The replacement of columns 'named model row of column.

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• Get the only table name in model executing the revese engineer but columns do not come

  Get the only table name in model executing the revese engineer but columns do not come. I used the standard procedure.  Please let me know why I am not getting column in my model.

  I have attached the screen shot for the same thing.

  This is a table or a synonym? In the case of synonym or try to add the property as it appears below thread.

  Reverse engineering a synonym in ODI 11 G.

  Or maybe go with personal setbacks.

• How to refer to the primary key column of newly inserted rows of tabular form

  Hello

  I use APEX 4.2.0.00.27 with Oracle DB 11.2.0.3.0.

  I work with a tabular presentation wizard-created for insert and update a table using the integrated SRM process (sequence 10).  I'm trying to use a process of anonymous block of PL/SQL (sequence 30) to make another manipulation of table after the records were inserted or updated.  The manual process is associated with my tabular form and I use the variables of name of column binding in my program block.

  My (rsn_test) table has 3 columns: test_id (number), test_nbr (number), test_id2 (number).  Test_id column is identified as the primary key and the type of the source already exists a sequence rsn_test_seq.  Column test_id2 gets its default value 0 to a hidden page element.

  I would use my manual process for updating the value of the test_id2 column.  If it's 0 then I want to put the value of the column test_id.  If it is any other value, then it must remain at this value.  My logic works very well for an existing line, but I'm running into a problem with the newly added lines.  The new lines get inserted, but the test_id2 column remains the default value 0.  I can tell the debugger that the SRM process is triggered first and inserts the line, then my manual dealing with fires.  The problem seems to be that the connection variable: TEST_ID for the primary key column remains NULL after insertion.  I don't know how to get the value of the column test_id of my newly created line to use in my PL/SQL block to my update.

  Process of PL/SQL:

  DECLARE
  BEGIN
     :P7_SHOW := NULL;
     :P7_SHOW := NVL(:TEST_ID2,555) || ' and ' || NVL(:TEST_ID,787) || ' and ' || NVL(:TEST_NBR,9999);
     IF :TEST_ID2 = 0 AND :TEST_ID IS NOT NULL THEN
        UPDATE rsn_test
           SET test_id2 = :TEST_ID
         WHERE test_id = :TEST_ID;
     ELSE
        :TEST_ID2 := :TEST_ID2;
     END IF;
  END;
  
  

  Excerpt from the debugger:

  0.01625 0.00010 Processes - point: ON_SUBMIT_BEFORE_COMPUTATION
  0.01635 0.00008 Branch point: Before Computation
  0.01643 0.00003 Process point: AFTER_SUBMIT
  0.01646 0.00022 Tabs: Perform Branching for Tab Requests
  0.01668 0.00008 Branch point: Before Validation
  0.01676 0.00024 Validations:
  0.01700 0.00135 Perform basic and predefined validations:
  0.01835 0.00020 Perform custom validations:
  0.01855 0.00049 ...Validation "TEST_NBR must be numeric" - Type: ITEM_IS_NUMERIC
  0.01904 0.00007 ......Skip for row 1 because row hasn't changed
  0.01911 0.00016 ......Skip for row 2 because row hasn't changed
  0.01927 0.00012 ...Validation "TEST_ID2 must be numeric" - Type: ITEM_IS_NUMERIC
  0.01939 0.00007 ......Skip for row 1 because row hasn't changed
  0.01945 0.00018 ......Skip for row 2 because row hasn't changed
  0.01964 0.00005 Branch point: Before Processing
  0.01968 0.00004 Processes - point: AFTER_SUBMIT
  0.01972 0.00588 ...Process "ApplyMRU" - Type: MULTI_ROW_UPDATE
  0.02560 0.00154 ...Execute Statement: declare function x return varchar2 is begin begin for c1 in ( select "RSN_TEST_SEQ".nextval pk from sys.dual ) loop return c1.pk; end loop; end; return null; end; begin wwv_flow.g_value := x; end;
  0.02714 0.00140 ......Row 3: insert into "APPPCSRSN"."RSN_TEST" ( "TEST_ID", "TEST_NBR", "TEST_ID2") values ( :b1, :b2, :b3)
  0.02854 0.00011 ...Process "ApplyMRD" - Type: MULTI_ROW_DELETE
  0.02865 0.00004 ......Skip because condition or authorization evaluates to FALSE
  0.02869 0.00015 ...Process "Process Submit" - Type: PLSQL
  0.02884 0.00007 ......Skip for row 1 because row hasn't changed
  0.02891 0.00012 ......Skip for row 2 because row hasn't changed
  0.02903 0.00012 ......Process row 3
  0.02915 0.00429 ...Execute Statement: begin DECLARE BEGIN :P7_SHOW := NULL; :P7_SHOW := NVL(:TEST_ID2,555) || ' and ' || NVL(:TEST_ID,787) || ' and ' || NVL(:TEST_NBR,9999); IF :TEST_ID2 = 0 AND :TEST_ID IS NOT NULL THEN UPDATE rsn_test SET test_id2 = :TEST_NBR WHERE test_id = :TEST_ID; ELSE :TEST_ID2 := :TEST_ID2; END IF; END; end;
  0.03344 0.00013 ...Session State: Saved Item "P7_SHOW" New Value="0 and 787 and 1300"
  0.03356 0.00004 Branch point: After Processing
  0.03360 0.00048 ...Evaluating Branch: "AFTER_PROCESSING" Type: REDIRECT_URL Button: (No Button Pressed) Condition: (Unconditional)
  0.03407 0.00013 Redirecting to f?p=290:7:8717971109610:::::&success_msg=0%20row(s)%20updated%2C%201%20row(s)%20inserted.Success%2FEBD244168556408CBA714E3974918C09%2F
  0.03420 0.00012 Stop APEX Engine detected
  0.03432 0.00007 Stop APEX Engine detected
  0.03439 - Final commit
  
  

  Any suggestions?

  I have run tests on

  https://apex.Oracle.com/pls/apex/f?p=83488:1 demo/demo

  to see your problem.

  I have 2 solution for your problem.
  I add trial NOT tabular just usual block of PL/SQL

  	BEGIN
  	I'm IN (SELECT TEST_ID FROM RSN_TEST WHERE TEST_ID2 = 0)
  	LOOP
  	UPDATE RSN_TEST
  	SET test_id2 = TEST_ID
  	WHERE test_id = i.TEST_ID;
  	END LOOP;
  	END;

  and works very well, you can see in the sample.

  The other solution is to show new generated TEST_ID

  Adding a sequence as a default value for a column in a table field

  And to execute your procedure.

  I get how is with the good luck of time.

  By

• Request to remove row where the value of column contains alphabets

  Hello

  Could someone please help me to get this application working.

  Request to remove row where the value of column contains alphabets.

  DELETE FROM BIN_ITEM WHERE order_nmb LIKE '% [A - Z] % ' | LIKE '% [a - z] %'

  Thank you and best regards,

  Madam.

  SELECT order_nmb FROM BIN_ITEM WHERE regexp_count(order_nmb,'[0-9]') = 0

  ----

  Ramin Hashimzade

• Remove the separator of columns and rows in spark DataGrid

  

  Hello

  try searching a bit on the web with no success - how can I remove / handful of visibility of the separators of columns and rows in the DataGrid to spark flex 4.5

  See photo with separators:

  Two ways:

  (1) write a simple custom following appearance (the empty rectangles will cause the separators to disappear):

  (2) make a copy of the default Datagridskin and remove parts of skin 'columnSeparator' and 'rowSeparator.

  -Kevin

• rows in the bi publisher columns

  How convert the lines into columns in bi publisher, I have ministries of the column, I want to display each Department in the form of columns, for example:

  Table1:

  now, it displays as:
  

  Resource Department role

  ____   ________     __________
  

  Role1 resource1 ministere1

  Role2 resource2 department2

  3 resource3 ministere3

  I want to display it like this:

  Role Resource ministere1 ministere3 department2

  ____   ________     __________     ___________    ___________
  

  Role1 resource1 *.

  Role2 resource2 *.

  role3   resource3                                                           *

  
  

  and how to do it, if I don't know the number of departments

  
  

  IM finding the solution, install oracle bi publisher desktop and that is all.

• I have the table of 3 columns A, B, C. I want to store the sum of columns A B in the C column without using the DML statements. Can anyone help please how to do. ?

  I have the table of 3 columns A, B, C. I want to store the sum of columns A B in the C column without using the DML statements. Can anyone help please how to do. ?

  11.1 and especially you have virtual column

  SQL> create table t
    2  (
    3     a number
    4   , b number
    5   , c generated always as (a+b) virtual
    6  );
  
  Table created.
  
  SQL> insert into t (a, b) values (1, 2);
  
  1 row created.
  
  SQL> select * from t;
  
           A          B          C
  ---------- ---------- ----------
           1          2          3
  

  Before that, a front insert - trigger

  SQL> create table t
    2  (
    3     a number
    4   , b number
    5   , c number
    6  );
  
  Table created.
  
  SQL> create or replace trigger t_default before insert on t for each row
    2  begin
    3    :new.c := :new.a+:new.b;
    4  end;
    5  /
  
  Trigger created.
  
  SQL> insert into t (a, b) values (1, 2);
  
  1 row created.
  
  SQL> select * from t;
  
           A          B          C
  ---------- ---------- ----------
           1          2          3
  

• Flag value does not change after the SCD TYPE1 column update

  Hello

  I had scd type3, type2 successfully.

  I'm trying to implement the type 1 scd.

  For this, I change slow dimension & ckm oracle the oracle select ikm.

  the source and target tables are the following. for the type 1 scd, I chose scd behavior as existing lines updated on behalf of the emp, sal columns.

  Start timestamp to join date and the current flag to flag column.

  first ename is smith when empno is 7369.

  I've updated ename

  Update scdtype1_source set ENAME = 'AA' where EMPNO = 7369

  After running, I don't have to change the flag o to 1 in the target table.

  SCD type1 mainly used for replaces old values., but I add flag column in the target table for easy identification. () column in which I updated)

  I have not any change in the flag.

  Please help me,

  Thnaks in advance,

  A.Kavya

  

  Hello

  I'm not sure what you're trying to do will work. In the case of Type 1 SCD are you still using the dimension of change slow ikm oracle? The flag is updated to 0 in the case of CDs because of the code in step 2 "' Historize old rows where CPCs flag is set to '0'.» In your case, that no new record is added in the case of an update so the IKM does not change the flag.

  I'm not sure of your requirement either. You say you want to identify the column in which you have updated. How is an indicator will tell you what the column value has been changed? Maybe you want to know which line you have updated? If this is the case and lets say you set the flag to 1 in case of update what happens when another updated same record?

  I would suggest you add an updated time stamp column to your table and set of sysdate but in properties check only the update and will not insert. What that would do is update your record, it will fill the current date and time so that you can identify that this record has been updated.

  If you want to always go for the flag, then follow the same approach but in your mapping, change the value of the flag to 1 instead of 0 and new check only the update box (uncheck the box insert). In your create table statement the default value of this option to 0. So when the new line is inserted database is automatically assigned the flag to 0 and where there is an update, ODI it will change to 1.

  Thank you

  Ajay

• Coverting a line in the values in columns

  Hi friends Expert SQL,
  
  I have a line that contains 6 columns where I want the data to appear in the form of columns, as shown here:
  
  From:
  
  Select item1, item2, item3, amt1, amt2, amt3 in item_table, when sno = 1; <-returns 1 row as below
  
  ITEM1 ITEM2 ITEM3 AMT1 AMT2 AMT3
  ---------- ------------ ------------- ----------- ------------ ----------
  AAA BBB CCC 10,00 20,00 15,00
  
  
  Explanation of data: item1 (AAA) price is amt1 (10.00), item2 (BBB) price is amt2 (20 h 00) and item3 (CCC) price is amt3 (15.00). Ok.
  
  Now I want that data to be converted to columns, as shown here:
  
  TO:
  
  AMT ELEMENTS
  --------- ---------
  AAA 10.00
  BBB 20.00
  CCC 30.00
  
  
  Please help me guys, I want a SQL to display these data.
  
  I found a single query that converts a row of columns, but this is not my requirement: [for your reference only]
  
  SQL > select substr (the_string
  , decode (level, 1, 1, instr(the_string,',',1,level-1) + 1)
  , decode (instr(the_string,',',1,level), 0, length (the_string), instr(the_string,',',1,level) - decode (level, 1, 0, instr(the_string,',',1,level-1))-1)
  ) the_value
  from (select (select item1 |)) «, » || Item2. «, » || Item3 item_table where sno = 1) ELEMENTS
  the double)
  connect by level < = length (the_string) - length (replace(the_string,',')) + 1
  
  
  Thank you and best regards,
  Kiran

  WITH pivot_data
       AS (SELECT 'AAA' ITEM1,
                  'BBB' ITEM2,
                  'CCC' ITEM3,
                  '10.0' AMT1,
                  '20.0' AMT2,
                  '15.00' AMT3
             FROM DUAL)
  SELECT t1.items, t.amount
    FROM (SELECT NULL items, amount, ROWNUM rn
            FROM pivot_data UNPIVOT INCLUDE NULLS (amount
                            FOR items
                            IN (AMT1, AMT2, AMT3) )) t,
         (SELECT items, NULL amount, ROWNUM rn
            FROM pivot_data UNPIVOT INCLUDE NULLS (items
                            FOR amount
                            IN (ITEM1, ITEM2, ITEM3))) t1
   WHERE t.rn = t1.rn
  

  ITEMS     AMOUNT
  AAA     10.0
  BBB     20.0
  CCC     15.00
  

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  I want to know the number of lines and columns not giving those in C code automatically.

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