Using SQL to ensure the matching records are mutually exclusive.
There are two tables defined in the following way:
Table A
Number 1
Number 2
Date
ROWID
Table B
Number 1
Number 2
Date
Identifier of the line
Each table stores a call between number 1 and 2 on a specific date. The goal is to map exactly one entry of table A with exactly the record in table B
in a mutually exclusive way. So a single call to a table must be associated with exactly one call the other table (the key is here
A.Number1 is B.Number1 and A.Number2 = B.Number2). Because it is a relationship is many to many (the number of source and destination may be paired multiple)
(time), I'm not able to build a series of sql statements that will allow me to get a relationship one between pairs of telephone numbers.
I'm not allowed to develop a PL/SQL procedure, which would easily solve this problem.
I was able to find a solution using MIN(Number 1) KEEP (DENSE_RANK FIRST ORDER BY Date) to THE (PARTITION BY x) the form x
using temporary tables, which allows me to reach a breaking successively much many relationships (i.e. three broken bones in a 01:58 after
an iteration, and after one iteration, I arrive at a one to one relationship). However, I can't break these relations some n number of times because it requires number n
hard curls. Therefore, I need a sophisticated solution that will allow me to achieve a relationship one by one.
Example of
Table A
Record 1
Number 1:451923456789
Number 2:541969432045
Date: 29/07/2015-09:01
Worksheet 2
Number 1: 451923456789
Number 2: 541969432045
Date: 29/07/2015-09:03
Table B
Record 1
Number 1: 451923456789
Number 2: 541969432045
Date: 29/07/2015-09:04
Worksheet 2
Number 1: 451923456789
Number 2: 541969432045
Date: 29/07/2015-09:05
If we unite our table A and B by A.Number1 = B.Number1 and A.Number2 = B.Number2, we have 4 records. I'm looking for exactly two records.
The criteria is to associate by the minimum of the sum of the date of the table A table B date. Therefore, the final result should match:
(1) record 1 of table A with record 1 of table B.
sheet 2) 2 table A with 2 record in table B.
So we must do something to reduce the 4 records resulting from the join of two records describe as we see above.
The result of the join:
1st row: TableA.Record1 with TableB.Record1
2nd place: TableA.Record1 with TableB.Record2
Rank 3: TableA.Record2 with TableB.Record1
4th place: TableA.Record2 with TableB.Record2
What I'm looking for, which is easily achievable with a slider, but not with SQL:
1st row: TableA.Record1 with TableB.Record1
4th place: TableA.Record2 with TableB.Record2
Note that if the minimum date condition allows us to select the necessary records, we won't get the expected results. In other words, using the minimum date.
the results will be:
1st row: TableA.Record1 with TableB.Record1
Rank 3: TableA.Record2 with TableB.Record1
(criteria - table a minimum date)
or
1st row: TableA.Record1 with TableB.Record1
2nd place: TableA.Record1 with TableB.Record2
(criteria - date minimum table B)
Two of these results to break the rule are mutually exclusive.
Post edited by: 3000640
If I understand correctly, something like:
SQL > with tableA (id, telephone1, telephone2, call_date) as)
2. Select 1, ' 451923456789 ', ' 541969432045',
3 to_date (July 29, 2015 09:01 ', 'dd.mm.yyyy hh24')
4 union double all the
5. Select 2, ' 451923456789 ', ' 541969432045',
6 to_date (July 29, 2015 09:03 ', 'dd.mm.yyyy hh24')
double 7),
TableB 8 (id, telephone1, telephone2, call_date) as)
9. Select 1, ' 451923456789 ', ' 541969432045',
10 to_date (July 29, 2015 09:04 ', 'dd.mm.yyyy hh24')
11 double Union all the
12. Select 2, ' 451923456789 ', ' 541969432045',
13 to_date (July 29, 2015 09:05 ', 'dd.mm.yyyy hh24')
14 double)
15 select a.id help, a.phone1 aphone1, a.phone2 aphone2,
16 a.call_date acall_date, b.id offer, b.phone1 bphone1,
17 b.phone2 bphone2, b.call_date bcall_date
18 (select id, telephone1, telephone2, call_date,
19 row_number() over (partition by numbers1, telephone2
RN 20 order by call_date)
tablea 21) a
22 join (select id, telephone1, telephone2, call_date,
23 row_number() over (partition by numbers1, telephone2
RN 24 order by call_date)
tableb 25) b
26 on a.phone1 = b.phone1 and
27 a.phone2 = b.phone2 and
28 a.rn = b.rn;
HELP APHONE1 APHONE2 ACALL_DATE BPHONE1 BPHONE2 BCALL_DATE OFFERS
---------- ------------ ------------ -------------------- ---------- ------------ ------------ --------------------
1 451923456789 541969432045 July 29, 2015 09:01 1 451923456789 541969432045 July 29, 2015 09:04
2 451923456789 541969432045 July 29, 2015 09:03 2 451923456789 541969432045 July 29, 2015 09:05
John
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N. SaridakisIs that what you are looking for:
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Maybe you are looking for
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Hello Is it possible to reset the BIOS password on my Toshiba Satellite U400 laptop? My friend changed my password in the BIOS. And unfortunately he forgot. Any ideas? P.S.: I don't want my laptop disassembly and clear the CMOS settings by removing t
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Hello, in my office we recently bought printer HP Designjet T2500 and, so far, works great but I have a doubt with the procedure of the Analyzer in the case where the main panel is malfunctioning. How can I scan a document without the help of the mai
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RN204 not reconnect the USB in the port back after reboot.
I don't know if that's a problem, but my new RN204 unit will not see my USB stick after reboot. Key, I inserted into the lower back USBport. Port superior return I got UPS. Inverter is connected ok after reboot. If the USB is in front of USB port, un
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Recently my computer has been reformatted, now Vista gives me the penalty.
I recently had my computer back in shape by a local group of professionals. They have done several computers for me in the past so I think that the problem is not with them. Now my computer has a lot of free memory space, and I'm beginning to re - i