Two tasks that share the same resource in sequence

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• Issue of multiple Disqualification tasks that use the same snapshot

  Details of the environment

  ======================

  Disqualification Version: 12.1.3.0.0

  
  

  A snapshot has been created in which the WHERE clause is outsourced and this snapshot table is used in a data quality process.

  Since there are different values passed to the WHERE clause, different jobs who have their own data quality process, but these process reads from the same snapshot table.

  Disqualification does not allow execution of different tasks that uses the same shot to run at the same time.

  Job1 is in operation, job2 throws an exception that the snapshot is locked.

  Any reason why Disqualification has this restriction? Processes are just doing a read on the snapshot table operation, so I was wondering why it was necessary to lock the object.

  We have more than 60 jobs that use the same snapshot and it would inhibit scalability if we are forced to run 60 jobs in sequence and not allow them to run in parallel.

  Can you advice how to fix this problem?

  The short answer is that each task must be executed with his own label of execution. Otherwise, each work is actually being run in the same context, and you will have problems of blocking.

  Please read on the labels of the execution and run profiles in the online help.

  Note that when running with a label of execution, complete results are not written; you need to decide exactly what to write work featuring the views of results you need. All data staged (including the snapshot itself) will be written with a label execution context and you can view the results in the Console of the server. Director will only show the results of the last run.

• two elements that have the same source

  Hi guys,.
  
  I am trying to use the display on a Google Map plugin location. As I had this plugin requires two elements that have the same source:
  
  Article 1 - A text to insert the value (address) in the database. The source of this question would be 'MAP' column.
  2 - Google Map plugin ELEMENT to visualize on the map. The source of this issue should also be "Map" the column that is used to read the address.
  
  But the problem, as you saw, we can not create a new record if we have two items with the same source. How can I get around this?
  
  Here is the link to the plugin:
  
  http://Apex.Oracle.com/pls/Apex/f?p=plugins:LOCATION_MAP:2943553726537511
  
  Kind regards
  Fateh
  
  Published by: Fateh July 21, 2011 02:52

  Hi Fateh,

  Tried the plugin you mentioned! Had a preview of your problem.
  >
  I am trying to use the display on a Google Map plugin location. As I had this plugin requires two elements that have the same source
  >
  As your form seems to be running automatic process line processing DML that will obviously give an error if you have two items
  with the same source i.e. 'MAP' that is your database column.
  >
  Article 1 - A text to insert the value (address) in the database. The source of this question would be 'MAP' column.
  >
  I think that this point is already with you as you may have created form based on a Table or form and report based on a Table.
  Leave the source of this article because it's IE card - the database column.
  >
  2 - Google Map plugin ELEMENT to visualize on the map.
  >
  Change the source of this article as:
  Source type: static assignment (value corresponds to the source attribute)
  Source of value or expression:

  &P1_ADDRESS.
  

  Where P1_ADDRESS is the element:
  >
  Article 1 - A text to insert the value (address) in the database. The source of this question would be 'MAP' column.
  >

  I hope that helps!
  Kind regards
  Kiran

• 3 different comboboxes that share the same dataprovider

  Is it possible to have separate such FilterFunction for each other without having different 3 of dataprovider if I have 3 different comboboxes that share the same dataprovider?

  Well, you have to build different data providers. For example,.

  var sharedSource:Array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

  var dp1:ArrayCollection = new ArrayCollection (sharedSource);

  DP1.FilterFunction = function(o:Object):Boolean {return int (o)< 5;="">

  var dp2:ArrayCollection = new ArrayCollection (sharedSource);

  DP2.FilterFunction = function(o:Object):Boolean {return int (o) % 2! = 0 ;};}

  var dp3:ArrayCollection = new ArrayCollection (sharedSource);

  DP3.FilterFunction = function(o:Object):Boolean {return int (o) > 6 ;};}

• Two virts never share the same host... What are my options?

  Hi all

  Ive got two virts which are nearly identical and work in an active/active load. What are the options I have to ensure that these two virts never end up on the same physical host?

  I'm not looking for FT. I'll have two functional virts at the same time.

  Thank you!

  You can do this by setting VM - VM DRS anti affinity rules.

  André

• How to stop the connectivity between two computers that use the same IP address... ?

  Today, I managed to connect two computers with the same IP address. But now it is to be feared. for example, a person can access my computers using my IP and MAC address. So now, how can I stop the connectivity between these two computers. should what setting I use to stop.

  Tahnks.

  Hello

  1 have. what measures you taken to connect 2 computers with the same IP address?

  2. How are the 2 computers connected?

  3. how exactly you want to stop the connectivity between 2 computers?

  I want to tell you that 2 computers on the same network cannot have the same address. Each machine must have a unique address to identify it. A private network, as a home network connected to the internet, can be connected to a router to connect to the network, will have only 1 address, public IP address.

  In addition, if we know the IP address of a computer along the user ID and password, we can access the computer/shared files.

   
  If you are referring to the change of the IP address of the two computers, you can follow these steps and check.
   
  a. network connections open. Click the Start button, and then click Control Panel. In the search box, type 'adapter' and then, under center network and sharing, click view network connections.
  b. right click on the connection you want to change. Click on properties. If you are prompted for an administrator password or a confirmation, type the password or provide confirmation.
  c. click on the network tab. Under this connection uses the following items, click Internet Protocol Version 4 (TCP/IPv4) or Internet Protocol Version 6 (TCP/IPv6), and then click the properties button. To specify your IP for IPv4, click on use the following IP address, and then, at the address IP, subnet mask, and gateway boxes by default, type IP address settings.
   
  A typical IPv4 address looks like 192.168.0.2; a typical subnet mask is 255.255.255.0. The default gateway is usually the address of your router.
  For example, IP address: 192.168.0.2 by 192.168.0.12 (for computers)
  Subnet mask: 255.255.255.0
  DNS: 192.168.0.1
   

  I hope this helps. If you have any other queries/issues related to Windows, write us and we will be happy to help you further.

• Allows to print on a printer connected to an iMac that share the same portable router Windows7?

  I have a small home network with an iMac and a HPLaptop running Windows 7 and use the same access to the internet router.  The Windows 7 laptop to print on the printer connected to the iMac?

  I have a small home network with an iMac and a HPLaptop running Windows 7 and use the same access to the internet router.  The Windows 7 laptop to print on the printer connected to the iMac?

  Not really a Windows problem... More to find out how to SHARE the resources of your macintosh.
   
  http://support.Apple.com/kb/PH11450

• Two virtual machines share the same physical network adapter

  I have a virtual network adapter that I linked to a physical network adapter on my box where two virtual machines are running.

  I assigned two virtual machines to this vmnet adapter.

  On one I can ping other machines of physics on the same subnet as the physical computer, but the other VM can ping only other virtual machines.

  When I try to ping from one physical computer to this virtual machine I get the error message windows "ping transmission has failed. General failure. ».

  Is what I'm trying to are not not possible?

  First thing to do is to ensure the automatic bypass is enabled disabled in the VMnet virtual network editor your use to the bridge to.

  Second need to see the output of ipconfig/all on the Windows host and guests and or ifconfig on the Linux host and or guests.

  DO NOT copy and paste the output directly in the body of the response rather redirect the output of the commands in a text file and then archive (compress) files in a single zip archive and attach it to an answer.

  You can use the following example:

  Under Windows:

  ipconfig/all > "% USERPROFILE%\Desktop\host_ipconfig.txt".

  ipconfig/all > "%USERPROFILE%\Desktop\guest (n) _ipconfig.txt".

  Linux:

  ifconfig > ~/Desktop/host_ipconfig.txt

  ifconfig > ~/Desktop/guest (n) _ipconfig.txt

  Also include in the archive .zip .vmx and vmware*.log for two Virtual Machines configuration files.

• iPhones share the same id

  I have 2 iphones that share the same appleid. One is essentially one clone of the other. It worked successfully for some time, but on a reset caused by one of the phones stop, 2 phones have been connected together somehow. Both sound when someone calls one of the numbers (but not vice versa) and both get the same texts sent to one or the other

  Reading some of these blogs, it seems that the only way to 'decouple' them is to create an id for each phone and let them live their own lives; but we only have one e-mail address and don't really want to set up another

  Help

  You can stop the calls in

  Settings - Phone - calls on other devices - OFF toggle

  Also IF the phones have different numbers

  Settings - Messages - Send and Receive - disable and remove the Apple ID from there, leaving only the verified number

  This should stop the cross-over if all goes well

• A target table is in charge of two different sources but the same columns, but a source is one database and another in a flat file.

  We all hope you are doing well.

  I have a business problem to implement in ODI 11 G. It's here. I'm trying to load a target table from two sources that have the same column names. But a source is to the file format and the other is in the Oracle database.

  That's what I think I'll create two mappings in the same interface by using the Union between the sources. But I don't know how the interface would connect to different logical architecture to connect to two different sources.

  Thank you

  SM

  You are on the right track, all in a single interface. Follow these steps

  (1) pull model of your data in the designer of the source file and your table model target to the target pane.

  (2) all relevant columns map

  (3) in the source designer to create a new dataset and choose as the UNION join type (this will create a separate tab in the source designer pane)

  (4) select the new dataset tab in the source designer pane and pull your source oracle table data model in the designer of the source. All columns that are relevant to the target card

  (5) make sure that your staging location is set to a relational technology i.e. in this case the target would be an ideal candidate because it is where the ODI will organize the data from source two files and oracle and perform the UNION before loading to the target

  If you want to watch some pretty screenshots showing the steps above, take a look at http://odiexperts.com/11g-oracle-data-integrator-part-611g-union-minus-intersect/

• Two computers share the same wi - fi Modem. When A computer reads a message that is marked as read on two PCs, not allowing computer B see what needs to be read.

  Two computers share the same WI - fi Modem. When A computer reads a message that is marked as read on the two PC, not allowing the B to see what still needs to be read. Email is Thunderbird.
  Please help, thank you for this option online support

  I should add that if you operate the account using Pop then messages can be left on the server without any indication that they have been read. You define each customer to leave them on the server.

  However if you don't know what messages have been read, I know not how will you know which ones to delete and when to do it. Without active maintenance your server could quickly become full.

• How do I keep my wifes calls appear on my phone and mine appear on hers, we share the same acct icloud and itunes? It just started this on one or two updates ago

  How do I keep my wifes calls appear on my phone and mine appear on hers, we share the same acct icloud and itunes? It just started this on one or two updates ago

  Welcome to the Apple community.

  I'm afraid that is what happens when you share an Apple ID.

  Ideally you should each have your own ID and use family share for share purchases, but at least you would be better to have your own ID's for everything except iTunes.

  I suspect that your problem is that you share an ID for FaceTime, you must either stop this or make sure that you have only and that your caller ID is only your phone number.

• two user profiles on vista will share the same applications on hard drive

  my granddaughter has created two user profiles on vista with variations of his name.  can copy icons above his profile from first to second?

  Hello

  Yes, it is possible to share the same applications on the hard drive by using two or more different user accounts in Windows Vista.

  For more information see the link below.

  http://Windows.Microsoft.com/en-us/Windows-Vista/demo-understanding-user-accounts

• 'NUMBER of IP' received a very short message that my PC share the same IP number as another system...

  , I used my desktop PC and a pop-up message briefly appeared on my screen... I saw only part of the message because he was then briefly on my screen and I didn't get in time. What I did ise in the message was "My PC shares the same number as another system of intellectual property... I saw the message from but nobody knows what can happen here and how I can solve the problem, is there a... Also if I'm not mistaken, I also saw something about all the help is much appreciated...

  Thank you very much
  Marvin
  P.S. I am running Windows 7 Home Premium...  I am also very good with instructions so it is not that I'll forget everything that said "PLEASE" help if you can...  I don't want to screw up my PC!

  usually in a home network the IP address is assigned automatically by the router to each device network from a range of ip addresses. Your problem may occur if you set a static IP address to a network device and it is in the range of addresses used by the router.

  For example on my router, it begins to assign addresses to 192.168.2.2. then the following it would assign would be 192.168.2.3, then 192.168.2.4 and so on and so forth until it reached 192.168.2.100.  After that, it will start again.  You have all the devices to which you have assigned a static IP address on your network, if so you will need to assign outside the range the router is using.  With the help of my linksys router for example 192.168.2.101 or higher.  If you don't assign a static IP address to your all your networked devices, just restart the pc and the router should solve it easily.

  Good luck

  Chris

• If two objects are the same resource in the library, how can I check it?

  Seen as below in the code, I created two objects of an object in the library. When you click it, the trace says

  object sample_mc for both. So, how can I check it in the code if several objects are of the same resource of the library...

  
  var a1:MovieClip = new sample_mc();
  var a2:MovieClip = new sample_mc();
  var arr:Array = new Array();
  addChild (a1);
  addChild (a2);
  A1.x = 50;
  A1.y = 50;
  A2.x = 150;
  A2.y = 50;

  A1.addEventListener (MouseEvent.Click, f_achil);
  A2.addEventListener (MouseEvent.Click, f_achil);

  
  function f_achil(event:MouseEvent):void {}
  trace (Event.Target);
  If (arr. Length < 2) {}
  arr.push (Event.currentTarget) ;}
  trace ("arr:" + arr);
  {if(arr[0]==arr[1])}
  trace ("OK") ;}
  }

  Yes! But there is a work around to get the class name using the getQualifiedClassName . Now you get success. under the rocks of code for you:

  If (getQualifiedClassName (Object(arr[0])) == getQualifiedClassName (Object(arr[1])))
  trace ("OK");

  It will now compare with your class name at last. Cast object is optional.