The first mention of an inner join of return?

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• Oracle: Inner join syntax

  Hello
  I am confused with Inner Join syntax.
  According to the defination of Inner Join, it is said that
  Inner joins return all rows in multiple tables satisfied the join condition.
  
  By the way by examples of inner join in web, join Inner is written in these syntaxes as indicated:
  
  First syntax:
  
  SELECT Person.LastName, Person.FirstName, person Sales.OrderNo INNER JOIN sales on Person.P_Id = Sales.P_Id
  
  Second syntax:
  
  SELECT suppliers.supplier_id, suppliers.supplier_name, orders.order_date
  FROM the suppliers orders
  WHERE suppliers.supplier_id = orders.supplier_id;
  
  Please tell me if the keyword Inner Join its use is mandatory or not?
  
  Thank you for reading.

  user672373773 wrote:
  First of all, thanks Anurag to your prompt response.

  I have a request here, please tell me why oracle has provided two syntax? This is the ANSI and non-ANSI syntax

  I know, it's the Oracle had a format no ANSI to join since its initial versions. In later versions, oracle decided to except ANSI format too since Oracle want to support the ansi format in almost everything.

  So since he was using the ansi non format, it can't support/stop using only for backward compatibility and also it as having the users to use the ansi format, it is both.

  Concerning
  Anurag

• difference between Inner Join join natural r

  Experts,

  I'm trying to understand the difference between Natural Join and inner join.

  Inner join: the following query provides 106 lines based on two tables

  SQL > SELECT EMPLOYEE_ID EID, last NAME, DEPT_NAME DEPARTMENT_NAME

  2 EMPLOYEES A, B MINISTRIES

  3. WHERE A.DEPARTMENT_ID = B.DEPARTMENT_ID

  4 order employee_id;

  Natural Join: This is the combination or combined result of all the columns in both tables.

  When I run the Sub statement, it combines employees and the table from department of a HR schema and provides only 32 ranks

  SQL > select employe_id, first_name, department_name

  2 departments of NATURAL JOIN employees;

  
  

  EMPLOYEE_ID NAME DEPARTMENT_NAME

  ----------- -------------------- -------------------

  Neena 101 Executive

  Lex 102 Executive

  104 Bruce IT

  David 105 HE

  question: why the NATURAL JOIN query omit the employee_id 103 and on what basis it omit a few other employee_id

  Thanks in advance

  Hello

  The main difference is that INNER JOIN is used in real life; NATURAL JOIN is used only in textbooks.

  More rigorously, FRANCKLIN JOIN is an inner join, involving all the columns that have the same name.  The hr.departments and hr.employees have 2 columns with the same name: department_id and manager_id, so

  OF hr.departments d

  NATURAL JOIN e hr.employees

  is equivalent to

  OF hr.departments d

  INNER JOIN hr.employees e ON e.department_id = d.deparment_id

  AND e.manager_id = d.manager_id

  or, using the old join syntax

  OF hr.departments d

  e hr.employees

  WHERE e.department_id = d.deparment_id

  AND e.manager_id = d.manager_id

• OUTER JOIN query returns the results of JOIN IN-HOUSE 11.2.0.1.0

  I'm data transfer in 11.2.01.0 (Windows XP 32-bit) and I wanted to compare the sizes of table with the same Table name in two different patterns, ML and SILENT, with a FULL OUTER JOIN (to account for all the tables and NULL values in a diagram).
  
  The scheme of ML has 176 tables: schema TUT a 133 tables. The use of a standard INNER JOIN gives 131 paintings.
  
  I get precisely the results with a FULL OUTER JOIN I get with an INTERNAL JOIN (not the same NULL values so I know they exist).
  
  This happens in SQL-Plus, SQL_Developer and using Oracle Wire pilot of Data_Direct.
  
  Here is the code:
  
  Login: SYS as SYSDBA or SYSTEM (same results for either)
  
  SELECT M.TABLE_NAME, M.NUM_ROWS, T.TABLE_NAME, T.NUM_ROWS
  OF SYS. ALL_TABLES M FULL OUTER JOIN SYS. ALL_TABLES T ON M.TABLE_NAME = T.TABLE_NAME
  WHERE
  M.OWNER = 'ML' AND
  T.OWNER = 'TUT';
  
  Produce the same results with LEFT OUTER joins and RIGHT OUTER joins in ASI and Oracle (+) syntax.
  
  Any thoughts?

  Hello

  If you read what I posted, forget it. MScallion (below) gave the correct answerr.

  If conditions such as

  owner   = 'ML'
  

  in the WHERE clause, and then they will reject the rows of the result set formed by the join condition.

  The inner join returns only 131 lines where the two 'paintings' have the same table_names.
  The outer joins return multiple lines (133, 176 or 178) before the place WHERE the provision is applied , but the WHERE clause eliminates all lines except the 131 found by the inner join.

  Published by: Frank Kulash, July 10, 2010 14:23

• Calculation for cutting the first part of the string in the Manager list item values

  Hello

  Please help me with a calculation after submit pl/sql function process for cutting the first part of the string (CQ.) within the values of list manager. For example the list manager support contains values such as

  CQ... SAMPLE1... TEST1

  CQ... SAMPLE2... TEST2

  CQ... SAMPLE1... TEST2

  The calculation process should cut the first part(CQ..) and must return to the list of values of Manager as

  SAMPLE1... TEST1

  SAMPLE2... TEST2

  SAMPLE1... TEST2

  Oracle APEX 4.0.2 is the version and Oracle 10 g r2 is the database.

  Please help me with possible approaches in the development of the service. Thanks in advance.

  Thank you

  Orton

  orton607 wrote:

  But when I insert/update Manager list item values I don't want the first part of the string in the database.

  I still don't understand why you can't change the LOV or create a new...

  The LOV should be:

  SELECT original_value  AS HUMAN_SEES_THIS_VALUE
      ,LTRIM (SUBSTR ( original_value, INSTR (original_value, '..') + 2))
        AS DATABASE_GETS_THIS_VALUE
  FROM (
    -- place original SQL for LOV here
  )
  

• Help of query SQL - inner joins and the separate results

  Hello
  
  ASP VB, SQL Server
  
  I have a structure of data base with 3 tables - users, albums and photos. each user has a identifier unique, each record has a unique albumid and also contains a column with the user name. each record in the photo has a unique id so that store the user name and the album in which the image belongs.
  
  I'm writing a query that returns a list of the albums for a particular user (based on a user name query string) and who will also bring back the id of the first record in the table for each of these albums photo.
  
  the closest I get is to run a query to select albumid albums where userid = varuserid with a join internal on the pictures table to remove the photo ID - problem I then it comes out all the photos from the photos table where userid = varuserid, so when I do a repeat region to display a list of albums for a certain user It produces a list of all the photos where userid = varuserid
  
  I really want to return just a list of ID album based on the username variable, but also to return the first record in the table of photos for each of these albumids
  
  I tried different combinations of inner joins, select distinct etc but no joy.
  
  any suggestion would be appreciated as am floundering here...
  
  
  
  
  

  First, you must define 'first' with regard to the photos. Is there a
  timestamp? They are numbered inside the album? Do you really care who is
  "first", or do you want simply a shot? You also neglected to indicate if they are
  empty photo albums have been allowed. I assumed that the empty albums are not
  allowed.

  Whatever you decide, the answer will be similar.
  SQL Server tends to get better results with joins with subqueries. You will have
  See such a written request more often with subqueries, and there isn't
  nothing wrong with that, but I'll use a join on a derived table. I have
  have not all column names (hint, hint), so I made them, but the
  Comments should help out you.

  SELECT A.Title, P.PhotoID, P.Caption, A.AlbumID, P.ImagePath
  FROM dbo. A albums
  -build a table derived, consisting of photo ID lowest for each
  album.
  INNER JOIN (SELECT AlbumID, MIN (PhotoID) AS FirstPhoto FROM dbo. Photos
  AlbumID GROUP) AS PM WE A.AlbumID = PM. AlbumID
  -details of the photo for the photo shown in the table above
  INNER JOIN dbo. Photos P on A.AlbumID = P.AlbumID AND
  H. FirstPhoto = P.PhotoID
  User A.UserID ='some WHERE '

  "tedstar" wrote in message
  News:ee4pfn$de$1@forums. Macromedia.com...
  > I am writing a query that returns a list of the albums for a
  > particular user (based on a user name query string) and also bring
  > return
  > the id of the first record in the table for each of these albums photo.

• 'My card' when contact is not me, and it won't let me change it or delete the info. for the person mentioned (which is having the same first name as I do). Any ideas?

  'My card' when contact is not me, and it won't let me change it or delete the info. for the person mentioned (which is having the same first name as I do). Any ideas?

  iPhone OS 9.2 6.

  I already tried to delete information about the person identified as "my card". Because the phone think it is 'my card' delete the contact and/or modify the information. does not work.

  Create a new contact with your correct information, who like 'My card' to:

  Settings > Mail, Contacts, calendars > Contacts > my info

• Computers Dell laptops E5520, joined to the domain with the applications installed suddenly forget everything and goes back to the first bootup users

  I have a Dell laptops 5520 during the first boot, I created an Admin account and set the timezone, etc.  Then I joined laptops to our AD domain, software installed, such as Microsoft Office 2010 and Adobe.  Laptops have worked for a few weeks and now containing several profiles of my domain users.  All of a sudden, some laptops from start-up to the original Admin Login (the first user created).  When I connect, the NetBIOS shows is more that the laptop is part of a domain, and none of the applications that are installed are listed in all programs more (programs and profiles of school boards, however, still exist on the hard disk).  I have system restore disabled by GPO, and I limit the applications of the Panel as well.  I contacted Dell and they have never heard of this issue.  If I join the laptop to the field, he finds the original computer account but this does not all installed software and profiles will reappear.  Here is Windows 7 Professional on a Windows 2008 domain.  Any ideas?

  Hello

  The Microsoft Answers community focuses on the context of use. Please reach out to the business community of COMPUTING in the TechNet forum below:

  http://social.technet.Microsoft.com/forums/en/category/w7itpro/

• Hello, a few months ago, I joined a CC + adobe stock subscription. I downloaded my first 10 images of the first month and paid the other. The problem is that since the second month, I have not my 10 free photos more... why? Thanks to you all

  Hello, a few months ago, I joined a CC + adobe stock subscription. I downloaded my first 10 images of the first month and paid the other. The problem is that since the second month, I have not my 10 free photos more... why? Thanks to you all

  Hello

  Sorry - I've added the image apply to your account.

  Kind regards

  Bev

• Urgent help please.  Inner join caused the error ora-00933

  I ran it, works great:
  SELECT DIFFERENT EXP. EXP_ID,
  EXP. DATU_EXP_WIRE_CENTER_CLLI,
  EXP. DATU_EXP_IP,
  EXP. DATU_EXP_CLLI,
  EXP. DATU_EXP_PORT,
  EXP. DATU_EXP_NAME,
  EXP. DATU_EXP_CITY,
  EXP. DATU_EXP_STATE,
  EXP. DATU_EXP_SW_VERSION,
  DECODE (LAST_ALARM. LAST_ALARM_DATE, NULL, TO_CHAR (SYSDATE, ' YYYY/MM/DD HH24:MI:SS'),
  TO_CHAR (LAST_ALARM. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS STATUS_DATE,
  DECODE (LAST_ALARM. ALARM_NAME, NULL, "disconnected", LAST_ALARM. ALARM_NAME) AS DATU_STATUS,
  DECODE (LAST_ALARM. ALARM_CLASS, NULL, 'OTHER', LAST_ALARM. ALARM_CLASS) AS IS_ERROR_STATUS,
  
  DECODE (LAST_RESOURCE. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_RESOURCE. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS RESOURCE_STATUS_DATE,
  DECODE (LAST_RESOURCE. RESOURCE_CODE_NAME, NULL, ", LAST_RESOURCE. RESOURCE_CODE_NAME) AS RESOURCE_STATUS,
  DECODE (LAST_RESOURCE. RESOURCE_CODE_CLASS, NULL, ", LAST_RESOURCE. RESOURCE_CODE_CLASS) AS IS_RESOURCE_ERROR_STATUS,
  DECODE (LAST_OPER. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_OPER. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS OPER_STATUS_DATE,
  DECODE (LAST_OPER. OPER_CODE_NAME, NULL, ", LAST_OPER. OPER_CODE_NAME) AS OPER_STATUS,
  DECODE (LAST_OPER. OPER_CODE_CLASS, NULL, ", LAST_OPER. OPER_CODE_CLASS) AS IS_OPER_ERROR_STATUS,
  
  EXP BEGIN_MAINT_WINDOW, RTU. RTU_NAME
  OF TT_DATU_EXP_UNIT_INFO EXP
  left outer join
  (SELECT distinct alarmed_datus. EXP_ID, c.ALARM_NAME, c.ALARM_TYPE, c.ALARM_CLASS and alarmed_datus. LAST_ALARM_DATE
  Of alarmed_datus (SELECT EXP_ID, MAX (ALARM_TIME) AS LAST_ALARM_DATE FROM TT_DATU_EXP_ALARM_INFO GROUP BY EXP_ID)
  inner join TT_DATU_EXP_ALARM_INFO b on b.EXP_ID = alarmed_datus. EXP_ID AND b.ALARM_TIME = alarmed_datus. LAST_ALARM_DATE
  inner join TT_DATU_EXP_ALARM_TYPES c on b.ALARM_TYPE = c.ALARM_TYPE
  ) LAST_ALARM on EXP.. EXP_ID = LAST_ALARM. EXP_ID
  left outer join
  (SELECT distinct a.EXP_ID, c.RESOURCE_CODE_NAME, c.RESOURCE_CODE_TYPE, c.RESOURCE_CODE_CLASS, a.LAST_ALARM_DATE
  FROM (SELECT EXP_ID, MAX (RESOURCE_CODE_TIME) AS LAST_ALARM_DATE
  OF TT_DATU_EXP_RESOURCE_CODE_INFO GROUP BY EXP_ID) a
  inner join TT_DATU_EXP_RESOURCE_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.RESOURCE_CODE_TIME = a.LAST_ALARM_DATE
  inner join TT_DATU_EXP_RESOURCECODE_TYPES c on b.RESOURCE_CODE_TYPE = c.RESOURCE_CODE_TYPE
  ) LAST_RESOURCE on EXP.. EXP_ID = LAST_RESOURCE. EXP_ID
  left outer join
  (SELECT distinct a.EXP_ID, c.OPER_CODE_NAME, c.OPER_CODE_TYPE, c.OPER_CODE_CLASS, a.LAST_ALARM_DATE
  FROM (SELECT EXP_ID, MAX (OPER_CODE_TIME) AS LAST_ALARM_DATE
  OF TT_DATU_EXP_OPER_CODE_INFO GROUP BY EXP_ID) a
  inner join TT_DATU_EXP_OPER_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.OPER_CODE_TIME = a.LAST_ALARM_DATE
  inner join TT_DATU_EXP_OPER_CODE_TYPES c on b.OPER_CODE_TYPE = c.OPER_CODE_TYPE) LAST_OPER on EXP.. EXP_ID = LAST_OPER. EXP_ID
  inner join TT_DATU_LRN_MAP on exp. EXP_ID = NAB NAB. EXP_ID AND TRIM (NAB. LRN) AS p_LRN
  inner join TT_RTU_TYPES on exp. RTU_TYPE_ID = RTU RTU. RTU_TYPE_ID
  WHERE THERE IS NOT (SOME SATELLITE_EXP_ID OF TT_HOST_SATELLITE WHERE EXP. EXP_ID = SATELLITE_EXP_ID)
  AND EXP.IS_PRIMARY_ADDRESS LIKE p_isPrimary;
  ON THE OTHER
  OPEN FOR V_cursor
  SELECT EXP. EXP_ID,
  EXP. DATU_EXP_WIRE_CENTER_CLLI,
  EXP. DATU_EXP_IP,
  EXP. DATU_EXP_CLLI,
  EXP. DATU_EXP_PORT,
  EXP. DATU_EXP_NAME,
  EXP. DATU_EXP_CITY,
  EXP. DATU_EXP_STATE,
  EXP. DATU_EXP_SW_VERSION,
  DECODE (LAST_ALARM. LAST_ALARM_DATE, NULL, TO_CHAR (SYSDATE, ' YYYY/MM/DD HH24:MI:SS'), TO_CHAR (LAST_ALARM. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS STATUS_DATE,
  DECODE (LAST_ALARM. ALARM_NAME, NULL, "disconnected", LAST_ALARM. ALARM_NAME) AS DATU_STATUS,
  DECODE (LAST_ALARM. ALARM_CLASS, NULL, 'OTHER', LAST_ALARM. ALARM_CLASS) AS IS_ERROR_STATUS,
  
  DECODE (LAST_RESOURCE. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_RESOURCE. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS RESOURCE_STATUS_DATE,
  DECODE (LAST_RESOURCE. RESOURCE_CODE_NAME, NULL, ", LAST_RESOURCE. RESOURCE_CODE_NAME) AS RESOURCE_STATUS,
  DECODE (LAST_RESOURCE. RESOURCE_CODE_CLASS, NULL, ", LAST_RESOURCE. RESOURCE_CODE_CLASS) AS IS_RESOURCE_ERROR_STATUS,
  DECODE (LAST_OPER. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_OPER. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS OPER_STATUS_DATE,
  DECODE (LAST_OPER. OPER_CODE_NAME, NULL, ", LAST_OPER. OPER_CODE_NAME) AS OPER_STATUS,
  DECODE (LAST_OPER. OPER_CODE_CLASS, NULL, ", LAST_OPER. OPER_CODE_CLASS) AS IS_OPER_ERROR_STATUS,
  
  EXP BEGIN_MAINT_WINDOW, RTU. RTU_NAME
  OF TT_DATU_EXP_UNIT_INFO EXP
  (in left outer join
  SELECT distinct alarmed_datus. EXP_ID, c.ALARM_NAME, c.ALARM_TYPE, c.ALARM_CLASS and alarmed_datus. LAST_ALARM_DATE
  Of alarmed_datus (SELECT EXP_ID, MAX (ALARM_TIME) AS LAST_ALARM_DATE FROM TT_DATU_EXP_ALARM_INFO GROUP BY EXP_ID)
  inner join TT_DATU_EXP_ALARM_INFO b on b.EXP_ID = alarmed_datus. EXP_ID AND b.ALARM_TIME = alarmed_datus. LAST_ALARM_DATE
  inner join TT_DATU_EXP_ALARM_TYPES c on b.ALARM_TYPE = c.ALARM_TYPE)
  LAST_ALARM on EXP.. EXP_ID = LAST_ALARM. EXP_ID
  left outer join
  (SELECT distinct a.EXP_ID, c.RESOURCE_CODE_NAME, c.RESOURCE_CODE_TYPE, c.RESOURCE_CODE_CLASS, a.LAST_ALARM_DATE
  FROM (SELECT EXP_ID, MAX (RESOURCE_CODE_TIME) AS LAST_ALARM_DATE
  OF TT_DATU_EXP_RESOURCE_CODE_INFO GROUP BY EXP_ID) a
  inner join TT_DATU_EXP_RESOURCE_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.RESOURCE_CODE_TIME = a.LAST_ALARM_DATE
  inner join TT_DATU_EXP_RESOURCECODE_TYPES c on b.RESOURCE_CODE_TYPE = c.RESOURCE_CODE_TYPE) LAST_RESOURCE on EXP.. EXP_ID = LAST_RESOURCE. EXP_ID
  left outer join
  (SELECT distinct a.EXP_ID, c.OPER_CODE_NAME, c.OPER_CODE_TYPE, c.OPER_CODE_CLASS, a.LAST_ALARM_DATE
  FROM (SELECT EXP_ID, MAX (OPER_CODE_TIME) AS LAST_ALARM_DATE
  OF TT_DATU_EXP_OPER_CODE_INFO GROUP BY EXP_ID) a
  inner join TT_DATU_EXP_OPER_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.OPER_CODE_TIME = a.LAST_ALARM_DATE
  inner join TT_DATU_EXP_OPER_CODE_TYPES c on b.OPER_CODE_TYPE = c.OPER_CODE_TYPE
  ) LAST_OPER on EXP.. EXP_ID = LAST_OPER. EXP_ID ORDER BY EXP. DATU_EXP_CLLI
  inner join TT_RTU_TYPES on exp. RTU_TYPE_ID = RTU RTU. RTU_TYPE_ID
  WHERE THERE is NOT (SOME SATELLITE_EXP_ID OF TT_HOST_SATELLITE WHERE EXP.. EXP_ID = SATELLITE_EXP_ID) AND EXP.IS_PRIMARY_ADDRESS love
  p_isPrimary;
  
  
  However this one:
  
  SELECT EXP. EXP_ID,
  EXP. DATU_EXP_WIRE_CENTER_CLLI,
  EXP. DATU_EXP_IP,
  EXP. DATU_EXP_CLLI,
  EXP. DATU_EXP_PORT,
  EXP. DATU_EXP_NAME,
  EXP. DATU_EXP_CITY,
  EXP. DATU_EXP_STATE,
  EXP. DATU_EXP_SW_VERSION,
  DECODE (LAST_ALARM. LAST_ALARM_DATE, NULL, TO_CHAR (SYSDATE, ' YYYY/MM/DD HH24:MI:SS'),
  TO_CHAR (LAST_ALARM. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS STATUS_DATE,
  DECODE (LAST_ALARM. ALARM_NAME, NULL, "disconnected", LAST_ALARM. ALARM_NAME) AS DATU_STATUS,
  DECODE (LAST_ALARM. ALARM_CLASS, NULL, 'OTHER', LAST_ALARM. ALARM_CLASS) AS IS_ERROR_STATUS,
  
  
  DECODE (LAST_RESOURCE. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_RESOURCE. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS RESOURCE_STATUS_DATE,
  DECODE (LAST_RESOURCE. RESOURCE_CODE_NAME, NULL, ", LAST_RESOURCE. RESOURCE_CODE_NAME) AS RESOURCE_STATUS,
  DECODE (LAST_RESOURCE. RESOURCE_CODE_CLASS, NULL, ", LAST_RESOURCE. RESOURCE_CODE_CLASS) AS IS_RESOURCE_ERROR_STATUS,
  DECODE (LAST_OPER. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_OPER. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS OPER_STATUS_DATE,
  DECODE (LAST_OPER. OPER_CODE_NAME, NULL, ", LAST_OPER. OPER_CODE_NAME) AS OPER_STATUS,
  DECODE (LAST_OPER. OPER_CODE_CLASS, NULL, ", LAST_OPER. OPER_CODE_CLASS) AS IS_OPER_ERROR_STATUS,
  
  
  EXP BEGIN_MAINT_WINDOW, RTU. RTU_NAME
  OF TT_DATU_EXP_UNIT_INFO EXP
  left outer join
  (
  SELECT distinct alarmed_datus. EXP_ID, c.ALARM_NAME, c.ALARM_TYPE, c.ALARM_CLASS and alarmed_datus. LAST_ALARM_DATE
  Of alarmed_datus (SELECT EXP_ID, MAX (ALARM_TIME) AS LAST_ALARM_DATE FROM TT_DATU_EXP_ALARM_INFO GROUP BY EXP_ID)
  inner join TT_DATU_EXP_ALARM_INFO b on b.EXP_ID = alarmed_datus. EXP_ID AND b.ALARM_TIME = alarmed_datus. LAST_ALARM_DATE
  inner join TT_DATU_EXP_ALARM_TYPES c on b.ALARM_TYPE = c.ALARM_TYPE) LAST_ALARM on EXP.. EXP_ID = LAST_ALARM. EXP_ID
  
  left outer join
  (SELECT distinct a.EXP_ID, c.RESOURCE_CODE_NAME, c.RESOURCE_CODE_TYPE, c.RESOURCE_CODE_CLASS, a.LAST_ALARM_DATE
  FROM (SELECT EXP_ID, MAX (RESOURCE_CODE_TIME) AS LAST_ALARM_DATE
  OF TT_DATU_EXP_RESOURCE_CODE_INFO GROUP BY EXP_ID) a
  inner join TT_DATU_EXP_RESOURCE_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.RESOURCE_CODE_TIME = a.LAST_ALARM_DATE
  inner join TT_DATU_EXP_RESOURCECODE_TYPES c on b.RESOURCE_CODE_TYPE = c.RESOURCE_CODE_TYPE) LAST_RESOURCE on EXP.. EXP_ID = LAST_RESOURCE. EXP_ID
  left outer join
  (SELECT distinct a.EXP_ID, c.OPER_CODE_NAME, c.OPER_CODE_TYPE, c.OPER_CODE_CLASS, a.LAST_ALARM_DATE
  FROM (SELECT EXP_ID, MAX (OPER_CODE_TIME) AS LAST_ALARM_DATE
  OF TT_DATU_EXP_OPER_CODE_INFO GROUP BY EXP_ID) a
  inner join TT_DATU_EXP_OPER_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.OPER_CODE_TIME = a.LAST_ALARM_DATE
  inner join TT_DATU_EXP_OPER_CODE_TYPES c on b.OPER_CODE_TYPE = c.OPER_CODE_TYPE
  ) LAST_OPER on EXP.. EXP_ID = LAST_OPER. EXP_ID ORDER BY EXP. DATU_EXP_CLLI
  inner join TT_RTU_TYPES on exp. RTU_TYPE_ID = RTU RTU. RTU_TYPE_ID
  WHERE the EXP.IS_PRIMARY_ADDRESS as p_isPrimary;
  
  It does not work kept send me errors:
  [ORA-00933: SQL not correctly completed command]
  
  
  Any guru can help? I need to have this resolved effect today.
  Thanks in advance.
  

• helps the inner join

  Hi all

  I am trying to learn something new, and I'm having a little difficulty.  I'm trying to learn more about inner joins.  I looked at countless books, tutorials, and all the rest have that I can find, but I can't seem to understand that.  Nothing I try works.

  I have related tables, and I try to get the data to display.  I have the database set up as follows:

  films (table name) has the movie_id, movie_name and movie_star_rating fields

  family_rating (table name) has star_id, star_name, and star_file_name fields

  in PHPMyAdmin, I had movies.movie_star_rating internally associated with family_rating.star_id

  When I view the data, I'm pulling the table of movies, but instead of having a number, I would like to have displayed family_rating.star_name.  I have the following code to do this:

  $query="SELECT * FROM movies
    INNER JOIN family_rating ON movies.movie_star_rating=family_rating.star_id 
    WHERE movies.movie_name_series='$search'";
  
  $result= mysql_query($query)or die (mysql_error());
  
  while($row=mysql_fetch_array($result)){
  
  // Display the data 
  
   echo $row['movies.movie_name'];
   echo $row['family_rating.star_file_name'];
  }
  

  
  Can someone let me know what I am doing wrong?  Thanks for your help.

  $query = "SELECT * FROM movies, family_rating"
  INNER JOIN family_rating ON movies.movie_star_rating = family_rating.star_id
  WHERE movies.movie_name_series = '$search';

  OK, that SQL is not the same as your original post.

  > Not unique table/alias: 'family_rating '.

  This tells us what's wrong. You specify the two tables after the from clause. Try again with your original query:

  $query = "SELECT * FROM movies"
  INNER JOIN family_rating ON movies.movie_star_rating = family_rating.star_id
  WHERE movies.movie_name_series = '$search';

• Difference between Inner join and right outer join...

  Which is precisely the difference between an Inner join and right outer join...

  JOIN INTERNAL:-to return all rows from the two tables where there is a football game. That is to say. the table resulting from all the rows and columns will have values.

  AND

  RIGHT OUTER JOIN:-Returns all rows in the second table, even if there is no match in the first table.

• Only show the first page of the chapters and expandable pages

  I just downloaded a book and its showing only the first page of a large number of chapters. When I arrived at the end of the first chapter (if it is still in the right order) he repeated the same page several times. From there, the next 4 chapters were only the first page of each chapter. Is it possible to fix this? What is the cause? I closed iBooks repeatedly, I restarted my phone several times, whenever it is the same.

  Have you tried to delete the book and it redownloading via the bought? If it's that the same are all recent comments mentioning the same problem? If it's a recent purchase, you could contact iTunes Support: http://reportaproblem.apple.com

• Turn on iPhone 5 s for the first time?

  Hello

  I just bought all new iPhone 5 S in a shop and after I searched (google) answers with regard to the maintenance of the battery, I'm a bit confused. Some say it is wise to drain the battery until the phone turns off and that completely... some people say that is nonsense so that you must charge your phone charge straigh away from the box and don't let not phone to turn off... some are mentioning the procedure 3 hours but I know it's nonsense...

  Can you tell which procedure is best for the first time.

  Thank you very much.

  Here's what I consider some good advice on the pricing of your iPhone:

  When to charge your iPhone or iPad

• Why can I only type on the first page if I have more than one open?

  If I have several pages open, I can only tap the first barrier that I opened.
  If I tap on another page the text appears somewhere on the original page... chat box, search box, sign in.
  If I restart FireFox it will be ok for a few minutes and then comes back to the issue.
  This does not happen with other browsers. If I want to use FireFox for games (best browser I would say) I have to open another browser if I want to do other things online.
  IE. If I am games on Firefox, I use Chrome, if I want to access my Youtube account.

  Thanks for your help.

  Follow the suggestions mentioned in the following article:

  • Troubleshoot extensions, themes, and issues of hardware acceleration to resolve common problems of Firefox

  Check and tell if its working.