;
now both the table has the same data.
How to find a 'data' in the two tables are the same?Hello
SELECT * FROM emp01 MINUS SELECT * FROM emp02 UNION SELECT * FROM emp02 MINUS SELECT * FROM emp01
You can also compare resultset hash to select * in emp01 and select * from emp02 by using dbms_sqlhash.
Best regards
Nikolai
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