Update the name of limit to the execution of the step

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  The WMP library works in mysterious ways and causes confusion - it took me a while to get the hang of it. WMP takes the news of the title of 'details' 'properties' rather than the file name, so I think that's what you need to change.

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• Problem of JMS deployment plan for updating the JNDI names

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• How mass update the display name for a group of existing emails?

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  Thank you

  Oubous khalid

  NOTE: If you consider your question/problem answered/resolved, please, rate this answer as Correct or useful.

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• Impossible to update the full name with post-process Manager field

  Hello

  I have a manager post-process that updates some fields when a user is changed. The post-process Manager update correctly the e-mail, and common name fields. However, for some unknown reason, I am unable to update the display name. There is no error message, but the value is not updated.

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  EntityManager entityManager = Platform.getService (EntityManager.class);

  HashMap < String, Object > uploading = new HashMap < String, Object > ();

  attrs.put (UserManagerConstants.AttributeName.DisplayName.GetId (), 'New value');

  entityManager.modifyEntity (orchestration.getTarget () .getType (), userEntityId, uploading);

  There also seems to be something different with the full name field. When I print all the fields and values for a particular user, I get something like:

  First name = John

  Family name = Doe

  Email = [email protected]

  [...]

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  Display name = {base = John Doe}

  I also tried to set a new value in the format "{base = new value}", but it does not work either.

  Am I missing something?

  Thank you

  -jtellier

  Display name must be placed in a Hashtable as follows:

  Map dispNameMap = new HashMap();
  dispNameMap.put ("base", lastName + "" + firstName); then pass this card as:

  Parameters.put ("Display Name", dispNameMap);

• Rookie here: I can't update the DNS where stands the domain name...

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• update the name of the Organization

  Hello
  We have a requirement for change of names of the Organization for some organizations.
  I checked the api and he said: update_organization cannot be used to update the name of the organization.
  So I used a command update on hr_all_organization_units for some organizations.
  (updated HR_ALL_ORGANIZATION_UNITS
  the game name = NewName
  where ORGANIZATION_ID =: ORGANIZATION_ID
  )
  
  My question is, I can see the new values in the hr_all_organization_units table, but in the application (super HRMS-> work structures-> organization), I see the old values only.
  
  Is there a program that must be run in order to reflect the new names or I missed a step or the method I used was bad?
  
  Your comments are much appreciated.
  
  Thank you.
  
  Kind regards
  Pascal Valley

  See the table of the TL -

  HR_ALL_ORGANIZATION_UNITS
  HR_ALL_ORGANIZATION_UNITS_TL
  

  See you soon,.
  Vignesh

• update the XML name by using sql

  Hello
  
  IAM using oracle 11g
  
  create table example (ch. clob);
  insert into a values (sample)
  ? XML version = "1.0"? (> < ABC > < company > < / ABC > < A employee > < name > < / name > < sex > M < / sex > < / employee > < employee > < name > B < / name > < sex > M < / sex > < / employee > < employee > < name > c < / name > < sex > F < / sex > < / employee > < / business > ');
  
  for example I want to update the 'ABC' to 'CDE' XML element
  
  ? XML version = "1.0"? (> < company > < ORDER > < / EBR > < A employee > < name > < / name > < sex > M < / sex > < / employee > < employee > < name > B < / name > < sex > M < / sex > < / employee > < employee > < name > c < / name > < sex > F < / sex > < / employee > < / company > ');
  
  
  How can I update this XML element name.
  
  I search the web, I found UPDATEXML it is used to change the value of XML. but I want to display xml name.
  
  Concerning
  Oracle user

  To start, if you want a pure XML solution, you should really use an XMLType column to store XML data in the first place.
  It allows several types of optimization takes place, according to the model of storage used.
  11 g, I highly recommend the use of binary XML storage (this is the default template from 11.2.0.2).

  IAM using oracle 11g

  What version exactly?

  On 11.2.0.3, you can use XQuery Update Facility:

  SQL> create table sample_data (doc xmltype);
  
  Table created
  
  SQL> insert into sample_data values (
    2  '
    3  
    4   
    5   AM
    6   BM
    7   cF
    8  ');
  
  1 row inserted
  
  SQL> commit;
  
  Commit complete
  
  SQL> set long 500
  SQL> select xmlserialize(document
    2           xmlquery(
    3            'copy $d := /Company
    4             modify rename node $d/ABC as "CDE"
    5             return $d'
    6            passing t.doc
    7            returning content
    8           )
    9           as clob indent
   10         )
   11  from sample_data t
   12  ;
  
  XMLSERIALIZE(DOCUMENTXMLQUERY(
  --------------------------------------------------------------------------------
  
    
    
      A
      M
    
    
      B
      M
    
    
      c
      F
    
  
   
  

  Other solutions of "XML" involve recursive or as mentioned XQuery, XSLT functions:

  SQL> SELECT XMLSerialize(DOCUMENT
    2    XMLTransform(
    3      t.doc
    4    , xmltype('
    5       
    6        
    7          
    8            
    9          
   10        
   11        
   12          
   13            
   14          
   15        
   16      ')
   17    )
   18    AS CLOB INDENT
   19  )
   20  FROM sample_data t
   21  ;
  
  XMLSERIALIZE(DOCUMENTXMLTRANSF
  --------------------------------------------------------------------------------
  
  
    
    
      A
      M
    
    
      B
      M
    
    
      c
      F
    
  
   
  

• Update the properties by name

  I have a need to update the property of a given class name.
  
  I found that if I had used the notation:
  
  obj ["name"] = "hello world!"
  
  that this does not update the property 'name' of the instance of the class sealed "obj".
  
  To be more explicit, suppose I have the following class definition:
  
  public class Foo
  {
  private var _name: String = "";
  
  public function get name(): String
  {
  Return _Nom;
  }
  
  public function set name(name: String): void
  {
  If (name == null) / / protect against defining it as null, for some reason any...
  name = "";
  _name = name;
  }
  }
  
  and then I have a code that knows an object has a reference to a property called "name", but that it's generic code and there the object reference is not explicit. So, I was hoping to do this:
  
  public void setProperty (instance: object, propertyName: String, propertyValue: Object): void
  {
  instance [propertyName] = propertyValue;
  }
  
  However, this does not work, as it attempts to create a dynamic new property and can not.
  
  Is there another way to set the value of the property, similar to the way in which you can set a property to a JavaBean?
  
  Thank you!
  
  Rhys
  
  PS apologies for not put code in the form correctly. I can't find the function "join code" as I continue to read everything.

  It was idiocy on my part.

  The example does not work!

• How update the name and the date of last update its?

  Hello
  
  In a data entry form, I have Undated_On and Updated_By fields.
  I put & APP_USER. and to_char(sysdate,'DD-MON-RR') than their default values.
  When the saved data are changed, I want the name and date of update the last updated person.
  But even if I update with different user login ID, only the default values are displayed.
  How can I change the name and the date of last update its?
  
  Thank you
  Guy
  
  -----
  H5. FYI, I am very new to SQL, PL/SQL, and APEX. Would appreciate much more explanation and full path (for example. Shared components > change the security attributes > VPD)

  Hi guy,

  I have a form based on the employees table. If someone makes any changes on the form, it will update the user_id and last_updated columns in the table. I use the trigger on the table to update these columns:

  CREATE OR REPLACE TRIGGER biud_employees
  FRONT
  INSERT OR UPDATE
  ON employees
  REFERRING AGAIN AS NINE OLD AND OLD
  FOR EACH LINE
  Start
  : new.user_id: = nvl (v ('APP_USER'), user);
  : new.last_updated: = sysdate;
  end;
  /

  It will be useful.
  Thank you
  Zahid

• Update the name of the client using the api HZ_PARTY_V2PUB.update_organization

  Hi all
  
  I'm trying to update the following fields (OrganizationName, known_as, organization_name_phonetic) for the client (hz_parties) and using the script below update records with the success in the hz_parties table, but I am unable to view the new customer to the customer's screen.
  
  I use the Version 12.1.3.
  
  Here's the script:
  
  
  DECLARE
  l_organization_rec HZ_PARTY_V2PUB.ORGANIZATION_REC_TYPE;
  l_party_rec HZ_PARTY_V2PUB. PARTY_REC_TYPE;
  l_profile_id NUMBER;
  l_return_status VARCHAR2 (10);
  l_msg_count NUMBER;
  l_msg_data VARCHAR2 (2400);
  l_party_obj_version NUMBER: = 2;
  BEGIN
  l_party_rec.party_id: = 363173;
  l_organization_rec.organization_name: = 'xxxxxxxtestchange ';
  l_organization_rec.known_as: = 'xxxxxxtest price changes. "
  l_organization_rec.organization_name_phonetic: = "course change xxxxxx";
  l_organization_rec.party_rec: = l_party_rec;
  HZ_PARTY_V2PUB.update_organization (p_init_msg_list = > FND_API.) G_FALSE,
  p_organization_rec = > l_organization_rec,
  p_party_object_version_number = > l_party_obj_version,
  x_profile_id = > l_profile_id,
  x_return_status = > l_return_status,
  x_msg_count = > l_msg_count,
  x_msg_data = > l_msg_data);
  
  Dbms_output.put_line ('Status of the api call' | l_return_status);
  
  COMMIT;
  EXCEPTION
  WHILE OTHERS THEN
  DBMS_OUTPUT. Put_line (' error :::'||) SQLERRM);
  ROLLBACK;
  END;
  
  My problem is that I am able to view the records updated to back-end, but unable to display front end.
  
  Thanks and greetings
  El M

  "DQM series Sync Index program" run it after that you have made the updates. If not try manually submit this work and see if you can view your changes

• Enter the name of app_user by updating the tabular form of builtin apex

  Hi people,
  
  I am a new to apex and trying to implement a tabular apex that has only an editable field box and form two audit field. Last updated by and updated, I use the built-in tabular form Apex.
  
  Properly put form to update the field box to check and it works as it is supposed to be, the two audit field and Updated_by Update_date, I'm updating via slot table form and not updated.
  
  Any help will be much appreciated. After the code that I use in the application process after submit
  
  BEGIN
  II in 1... APEX_Application.g_f02. COUNTY
  LOOP
  (ii) apex_application.g_f08: =: sysdate;
  apex_application.g_f09 (II (: = v ('APP_USER');))
  /*
  UPDATE MG_RESTRICTION_DEV SET UPDATED_BY = v ('APP_USER')
  WHERE MG_ID = APEX_APPLICATION. G_F05 (II);
  */
  END LOOP;
  END;
  
  My goal is to use the max integrated apex and want to use the default MRU apex process. I get the success message, but the value does not get updated on the table.
  
  Thank you
  
  Shabbir
  
  Published by: user13413381 on July 4, 2011 10:39

  Post this question in the forum asking Express. This is the forum of forms.

• the form of course update the user field value

  Can experts tell me if we can retrieve the data from the form of courses and update the user field. If so, please could you tell me how to do and a simple example will be useful.
  
  Thank you very much

  Write an adapter to transfer and pass the value of the form attribute of the user

  How to create a transfer adapter: -.

  Name of the adapter:-adapter task of transfer process
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• How to update the password on the other table based on the mod

  Hello
  
  I need to update the password for the other table based on the mod.
  
  I have two table 'user' and 'reset '.
  
  
  User:
  
  Username username password date_exp
  
  s232322 Bobby John sdds4545df4r 10/12/2010
  s454566 George Bill f444556gh76 07/14/2010
  s343466 Bill Clinton fgf54tyujkkkhj 06/12/2011
  .
  .
  .
  
  
  Reset:
  
  Series encrypt decrypt
  
  fgf5656fg 0 Watellemon
  1 dfggf5665 lime juice
  dfdffd545 2 applesalad
  3 54r4gggt airlines
  construction of 4 hg44hh63
  5 fgf4343yh security
  .
  .
  .
  
  How can I update the password of a table to another table "reset"?
  
  Ex: query
  
  Update user set password = (select Encrypt reset where mod (length (username), 10))
  
  
  If mod (length (username), 10) is 0, it should take series "0" encrypt the password and update the password in the table "user".
  If mod (length (username), 10) is 1, it should take serial '1' encrypt the password and update the password in the table "user".
  If mod (length (username), 10) is 2, it should take series '2' encrypt the password and update the password in the table "user".
  If mod (length (username), 10) is 3, it should take series '3' encrypt the password and update the password in the table "user".
  If mod (length (username), 10) is 4, it should take series '4' encrypt the password and update the password in the table "user".
  ....
  
  
  Please help me write an update query.
  
  
  
  
  Thank you
  Nihar

  Hi, Nihar,

  You almost had it! You just need to correlate the subquery for the main UPDATE statement, like this:

  UPDATE     user_table     u     -- USER is a built-in function; it's not a good table name
  SET     password = ( SELECT  encrypt
                 FROM    reset     -- RESET isn't a very good table name, either
                 WHERE   serial     = MOD ( LENGTH (u.username)
                                           , 10
                                 )
               );