The data return based on the length

How can we display data lines based on the length?

Published by: 863765 on July 9, 2011 17:51

863765 wrote:
display data based on the length as given

Select the table where length between merchantname? and?

SELECT MERCHANTNAME COMPANIES WHERE LENGTH (MERCHANTNAME) BETWEEN 5 AND 10

Tags: Database

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    1 disabled all triggers and ran ALTER statement to increase the length. It took hours and did not finish in a reasonable amount of time, even if no error, but it took more than 12 hours.

    2 tried DBMS_REDEFINITION package but it does not work with the standard version of Oracle 10 g.

    I think to try next

    I think same Optics:

    Say my name of the existing table is OLD_T1 where the length of column need to increase

    -Create a copy (with increased column length) table of OLD_T1, Say NEW_T1

    -Move data from in OLD_T1 to the new table NEW_T1

    -Lower OLD_T1 (or rename it to OLD_T1_TMP)

    -Rename NEW_T1 to OLD_T1

    -Create all indexes, triggers, constraints etc..

    I wish to confirm, if my approach is correct? Or someone has a better idea to do this?

    Please note: I know that the CHAR data type gives the problem but it is an old system and I don't have authority to change the design of database.

    Appreciate any comment/suggestion

    Thanks in advance

    > I mean, can any application break if it depends on fixed-length?

    Yes, because the code can be expected completed on the right areas.

  • Where conditional Clause based on the length of the field

    Hello people,
    I tried to search for this scenario in OTN and not been able to find any success so I will post the question here.

    I have two tables - with the detail records and the other being a table of codes. I need to join these two tables based on the code and the length of the code. Let me explain using examples.

    Scripts for creating the table and inserts
    create table ILLNESS_CODES(illness_code varchar2(4), illness_description varchar2(100));
    create table PATIENT_TB(patient_id varchar2(4), primary_cause varchar2(4));
    
    insert into illness_codes values('B10', 'Flu');
    insert into illness_codes values('B30', 'Hepatitis');
    insert into illness_codes values('B301', 'Hepatitis A');
    insert into illness_codes values('B302', 'Hepatitis B');
    insert into illness_codes values('B303', 'Hepatitis C');
    
    insert into patient_tb values ('1001', 'B101');
    insert into patient_tb values ('1002', 'B102');
    insert into patient_tb values ('1003', 'B30');
    insert into patient_tb values ('1004', 'B301');
    insert into patient_tb values ('1005', 'B302');
    insert into patient_tb values ('1006', 'B302');
    insert into patient_tb values ('1007', 'B303');
    insert into patient_tb values ('1008', 'B30');
    As you can see that patients * 1001 * and * 1002 * have no codes in the Master table. In this case, I want only the first 3 characters of the ILLNESS_CODES table.
    However, for B30, it has a Code and the same for B301, B302 B303 where I would meet the description based on the exact code.

    Example of output
    Patient ID   Illness Description
    =====================================
    1001         Flu
    1002         Flu
    1003         Hepatitis
    1004         Hepatitis A
    1005         Hepatitis B
    1006         Hepatitis B
    1007         Hepatitis C
    1008         Hepatitis
    Thanks in advance!
    SELECT p.*,
           NVL ( (SELECT illness_description
                    FROM ILLNESS_CODES I
                   WHERE i.illness_code = p.primary_cause),
                (SELECT illness_description
                   FROM ILLNESS_CODES I
                  WHERE i.illness_code = SUBSTR (p.primary_cause, 1, 3)))
      FROM PATIENT_TB p;
    
  • Insert data according to the length of column in table

    Hello

    If the length of the characters is more than one defined causes error. It's very embarrassing especially when get data dynamically

    and our query does not insert information that we expect.

    While trying to find the solution an idea came to my mind that, before insertion, so we check that the next data is greater than the specified length

    Take only the amount of characters that can be inserted and ignore the rest.

    I thought that the query as follows but failed.
    SQL> insert into cvDetails(cv_id,objectives) values(9687,substr("Hello",1,3950));
    insert into cvDetails(cv_id,objectives) values(9687,substr("Hello",1,3950))
                                                               *
    ERROR at line 1:
    ORA-00984: column not allowed here
    Is it possible to insert data up to the amount this column length defined by ignoring the obsolete characters and if the data

    length is less defined length of column, and then insert it as it is?

    Thank you in anticipation

    Hello

    Do not use double quotes as the string delimiters:

    SQL> create table test_nsa (str varchar2(10));
    
    Table created.
    
    Elapsed: 00:00:00.88
    SQL> insert into test_nsa values (substr('aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa',1,10));
    
    1 row created.
    
    Elapsed: 00:00:00.08
    
  • County of SQL based on the length

    SELECT LENGTH(site_id),
      COUNT(site_id)
    FROM site_data
    GROUP BY LENGTH(site_id)
    Results:
    1 12
    1 of 3
    6-11209
    7 17519
    * (null) 0 *.

    I wrote the query above to get the number of a column based on its length. But the problem is that the table has a lot of values null, which is not showing in the results.

    Is there something fundamentally wrong with the query? Please help me.

    Thank you.

    Guru wrote:

    SELECT LENGTH(site_id),
    COUNT(site_id)
    FROM site_data
    GROUP BY LENGTH(site_id)
    

    Results:
    1 12
    1 of 3
    6-11209
    7 17519
    * (null) 0 *.

    I wrote the query above to get the number of a column based on its length. But the problem is that the table has a lot of values null, which is not showing in the results.

    Is there something fundamentally wrong with the query? Please help me.

    Thank you.

    COUNT as defined ONLY charges the non-null instances.

    If you want a count, you want to use COUNT (*) in place of COUNT (site_id);

  • createTextField setting width based on the length of the string

    I wonder if there is a way to easily calculate how wide to make a textfield you create dynamically with createTextField based on the length of a string that is passed as an argument. In other words, if you know you are going to use the font size, is there a way to know how many pixels you need? Thanks in advance to anyone who can offer assistance.

    have you looked into "TextField.autoSize?

    SPGAnne wrote:
    > I wonder if there is a way to easily calculate how wide to make a textfield
    > you create dynamically with createTextField based on the length of a
    > string passed as an argument. In other words, if you know the police
    > size you plan to use, is there a way to know how many pixels you need?
    > Thanks in advance to anyone who can offer assistance.
    >

  • Result of the query restriction based on the length of the field

    Hello

    I want to restrict the output of the query according to the length of a field (in fact, the length of the contents of a field).
    Ex: only those records where the length of the data in a field is more than 20 characters.

    Is it possible, can you give some advice on this subject...

    Thank you

    Hello

    Example:

    Connected to Oracle Database 10g Express Edition Release 10.2.0.1.0
    Connected as hr
    
    SQL> select to_date('16/8/2009 11:21:46','DD/MM/YYYY HH24:MI:SS') from dual;
    
    TO_DATE('16/8/200911:21:46','D
    ------------------------------
    16/08/2009 11:21:46
    
    SQL> select first_name from employees where length(first_name) > 20;
    
    FIRST_NAME
    --------------------
    
    SQL> select first_name from employees where length(first_name) > 10;
    
    FIRST_NAME
    --------------------
    Christopher
    Jose Manuel
    
    SQL> 
    

    Kind regards

  • divide characters based on the length

    How can I split string such as 'HELLO' => 'H' 'E' 'L' "L", "O" using the length

    OATTelecom wrote:

    How can I split string such as 'HELLO' => 'H' 'E' 'L' "L", "O" using the length

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  • Error ORA-12899, even you the length of the data is correct.

    Dear all,

    I'm getting ORA-12899 problem: value too large for column 'TEST '. "'"' STUDENT'."" NAME"(size: 94, maximum: 79).
    Valer'evne you the length of the column 'Name' is less than 79.

    Infact I am getting the value of 'Name' of the other database, processing in Java and you try to insert the value in Oracle database with the help of hibernation, the length of the 'name' is located only 60 I checked in Java, before inserting this value.

    Even after having inserted the length is only 60 too, I see Oracle. So why Oracle throws this error at the time of the insertion of the value of the "name"?

    Any body have an idea on the question, please help.

    Thanking you all.

    AL32UTF8 is a multibyte character set: each character can take up to 4 bytes. So, you have to modify the table definition for this with something like (assuming that the maximum number of bytes would be 320):

    alter table student modify (name varchar2(320));
    
  • Unit test: calculation of the length of the different columns in recordsets provided and received led to false a test failure

    Dear team of SQL Developer,

    It seems that the calculation of the length of the column in the expected and received recordsets behaves differently in some cases (when stored proc variables are used in the generation of the REF CURSOR, despite the explicit definition of the type of record): the length of the header and the length of the value in the set of records received are truncated to arbitrary length based on the returned value which leads to a false failure of a unit test. I.e. registries are the same in both sets of records, but the test run fails to the comparison of the recordsets because of different length. Please see the screenshot below:

    Expected_and_Received_RecordSets.jpg

    Here's the test case if you need to reproduce the problem/bug in your environment:

    1. use the default schema of HR of the Oracle examples package that comes with an 11 g database.

    2. change the HR. Table EMPLOYEES with the addition of a new column VARCHAR2 (4000) LONG_LAST_NAME:

    ALTER TABLE HR. EMPLOYEES

    ADD (LONG_LAST_NAME VARCHAR2 (4000));

    Update hr.employees set long_last_name = last_name;

    commit;

    3. create a PKG_TEST2 package with the source code below in the HR schema:

    ----------------------------------------------------------------------------------------------------------------------

    create or replace PACKAGE PKG_TEST2 AS

    TYPE EmployeeInfoRec IS RECORD

    (

    long_last_name employees.long_last_name%TYPE,

    first name employees.first_name%TYPE,

    E-mail employees.email%TYPE

    );

    TYPE EmployeeInfoRecCur IS REF CURSOR RETURN EmployeeInfoRec;

    FUNCTION getEmployeeInfo (p_Emp_Id employees.employee_id%TYPE)

    RETURN EmployeeInfoRecCur;

    END PKG_TEST2;

    ----------------------------------------------------------------------------------------------------------------------

    CREATE OR REPLACE PACKAGE BODY PKG_TEST2 AS

    FUNCTION getEmployeeInfo (p_Emp_Id employees.employee_id%TYPE)

    RETURN EmployeeInfoRecCur AS

    v_EmployeeInfoRecCur EmployeeInfoRecCur;

    v_LongLastName varchar2 (4000);

    BEGIN

    Select long_last_name from v_LongLastName

    employees

    where employee_id = p_Emp_Id;

    --

    OPEN FOR V_EmployeeInfoRecCur

    V_LongLastName SELECT long_last_name,

    first name,

    E-mail

    This_is_very_long_table_alias employees

    WHERE employee_id = p_Emp_Id

    order by 1 CSA;

    --

    RETURN v_EmployeeInfoRecCur;

    EXCEPTION

    WHILE OTHERS THEN

    LIFT;

    END getEmployeeInfo;

    END PKG_TEST2;


    ----------------------------------------------------------------------------------------------------------------------

    4. create a unit test for the PKG_TEST2.getEmployeeInfo stored procedure: (click the command create Test, select the stored procedure, click Ok for the pop-up message, click Next, click Finish).

    5. update the default value of dynamic query of value with the one below and save/post changes.

    Select the cursor)

    SELECT long_last_name,

    first name,

    E-mail

    Employees

    WHERE employee_id = idqry.employee_id

    order of the 1 CAD

    ) RETURNS $,.

    idqry.employee_id as P_EMP_ID

    from (select employee_id

    employees

    where rownum < = 5) idqry

    6. run the unit test newly created in the debug mode to display the shot.

    Thus, the record type 'EmployeeInfoRec' in the package clearly defines the LONG_LAST_NAME as VARCHAR2 (4000) through reference for the data type of column in the referenced table.

    But for some reason, the SQL Developer does not calculate correctly its length in the recordset "Receipts" If a variable is used (could be one as variable simple varchar2 in this reproducible test or complex variable of type of the object).

    Any ideas on that? Looks like another bug...

    Thank you

    Val

    The bug has been reproduced by the SRB and documented within the system of Support of Oracle SQL Developer team to pick it up:

    Bug 19943948 - TEST UNIT RETURNS EXPECTED ERROR: [LONG_LAST_NAME

    Hope the bug name can later be changed to something more descriptive, but it is not really... my only concern is the speed at which the known bugs would be fixed...

    Thank you

    Val

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