Table update with several links

Similar Questions

• problems with several links

  I don't know that this is the basis, but out of my reach. I try to have several links off site, but have hit a brick wall.

  If I have the code below, it opens the second link as soon as you open the page of links, if I have the "function onLinkClick (evt)", above btn6_btn I end up with the error message twice. Is it possible to have multiple buttons on a page link. I played with it for hours.

  Thank you

  Steve

  btn5_btn.addEventListener (MouseEvent.CLICK, onLinkClick);

  function onLinkClick (evt) {}
  siteURL var = new URLRequest ("http://forums.adobe.com/community/flash");
  navigateToURL (siteURL, "_blank");
  }
  btn6_btn.addEventListener (MouseEvent.CLICK, onLinkClick);
  siteURL var = new URLRequest ("http://graphics.palomar.edu/graphics/");
  navigateToURL (siteURL, "_blank");

  There are a few ways to do this, but perhaps the simplest is to have a function of earphone separated for each of the buttons of your:

  btn5_btn.addEventListener(MouseEvent.CLICK, onLinkClick);
  
  function onLinkClick (evt:Event) :void{
      var siteURL = new URLRequest("http://forums.adobe.com/community/flash");
      navigateToURL(siteURL, "_blank");
  }
  
  btn6_btn.addEventListener(MouseEvent.CLICK, onLinkClick2);
  function onLinkClick2 (evt:Event) :void{
      var siteURL = new URLRequest("http://graphics.palomar.edu/graphics/");
      navigateToURL(siteURL, "_blank");
  }
  

  EDIT: OMG 3 responses within one minute of each other!

• Update with no link between the tables

  Hi all
  Let us, considering what follows in 11g:
  

  SQL> create table t1 (col1 number , col2 number);
   
  Table created
   
  SQL> create table t2 (col1 number, col2 number);
   
  Table created
   
  SQL> insert into t1 values(1,2);
   
  1 row inserted
   
  SQL> insert into t1 values(2,3);
   
  1 row inserted
   
  SQL> insert into t1 values(3,4);
   
  1 row inserted
   
  SQL> insert into t2 values(5,6);
   
  1 row inserted
   
  SQL> insert into t2 values(7,8);
   
  1 row inserted
   
  SQL> insert into t2 values(9,10);
   
  1 row inserted
   
  SQL> commit;
   
  Commit complete

  How can I update the table T2 col1 - column - with values of column in table T1 - col2? No order no required - just the values :)
  Maybe it's simple, but I can't get there...
  
  Thanks in advance,
  Alexander.

  select *
  from t1;
  
  COL1 COL2
  ---- ----
     1    2
     2    3
     3    4 
  
  select *
  from t2;
  
  COL1 COL2
  ---- ----
     5    6
     7    8
     9   10 
  
  merge into t2
  using (
   select *
   from ( select rowid rid,row_number() over(order by null) rn1
            from t2
          ) a,
         (
           select t1.*,row_number() over(order by null) rn2
           from t1
         ) b
   where a.rn1 = b.rn2
        )   x
  on (t2.rowid = x.rid)
  when matched then update set t2.col1 = x.col2;
  
  3 rows merged.
  
  select *
  from t2;
  
  COL1 COL2
  ---- ----
     2    6
     3    8
     4   10 
  

  Published by: JAC on November 5, 2012 18:36
  Amended or the requirement

• association table update with post boxes php/mysql table

  OK, I have a dynamic site for the checkboxes are dynamically added to the page database. the name of check boxes affect one table "checkbox []". now my $_Post ['checkbox'] will be an array. now I want to take this picture and make a loop for which updates my table once for each variable in the table, but it is not working and I am perplexed...

  if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) {
    for ($i=0;$i<count($_POST['SpecificationEquipped']);$i++) {
     $updateSQL = sprintf("UPDATE TestersSpecifications SET SpecificationEquipped=%s WHERE TesterModel=%s AND SpecificationID=%s",
           GetSQLValueString(isset($_POST['SpecificationEquipped'][$i]) ? "true" : "", "defined","1","0"),
           GetSQLValueString($_POST['TesterModel'], "text"),
           GetSQLValueString($_POST['SpecificationID'][$i], "int"));
   
    mysql_select_db($database_ampacin1_ampac, $ampacin1_ampac);
    $Result1 = mysql_query($updateSQL, $ampacin1_ampac) or die(mysql_error());
    }
  }
  

  I don't know how make table works how the code is to "set". Anyone who thinks that they can tell me the best way to do it?

  Impression of SQL to see what is generated is the best way to solve problems with dynamically generated queries.

  It is not easy to understand exactly what you're trying to do. However, it might help you to solve the problem if you understand what does the following section of code:

  GetSQLValueString(isset($_POST['checkbox']) ? "true" : "", "defined","1","0")
  

  When a form is submitted, the value of a checkbox control is submitted through array $_POST only if the box is checked. Let's say you have a box like this:

  If the box is checked, the value of $_POST ["accept"] is "o". If the check box is disabled, $_POST ["accept"] is NOT defined. It is not empty, null, or something like that. There is simply not.

  That Dreamweaver verifies if the variable check box exists (isset()). If so, it inserts 1 in the database field. Otherwise, it inserts 0.

  The problem is that you have created a check box group, using a table. Let's say you have 10 check boxes in this group, if only 5 are selected, your table will contain only 5 Articles.

  Depending on how you configure things, I think you must have differently named checkboxes for each record that must be inserted into the database. You can do it with a counter and a loop:

  If you don't know in advance the number of items will be in your loop, you can use $i as the value for a field hidden once the loop is completed. This will allow you to browse your update queries, using the value of the hidden field to control the loop and using a meter to change the name of the boxes.

  for ($i = 1; $i < $_POST['count']; $i++) {
  // other stuff
  GetSQLValueString(isset($_POST["cb_$i"]) ? "true" : "", "defined","1","0")
  // other stuff
  }
  

• Table updated with the list

  I have a form with a list of table row id numbers in the order that I want the lines to be displayed. I need day field of 'dispalyOrder' of the table based on this list.
  
  Currently, I am looping through the list and set the "Form.displayOrder" variable with the number of loops and setting the "Form.catID" variable with the element in the County using ListGetAt list. I then do a cfupdate to update the line.
  
  It's fine for the short list, but when there are 100 or more items in the list there are a lot of hits to the database and usually stops at one point.
  
  Is there a way to make a to the database to update all the lines?
  
  I'm a programmer turned designer so that I can't seem to find online help I don't understand yet.
  Thanks for any help provided.
  
  I use 7 MX with a SQL 2000 database.
  
  
  My current code is attached below.
  
  

  Now all the code in your first post is replaced by this one cfquery (which should be 100 times faster.)

  Please note that I used my best guess on the form and the column names.

• external table data with several locations pump

  Hello
  I'm on:
  Oracle Database 10 g Enterprise Edition release 10.2.0.3.0 - 64biit
  SunOS 5.10
  
  I am trying to create a table of data pump external at the same time, with the location of the files previously created using pump.
  This is the same as the example given in step 10-13 here:
  http://docs.Oracle.com/CD/B19306_01/server.102/b14215/et_dp_driver.htm#i1007502
  
  But when I do this and select all the lines in the resulting table, I get the error:
  
  ORA-29913: error in executing ODCIEXTTABLEFETCH legend
  ORA-29400: data cartridge error
  KUP-11011: file / < filepath > sys_tables.dmp is not valid for this load operation
  ORA-06512: at "SYS." ORACLE_DATAPUMP', line 52
  
  Can anyone help?
  Here is a script of what I do...
  
  
  create the directory message_archive_dir as ' / your/path/directory "; -change default directory
  -chmod 777 your way
  
  create the sys_tables table
  external organization
  (type ORACLE_DATAPUMP
  THE DEFAULT DIRECTORY MESSAGE_ARCHIVE_DIR
  LOCATION ("sys_tables.dmp"))
  AS
  Select object_id, object_type
  of object
  where owner = 'SYS '.
  and object_type = 'TABLE '.
  and rownum < 11;
  
  create the table sys_indexes
  external organization
  (type ORACLE_DATAPUMP
  THE DEFAULT DIRECTORY MESSAGE_ARCHIVE_DIR
  LOCATION ("sys_indexes.dmp"))
  AS
  Select object_id, object_type
  of object
  where owner = 'SYS '.
  and object_type = 'INDEX '.
  and rownum < 11;
  
  Select * from sys_tables
  Union
  Select * from sys_indexes;
  
  -all 20 rows returned!
  -now I combine the two dmp files in a single table...
  
  create the table sys_objects
  (
  object_id NUMBER (14).
  object_type VARCHAR2 (30)
  )
  EXTERNAL ORGANIZATION
  (
  TYPE ORACLE_DATAPUMP
  THE DEFAULT DIRECTORY MESSAGE_ARCHIVE_DIR
  LOCATION ('sys_indexes.dmp', 'sys_tables.dmp')
  );
  
  Select *.
  of sys_objects
  where rownum = 1;
  
  -ok returnes one line (one of the dmp files work)
  --Choose so all lines...
  
  Select *.
  of sys_objects;
  
  ORA-29913: error in executing ODCIEXTTABLEFETCH legend
  ORA-29400: data cartridge error
  KUP-11011: file / < filepath > sys_tables.dmp is not valid for this load operation
  ORA-06512: at "SYS." ORACLE_DATAPUMP', line 52
  
  Can you see what I'm doing wrong?
  
  Any help is greatly appreciated!
  Thank you.

  user9969845 wrote:
  ... Etc...

  TYPE ORACLE_DATAPUMP
  THE DEFAULT DIRECTORY MESSAGE_ARCHIVE_DIR
  LOCATION ('sys_indexes.dmp', 'sys_tables.dmp')

  Combination dump files

  Files dump populated by different external tables can all be specified in the LOCATION of another external table clause. For example, data from different databases can be unloaded in separate files, and these files can then be included in an external table defined in a data warehouse. This provides an easy way to aggregate data from multiple sources. The only restriction is that the metadata for all external tables is exactly the same. This means that the game characters, time zone, schema name, table name, and column names must match. In addition, the columns must be defined in the same order, and their data types must be identical. This means that after you create the first external table you must remove it so that you can use the same table name for the second outer table. This ensures that the metadata in two dump files is the same and they can be used together to create the external table even.
  8 2

• Need help with the update with several joins statement

  I have the following select statement, which takes 29 records:
  SELECT
  PAA. PROJECT,
  PAA. SEGMENT1,
  PEIA.expenditure_item_id,
  PEIA.expenditure_type,
  PEC.expenditure_comment
  OF PA.PA_PROJECTS_ALL APP.
  PEIA PA.pa_expenditure_items_all,
  PEC PA.pa_expenditure_comments
  where PPA.segment1 < '2008' and
  PPA.project_id = 52 and - just run for project # 20077119 for the test
  PEIA.expenditure_type = 'PAY' and
  PEIA.project_id = ppa.project_id and
  PEC. EXPENDITURE_ITEM_ID = PEIA. EXPENDITURE_ITEM_ID;
  
  I need to update the pec.expenditure_comments to a static field for 29 records. I guess I should start with the following, but don't know how to fill in the where:
  Update
  PEC PA.pa_expenditure_comments
  Set pec.expenditure_comment = ' REFERENCE HD #728'.
  where
  ???
  
  First time we have ever needed to update, so any help appreciated.

  Try using are:

  update pa.pa_expenditure_comments pec
  set    pec.expenditure_comment = 'REFERENCE HD#728'
  where exists ( select null
                 from   pa.pa_projects_all ppa
                 ,      pa.pa_expenditure_items_all peia
                 ,      pa.pa_expenditure_comments pec2
                 where  ppa.segment1 < ''    -- not sure what you posted here, so for next time:
                                             -- please put your examples between the code tags.
                 and    ppa.project_id = 52  -- just run for project # 20077119 for testing
                 and    peia.expenditure_type = 'PAYROLL'
                 and    peia.project_id = ppa.project_id
                 and    pec2.expenditure_item_id = peia.expenditure_item_id
                 and    pec2.expenditure_item_id = pec.expenditure_item_id
               );
  

• Pass reference in table 2D with several lines-&gt; Subvi - sees only 1 rank of the number of lines

  What I am doing wrong?

  Of course it is. The Value property. That feed into the size of the array. The output of the size of the table is a table - one element for each dimension of your table.

• update of several columns of values in another table

  Hello
  
  I have two tables in a database of 11 GR 2 that contain similar data. There is no FK relationship between the two tables, and for now, I need the data in MASTER to match what is in the SECONDARY. Table data types are the same with the same length.
  
  Table 1 is called MASTER and columns are:
  MTID
  ADDRESS1
  ADDRESS2
  CITY
  
  Table 2 is called SECONDARY and columns are:
  SDID
  ADDRESS1
  ADDRESS2
  CITY
  
  MID and SID are the same on both, but the rest of the columns may be the same or in some cases are different.
  
  I ran the following query that lets me know there are 20 k odd rows that have different data in these lines (I'm not at work at the mo so do not have the exact query I ran or table column names, but it's close enough).
  

  select
  m.address1 as maddress1,
  s.address1 as saddress1,
  m.address2 as maddress2,
  s.address2 as saddress2,
  m.city as mcity,
  s.city as scity
  from master m, secondary s
  where m.mtid = s.sdid
  and m.address1 != s.address1
  or m.address2 != s.address2
  or m.city != s.city
  /

  I need to update the rows in the master of secondary school where these values are different. I tried a few different queries updated with no luck.
  
  I want to do something like
  

  update m.address1
  set m.address1=s.address1
  where m.address1 != s.address1
  and m.mtid = s.stid;

  But I want to update columns address1 and address2, city of master.
  
  Any ideas on how I can do this? After you run the update results of my select query should return no rows.
  
  Thanks in advance and I hope that the question made sense.

  1008991 wrote:
  I got a similar error as well:

  update master m
  set (sm_user_addr_1, sm_user_addr_2, sm_user_city, sm_user_postal_cde)
  = (select sm_user_addr_1, sm_user_addr_2, sm_user_city, sm_user_postal_cde
  from secondary s
  where s.sd_key = m.sm_key
  )
  where exists (
  select 1 from secondary s
  where s.sd_key = m.sm_key
  and (s.sm_user_addr_1     != m.sm_user_addr_1 or
  s.sm_user_addr_2     != m.sm_user_addr_2 or
  s.sm_user_city       != m.sm_user_city   or
            s.sm_user_postal_cde != m.sm_user_postal_cde));
  
  ERROR at line 3:
  ORA-01427: single-row subquery returns more than one row
  

  It simply means that you have several lines with the same sd_key for a given sm_key.
  Is that you have secondaries for one master. You must choose only one line
  If you need additional terms in your where clause

  select sm_user_addr_1, sm_user_addr_2, sm_user_city, sm_user_postal_cde
             from secondary s
           where s.sd_key = m.sm_key
  

• Update using several terms from multiple tables

  Hello
  
  I'm quite new to PL/SQL.
  
  I need to update a record in a table with several conditions in which the clause of several tables.
  
  On the internet I found something like
  
  Update < table >
  Set < column > = < value >
  < Table >
  Join them < table >
  on < condition >
  Where < condition >
  And < another condition >
  
  Now, I have:
  
  Update outbound_order
  Set outbound_order_sorting_code = "A".
  to orderref o, oo outbound_order
  where oo.ordernumber = o.ordernumber
  and o.delivery_status = 'c ';
  
  It gives ORA00933 of Pl/SQL to->
  
  I can't use more than one table in update?
  
  Kind regards
  
  Chi Wai

  update outbound_order o
  set outbound_order_sorting_code = 'A'
  where exists(select 1 from orderref oo
                where oo.ordernumber = o.ordernumber)
  and delivery_status = 'c';
  

• Update with select table from another table

  Hallo,
  
  I'd like to update table b with a mapping a table codes.
  
  one has:
  
  town_id, town_code, town_name
  
  b town_code, town_id, town_population, town_zip_code...
  
  Table a has all the details - town_id, town_code and town_name and acts as the mapping between town_id and town_code
  
  In table b, town_code is null. I want to update the column b.town_code with town_code table where a.town_id = b.town_id.
  
  How the update query will look like?
  
  I tried
  UPDATE B SET town_code = (SELECT A.town_code FROM A, B WHERE A.town_id = B.town_id)
  
  and I get the error "einreihig subquery returns several lines.
  
  You will appreciate your assistance

  OK, now I see where you went wrong.

  It's your query:

  UPDATE TOWN_INFO
  SET TOWN_CODE=(SELECT B.TOWN_CODE FROM TOWN_MAPP B, TOWN_INFO C
  WHERE B.TOWN_ID=B.TOWN_ID)
  /
  

  You have added an additional TOWN_INFO table reference in your subquery. You really wanted to refer to the TOWN_INFO in your UPDATE statement for that to be a CORRELATED subquery. Delete this reference as I did below.

  Here's the correct query:

  UPDATE  TOWN_INFO TI
  SET     TOWN_CODE = (
                          SELECT  TOWN_CODE
                          FROM    TOWN_MAPP TM
                          WHERE   TI.TOWN_ID = TM.TOWN_ID
                  )
  ;
  

• Unable to create cache with several tables group

  Hello
  
  I need to create a group of cache with several tables, which are referential to the other.
  
  There are 2 related tables and table 1 child...
  While trying this thing, it gives me an error:
  
  8222: multiple parent tables found
  
  It is not possible to use several tables of root in a single cache group? Is there another way to use it?
  
  Script, I used is:
  
  create a cache group asynchronous writethrough TEST. CG1
  of the TEST. ROOT1)
  KEY PRIMARY ID VARCHAR2 (8 BYTES),
  NAME VARCHAR2 (50 BYTE),
  DESCRIPTION VARCHAR2 (255 BYTE),
  POLICYTYPEID VARCHAR2 (7-BYTE)),
  
  TEST. ROOT2)
  PARAMTYPEID VARCHAR2 (5 BYTES) PRIMARY KEY,
  PARAMETERUSAGE VARCHAR2 (1 BYTE),
  NAME VARCHAR2 (25 BYTE),
  DESCRIPTION VARCHAR2 (255 BYTE)),
  
  TEST. CHILD1)
  PARAMDETAILID NUMBER (20) PRIMARY KEY,.
  ID VARCHAR2 (8 BYTE),
  PARAMETERUSAGE VARCHAR2 (1 BYTE),
  DISPLAYVALUE VARCHAR2 (255 BYTE),
  OPERATORID VARCHAR2 (5 BYTE),
  VENDORID NUMBER (20).
  FOREIGN KEY REFERENCES TEST. ROOT1 (ID),
  TEST KEY (PARAMETERUSAGE) REFERENCES STRANGERS. ROOT2 (PARAMETERUSAGE));

  You can't have multiple root within a group of cache tables. The requirements for tables in the group a cache are very strict; There must be only one top-level (root table) table and there may possibly be several children tables. Tables of the child should be linked through foreign keys to the root table or a child table above in the hierarchy.

  The solution for your case is among the tables of root and the other root table in a separate cache group and the child table in a cache group. If you do this, you must take care of a few things:

  1. you cannot define foreign keys between the tables of groups of different cache in TimesTen (keys may exist in Oracle) so the application must enforce referential integrity itself for these cases.

  2. If you load data in a cache group (using LOAD the GROUP CACHE or "load we demand") and Timesten will not automatically load the corresponding data in the other group of cache (since he doesn't know the relationship). The application must load the data into the other group of cache explicitly.

  There is no problem with transactional consistency when changes are pushed to Oracle. TimesTen maintains and reinforces the coherence transactional regardless of how the tables are arranged in groups cache correctly.

  Chris

• How to place a shortcut on the desktop screen to an existing bookmark FOLDER with several web links?

  I have several web links AND folders with many links in bookmarks.
  I want to place a shortcut on my desktop screen to a FOLDER that is in my favorites that will have all these web links.

  Thank you

  Sorry, this is not possible.

• I bought an iphone used several years ago... hen his recently updated with the new iOS 7.1.2 it was locked with the previous owners account.how can I use my iphone is back with my apple and pass

  I bought an iphone used several years ago... When updating with the new iOS 7.1.2 recently, he was locked with previous apple owners account.

  its now useless. I didn't know all these crappy activation locks and all.now I have no idea

  How can I find my iphone is off and use my phone back

  iphone 4 32 gb

• Update with the Lead feature and several lines

  I have a table such as:

  Table1:

  OrderNumber EFFECTIVE_DATE EFFECTIVE_END_DATE FileName

  123 11/5/2015-12/31/2099 File5.txt

  123, 7/11/2015-12/31/2099 File7.txt

  or it can look like:

  Table2

  OrderNumber EFFECTIVE_DATE EFFECTIVE_END_DATE FileName

  123 11/5/2015-11/7/2015 File5.txt

  123, 7/11/2015-11/9/2015 File7.txt

  123 11/9/2015-12/31/2099 File9.txt

  123 11/15/2015-12/31/2099 File15.txt

  I want to take the 2nd to the last EndDate and update with the previous value.

  So in fact, it would look like this.

  Table1:

  OrderNumber EFFECTIVE_DATE EFFECTIVE_END_DATE FileName

  123 11/5/2015-11/7/2015 File5.txt

  123, 7/11/2015-12/31/2099 File7.txt

  or

  Table2

  OrderNumber EFFECTIVE_DATE EndDate FileName

  123 11/5/2015-11/7/2015 File5.txt

  123, 7/11/2015-11/9/2015 File7.txt

  123-11/9/11/15 to 2015/2015 File9.txt

  123 11/15/2015-12/31/2099 File15.txt

  I got it work in a select statement to a single value. now I just need help it enter an UPDATE statement and update all records.

  SELECT W.EFFECTIVE_DATE, W.EFFECTIVE_END_DATE,

  NVL (LEAD (W.EFFECTIVE_DATE, 1) (ORDER implementation W.EFFECTIVE_DATE), December 31, 99 ') AS 'EFFECTIVE_DATE_NEW '.

  OF WH_ORDERS_REPORT W

  WHERE ORDERNUMBER = '10460992';

  It did not work:

  UPDATE WH_ORDERS_REPORT WH

  SET EFFECTIVE_END_DATE = (SELECT NVL (LEAD (WH2. EFFECTIVE_DATE, 1) (ORDER of WH2. (EFFECTIVE_DATE), DECEMBER 31, 99 ')

  OF WH_ORDERS_REPORT WH2

  WHERE WH. ORDERNUMBER = WH2. ORDERNUMBER)

  I appreciate your help in the creation of an update statement to do this.

  Rap, but it's working now.  I'll confirm with a few other records before I mark as correct, but what I see so far, it is beautiful, thank you!

  merge into WH_LIFELINE_ORDERS_REPORT D

  a_l'_aide_de)

  Select

  DISTINCT ORDERNUMBER,

  CURRENTSTATUSDATETIME,

  NVL (LEAD(EFFECTIVE_DATE, 1) ON (ORDERNUMBER partition

  (EFFECTIVE_DATE order), December 31, 99 ') as EFFECTIVE_END_DATE

  of WH_LIFELINE_ORDERS_REPORT

  ) S

  WE (D.ORDERNUMBER = S.ORDERNUMBER

  AND D.CURRENTSTATUSDATETIME = S.CURRENTSTATUSDATETIME

  )

  When matched then

  setting a day of set D.EFFECTIVE_END_DATE = S.EFFECTIVE_END_DATE;