The appropriate to a MAX on an analytical function syntax
I am trying to apply a MAX function on a function analytically than doing a MAX as well. However, I can't understand the appropriate syntax. That's what I tried:SELECT MAX(MAX(t.col1) OVER (PARTITION BY t.col2) AS max_col
FROM sample_table t;You must encapsulate the query that has the analytical function in another query and then make the max in the outer query.
Tags: Database
Similar Questions
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I have records that a load dates repeat.
I would like to return records with the maximum load_dates.
My data source looks like this-
(select 60589 as C_number, to_date('01/08/2012','DD/MM/YYYY') as load_dt of all the double union)
Select 60768, to_date('01/08/2012','DD/MM/YYYY') of all the double union
Select 60888, to_date('01/08/2012','DD/MM/YYYY') of all the double union
Select 12345, to_date('01/09/2012','DD/MM/YYYY') of all the double union
Select 54321, to_date('01/09/2012','DD/MM/YYYY') of all the double union
Select 66666, to_date('01/10/2012','DD/MM/YYYY') of all the double union
Select 55555, double to_date('01/10/2012','DD/MM/YYYY'))
;
I would like to return records with the max load_dt which means
C_number load_dt
666666 1 October 12
555555 1 October 12
I wrote an analytical function of the oracle, but it does not work as it should be-
My query looks like this-
Select a.*
Of
(
Select
c_number,
load_dt,
Max (load_dt) more (load_dt partition) as mx_dt
from table_name
)
where
load_dt = mx_dt;
It returns all the lines for some reason any.
Any help or advice is much appreciated
PJmax(load_dt) over (partition by load_dt) as mx_dtshould be
max(load_dt) over () as mx_dtIf you want the maximum all the records, otherwise your was just the maximum per load_dt partition (think of partitions as being groups of data)
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Unable to get the database searched with MAX and GROUP BY function
Hello
All the
I have a table as below:
COLUMN TYPE
User_id VARCHAR2 (10 byte)
ID_processus VARCHAR2 (30 bytes)
END_TIME DATE (STAMP)
TO_LOC VARCHAR2 (12 bytes)
TO_LOC_TYPE VARCHAR2 (15 bytes)
FROM_LOC VARCHAR2 (12 bytes)
ITEM_ID VARCHAR2 (25 bytes)
CASE NUMBER (12.4)
LMS_UDA1 VARCHAR2 (250 bytes)
AREA VARCHAR2 (2 bytes)
I only want to get one record with all the columns, have only one clause MAX (END_TIME)
But the other column value of the difference.
When I use MAX (END_TIME) and GROUP OF USER_ID, ID_processus, CASE...
the sql did not a single record,
It gives the number of records
Please help me on this
Concerning
Saven>
I only want to get one record with all the columns, have only one clause MAX (END_TIME)
But the other column value of the difference.
>
Maybe it's not possible because it depends on your data.If the combination of all columns except END_TIME is not unique then there will be multiple records; a record for each unique combination (GROUP BY) of all other columns.
The only way to ensure that a record is
SELECT MAX(END_TIME) FROM myTable -
Purpose of the ORDER BY clause in the analytic function Min Max
I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.user10566312 wrote:
I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.It is a good point that many developers are not so aware. As far as I understand it the way it works.
Some analytical functions do not need an order by or windowing clause (SUM, COUNT, MIN, etc.). If there is no specified window, then the full score is the window.
As soon as you add a command also add you a windowing clause. This window has the default value of 'rank ofrowsbetween unbounded preceding and current_row. So as soon as you add an order by clause, you get a sliding window.Documentation: http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions001.htm
windowing_clause
...
You cannot specify this clause unless you specified the order_by_clause. Window limits defined by the clause RANGE you can not specify only a single expression to the > order_by_clause. Please refer to 'Restrictions on the ORDER BY Clause'.example of
with testdata as (select 10 numval, level lv from dual connect by level < 10) select lv, numval, sum(numval) over () sum1, sum(numval) over (order by lv) sum2 from testdata; LV NUMVAL SUM1 SUM2 -- ------ ---- ---- 1 10 90 10 2 10 90 20 3 10 90 30 4 10 90 40 5 10 90 50 6 10 90 60 7 10 90 70 8 10 90 80 9 10 90 90Published by: Sven w. on 25 Sep 2012 16:57 - default behavior has been corrected. Thanks to Chris
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A question about the analytical function used with the GROUP BY clause in SHORT
Hi all
I created the following table named myenterprise
If I want to find which is the total sales by city? I'll run the following queryCITY STOREID MONTH_NAME TOTAL_SALES ---------- ---------- ---------- ---------------------- paris id1 January 1000 paris id1 March 7000 paris id1 April 2000 paris id2 November 2000 paris id3 January 5000 london id4 Janaury 3000 london id4 August 6000 london id5 September 500 london id5 November 1000
that works very well and produces the expected result, i.e.SELECT city, SUM(total_sales) AS TOTAL_SALES_PER_CITY FROM myenterprise GROUP BY city ORDER BY city, TOTAL_SALES_PER_CITY;
Now in one of my books SQL (Mastering Oracle SQL) I found another method by using the SUM, but this time as an analytic function. Here's what the method of the book suggests as an alternative to the problem:CITY TOTAL_SALES_PER_CITY ---------- ---------------------- london 10500 paris 17000
I know that the analytic functions are executed after the GROUP BY clause has been transformed completely and Unlike regular aggregate functions, they return their result for each line belonging to the partitions specified in the partition clause (if there is a defined partition clause).SELECT city, SUM(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY FROM myenterprise GROUP BY city ORDER BY city, TOTAL_SALES_PER_CITY;
Now my problem is that I do not understand what we have to use two functions SUM? If we only use one only, i.e.
This generates the following error:SELECT city, SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY FROM myenterprise GROUP BY city ORDER BY city, TOTAL_SALES_PER_CITY;
The error is generated for the line 2 column 11 which is, for the expression SUM (total_sales), well it's true that total_sales does not appear in the GROUP BY clause, but this should not be a problem, it has been used in an analytical function, so it is evaluated after the GROUP BY clause.Error starting at line 2 in command: SELECT city, SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY FROM myenterprise GROUP BY city ORDER BY city, TOTAL_SALES_PER_CITY Error at Command Line:2 Column:11 Error report: SQL Error: ORA-00979: not a GROUP BY expression 00979. 00000 - "not a GROUP BY expression" *Cause: *Action:
So here's my question:
Why use SUM (SUM (total_sales)) instead of SUM (total_sales)?
Thanks in advance!
:)
In case you are interested, that's my definition of the table:
Edited by: dariyoosh on April 9, 2009 04:51DROP TABLE myenterprise; CREATE TABLE myenterprise( city VARCHAR2(10), storeid VARCHAR2(10), month_name VARCHAR2(10), total_sales NUMBER); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('paris', 'id1', 'January', 1000); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('paris', 'id1', 'March', 7000); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('paris', 'id1', 'April', 2000); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('paris', 'id2', 'November', 2000); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('paris', 'id3', 'January', 5000); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('london', 'id4', 'Janaury', 3000); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('london', 'id4', 'August', 6000); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('london', 'id5', 'September', 500); INSERT INTO myenterprise(city, storeid, month_name, total_sales) VALUES ('london', 'id5', 'November', 1000);It is clear that thet Analytics is reduntant here...
You can even use AVG or any analytic function...SQL> SELECT city, 2 avg(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY 3 FROM myenterprise 4 GROUP BY city 5 ORDER BY city, TOTAL_SALES_PER_CITY; CITY TOTAL_SALES_PER_CITY ---------- -------------------- london 10500 paris 17000 -
Hello
Don't you know that it is the analytical function used to access an earlier date for example table RRODUCT
Date amount CN code 25/09/2012 1000 20 26/09/2013 2000 15 27/09/2011 1000 8 28/09/2012 2000 12 29/09/2013 2000 2 30/09/2004 1000 4
and this table contains more than 1000 lines in difeerent years now, I want to get the amount in a given year and the previous year like this 20 + 15 + 12 + 4
I need analytical control that find the previous year 2012 if my year 2013 or find out if 2010 my 2011 yeaar
You can use the YEAR-1 right? SHIFT of analytic function can be used to access the previous line. Your condition is to get the value of the previous year and previous row not. If this isn't what you are looking for then can you post output necessary for data provided?
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FIRST_VALUE() and LAST_VALUE Analytic Functions
Hi all
May be that it is a fundamental issue. But I'm having a hard time understanding the difference between FIRST_VALUE() and LAST_VALUE() of analytical functions.
As much as what I read the FIRST_VALUE function picks up the first record after the partition and order by and he returned after all calculation. And the LAST_VALUE does the opposite. But the result of the second query as I expected, are not (last value of the partition). It would be useful that someone could throw some light on it.
select empno , ename , sal , first_value(ename) over(order by sal desc) from emp; empno ename sal first_value ------ ---------- --------- ----------- 7839 KING 5000.00 KING 7902 FORD 3000.00 KING 7788 SCOTT 3000.00 KING 7566 JONES 2975.00 KING 7698 BLAKE 2850.00 KING 7782 CLARK 2450.00 KING 7499 ALLEN 1600.00 KING 7844 TURNER 1500.00 KING 7934 MILLER 1300.00 KING 7654 MARTIN 1250.00 KING 7521 WARD 1250.00 KING 7876 ADAMS 1100.00 KING 7900 JAMES 950.00 KING 7369 SMITH 800.00 KING 14 Row(s) affected
Thank youselect empno , ename , sal , last_value(ename) over(order by sal desc) from emp; empno ename sal last_value ------ ---------- --------- ---------- 7839 KING 5000.00 KING 7902 FORD 3000.00 SCOTT 7788 SCOTT 3000.00 SCOTT 7566 JONES 2975.00 JONES 7698 BLAKE 2850.00 BLAKE 7782 CLARK 2450.00 CLARK 7499 ALLEN 1600.00 ALLEN 7844 TURNER 1500.00 TURNER 7934 MILLER 1300.00 MILLER 7521 WARD 1250.00 MARTIN 7654 MARTIN 1250.00 MARTIN 7876 ADAMS 1100.00 ADAMS 7900 JAMES 950.00 JAMES 7369 SMITH 800.00 SMITH 14 Row(s) affected
VincentHey, Vincent,.
When you use an analytic function with an ORDER BY clause, the results will be based on a window, which is a subset of the partition.
If you do not specify a window (using the keywords LINE or LINES) the window everything will be in order by the ORDER BY clause, until and including the current line, including links.For example, in your second query:
select empno , ename , sal , last_value(ename) over(order by sal desc) from emp; empno ename sal last_value ------ ---------- --------- ---------- 7839 KING 5000.00 KING 7902 FORD 3000.00 SCOTT 7788 SCOTT 3000.00 SCOTT 7566 JONES 2975.00 JONES 7698 BLAKE 2850.00 BLAKE 7782 CLARK 2450.00 CLARK 7499 ALLEN 1600.00 ALLEN 7844 TURNER 1500.00 TURNER 7934 MILLER 1300.00 MILLER 7521 WARD 1250.00 MARTIN 7654 MARTIN 1250.00 MARTIN 7876 ADAMS 1100.00 ADAMS 7900 JAMES 950.00 JAMES 7369 SMITH 800.00 SMITHThe analytic function
last_value(ename) over(order by sal desc)Returns the last ename, not of the entire table, but the window starting with the highest sal (since you say "ORDER BY sal DESC") and including the current line and all the other lines that have the same sal.
So consider the 1st row, ename = 'KING '. It has the most sal, so that a single line in the window, 'KING' IS THE LAST VALUE WINDOW.
Now consider the 2nd row, where ename = 'FORD' and sal = 3000. The window includes now everybody with a sal of 3000 and more, which means the 3 rows 'KING', 'FORD' and 'SCOTT '. The last of them (in descending order of sal) is 'SCOTT '. (In fact, there is a tie, you could just as well say that "JONES" is changed, because there is a tie between the two rows where sal = 3000) When this happens, one of the lines will arbitrarily designate the "last" line don't expect not to be always the same line.)
Because of this, LAST_VALUE is alwmost always used with an explicit windowing clause, beginning with the BEACH or LINES.
If you want a request as your first request, but it contains the name of the lowest paid employee (that is, he always says 'SMITH' in the last column instead of 'KING'), then use FIRST_VALUE, but reverse the sort order:
first_value(ename) over(order by sal ASC) -
I have a situation where I partitioned a Recordset. If in one partition on this recordset, the value of a field (field name registered) is '45' I need to order the result of this partition by - "outdate" desc "this provision" desc and order the other partition of desc 'key',' sequence ' desc, desc "outdate."
If the query looks like to.
Select row_number() over (partition by the order of the keys in sequence) RowNo, key, seq, status, outdate, receivedate from table1 where...
order by?
RowNo status outdate Seq key provision
1 200 0 24 9/13 / 2009 12/9/2009
2 200 1 23 9/10 / 2009 9/09/2009
3 200 2 24 9/09 / 2009 9/08/2009
1 210 0 24 9/13 / 2009 12/9/2009
2 210 1 * 45 * 9/09/2009-9/08/2009
3 210 2 24 9/10 / 2009 9/09/2009
So I need to get the query that will order the first series of partition by desc 'key',' order ' desc, desc "outdate" and the second set of partition (because the status of '45' exists in the second partition) by "outdate" desc "this provision" desc.
The output of the query should look like
RowNo status outdate Seq key provision
1 200 0 24 9/13 / 2009 12/9/2009
2 200 1 23 9/10 / 2009 9/09/2009
3 200 2 24 9/09 / 2009 9/08/2009
1 210 0 24 9/13 / 2009 12/9/2009
2 210 2 24 9/10 / 2009 9/09/2009
3 210 1 * 45 * 9/09/2009-9/08/2009
I don't know if this is possible using the analytical function.
I would appreciate if any can help me with that.
Thanks in advanceHello
Welcome to the forum!
You can use analytical functions in the ORDER BY clause.
I do not have your tables, so I'll use scott.emp to illustrate.
The following query sorts first by deptno. After this, the sort order for the departments that contain at least one seller is:
b job
(b) ename
DEPTNO = 30 is be the only Department with a seller, so it's the only sorting as shown above.
Other departments will be sorted by
(a) sal
(b) jobSELECT deptno , ename , job , sal FROM scott.emp ORDER BY deptno , CASE WHEN COUNT ( CASE WHEN job = 'SALESMAN' THEN 1 END ) OVER (PARTITION BY deptno) > 0 THEN ROW_NUMBER () OVER ( PARTITION BY deptno ORDER BY job , ename ) ELSE ROW_NUMBER () OVER ( PARTITION BY deptno ORDER BY sal , job ) END ;Output:
. DEPTNO ENAME JOB SAL ---------- ---------- --------- ---------- 10 MILLER CLERK 1300 10 CLARK MANAGER 2450 10 KING PRESIDENT 5000 20 SMITH CLERK 800 20 ADAMS CLERK 1100 20 JONES MANAGER 2975 20 SCOTT ANALYST 3000 20 FORD ANALYST 3000 30 JAMES CLERK 950 30 BLAKE MANAGER 2850 30 ALLEN SALESMAN 1600 30 MARTIN SALESMAN 1250 30 TURNER SALESMAN 1500 30 WARD SALESMAN 1250The small set of sample data you posted, the results you want can be achieved simply through
ORDER BY key , outdate DESCI guess it's just a coincidence.
If you need help, post some examples of data that requires really looking at the status column to get good results. Display the data in executable form, such as CREATE TABLE and the instructions INSERT, olr, as Salim, a WITH clause. (Maybe you can simply add or change a couple of lines in the example Salim already posted data).
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Hi guys,.
I have problems getting my sbRIO 9606 to deploy.
Everything's fine until during the deployment process, I get this:
Deployment of sbRIO 9606 chassis (sbRIO-9606)
LabVIEW: (Hex 0x80DF001E) could not find the plug-in for this deployment item. Make sure that the appropriate software is installed.I tried to reinstall LV (ensuring that FPGA & RT deployment options are checked) and the 9606 software shipped, but it made no difference. I'm still waiting my next serial key by NOR, I have to wait that I recorded it before I can deploy?
Please find attached the screenshots of my:
- License Manager OR
- Overview of the 9606 MAX
- My project folder
- Dialog box deployment where the error is displayed.
-Adam
Hi Tim,.
In time real 11 is installed according to the recommended software battery installation program included on the disc NEITHER RIO provided in the starter pack.
The problem is that the recommended Software NI Scan Engine 3.0 installation program.
The sbRIO 9606 does not support scanning engine.
Once the scanning engine support has been uninstalled, I could deploy on my 9606.
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Need help with the analytical function select maximum and minimum of the results of the column
Hey there OTN.
I have an interesting application that I was hoping you would be able to help me with. I have a requirement to conditionally select the max and min of a column in bi-editor and since my editor works from an OBIEE analysis, I need store MAX and MIN of the column values in separate columns to match with. See the example below. You will notice that there are 4 stores including today's sales. I must have OBIEE through all the results of the column for sales, then choose the max of the dataset object. I can't use MAX here because he will choose the MAX of the line which will return only sales of this line. Instead, one must analyze all sales results and choose the appropriate column. Any idea on how to do this in OBIEE/publisher? Or is this not possible.
Day Store Sales Sales of MAX Sales MIN 05/11/15 Store 1 5000 8000 1000 05/11/15 Store 2 7500 8000 1000 05/11/15 Store 3 1000 8000 1000 05/11/15 Store 4 8000 8000 1000 I'm waiting for your answers. Thanks in advance!
PS: I will always mark messages that are useful and eventually mark it as correct answer if we come to a resolution!
See you soon.
You can't do the same thing with RANK ("dirty")?
Rank ("dirty") = 1: the max value in the result of sales
RANK (-1 * "Sales") = 1: the min in the result of sales value
I guess you can and then format the cells based on these values, where a value of 1 is the max or min according to the RANKING formula you used...
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SQL using the analytic function
Hi allI want a help in the creation of my SQL query to retrieve the data described below:
I have a test of sample table containing data as below:
State ID Desc
MICHAEL 1 T1
ACTIVE 2 T2
T3 3 SUCCESS
DISABLE THE T4 4
The thing I want to do is to select all the lines with an ACTIVE status in the table but is there is no ACTIVE status, my request will give me the last line with MICHAEL status.
I can do this in a single request by using the analytical function for example, if yes can yiu help me on the request of unpacking.
Kind regards
Raluce
Something like that?
I had to fix it.
with testdata until)
Select 1 id, "T1" dsc "DISABLED" status of Union double all the
Select 2 id, 'T2' dsc, the status "ACTIVE" of all the double union
Select id 3, "T3" dsc, the status of 'SUCCESS' of all the double union
Select 4 id, "T4" dsc "DISABLED" status of double
)Select
ID
dsc
status
of testdata
where
status =
-case when (select count (*) in testdata where status = 'ACTIVE') > 0
then 'ACTIVE '.
Another 'DISABLED '.
end
and)
ID in (select id from testdata where status = ' ACTIVE')
or
ID = (select max (id) in testdata when status = 'DISABLED')
)STATE ID DSC
'2' 'T2' 'ACTIVE '.
Maybe it's more efficient
Select
ID
dsc
status
of testdata
where
status =
-case when (select count (*) in testdata where status = 'ACTIVE') > 0
then 'ACTIVE '.
Another 'DISABLED '.
end
and
ID =)
-case when (select count (*) in testdata where status = 'ACTIVE') > 0
then id
on the other
(select max (id) in testdata when status = 'DISABLED')
end
)Post edited by: correction of chris227
Post edited by: chris227
extended -
Here is an example of the table data:
I would get this:ID NAME Start 1 SARA 01-JAN-2006 2 SARA 03-FEB-2006 3 LAMBDA 21-MAR-2006 4 SARA 13-APR-2006 5 LAMBDA 01-JAN-2007 6 LAMBDA 01-SEP-2007
I tried using partition and run the function but partition name combines all the lines of Sara and Lambda lines into a single group/partition that is not I am trying to get.Name Start Stop SARA 01-JAN-2006 20-MAR-2006 LAMBDA 21-MAR-2006 12-APR-2006 SARA 13-APR-2006 31-DEC-2006 LAMBDA 01-JAN-2007 <null>
Is there an analytic function or other means to achieve to combine date ranges only when the same person appeared conescutively?
Thank you.This can be easily achieved using tabibitosan:
First of all, you need to identify 'groups', that each name in the list belongs
with sample_data as (select 1 id, 'SARA' name, to_date('01/01/2006', 'dd/mm/yyyy') start_date from dual union all select 2 id, 'SARA' name, to_date('03/02/2006', 'dd/mm/yyyy') start_date from dual union all select 3 id, 'LAMBDA' name, to_date('21/03/2006', 'dd/mm/yyyy') start_date from dual union all select 4 id, 'SARA' name, to_date('13/04/2006', 'dd/mm/yyyy') start_date from dual union all select 5 id, 'LAMBDA' name, to_date('01/01/2007', 'dd/mm/yyyy') start_date from dual union all select 6 id, 'LAMBDA' name, to_date('01/09/2007', 'dd/mm/yyyy') start_date from dual) select id, name, start_date, lead(start_date, 1, to_date('31/12/9999', 'dd/mm/yyyy')) over (order by start_date) next_start_date, row_number() over (order by start_date) - row_number() over (partition by name order by start_date) grp from sample_data; ID NAME START_DATE NEXT_START_DATE GRP ---------- ------ ---------- --------------- ---------- 1 SARA 01/01/2006 03/02/2006 0 2 SARA 03/02/2006 21/03/2006 0 3 LAMBDA 21/03/2006 13/04/2006 2 4 SARA 13/04/2006 01/01/2007 1 5 LAMBDA 01/01/2007 01/09/2007 3 6 LAMBDA 01/09/2007 31/12/9999 3You can see the group number is generated by comparing the rownumber overall of all lines (in order) with the rownumber of the rowset by name (in the same order) - when there is a gap because another name appears between the two, the group number changes.
Once you have identified the number of group for each set of rows, it is easy to find the min / max values in this group:
with sample_data as (select 1 id, 'SARA' name, to_date('01/01/2006', 'dd/mm/yyyy') start_date from dual union all select 2 id, 'SARA' name, to_date('03/02/2006', 'dd/mm/yyyy') start_date from dual union all select 3 id, 'LAMBDA' name, to_date('21/03/2006', 'dd/mm/yyyy') start_date from dual union all select 4 id, 'SARA' name, to_date('13/04/2006', 'dd/mm/yyyy') start_date from dual union all select 5 id, 'LAMBDA' name, to_date('01/01/2007', 'dd/mm/yyyy') start_date from dual union all select 6 id, 'LAMBDA' name, to_date('01/09/2007', 'dd/mm/yyyy') start_date from dual), tabibitosan as (select id, name, start_date, lead(start_date, 1, to_date('31/12/9999', 'dd/mm/yyyy')) over (order by start_date) next_start_date, row_number() over (order by start_date) - row_number() over (partition by name order by start_date) grp from sample_data) select name, min(start_date) start_date, max(next_start_date) stop_date from tabibitosan group by name, grp order by start_date; NAME START_DATE STOP_DATE ------ ---------- ---------- SARA 01/01/2006 21/03/2006 LAMBDA 21/03/2006 13/04/2006 SARA 13/04/2006 01/01/2007 LAMBDA 01/01/2007 31/12/9999If you want the date to appear as null max, you will need to use a cast or decode to change it - I'll leave that as an exercise for you to do! I'll also let you to find how to get the day before for the stop_date.
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confusion with the analytical functions
I created an example where I am right now with the help of analytical functions. However, I need the query below to return an additional column. I need to return the result from:-' factor_day_sales * max (sdus)'. Any ideas?
If the first column is located and must have the following results
777777, 5791, 10, 1.5, 15, 90, 135, 7050
the 1350 is the result, I don't know how to do. (some how to multiply factored_day_sales max (sdus) 15 470 = 7050
Thanks for lookingcreate table david_sales ( pro_id number(38), salesidx number (38,6), tim_id number(38)); truncate table david_sales create table david_compensations ( pro_id number(38), tim_id number(38), factor number(38,6)); insert into david_sales values (777777, 10.00, 5795); insert into david_sales values (777777,20.00, 5795); insert into david_sales values (777777, 30.00, 5794); insert into david_sales values (777777, 40.00, 5794); insert into david_sales values (777777, 100.00, 5793); insert into david_sales values (777777, 10.00, 5793); insert into david_sales values (777777,80.00, 5791); insert into david_sales values (777777, 10.00, 5791); insert into david_compensations values (777777, 5795, 1.5); insert into david_compensations values (777777, 5793, 2.0); insert into david_compensations values (777777, 5792, 1.0); insert into david_compensations values (777777, 5791, 1.5); SELECT s.pro_id sales_pro , c.pro_id comp_pro , s.tim_id sales_tim , c.tim_id comp_tim , s.salesidx day_sales , NVL(c.factor, 1) factor , s.salesidx * NVL(c.factor, 1) factored_day_sales , sum(s.salesidx ) over (partition by s.pro_id order by s.pro_id, s.tim_id) Sdus , sum(s.salesidx * NVL(c.factor, 1)) over (partition by s.pro_id order by s.pro_id, s.tim_id) sumMjCj FROM david_sales s , david_compensations c WHERE s.pro_id = c.pro_id(+) AND s.tim_id = c.tim_id(+) AND s.tim_id BETWEEN 5791 AND 5795Is that what you want?
SELECT s.pro_id sales_pro , c.pro_id comp_pro , s.tim_id sales_tim , c.tim_id comp_tim , s.salesidx day_sales , NVL(c.factor, 1) factor , s.salesidx * NVL(c.factor, 1) factored_day_sales , sum(s.salesidx ) over (partition by s.pro_id order by s.pro_id, s.tim_id) Sdus , sum(s.salesidx * NVL(c.factor, 1)) over (partition by s.pro_id order by s.pro_id, s.tim_id) sumMjCj , (s.salesidx * NVL(c.factor, 1) * sum(s.salesidx ) over (partition by s.pro_id order by s.pro_id, s.tim_id)) FROM david_sales s , david_compensations c WHERE s.pro_id = c.pro_id(+) AND s.tim_id = c.tim_id(+) AND s.tim_id BETWEEN 5791 AND 5795 SALES_PRO COMP_PRO SALES_TIM COMP_TIM DAY_SALES FACTOR FACTORED_DAY_SALES SDUS SUMMJCJ SUMMEDMULTI ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- 777777 777777 5791 5791 80 1.5 120 90 135 10800 777777 777777 5791 5791 10 1.5 15 90 135 1350I get the 1350
or did you mean:
SELECT s.pro_id sales_pro , c.pro_id comp_pro , s.tim_id sales_tim , c.tim_id comp_tim , s.salesidx day_sales , NVL(c.factor, 1) factor , s.salesidx * NVL(c.factor, 1) factored_day_sales , sum(s.salesidx ) over (partition by s.pro_id order by s.pro_id, s.tim_id) Sdus , sum(s.salesidx * NVL(c.factor, 1)) over (partition by s.pro_id order by s.pro_id, s.tim_id) sumMjCj , s.salesidx * NVL(c.factor, 1) * (sum(s.salesidx * NVL(c.factor, 1)) over (partition by s.pro_id order by s.pro_id, s.tim_id)) summedMulti FROM david_sales s , david_compensations c WHERE s.pro_id = c.pro_id(+) AND s.tim_id = c.tim_id(+) AND s.tim_id BETWEEN 5791 AND 5795 SALES_PRO COMP_PRO SALES_TIM COMP_TIM DAY_SALES FACTOR FACTORED_DAY_SALES SDUS SUMMJCJ SUMMEDMULTI 777777 777777 5795 5795 10 1.5 15 300 470 7050Note, in the second block, I changed it just to use sumMjCj instead of sDus which seems to correlate with what you wanted (15 * 470 = 7050) while sdus is 15 * 300 = 4500
Published by: tanging on December 11, 2009 06:17
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Using the analytical function.
Hello
I have this scenario.
We have two locations for a given item_id. Primary and in bulk.with t as ( select 21009 item_id,9 primary_available,450 max_qty,100 bulk_available,12122 bulk_locator_id from dual union all select 21009 item_id,9 primary_available,450 max_qty,2775 bulk_available,8704 bulk_locator_id from dual union all select 21009 item_id,9 primary_available,450 max_qty,524 bulk_available,15614 bulk_locator_id from dual union all select 21009 item_id,9 primary_available,450 max_qty,3300 bulk_available,15654 bulk_locator_id from dual) select t.* from t;
I'm trying to get a select statement out of this point of view, where I will be restock the primary AMOUNT of sites in bulk, BUT the smaller bulk first. Once she gets up, I shouldn't take more product.
There is an analytic function that would do this?
That's the max I could come up with.
So, in this scenario, I want to replen bulk_locator_id 100 ' 12122 'and ' 15614 bulk_locator_id 341'. That's all. ZERO of the other rentals (bulk_locator_id). If the question is not clear, please let me know.with t as ( select 21009 item_id,9 primary_available,450 max_qty,100 bulk_available,12122 bulk_locator_id from dual union all select 21009 item_id,9 primary_available,450 max_qty,2775 bulk_available,8704 bulk_locator_id from dual union all select 21009 item_id,9 primary_available,450 max_qty,524 bulk_available,15614 bulk_locator_id from dual union all select 21009 item_id,9 primary_available,450 max_qty,3300 bulk_available,15654 bulk_locator_id from dual) select t.*, max_qty - (primary_available + SUM(bulk_available) over(PARTITION BY item_id ORDER BY bulk_available)) replen_this_much from t;
Published by: RPuttagunta on September 11, 2009 16:23Hello
Thanks for posting the sample data.
It would be useful that you also posted the output you want. Is this?. BULK_ REPLEN_ ITEM_ PRIMARY_ MAX_ BULK_ LOCATOR_ THIS_ ID AVAILABLE QTY AVAILABLE ID MUCH ----- ---------- ----- ---------- ---------- ---------- 21009 9 450 100 12122 100 21009 9 450 524 15614 341 21009 9 450 2775 8704 0 21009 9 450 3300 15654 0If so, you can get to this:
SELECT t.* , GREATEST ( 0 , LEAST ( TO_NUMBER (bulk_available) , TO_NUMBER (max_qty) - ( TO_NUMBER (primary_available) + NVL ( SUM (TO_NUMBER (bulk_available)) OVER ( PARTITION BY item_id ORDER BY TO_NUMBER (bulk_available) ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING ) , 0 ) ) ) ) AS replen_this_much FROM t ORDER BY item_id , TO_NUMBER (bulk_available) ;You should really store your numbers in NUMBER of columns.
You essentially posted all what you need analytical functions. The problem was just wrapping this analytical function (or something very close to it) and LESS and more GRAND, so that the replen_this_much column is always between 0 and TO_NUMBER (bulk_available).
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