Time to Conversion Timestamp problem string
Hello
I tried to convert the time string timestamp, but I failed. What is wrong with it? I need a timestamp to create waveforms.
Hi beginner,
use ScanFromString:
Tags: NI Software
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How do I add time to the timestamp string
Hello
I have a problem with the addition of time to a timestamp string that is shown on the image below.
What I need is to add some time for example. 1 hour, but if this change happens between 23:00 and 00:00, I need to change the date.
Wanted for example results:
14:53, 22.4.2015. --> 15:53, 22.4.2015.
23:33, 22.4.2015. --> 00:33, 23.4.2015.
Help, please
Use the time to get based on seconds to get the time, use this form to add and subtract the time (to add an hour, simply add 60 * 60 seconds), use the entry timestamp in the Format Date/time function when you want an implementation of the chain.
Bob Schor
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Hello, I am working on an application targeting the OS version 4.5.x. I read a lot of messages and the links on this topic and can't seem to make the correct code.
OK, here's the problem. I ask a timestamp date string to a server. The timestamp is the local time on the server (IS / PST etc.) and not GMT.
My application must take time and subtract a number of days ranging from 1 day to 1 month. to get a "start" date The application must then provide the start and end date in a string format that it understands. Seems simple isn't?
Here's the catch, however the time stamps should NOT be changed by the local what is using the device. For example, a device in Italy can contact the server located in Ottawa and ask a timestamp, the calculations shouldn't care about DST or time zone. Just take the supplied date and subtract a fixed number of days from her. Nothing more or less. This proved incredibly hard to do. first the HttpDateParser.parse (ServerTimeStamp) will be the subject of Date GMT and my problem is back to the zone specified in ServerTimeStamp.
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My method
public String getDAFIXMLRange (String ServerTimeStamp) {}
String szRange;
First analyze the incoming date and record them at the time of the last election.
Day DAFIEndDate = new Date (HttpDateParser.parse (ServerTimeStamp));
m_lLastPollTime = DAFIEndDate.getTime ();
define the offset. Pre-programmed for simplification.
lOffsetNumberOfSeconds long = 2 * 24 * 60 * 60;
Calculate the start date by subtracting the offset. Multiply by 1000 to convert to milliseconds!
Date DAFIStartDate = new Date (DAFIEndDate.getTime () - (lOffsetNumberOfSeconds * 1000));!!!!!!!!!!!!! HOW the DATEFORMAT OBJECT is used to get the output format ' yyyy-MM-dd' you HH: mm: "without the marker of time zone. The server knows that it is local to it. !!!!!!!!!!
Now format the objects date as a string that includes the XML server.
DateFormat DafiDateFormat = DateFormat.getInstance (); ' YYYY-MM-dd' you HH.!!!!!!!!!!!!!! THIS IS THE PART I'M CONFUSED on, with the HELP of zone to create the good date. !!!
Time zone tz = TimeZone.getTimeZone ("IS");
int adjEST = tz.getRawOffset ();Convert 'em in string format.
String szDAFIStart = DafiDateFormat.format (DAFIStartDate);
String szDAFIEnd = DafiDateFormat.format (DAFIEndDate);Replace the date calculated in the end segment ranges date XML.
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}Hello
Yes would be better if the server could provide you date to the GMT time zone, or date as a long.
But if you can't ask the case on the server, one way might be to manually parse your string and create a new date of parameter values in a calendar, something like this
Calendar cal = Calendar.GetInstance ();
Cal.Set (Calendar.DAY_OF_MONTH, date)
Cal.Set (Calendar.MONTH, month-1)
Cal.Set (Calendar.YEAR, year);
' set the new time with the values, you must cal.setTime (cal.getTime ()-,...);
and then put the date with SimpleDateFormat.
I think that this could be a solution if you know the format string you recived that date and it won't change.
I'm not sure but maybe it could be a solution.
Kind regards
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Hello.
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Thank you very much
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If I understand correctly, then you can try something like this:
The formula in B2:
= LEFT (A, 8)
This removes SSTC and leaves a string of numbers that is able to recognize as a time.
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The result will be a string date and time, where the cell was formatted in does not show the part of the date.
SG
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We have treatment that uses hourly (as a shift of the day of treatment). I want to 'get' the time contained in a timestamp, so that I can compare it to one of our differences for example (pseudocode)
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I thought that "extract" was the right way to get the time portion of the time stamp, but it returns an interval based on UTC - so where I could expect
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During the first boot of a cRIO-9075, it shows in a TimeStamp, a time indicator system around 16:00 on 31 December 1969.
If I take this timestamp value and pass it in a "Format Date/time string function" to get a string representation of the time stamp, the date and time the chain gets really messed up. The same code to run on a Windows system works perfectly.
This could be the cause of the function format-stamp-to-string to fail on the cRIO?
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The time of LV start date is January 1, 1904 midnight GMT. Since your shows up to 6 hours before that, he must be GMT - 6. My horodateurs base are 19:00 31/12/1903, which is GMT - 5. Eastern time zone.
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You empty an array of waveform data to add. The default waveform has a T0 zero and a detachment of the 1. In the Sub - VI of waveform append inside your Subvi if dt' it does not raise an error, (in fact a caveat being the 1802 error code is positive.). But she proceeds to add data and use the dt and T0 the first waveform which is initially as the default data in the initial iteration. I think that if you start with an array of wavefrom that has the number of channels of the need, an empty array of Y, but a correct dt. Then the dt should be correct. That, or you can put in your Subvi a case structure where the first call, or if the incoming waveform is empty, it is not add and uses only the 2nd waveform.
You have also a little a Rube Goldberg enters your Subvi. It could be simplified as shown in the picture as an attachment.
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