the string conversion to

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• a stupid question about the string conversion error

  I learn generic

  well generic allows setting the data type that you add to the fields of the object, right?

  I made a simple example

  class generic < String >

  {

  The name of the string;

  void set (String name)

  {myIdName = name ;}

  String get() {return myIdName ;}

  }

  class using {}

  Public Shared Sub main (String [] args)

  {

  generic < String > gn = new

  (generics) < String >;

  GN. Set (90);

  System.out.println ("name entered is:" + gn.get ());

  }

  }

  now the line

  GN. Set (90);

  I know that I send a string to the value method, but I wanted to see the error that comes when I send the argument of type other than a string and sent 90 to set method (without quotes)

  the error that slammed me is

  method defined in the class generic < String > cannot be applied to the given types

  required: java.lang.String

  found: int

  reason: int real argument cannot be converted to a java.lang.String by method invocation conversion

  corresponding to a variable of type String: String extends the object declared in the class generic

  OK here is my stupid question

  I know that int cannot be converted to a string and put 90 quotes will correct the error

  What intrigued me is the last line

  "Chain extends object declared in the class generic.

  
  

  I know that everything is under the object class

  that means that means line... ??

  thnq

  What intrigued me is the last line

  "Chain extends object declared in the class generic.

  
  

  I know that everything is under the object class

  that means that means line... ??

  Which refers to the class definition you provided:

  generic class

  You "stated" in your 'generic' class a 'collar' stretching ' the object '. It reads as if it said "String declared in the class generic.

  See "Generic Types" in the Java Tutotial

  http://docs.Oracle.com/javase/tutorial/Java/generics/types.html

  Search for the word 'object' and you'll see that word highlighted in the world. Although it appears highlighted read this line:

  As you can see, all instances of the object are replaced by T. A variable of type can be any non-primitive type you specify: any type of class, any interface, any type of table or even another variable of type.

  On this page, you will see this:

  A generic class is defined with the following format:

  class name { /* ... */ }
  

  Where each one is read as: T1 extends object ', "T2 extends object", etc.

  When you said this:

  generic class

  You replaced "T1 extends object" with "String extends object".

• Points table for the string conversion of floating

  Is it possible to convert an array of floating point and keep the decimals, while in the version of the loop below, without no loop?

  

  How about using "String in array to worksheet" and the "worksheet of array of strings" back to back.

  

• Please run this logic of the string conversion

  One please implement the logic below
  
  I have an input string to be converted by adding "0" when necessary.
  
  Case 1
  
  If the entry is like "3,8,13,18,23,28,33,38,43,48,53,58" and I want the output as '03,08,13,18,23,28,33,38,43,48,53,58'
  
  Case 2
  
  If the entry is like '03,08,13,18,23,28,33,38,43,48,53,58' put it out should be like "03,08,13,18,23,28,33,38,43,48,53,58"
  
  
  Would be greate if someone could implement.
  
  Thank you-

  An option is to add a '0' to each number and remove all numbers 0 to 3 digits in the result:

  with t as (
  select '3,8,9,18,23,28,33,38,43,48,53,58' as s from dual union all
  select '03,08,13,18,23,28,33,38,43,48,53,58' from dual
  )
  select regexp_replace(
            regexp_replace(s,'(\d+)'  -- one or more digits
                                    ||'(,|$)' -- followed by a comma or end-of-string
                                    ,'0\1\2'  -- pad a 0 in front
                                 ),
                                '0(\d\d)'     -- a 0 followed by 2 digits
                                ,'\1')        -- remove the 0
            as s from t
  ;
  

  I guess you will never have 3 digits in your channel.

  Kind regards
  Bob

• On the digital unit of string conversion

  Hello world

  I'm trying to convert a digital control with min as a unit to a string.

  The fact is that it converts in seconds before it updates the channel indicator.

  

  I noticed that the format "in channel" will convert always first to the base unit (unit multiple value of units conversion value), as W kW (10 kW will display 10000 W) to watt unit.

  Is there a way to format the entry without this conversion value to the first base unit?

  Thank you...

  If you are looking for the syntax of using LabVIEW Format specifier, you'll see a unit option.

  This is the format that you want to keep the string in a few minutes: g {min} %

• string conversion appropriate type based on the content of string

  Hello

  I have a CSV with string values, and I want to assign them to good type in labview, then assing them to some pre-existing teststand properties.

  I think a particular way in a digital chain of detection should be in labview somewhere, but I can't seem to find it.  There is certainly decimal string number and string of fractional number, but an error during their passage of a string like "blah".  They just return 0.

  So my main challenge here is to feel a digital channel, either with a single point decimal or not and the impression that it is a 'number '.

  Example:

  Takes the string->

  1.234-> is the number

  1234-> is the number

  192.168.1.12-> is not a number

  I could write a vi to do this, but I was wondering if it wasn't already obvious tool in labview, which is escaping at that time.  I don't like to reinvent the wheel, even for something so simple.

  Thank you

  David J.

  david_jenkinson wrote:

  So my main challenge here is to feel a digital channel, either with a single point decimal or not and the impression that it is a 'number '.

  Example:

  Takes the string->

  1.234-> is the number

  1234-> is the number

  192.168.1.12-> is not a number

  In the more general case, you must also be able to properly analyze, for example - 10e6, 85.83E - 3 and such good number to floating point. Also your last example is basically a number U32, just formatted in the style of IP address.

  You must use 'analysis of the string' %f format and NaN as a default value. Then also check if the string is an empty string. If this isn't the case, then it is not a number according to your narrow definition.

  

• How to string conversion in the Nodelist XML in java

  Hai

  I need to convert the string to a nodelist in java

  Element parentcustom = (element) wink;

  String resultNodeValue = replaceAngleBracketsChildType (parentcustom.toString ());

  NodeList parentcustomList = resultNodeValue (NodeList);

  I did high way, but I don't get the right answer

  I need this resultNodeValue to be converted to nodelist.

  can someone help me

  Thanks in advance...

  Your requirement is to get the "parentcustomdetails" inside the node 'parentruledetails '.

  The following code will do that.

  NodeList children = doc.getDocumentElement().getChildNodes();
  for (int i = 0; i < children.getLength(); i++) {
       Node parentRule = children.item(i);
       if (parentRule.getNodeName().equals("Parentrule")) {
            NodeList nlParentRule = parentRule.getChildNodes();
  
            for (int j = 0; j < nlParentRule.getLength(); j++) {
                 Node parentRuleDetails = nlParentRule.item(j);
                 if (parentRuleDetails.getNodeName().equals(
                           "parentruledetails")) {
                      NodeList nlParentRuleDetails = parentRuleDetails
                                .getChildNodes();
  
                      for (int k = 0; k < nlParentRuleDetails.getLength(); k++) {
                           Node parentCustomDetails = nlParentRuleDetails
                                     .item(k);
                           if (parentCustomDetails.getNodeName().equals(
                                     "parentcustomdetails")) {
                                NamedNodeMap attributes = parentCustomDetails
                                          .getAttributes();
  
                                System.out.println(parentCustomDetails
                                          .getNodeName());
                                for (int l = 0; l < attributes.getLength(); l++) {
                                     Node attr = attributes.item(l);
                                     System.out.println("\t"
                                               + attr.getNodeName() + " -- "
                                               + attr.getNodeValue());
                                }
                           }
                      }
                 }
            }
       }
  }
  

  The output of this code is,

  parentcustomdetails
       CHILD_TYPE -- Console
       CMD_CODE -- 37135
       CMD_NAME -- login authentication [string]
       CMD_OPTION -- login authentication
       COLUMN_INDEX -- 0
       CONDN_OPER -- exists
       CONDN_VALUE -- True
       PARENT_RULE_CODE -- PR630
       RULE_TYPE_FLAG -- Customrule
  parentcustomdetails
       CHILD_TYPE -- Console
       CMD_CODE -- 37135
       CMD_NAME -- login authentication [string]
       CMD_OPTION -- string
       COLUMN_INDEX -- 1
       CONDN_OPER -- equalsto
       CONDN_VALUE -- AAAAAAAAA
       PARENT_RULE_CODE -- PR630
       RULE_TYPE_FLAG -- Customrule
  

• Conversion Date to integer to the string

  So what I try to do is to convert the results of a query. What is happening is that my data when the month is displayed as an integer from 1 to 12. I want to convert these numbers to the string month as Jan, Feb, Mar, and so forth. I tried using the DateFormatter, but I'm guessing that this does not work because he does not like the format that comes to him in the data. It is easier to explain by looking at my code:
  
  Here is my function to manage the date:
  public void fnShowMonth(item:Object,column:DataGridColumn):String
  {
  Return dfShowMonth.format(item[column.dataField]);
  }
  
  Here's Date formatter:
  < mx:DateFormatter id = "dfShowMonth" formatString = "MMMM" / >
  
  Here are the data grid I use for output:
  < mx:DataGrid
  ID = "grid2".
  dataProvider = "{cfcOutput}".
  >
  < mx:columns >
  < mx:DataGridColumn dataField = "MONTHS TOTAL" / >
  < mx:DataGridColumn dataField = "Month1" labelFunction = "fnShowMonth" / >
  < mx:DataGridColumn dataField = "Year1" / >
  < / mx:columns >
  < / mx:DataGrid >
  
  I used this method to other areas, but not a particular date field format. All I really want to do is convert these output numbers in a month in text in my datagrid. Right now, it gives me just an empty column "month1. I can get the numbers when I remove the labelFunction. Any ideas what I need to do?

  It is rather in bad taste, but it works. You'll want to provide verification of limits

  public static var months: Array = ["Jan", "Feb", "Mar", "Apr", "Peut", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "December"];

  public void fnShowMonth(column:DataGridColumn):String
  {
  back month [column.dataField - 1];
  }

  Joe

• Basic question on the string-to-number conversion

  Hello
  
  I have a string, for example '23,2445,45'
  I want to extract the numbers of this string and put it in an array of numbers.
  
  Any keyword SQL is available. What is the best way to do it.
  
  Thank you
  MD

  Try this

  declare
  
  type vnum is varray(20)  of number;
  
  vnum1 vnum :=vnum();
  
  j number;
  
  begin
  
  j:= 1;
     for i in (
     with t as (
     select '23,2445,45' product_string from dual
     )
     SELECT   *
         FROM (SELECT
                      RTRIM(LTRIM(SUBSTR(product_string,
                                         INSTR(',' || product_string||',', ',', 1, n),
                                           INSTR(',' || product_string||',', ',', 1, n + 1)
                                         - INSTR(',' || product_string||',', ',', 1, n))),
                            ' ,') AS prod
                 FROM t,
                      (SELECT     ROWNUM n
                             FROM DUAL
                       CONNECT BY LEVEL < 10))
       WHERE prod IS NOT NULL)
       loop
  
       vnum1.extend;
       vnum1(j):= to_number(i.prod);
  
       dbms_output.put_line(vnum1(j));
  
       j:=j+1;
  
       end loop;
  
       end;
    
  

  vnum1 vnum: = vnum (0,0,0,0,0,0,0,0,0);

  I did it because I don't know how to initialize the array. Need to read more about it.

  This will put the values in the vnum1 table.

  If you need to do something with the numbers in the string

  so you can do the following without using a table.

  declare
  begin
     for i in (
     with t as (
     select '23,2445,45' product_string from dual
     )
     SELECT   *
         FROM (SELECT
                      RTRIM(LTRIM(SUBSTR(product_string,
                                         INSTR(',' || product_string||',', ',', 1, n),
                                           INSTR(',' || product_string||',', ',', 1, n + 1)
                                         - INSTR(',' || product_string||',', ',', 1, n))),
                            ' ,') AS prod
                 FROM t,
                      (SELECT     ROWNUM n
                             FROM DUAL
                       CONNECT BY LEVEL < 10))
       WHERE prod IS NOT NULL)
       loop
  
  -----Do what ever you want with the number.
  
       dbms_output.put_line(i.prod);
  
       end loop;
       end;
    
  

  Published by: alvinder on March 11, 2009 15:18

  Discovered how to initialize the array.

• How to convert the string with numbers in U8 with ascii

  Hello

  I have a string with only numbers 0. 9 paper.

  Now, I want to convert to table-U8.

  He works here, but now the problem: How can I change each character to its ascii value?

  Example:

  entry: 123 (string)

  output: x 31, x 32, x 33 (U8-array)

  Thanks for the help

  It's very easy

  String to Byte Array Function
  Have the Palette: string/array/path Conversion functions

  Converts a string to an array of unsigned bytes. Each byte in the array has the ASCII value of the character corresponding to the string.

• Number to String Conversion

  So the question is, which is rounded up my numbers?  Or, more generally, what have I done wrong here?

  The main program this sub.vi works for the needs these numbers as strings, and I think I picked the wrong number to string conversion .vi or missed a configuration somewhere, because the program takes perfectly good number like - 0.340316 and rounded to-0 (zero negative? it's zero, negative).

  The zero negativity hand, the number of decimal string .vi is rounded up my whole numbers.

  The function is supposed to be converted in its entirety. Just go to help > show contextual help and read the description. The desired function is called fractional number of string.

• Save and load the string table

  Hello

  is possible except an array of channel with multiple line of text file and load new file to table with the same size of array?

  Because when I use the code in the picture, initialized array is 3 x 3 but after save and load file is table 5 x 3.

  

  If is an option how to save this table in the file into 3 x 3 table and charge back of file as a 3 x 3 table?

  Thank your for any suggestion,.

  Petr

  Your code is loaded in 5 x 3 is because two of your cells have newline characters (\n). The reading of the worksheet VI use return or line break characters and your delimiter to figure out how to split the string into an array.

  A solution might be to replace all characters from end of line with something else, and then reinsert it after reading of the worksheet.

  It can do what you want, even if it's a bit bulky. It's a little confusing if you don't understand "------" string formatting, but it essntially replaces all '\r' and '\n' with '\\r' and '\\n', including the conversion of the worksheet does not read as an end of line character.

  

• Encoding of the string for HTTP Post

  Hello

  I work with HTTP get and post at the moment, I have a server with a REST of apache based interface. Obtaining and displaying the data are no problem for 'normal' strings and characters, but I can't send characters like German "Umlaut" (Ä Ü Ö) or Japanese or Chinese characters. Coding for the Socket connection is UTF-8 and the command POST also contains a line of Content Type with character set UTF-8. The server expects UTF - 8, so I need my data in this encoding.

  When I send strings of InDesign now, I always get an error 'Bad Request' from my server. Looks like that the strings in ESTK is not UTF-8 - How can I create UTF-8 strings? I can't find methods of encoding conversion...

  Thank you

  Klaus

  OK, it took a while to find that - maybe someone else has the same problem and it is looking for a solution, I'll try to explain:

  I downloaded the source files for tomcat to know how tomcat with my data. I debugged deep into the code until I reached the CotoyeInputStream - here the reading of data from InDesign. And although I understood that the stream is read in the form of bytes and characters are counted. The Umlaute and other special characters are encoded as two bytes, but they are counted as a single character. For every Umlaut transferred the number of bytes is 1 higher than the number of characters.

  And at a time the flow is cut to the number of characters.

  So these are 13 bytes and 12 characters:

  {'name': 'u'}

  The byte stream is cut to 12 - last byte is lost and it will happen in my application server:

  {'name': 'u'}

  Support of closing is absent and that throws the Exception.

  My simple solution/solution: I'm adding several spaces. Tomcat is always cut the last characters, but now there are only spaces to be cut. And with spaces, it worked...

• Varchar2 to the number conversion problem

  I have some difficulty conversion strings to numbers. On my Oracle 9.2 server, it gives me an error ORA-1722:
  SELECT TO_NUMBER ('1.2') OF DOUBLE
  Apparently, this is because my server is configured to use the Greek number format (comma instead of decimal point) and substitute "1.2' above with '1.2' will work correctly."
  Is it possible for me to convert strings with decimal number type, independent of the culture so that my application will not have to depends on the locale setting of the server?
  
  Thank you.

  Hello

  Welcome to the forum!

  If you don't want to change the NLS settings for your session, you can specify what settings to use for a particular call to TO_NUMBER (and other features), like this:

  ALTER SESSION     SET NLS_TERRITORY = GREECE;
  
  SELECT     TO_NUMBER ('1.2')     AS wont_work
  FROM     dual;
  
  SELECT     TO_NUMBER ( '1.2'
              , '999999999.999999'
              , 'NLS_NUMERIC_CHARACTERS = '',.'''
              )          AS n
  FROM     dual;
  

  The output below shows the TO_NUMBER 1-argument fails, but the 3-argument TO_NUMBER works:

  Session altered.
  
  SELECT  TO_NUMBER ('1.2')       AS wont_work
                     *
  ERROR at line 1:
  ORA-01722: invalid number
  
           N
  ----------
         1,2
  

  The actual format of the string (the first argument) should not match precisely the format mask (the second argument). You can include signs, or omit the decimal points, so '3', ' '-1,2. '-3', ' + 1.2 ' and ' + 3' will be all converted correctly.»»» "

• I have a MacBook Pro.  Is there a way to implement a rarely used keyboard key that - WHENEVER - it is pressed the computer will insert the string, predetermined character at the cursor position?

  I have a MacBook Pro.  Is there a way to implement a rarely used keyboard key that - WHENEVER - it is pressed the computer will insert the string, predetermined character at the cursor position?

  Yes. You can add in system preferences > keyboard > text.