How to find the data in two tables are the same?

Similar Questions

• How to find the same column name in different tables in the same schema

  Hello
  
  I find the 'ename' column name in different tables in the same schema.
  
  Thank you
  Nr

  Hello

  Try this query

  Select column_name, table_name from user_tab_columns where column_name = 'ENAME ';

  Award points and end the debate, if your question is answered or mark if she was...

  Kind regards

  Lacouture.

• How do find no data in the table

  Hi all
  
  I have 250 table in my diagram and when I query like this
  
  Select * from object where type_objet = 'TABLE' and owner = 'MATTELLI.
  order by object_name CSA
  
  
  Some tables have no data in it. How to find the tables that not have data or records
  
  Thanks and greetings
  Srikkanth.M

  Hi Srikkanth,

  First of all, if you are only interested in object TABLE type, so you should better use dba_tables instead of dba_objects.
  Then, assuming that your statistics are up to date, it would look like:

  SELECT *
    FROM all_tables
   WHERE owner = 'MATTELLI'
    AND num_rows > 0
   ORDER BY table_name ASC
  

  Otherwise, you can go with a subquery and a 'select count.

  HTH,
  Thierry

• How do I know if the two tables are the same in the data they contain

  Hello
  
  How will I know if the two tables are the same in the data they contain?

  Hello

  Please check this thread [compare all columns | http://forums.oracle.com/forums/thread.jspa?messageID=3166309�].

  Kind regards

• Kindly help me with the request to find the data in two tables

  Hello Guru
  
  Kindly help me to recover the data from two tables-
  
  BASEBALL
  LEGAL_ENT_ID (PK)
  GAME_ID (FK)
  LEGAL_ENT_NM
  INACTIVE_DT
  DATE OF INS_TS
  INS_LOGIN
  DATE OF UPD_TS
  UPD_LOGIN
  
  
  FOOTBALL
  GAME_ID (PK)
  BRKR_NM,
  BRKR_ISR_ID
  BROKER_SYMBOL
  INACTIVE_DT
  BRKR_SWIFT_FLG
  BRKR_INTERNAL_FLG
  BRKR_CATEGORY
  UPD_TS
  MINORITY_FLG
  BROKER_TYP
  STATUS
  INS_TS
  INS_LOGIN
  UPD_LOGIN
  APP_USER
  ACTIVE_FLG
  
  and if I want fecth data from these two tables according to the following condition then it is fine with the suite of applications.
  
  1 select distinct values only table of BASEBALL by using the following query.
  
  SELECT DISTINCT B.GAME_ID as 'CLEARING GAME ID', B.BRKR_NM "NAME of THE GAME of COMPENSATION" OF BASEBALL A, FOOTBALL B WHERE A.BROKER_RELATION_CD IN ('FUTBRKR1', 'FUTBRKR2') AND A.GAME_ID = B.GAME_ID
  
  2 Select all the table BRKR_NM OF FOOTBALL as well by using the query - next
  
  SELECT GAME_ID "RUNNING GAME ID", 'NAME OF THE GAME OF EXECUTION' BRKR_NM SOCCER
  
  Now, my query is that--
  
  I want a query that gives me a combination of above mentioned queries... and if I tried to use Union or Union All, then she is not giving me the result as expected.
  
  I like the result to look like who has a few conditions such as -
  1 - the records in the table Football are high vs Baseball table because there is no condition to filter the records of the Football.
  2 - football is a superset of records and Baseball is a subset.
  3 - COMPENSATION NOM_JEU and RUNNING NOM_JEU may return the same values as well.
  
  I want the result to be in the following form-
  
  EXECUTION ID GAME | NAME OF THE GAME TO RUN. COMPENSATION ID GAME | DELETE THE NAME OF THE GAME.
  2123 test1 2345 test5
  2456 test10 2456 test10
  
  
  Thanks in advance. Kindly help me.
  
  Published by: user555994 on January 4, 2011 23:48

  In the output you want.
  All the values of baseball;
  Values of football that are matched;
  But on what condition you want to match?

• average of k: how to find the data clustred; : or how to assign number t0 each data group

  Hi Member

  I have download the LabVIEW Machine https://decibel.ni.com/content/docs/DOC-19328 learning package

  I want to run the K average algorithm to group the image in a group of two or three or more

  the problem is how to find the result I mean the image of clustred', the image that contain 2 or three threatened value only

  or how aasign a 1 value for all the intesity who

  belong to the cluster a and 255 for data that belongs to group 2

  for the look of the image as binary image?

  a my vi below

  Best regards

  my post before shows how to set the threshold manually using the slider of the graph.

  Here is the version k-means automated help .vi box tools

  

  

  Alex

• How to find the last date of execution of the objects in database

  Hi all
  
  We're going for an upgrade of the database 11g and for the same thing, we want to know the last date of the following-
  
  Packages, Tables, views
  Conc. programs / value Sets / look up / profile options
  
  Is there a way we can find the same thing.
  The answers would be really useful.
  
  Kind regards
  Shruti

  So can you provide clues on how to find the last opportunity registration

  I don't think you can find such a script with having activated audit.

  Thank you
  Hussein

• How to find the relationship between the tables

  Hello
  I am working in Oracle R12
  
  How to find the relationship between these tables INV_MIN_MAX_TEMP, po_requisition_lines_all and Per_all_people_f
  
  These two tables, I joined with po_requisition_lines_all and Per_all_people_f To_person_id of PO and anyone HR table but I can't able to join this table with other tables INV_MIN_MAX_TEMP
  
  concerning
  Srikkanth

  solved

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

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• How to find the value max and min for each column in a table 2d?

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• How to find the primary key columns in the tables in MS Access using SQL queries

  How to find the primary key columns in the tables in MS Access using SQL queries

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• How to find the size of the table?

  Hi all

  Can anyone suggest how to find the size of the table? I had a few (15272 selected lines) on the name of "CMPT_" How can I check only 'CMPT_' size tables?

  
  

  
  

  
  

  
  

  Please someone help give the SQL query to run.

  
  

  Thanks in advance.

  
  

  Vincent
  

  madala03 wrote:

  Hi thanks for the reply

  I'm out like below

  SUM(BYTES/1024/1024)

  --------------------

  25383.25

  But how to check all the name of tables CMPT and their sizes?

  Select nom_segment, dba_Segments sum(bytes/1024/1024) where nom_segment like ' % CMPT GROUP BY nom_segment;