Train hard calculate amounts

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  Hello
  
  I have a read-only view object named 'ConnectionVVO '. And there the database field name ' points of "(type is number)."»
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• need to sum all the sal

  My dear

  This query, I know sal sum in dept by job is

  I have to add new coumn in sum to give query for all dept

  and new line give sum for each Department

  as a matrix report

  WITH pivot_data AS (SELECT deptno, job, sal FROM emp)

  SELECT "JOB."

  "10."

  "20."

  '30 ',.

  "40".

  OF pivot_data PIVOT (SUM (sal)

  FOR deptno

  (10, 20, 30, 40)

  )

  Hello

  So, besides the total sal for each combination of deptno and job, you want also totals for each jdeptno (regardless of the job) and work (regardless of deptno) and a total general (no matter the deptno and employment).  This sounds like a job for the CUBE.  The following soLution uses the CUBE to calculate amounts and then uses the PIVOT just to combine lines.

  WITH all_jobs AS

  (

  SELECT DISTINCT job

  FROM scott.emp

  )

  data_to_pivot AS

  (

  SELECT deptno NVL (d.deptno, - 1)

  , NVL (j.job, 'ALL') AS job

  , NVL (SUM (e.sal), 0) AS sal

  GROUPING (j.job) AS job_agg

  OF scott.dept d

  CROSS JOIN all_jobs j

  LEFT OUTER JOIN scott.emp e ON e.deptno = d.deptno

  AND e.job = j.job

  GROUP BY CUBE (d.deptno, j.job)

  )

  Simply SELECT employment, '10', all_depts '20', '30', '40', - or everything *, if you don't mind saw job_agg

  OF data_to_pivot

  PIVOT (MIN (sal)

  TO deptno IN (10, 20, 30, 40

  All_depts AS-1

  )

  )

  ORDER BY job_agg

  work

  ;

  Output:

  ALL_DEPTS 10 20 30 40 JOB

  --------- ----- ----- ----- ----- ---------

  0 6000 0 0 6000 ANALYST

  1300 1900 950 0 4150 CLERK

  MANAGER OF 2450 2975 2850 0 8275

  THE PRESIDENT 5000 0 0 0 5000

  0 0 5600 0 5600 SELLER

  ALL THE 8750 10875 9400 0 29025

  Instead of deriving a "table" of all possible jobs, you should be able to use a partitioned outer join, something like this:

  WITH pivot_data AS

  (

  SELECT deptno NVL (d.deptno, - 1)

  , NVL (e.job, 'ALL') AS job

  , NVL (SUM (e.sal), 0) AS sal

  GROUPING (employment) AS job_agg

  OF scott.dept d

  LEFT OUTER JOIN scott.emp e PARTITION BY (e.job)

  ON e.deptno = d.deptno

  GROUP BY CUBE (e.job, d.deptno)

  )

  SELECT *.

  OF pivot_data

  PIVOT (MIN (sal)

  TO deptno IN (10, 20, 30, 40

  All_depts AS-1

  )

  )

  ORDER BY job_agg, job

  ;

  But the only effect of the outer join partitioned seems to cause CUBE to abandon some Super aggregates.  I do something ridiculous in this second request, or there is a bug in my version (11.2.0.2.0 Express).

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• Case statement does not work

  Dear all,

  We have the database oracle 11g r2 on windows.

  I created under function: -.

  SQL > CREATE OR REPLACE FUNCTION FUNC_TEST (P_TEST VARCHAR2)

  2 RETURN VARCHAR2

  3 AS

  4 V_TEST VARCHAR2 (20);

  5

  6 BEGIN

  7

  8 V_TEST: = P_TEST;

  9

  10

  11 CASES

  12. WHEN V_TEST = UPPER ('%UU%') THEN V_TEST: = REPLACE (V_TEST, 'UU', 'U');

  13. WHEN V_TEST = UPPER ('%OO%') THEN V_TEST: = REPLACE (V_TEST, 'OO', 'O');

  14. WHAT V_TEST = UPPER ('%NN%') THEN V_TEST: = REPLACE(V_TEST,'NN','N');

  15 ELSE V_TEST: = "CHANCHAL";

  END 16 CASES;

  17

  18

  19 V_TEST RETURN;

  20 EXCEPTION SO THAT OTHERS THEN

  21 DBMS_OUTPUT. PUT_LINE (' THERE IS AN ERROR ');

  22 END;

  23.

  The function is created.

  SQL > SHOW ERR

  No errors.

  SQL > SELECT FUNC_TEST('toon') FROM DUAL;

  FUNC_TEST ('TOON')

  --------------------------------------------------------------------------------

  CHANCHAL

  above function should show 'YOUR' build 'Toon' but its display "CHANCHAL";

  I train hard get the result OK but could not get it.

  Any suggestions would be very helpful.

  Kind regards
  Chanchal wankhade.

  Hello

  Chanchal Wankhade wrote:

  Dear all,

  We have the database oracle 11g r2 on windows.

  I created under function: -.

  SQL > CREATE OR REPLACE FUNCTION FUNC_TEST (P_TEST VARCHAR2)

  2 RETURN VARCHAR2

  3 AS

  4 V_TEST VARCHAR2 (20);

  5

  6 BEGIN

  7

  8 V_TEST: = P_TEST;

  9

  10

  11 CASES

  12. WHEN V_TEST = UPPER ('%UU%') THEN V_TEST: = REPLACE (V_TEST, 'UU', 'U');

  13. WHEN V_TEST = UPPER ('%OO%') THEN V_TEST: = REPLACE (V_TEST, 'OO', 'O');

  14. WHAT V_TEST = UPPER ('%NN%') THEN V_TEST: = REPLACE(V_TEST,'NN','N');

  15 ELSE V_TEST: = "CHANCHAL";

  END 16 CASES;

  17

  18

  19 V_TEST RETURN;

  20 EXCEPTION SO THAT OTHERS THEN

  21 DBMS_OUTPUT. PUT_LINE (' THERE IS AN ERROR ');

  22 END;

  23.

  The function is created.

  SQL > SHOW ERR

  No errors.

  SQL > SELECT FUNC_TEST('toon') FROM DUAL;

  FUNC_TEST ('TOON')

  --------------------------------------------------------------------------------

  CHANCHAL

  above function should show 'YOUR' build 'Toon' but its display "CHANCHAL";

  I train hard get the result OK but could not get it.

  Any suggestions would be very helpful.

  Kind regards
  Chanchal wankhade.

  I think you meant:

  CASE

  WHEN SUPERIOR (V_TEST) LIKE "% UU" THEN V_TEST: = REPLACE (UPPER (V_TEST), 'UU', 'U');

  WHEN SUPERIOR (V_TEST) LIKE '% OO %' THEN V_TEST: = REPLACE (UPPER (V_TEST), 'OO', 'O');

  ...

  '%' is a wildcard character only on the right-hand side of the LIKE operator. '%' has no particular meaning when you use the = operator.

  You can also use a CASE expression, rather than a CASE statement to this:

  v_test: = UPPER (p_test);

  v_test: = BOX

  WHEN v_test LIKE "% UU" THEN REPLACE (v_test, 'UU', 'U')

  WHEN v_test LIKE "% UU" THEN REPLACE (v_test, 'OO', 'o')

  ...

  END;

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  app.endPriv ();

  }

  );

  It happens with a specific file? Are you sure that the file path is correct?

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