Update of a Base Table in a view with a UNPIVOT function.
HelloI have a requirement to upgrade a Base Table in a view.
This view has the query by using a function of the UNPIVOT operator to display the columns in the tables of the basic of the lines.
I need to update/insert in / remove the Base Table by accessing the view (the user has access to the Base Table, so the DML on the view).
Here is the table I created:-
CREATE TABLE PERSON_DETAILS
(
PID VARCHAR2(10 BYTE),
FIRSTNAME VARCHAR2(1000 BYTE),
LASTNAME VARCHAR2(1000 BYTE),
PHONENUMBER VARCHAR2(1000 BYTE),
ADDRESS1 VARCHAR2(1000 BYTE),
ADDRESS2 VARCHAR2(1000 BYTE),
COUNTRY_CODE VARCHAR2(1000 BYTE),
LANGUAGE_CODE VARCHAR2(1000 BYTE),
EMAIL VARCHAR2(1000 BYTE)
)insert into person_details values ('1','XYZ','ABC','1234567890','India','Asia','IN','EN','[email protected]');
insert into person_details values ('2','XYZ2','ABC2','1234567890','India','Asia','IN','EN','[email protected]');CREATE OR REPLACE FORCE VIEW PERSON_DETAILS_VIEW
(
PID,
CD_NAME,
CD_VALUE
)
AS
SELECT "PID", "CD_NAME", "CD_VALUE"
FROM person_details UNPIVOT INCLUDE NULLS (cd_value
FOR cd_name
IN (firstname AS 'First Name',
lastname AS 'Last Name',
phonenumber AS 'Phonenumber',
address1 AS 'address1',
address2 AS 'address2',
country_code AS 'Country Code',
language_code AS 'Language Code',
email AS 'Email') );PID CD_NAME CD_VALUE
1 First Name XYZ
1 Last Name ABC
1 Phonenumber 1234567890
1 address1 India
1 address2 Asia
1 Country Code IN
1 Language Code EN
1 Email [email protected]
2 First Name XYZ2
2 Last Name ABC2
2 Phonenumber 1234567890
2 address1 India
2 address2 Asia
2 Country Code IN
2 Language Code EN
2 Email [email protected]update person_details_view
set cd_value = 'US' where CD_NAME = 'IN'I understand that I can write an INSTEAD OF trigger, but I don't know what logic to write in the trigger so that the condition is met.
My Version of Oracle
Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
PL/SQL Release 11.1.0.7.0 - Production
CORE 11.1.0.7.0 Production
TNS for Solaris: Version 11.1.0.7.0 - Production
NLSRTL Version 11.1.0.7.0 - ProductionThank you
Ankit Khare.
Published by: Ankit_Khare84 on June 28, 2012 14:47
It is definitely possible with an INSTEAD of trigger.
for example:
create or replace
TRIGGER ioft_person
INSTEAD OF UPDATE
ON person_details_view
FOR EACH ROW
declare
firstname1 person_details.firstname%type;
BEGIN
SELECT firstname_new into firstname1
FROM (SELECT pid, cd_name, cd_value
FROM
(
select * from person_details_view where (pid, cd_name) not in (select :new.pid, :new.cd_name from dual)
union all
select :new.pid, :new.cd_name, :new.cd_value from dual
)
)
PIVOT ( max(cd_value) AS new FOR (cd_name) IN
('First Name' AS firstname,
'Last Name' as lastname,
'Phonenumber' as phonenumber,
'address1' as address1,
'address2' AS address2,
'Country Code' as country_code,
'Language Code' as language_code,
'Email' as email
)
) where pid = :old.pid;
UPDATE person_details
SET firstname = firstname1
WHERE pid = :old.pid;
END ioft_role_perm;
and that run
update person_details_view
set cd_value = 'X|X' where cd_name = 'First Name' and pid=1
The logic is: you need to convert back the view through swivel
Tags: Database
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I am trying to create a trigger that updates instead of to day joined several tables in a view, but I can't get my trigger to work. The create view command was as follows:
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When I created first the relaxation above in SQLdeveloper it seems to run constantly. Then my computer crashed, not related to this work, and I lost session because I did not commit it. I was not ready to commit it because I believe that something is wrong.
I am in the trigger syntax correctly and I go about it in the right way? I want to only update the rows that have changed, that's why I was using: NEWS and: OLD.
Kind regards
Tim
Published by: user467357 on November 18, 2008 18:07
I modified my script a little because there were a few errors. for example. start and old as old and view name typoSomething like this->
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Kind regards.
LOULOU.
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NEXT
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AS
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SY.
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http://docs.Oracle.com/CD/B19306_01/server.102/b14223/basicmv.htm
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********************************
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>
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>
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>
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>
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>
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>
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>
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>
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>
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>
I need some information on 'base/local table base table' - what?
>
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See the doc of database Concepts
http://docs.Oracle.com/CD/B28359_01/server.111/b28318/schema.htm
>
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Of course, you can set src.err_length in the USING clause (where you can reference all_tab_columns) and use this value in the SET clause.
It is:MERGE INTO staging_table dst USING ( WITH got_lengths AS ( SELECT MAX (CASE WHEN column_name = 'ENAME' THEN data_length END) AS ename_len , MAX (CASE WHEN column_name = 'JOB' THEN data_length END) AS job_len FROM all_tab_columns WHERE owner = 'SCOTT' AND table_name = 'EMP' ) SELECT s.ename , s.job , CASE WHEN LENGTH (s.ename) > l.ename_len THEN 'ENAME ' END || CASE WHEN LENGTH (s.job) > l.job_len THEN 'JOB ' END AS err_length FROM staging_table s JOIN got_lengths l ON LENGTH (s.ename) > l.ename_len OR LENGTH (s.job) > l.job_len ) src ON (src.ename = dst.ename) WHEN MATCHED THEN UPDATE SET dst.err_length = src.err_length ;As you can see, you have to hardcode the names of the columns common to several places. I swam () to simplify that, but I found an interesting (at least for me) alternative grouping function involving the STRAGG user_defined.
As you can see, only the subquery USING is changed.MERGE INTO staging_table dst USING ( SELECT s.ename , s.job , STRAGG (l.column_name) AS err_length FROM staging_table s JOIN all_tab_columns l ON l.data_length < LENGTH ( CASE l.column_name WHEN 'ENAME' THEN ename WHEN 'JOB' THEN job END ) WHERE l.owner = 'SCOTT' AND l.table_name = 'EMP' AND l.data_type = 'VARCHAR2' GROUP BY s.ename , s.job ) src ON (src.ename = dst.ename) WHEN MATCHED THEN UPDATE SET dst.err_length = src.err_length ;Instead of the user-defined STRAGG (that you can copy from AskTom), you can also use the undocumented, or from Oracle 11.2, WM_CONCAT LISTAGG built-in function.
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trigger for update field in a table with the sum of the fields to another table
My experience in creation of triggers and pl/sql in general can be described in terms of oracle with the null value. I practiced by creating arrays and applications on my personal server at home to help me with some of my work related tasks. Right now I am creating a trigger which will, after insert, update, delete on the update of the table assignment_time_track the area of the time_spent on the table of assignments with the sum of the time_spent on the assignment_time_track table fields. I hope that run on the sentence it is clear to the people other than me. I tried this script on my own using the tool of creation of trigger for Oracle Database Express Edition, but I get the following error:
Create a trigger failed, for the following reason:
ORA-06552: PL/SQL: ORA-06553 finished Compilation unit analysis: PLS-320: the declaration of the type of the expression is incomplete or incorrect
Here is my attempt to create the trigger on my own.
create or replace trigger "ASSIGNMENT_TIME_TRACK_T1".
AFTER
INSERT or update or delete on 'ASSIGNMENT_TIME_TRACK '.
for each line
Start
update assignments
Set time_spent = (select sum (time_spent)
of assignment_time_track
where assignment_time_track.name = assignments.name);
end;
/
If what I posted is not clear or more detail is needed, let me know and I will respond with a full description of tables and my goals for each table. Thanks in advance for any help. I also gladly accepts links to tutorials or lessons that explain how to do this kind of thing.
Published by: bobonthenet on March 9, 2009 14:01I think I understand what you mean :)
Rather than use a trigger to keep the master table (assignments) in sync with the time spent on the details, it would be much easier to use a query to do this, maybe creating a view.
Something along the lines of
SQL> create table assignments 2 (id number primary key 3 ,name varchar2(10) 4 ); Table created. SQL> SQL> create table assignment_time_tbl 2 (id number primary key 3 ,assid number references assignments 4 ,time_spent number 5 ); Table created. SQL> SQL> insert into assignments 2 select rownum 3 , 'a' 4 from all_objects 5 where rownum < 5 6 / 4 rows created. SQL> SQL> insert into assignment_time_tbl 2 select rownum 3 , rownum 4 , rownum * 3 5 from all_objects 6 where rownum < 5 7 / 4 rows created. SQL> SQL> commit; Commit complete. SQL> SQL> SQL> select a.id 2 , a.name 3 , (select sum (time_spent) 4 from assignment_time_tbl 5 where assid = a.id 6 ) 7 from assignments a 8 / ID NAME (SELECTSUM(TIME_SPENT)FROMASSIGNMENT_TIME_TBLWHEREASSID=A.ID) ---------- ---------- ------------------------------------------------------------- 1 a 3 2 a 6 3 a 9 4 a 12 -
Add FK between a table and a view?
Is this possible in 4.1 to add a FK between a table and a view (off of course)?
If I'm in a view, it seems that I can define a FK to another view or a table, but if I start with a table, some views appear in the list. The view already has a defined PK.
Is it normal?
Use case: I have a table of generic code, so I'm set up views on the code for each type of code table. Then, I want at least diagram CF from specific code view of the code typed column on a table for the sub.
Hello Kent,
Is this possible in 4.1 to add a FK between a table and a view (off of course)?
Yes. You can do this by clicking on the icon of the new foreign key above the diagram, then by selecting the view first, then the table.
I connected an enhancement request to allow a foreign key to a view to be added using the table properties dialog box.
Thanks for pointing it.
David
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How can I update query joining multiple tables.
Hi team,
I want to update a column of TABLE 1, but it should rally with TABLE 2. Under certain conditions, that it should be updated.
I created as below. But it does not work.
Can you please suggest me how can I do?
UPDATE Table1 SET Table1.Column1 = 'name' FROM Table1 T1, Table2 T2 WHERE T1.id = T2.id and T1.name = T2.Name And T1.id = UPDATE Table1 SET Table1.Column1 = 'name' FROM Table1 T1, Table2 T2 WHERE T1.id = T2.id and T1.id = '100';
Hello
Your update statement is not at all clear.
Something like below:
UPDATE Table1 T1
THE T1 VALUE. Column1 = 'name '.
WHERE EXISTS (SELECT 1 FROM Table2 T2 WHERE)
T1.ID = T2.id and T1.name = T2. (Name);
(Or)
UPDATE Table1 T1
THE T1 VALUE. Column1 = 'name '.
WHERE EXISTS (SELECT 1 FROM Table2 T2 WHERE)
T1.ID = T2.id and T1.name = T2. The name) and T1.id = '100';
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name of the dynamic table in a view
How can I create a view of a table whose name is dynamically determined?
for example, I have tables for each month table_2010401, the table_201402, the 201403 table and so on. I need to extract the data from the last table. This is more or less what I want to do:
CREATE OR REPLACE VIEW VW_TABLE
AS
SELECT * FROM
(SELECT TRIM (MAX (TABLE_NAME)) FROM ALL_TABLES WHERE TABLE_NAME LIKE 'POL_LINK %' AND OWNER = 'ACTUARYD')
);
Can anyone help? Thank you in advance.
Most approach simple and straight forward it would be to recreate every month a CURRENT_TABLE view or a synonym that points to a table 'current' - table_2010401 or table_20140301.
You can recreate this view, or synonym every month just after creating the table current.
Another approach would be to create a view based on a function of pipeline that derives from a necessary table name and uses dynamic SQL statements to get the lines of him to channel them in the view.
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Hi, I'm developing a simple mobile app in DW CC 2015 using JQuery Mobile. LIKE I need the list view with description of the product, functionality and image, I would like to connect with database instead of "writing" all the tables in the bearings inside the Jquery page. In the future I would also be able to add, to remove the DB records. Any help, tutorial... Thanks TG
I would like to connect with the database instead of "writing" all the tables in the bearings inside the Jquery page
This is usually done with a CMS (content management system). There are commercial products CMS like WordPress, Joomla and perch. You create one or several layouts and then create pages of these page layouts using the CMS. In this way, it is possible to have hundreds of pages, each with unique content, but a page layout that can be managed in a place of sharing.
CMSs on shelf don't require programming skills. Otherwise, some of us write our own CMS with custom functions, but this requires back-end, as with PHP programming.
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