the number of games of beckup and their size in a backup
Hellois there a query to display the number of beckup games and their size in a backup? For example, I want to know how many backup sets I had in my last backup dekdak? I can't see them on the type.
Thank you very much
See if that helps you
http://oracledbasupport.co.UK/2008/06/05/RMAN-backup-reports/
You can customize
Tags: Database
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determine the number of Monday, Tuesday, Wednesday and Thursday
Hello all;
I want to determine the number of Monday, Tuesday, Wednesday and Thursday from January 1, 2011 to March 14, 2011. How can I go to write.
Any help is appreciated.
Thank you.Hello
Here's one way:
WITH parameters AS ( SELECT DATE '2011-01-01' AS start_date , DATE '2011-03-14' AS end_date FROM dual ) , all_days AS ( SELECT TO_CHAR ( start_date + LEVEL - 1 , 'fmDay' , 'NLS_DATE_LANGUAGE=ENGLISH' -- If necessary ) AS weekday_name FROM parameters CONNECT BY LEVEL <= end_date + 1 - start_date ) SELECT weekday_name , COUNT (*) AS cnt FROM all_days WHERE weekday_name IN ( 'Monday' , 'Tuesday' , 'Wednesday' , 'Thursday' ) GROUP BY weekday_name ;
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I just saw your second message. Thanks for posting this; It may be useful to see your code, even if this does not work.
It sounds like you have the CONNECT BY part properly, but you do a lot of difficult operations on dates. Oracle provides several very useful date manipulation functions, as well as the DATE arithmentic. Beware of excessive conversion of DATE in VARCHAR2, or vice versa. For exampleto_char(to_date(...
It almost never be in Oracle.
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determine the number of Monday, Tuesday, Wednesday and Thursday in a month
Hello all;
I'm still trying to think and understand it. Y at - it a syntax that you can use to determine the number of Mondays, Tuesdays, Wednesdays and Thursdays for a month for a given year, taking into account leap years.
Thank you.Hello, welcome to the forums.
Something like this should do it:
with day_tab as ( select mon_dt + level - 1 dt, to_char(mon_dt + level - 1, 'DY', 'NLS_DATE_LANGUAGE=''ENGLISH''') dy from (select trunc(to_date(m || '/' || a, 'MM/YYYY'), 'MM') mon_dt from (select &v_month m, &v_year a from dual)) connect by mon_dt + level - 1 <= last_day(mon_dt)) select count(*) cnt_tot from day_tab where dy in ('MON', 'TUE', 'WED', 'THU');
Run the example:
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If by chance you want to see a number of days of the week just to use a group of:
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If you want to list these days, with a number by day of the week:
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