These can be wired together as their data types (digital, string, array, cluster, etc.) do not match.

Similar Questions

• the selection of all colomns_names of a table, with their data types...

  HI :)
  
  I would like to know, how to select in SQL for all the names of columns in a table with their data types so that I get something like this:
  
  Table 1: table_name
  
  the ID of the column has the NUMBER data type
  the name of the column has Datatype Varchar2
  *....*
  
  --------------------------------------------------------------
  
  Table 2: table_name
  
  the check in the column has the NUMBER data type
  the air of the column has Datatype Varchar2
  *....*
  
  
  and it must be for all the tables that I own!...
  
  P. S: I'm trying to do this with java, so it s would be enough if you just tell me how to select all tables_names with all their colums_names and all their data types!...
  
  Thanks :)
  
  
  
  I've heard this can be done with USER_TABLES... but I have no idea how: (...)
  
  Edited by: user8865125 the 17.05.2011 12:22

  Hello

  USER_TAB_COLUMNS data dictionary view has a row for each column of each table in your schema. The columns TABLE_NAME, COLUMN_NAME and DATA_TYPE contains all the information you need.
  Another view of data, USER_TABLES dictionary, can be useful, too. He has a line of table pre.

• I want to convert the double data type to string type

  I want to convert the double data type to string, have idea about that

  Hello

  Use f

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• How can I find what is the data type of a column of a Table in oracle or SQL?

  (a) what happens if I want to know the type of data in a specific column in the Table.

  (b) how to find the column data types?

  Can someone help me please. I am new to oracle and try to learn a few tricks

  Hello

  How to do

  SQL > desc

  SQL> desc emp
   Name                                      Null?    Type
   ----------------------------------------- -------- ----------------------------
   EMPNO                                     NOT NULL NUMBER(4)
   ENAME                                              VARCHAR2(10)
   JOB                                                VARCHAR2(9)
   MGR                                                NUMBER(4)
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• CHD: the string is used as an index of change in data type? String to double?

  Hello

  I'm new to the tiara. I'm reading the line of a channel number and then to read the data of a channel which is in the same line of another channel.

  That's why I use the SMC function but my index seems not to fit. What I need to change in the code?

  error:

  CHD (2, NOVALUE): = 785 wird die Textvariable «...» CHD (2, > N)

  Code:

   

  DIM intloop, zeilenwerte
  
  Line DIM, aktwert, index
  
  Call ChnAlloc ("zeilenwerte", lang, 1, DataTypeFloat64)          ' Create channel,  'lang' is the size of a channel
  
  index = 0
  
  index = 1 to lang
  
     index = index + 1
  
     aktwert zeit (index) =                         ' get the value that will be compared to the SOPS in the following line of code
  
     Line = PNo (myChannel, aktwert)        ' it returns the line only by comparing aktwert valued myChannel
  
     CHD (line, zeilenwerte) = intloop           '  <--->here the error. try to get the value in a line @index do String data types does not match? what do I do then?
  
  Next

  Thank you very much for your help!

  Buddhist salvation,

  It seems to me that you would be better to use "Linear Mapping" in the palette of ANALYSIS "Suitable curve", but you should be able to get your code works by passing the name of the channel in this second parameter instead of an empty string variable.  You would have noticed that if you had OPTION EXPLICIT the first line of your code - always a good idea.

  Brad Turpin

  Tiara Product Support Engineer
  National Instruments

• How can I assign an F key to type a string of chatracters

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• How can I change the size of the type for my emails, facebook, etc.?

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• Oracle data type for a bit column

  I want to add a new column to my table, but I can't seem to find any data type in oracle. the only data on the ground will be 1 or 0. What is the best type of data to use?
  
  Also, is this correct SQL to add a new 'flag' titles to the table tblLocations:
  
  ALTER TABLE tblLocations
  Bit flag ALTER COLUMN
  
  Thank you
  Mark

  user8721624 wrote:
  Also, is this correct SQL to add a new 'flag' titles to the table tblLocations:

  ALTER TABLE tblLocations
  Bit flag ALTER COLUMN

  It should be something like:

   ALTER TABLE tbllocations
   ADD  FLAG_BIT CHAR(1)
  

  I guess you can use the char(1) data type to contain these data. Also, you can create a check on the flag_bit column constraint to ensure that only 0 and 1 can be stored in the column.

  I hope this helps.

  Kind regards
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• Is it possible to get the data type of element of a queue to itself?

  Hello world

  I have a Q which has a cluster as data type of element.

  now when I want to enqueue

  I will use bundle-default-

  and for this I have to have my current data type

  (long cable as (perhaps after where I got the Q).

  My question is,

  If there is a method/property-node/something that allows me to

  the queue of wire inside Refnum and receive the data element type.

  If I can get into the top of bundle-default?

  (I really want to have this cable in all directions)

  is this the reason why I'm asking here

  aid for the Refnum of outgoing queue to get a queue, the method

  indicates the data type of element and so I hope that there could be a solution.

  thx for your time

  and soon

  j

  Get queue status must be output with the type of data (more precisely an array of the data type and an array of clusters if the data is itself a table). If you do not set the items back to entry to T, this should not even cost anything.

  That said, I agree with others that it is better to what actually a typedef.

• ODI-15005: data type "varchar" does not close in technology: file?

  Hello

  I created the interface that loads data from flat file (source) oracle (target).

  For this, I took LKM SQL FOR SQL and SQL TO ADD FILE IKM.

  Please check the source and target data types.

  

  When I am executing this interface, I get the error as

  ODI-15005: data type "varchar" does not close in technology: file.

  
  

  To resolve this error, I changed the types of flat file data.

  I went to the Manager of topology-> select technology of files-> data types: string - > orcle to the number data type.

  Even if I do not correct this error. Please help me.

  
  

  Thanks in advance,

  A.Kavya.
  

  Hello

  Can you please check what are the data types for the columns in your data target store. As you say it's a file, can you check if the data type for the two columns has the String value (and not varchar).

  Thank you

  Ajay

• A question about the conservation of fields (hour, min, sec) time DATE type in the table on the changes of NLS_DATE_FORMAT

  Hello

  Oracle version: 12.1.0.1.0 - 64 bit

                    OS:   Fedora Core 17 X86_64

  My question is about the conservation of fields (hour, minute, second) time DATE type in the array on NLS_DATE_FORMAT changes.

  Take the following test case:

  SQL> create table tmptab(dateval date);
  
  Table created.
  
  SQL> alter session set nls_date_format = 'yyyy-mm-dd hh24:mi:ss';
  
  Session altered.
  
  SQL> insert into tmptab(dateval) values('2014-01-01 00:00:00');
  
  1 row created.
  
  SQL> insert into tmptab(dateval) values('2014-01-01 10:00:00');
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> select * from tmptab;
  
  DATEVAL
  -------------------
  2014-01-01 00:00:00
  2014-01-01 10:00:00
  
  SQL> alter session set nls_date_format = 'yyyy';
  
  Session altered.
  
  SQL> select * from tmptab where dateval > '2014';
  
  no rows selected
  
  SQL>
  

  I don't understand why it returns nothing. The second test case above insert statement inserted a line with 10 as the value for the time of the DATE field column dateval.

  Accordingly, while comparing this with the literal '2014' (which based on the new value of NLS_DATE_FORMAT = "yyyy" is implicitly converted to DATE), shouldn't the above query returns the line 2014-01-01 10:00 ?

  I mean, I changed the NLS_DATE_FORMAT but data from time in the table fields are preserved and that's why they should normally be taken into account in the comparison of date.

  What I'm trying to say is that for me (Please correct me if I'm wrong), no matter what NLS_DATE_FORMAT configuration is the following test

  SQL> select * from tmptab where dateval > '2014';
  

  is the same thing that

  SQL> select * from tmptab where dateval > to_date('2014-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss');
  

  And because the line 2014-01-01 10: 00:00 in the tmptab table. The following test

  2014-01-01 10:00:00 > to_date('2014-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')
  

  evolves normally true (beucase of TIME = 10 on the left side of the test) and therefore this line must be returned which is not the case in the test above.

  You kindly could you tell me what I misunderstood?

  Thanks in advance,

  This is the price for the use of implicit conversions. Implicit DATE conversion rules are not as direct as it can be assumed. In your case, all you provide is year as date format. In this case date implicit conversion rules assumes that month in the current month, day 1 and time as 00:00:00.

  SQL > alter session set nls_date_format = "yyyy";

  Modified session.

  SQL > select to_char (to_date ('2014 "), ' mm/dd/yyyy hh24:mi:ss') twice;

  TO_CHAR (TO_DATE('20)
  -------------------
  01/08/2014-00:00:00

  SQL >

  So, when you start:

  Select * from tmptab where dateval > '2014 '.

  Oracle implicitly converts date using "YYYY", which translates as August 1, 2014 '2014'. That's why your quesry returns no rows.

  SY.

• Equals (=) vs SIMILAR to data type date

  First of all, I am aware that the equal (=) operator is a "comparison operator compares two values for equality."  In other words, in a SQL statement, it will not return true unless both sides of the equation are equal.  For example:

  SELECT * FROM Store WHERE Quantity = 200;

  The LIKE operator "implements a comparison of pattern match" which attempts to match "a string against a string of models value containing wildcard characters.  For example:

  SELECT * FROM Employees WHERE Name LIKE 'Chris%';

  Here,

  I ask about the date on the ORACLE database data, I found the following, when I write the select statement in this way:

  SELECT ACCOUNT.ACCOUNT_ID, ACCOUNT.LAST_TRANSACTION_DATE FROM ACCOUNT WHERE ACCOUNT.LAST_TRANSACTION_DATE LIKE '30-JUL-07';

  I get all the lines, I'm looking for. but when I use the equal sign = instead:

  SELECT ACCOUNT.ACCOUNT_ID, ACCOUNT.LAST_TRANSACTION_DATE FROM ACCOUNT WHERE ACCOUNT.LAST_TRANSACTION_DATE = '30-JUL-07';

  I get nothing even if nothing is different except the equal sign. I can't find any explanation for this you?

  Hawk333 wrote:

  Here,

  I ask about the date on the ORACLE database data, I found the following, when I write the select statement in this way:

  SELECT ACCOUNT.ACCOUNT_ID, ACCOUNT.LAST_TRANSACTION_DATE FROM ACCOUNT WHERE ACCOUNT.LAST_TRANSACTION_DATE LIKE '30-JUL-07';
  

  I get all the lines, I'm looking for. but when I use the equal sign = instead:

  SELECT ACCOUNT.ACCOUNT_ID, ACCOUNT.LAST_TRANSACTION_DATE FROM ACCOUNT WHERE ACCOUNT.LAST_TRANSACTION_DATE = '30-JUL-07';
  

  I get nothing even if nothing is different except the equal sign. I can't find any explanation for this you?

  Just to explain your results...

  The LIKE operator only works on strings, so, in that your first example, it causes the left hand side (your DATE column) to be implicitly converted to a string.  Now, your NLS_DATE_FORMAT is obviously DD-MON-RR, so it converts the date to a string of this format, which then matches the string that you have provided on the right side and you get lines.  Now, if your dates got to them, the components then this conversion implcit decreases time to give only the part of the date, so that a very similar match for your channel.

  The '=' operator is overloaded to work with many different data types, so in this case, Oracle takes the data type of the left as being the type of data to use, which is DATES, and implcitly converts then the side right (your VARCHAR2 string) to a DATE.  This makes the right hand side a DATE with the component data type "time" 00:00:00.  As your transaction date is likely to have components, they are unlikely to be 00:00:00 (in most cases) If you you games for 30 July 2007 00:00:00, if it was be a line with that timestamp.

• How to determine if a data type is used in the comic book?

  Background:
  I am currently planning to install GoldenGate proof of Concept and have questions about the data types supported by the capture mode (pg 1-5, 1-6 in the installation guide). Is not in itself a matter of GoldenGate.
  
  Our source and target databases are 11.2.0.2
  The GG server will be 11.2.0.3
  I'm new to the environment and want to confirm that we needn't upgrade the source and target the DBs to 11.2.0.3 in order to use the integrated capture mode. This forces me to know if 3 specific types of data are used in the comics. The problem is, Oracle docs aren't clear to me, when they refer to 3 specific data types.
  
  Here's the question:
  
  Does anyone know how I can confirm that the following 3 data types are used in the DB by querying the dictionary: "XML stored in binary form',"XML stored as object-relational","abstract data Type "?
  
  If I select the types of data separate from dba_tab_columns, I see no data enumerated type that indicates, for example, that an XML string is stored as a ' binary '.
  
  For me, when Oracle made reference to a "stored as binary XML" on page 1-6 on the installation guide, I guess that makes Oracle refers to a BLOB that contains an XML reference, but I can't be sure.
  
  Someone has an idea that they could share? I just want to confirm that we do not have to upgrade our source and target DBs at 11.2.0.3 by searching in the database is possible to confirm that the above 3 data types are not used by the application.
  
  Thanks in advance for any help.
  Tony G

  You should find XML columns stored in binary form or CLOB using the DBA_XML_TAB_COLS view referenced in http://docs.oracle.com/cd/E11882_01/appdev.112/e23094/xdb01int.htm#g644983.

  You should find XML tables using storage relational object in the view DBA_OBJECT_TABLES with:

  select
  owner,
  table_name,
  table_type
  from
  dba_object_tables
  where
  table_type='XMLTYPE';
  

  To abstract data type, you can query DBA_TAB_COLUMNS using ADT as literal for DATA_TYPE column:

  SQL> select * from v$version;
  
  BANNER
  --------------------------------------------------------------------------------
  Oracle Database 11g Express Edition Release 11.2.0.2.0 - Production
  PL/SQL Release 11.2.0.2.0 - Production
  CORE    11.2.0.2.0      Production
  TNS for 32-bit Windows: Version 11.2.0.2.0 - Production
  NLSRTL Version 11.2.0.2.0 - Production
  
  SQL> drop table t purge;
  
  Table dropped.
  
  SQL> drop type adt;
  
  Type dropped.
  
  SQL> --
  SQL> create type adt is object
    2  (
    3   c1 number,
    4   c2 varchar2(30)
    5  ) final
    6  /
  
  Type created.
  
  SQL> show errors
  No errors.
  SQL> create table t
    2  (
    3  c adt
    4  )
    5  /
  
  Table created.
  
  SQL> show errors
  No errors.
  SQL> --
  SQL> column table_name format a10
  SQL> column column_name format a10
  SQL> column data_type format a10
  SQL> select
    2  table_name,
    3  column_name,
    4  data_type
    5  from user_tab_columns
    6  where
    7  table_name='T';
  
  TABLE_NAME COLUMN_NAM DATA_TYPE
  ---------- ---------- ----------
  T          C          ADT
  

  Edited by: P. Forstmann on 8 Apr. 2013 20:28

  Edited by: P. Forstmann on 8 Apr. 2013 21:05

• Change data type for the column in a table - Oracle 8i

  Team,
  
  I need to change a VARCHAR2 column in number.
  
  ALTER table xyz change number abc;
  
  By giving the above statement, it says I need empty this column before you change.
  
  I can't change the data type before emptying this column.
  
  Please indicate any other solution. Give me some suggestions.
  
  Empty the column for me here BIG task.

  user11081688 wrote:
  I can't change the data type before emptying this column.

  Not according to the documentation:

  You can change the data type of any column or decrease the size of the entire column if all rows in the column contains NULL values.

  Please indicate any other solution. Give me some suggestions.

  You can add another column with the correct data type.

  ALTER TABLE xyz ADD COLUMN def NUMBER;
  UPDATE TABLE xyz SET def = TO_NUMBER(abc);
  ALTER TABLE xyz DROP COLUMN abc;
  ALTER TABLE xyz ADD COLUMN abc NUMBER;
  UPDATE TABLE xyz SET abc = def;
  ALTER TABEL xyz DROP COLUMN xyz;
  

  If I remember correctly, Oracle 8i does not support the change of name of column if this solution is a bit more complicated than 9i and above. Another option would be to create a new table with CREATE TABLE AS... SELECT, drop the old one and rename a new one to the old.

• match the number with the varchar data type

  Hi all
  
  I want to compare the number data type with string. Is this possible? I use the function to_char. The example below.
  

  SQL> select * from tab_a;
   
   PLOT_NUMBER
  ------------
             1
             2
             3
             4
             5
             6
   
  6 rows selected

  SQL> select * from tab_b;
   
  PLOT_NAME       PLOT_NUMBER
  --------------- ------------
  seawods         5
  bridge cros     2,4
  hill park       1
  bash hunk       3,6

   
  SQL> select a.*, b.* from tab_a a, tab_b b where to_char(a.plot_number)=b.plot_number;
   
   PLOT_NUMBER PLOT_NAME       PLOT_NUMBER
  ------------ --------------- ------------
             1 hill park       1
             5 seawods         5

  as you can see here this number of parcel 2, 4, and plot_number 3.6 not reported because they are string.
  
  Can anyone please suggest what can do us in this case.
  
  I can't do chane data type.
  
  Thanks in advance
  SAZ

  What you can do in the case?

  Drop table table_b purge

  as the 'design' of this table is obviously out of whack, and the content should have been

  PLOT_NAME       PLOT_NUMBER
  --------------- ------------
  seawods         5
  bridge cros     2
  bridge cros     4
  hill park       1
  bash hunk       3
  bash hunk       6
  

  You now have the instr function to the "join".
  I would recommend standardization of the design. NOW

  -----------------
  Sybrand Bakker
  Senior Oracle DBA