Using SQL to display the date range
Gurus,I have a sql statement such as
select MIN(HIREDATE), MAX(HIREDATE) FROM EMP WHERE DEPTNO = 30MIN(HIREDATE) MAX(HIREDATE)
12/30/1998 12/30/2001I need a SQL to generate the output as
30/12/1998
30/01/1999
28/02/1999
---
---
until the Max value (HIREDATE)
In February, we have 30 days, in this case to the last day of the month.
Thanks for the great help
C 007
Hello
put my post to correct and others with useful, please
Is salim.
Tags: Database
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I use:
Oracle SQL Developer (3.0.04) build hand - 04.34 Oracle Database 11 g Enterprise Edition 11.2.0.1.0 - 64 bit Production
How do we use the function sum with a structure of matter inside.
so I gave that looks like have an ID, date and value. I'm looking to get the day 7 medium for the date range of 04/01/2013 to 20/04/2013
* Please let me know if the table does not load.with t as ( select 1 ID_Key,to_date('4/1/2013','mm-dd-yyyy') date_val, 10 Value_num from dual union all select 1 ID_key,to_date('4/2/2013','mm-dd-yyyy'), 15 from dual union all select 1 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 20 from dual union all select 1 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 0 from dual union all select 1 ID_key,to_date('4/8/2013','mm-dd-yyyy'), 12 from dual union all select 1 ID_key,to_date('4/9/2013','mm-dd-yyyy'), 8 from dual union all select 1 ID_key,to_date('4/10/2013','mm-dd-yyyy'), 6 from dual union all select 1 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 10 from dual union all select 1 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all select 1 ID_key,to_date('4/14/2013','mm-dd-yyyy'), 0 from dual union all select 1 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 10 from dual union all select 1 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 5 from dual union all select 1 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 2 from dual union all select 1 ID_key,to_date('4/20/2013','mm-dd-yyyy'), 3 from dual union all select 2 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 12 from dual union all select 2 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 15 from dual union all select 2 ID_key,to_date('4/6/2013','mm-dd-yyyy'), 5 from dual union all select 2 ID_key,to_date('4/7/2013','mm-dd-yyyy'), 7 from dual union all select 2 ID_key,to_date('4/9/2013','mm-dd-yyyy'), 10 from dual union all select 2 ID_key,to_date('4/11/2013','mm-dd-yyyy'), 5 from dual union all select 2 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 0 from dual union all select 2 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all select 2 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 6 from dual union all select 2 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 8 from dual union all select 2 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 0 from dual union all select 2 ID_key,to_date('4/18/2013','mm-dd-yyyy'), 10 from dual union all select 2 ID_key,to_date('4/19/2013','mm-dd-yyyy'), 5 from dual )
I would get the average of 7 days, as long as there is date for the rank of enough previous dates, is it not, then it returns a null value.
the results should look like this
As you can see, there are gaps in the dates, the value is then processed by zeros for the 7Day_Avg and then ignored for the 7Day_Avg2 (not counted in the number of days on average do to no valu_num line)ID_Key date_val Value_num 7Day_Avg 7Day_Avg2 1 4/1/2013 10 null null 1 4/2/2013 15 null null 1 4/3/2013 20 null null 1 4/5/2013 0 null null 1 4/8/2013 12 6.71 11.75 1 4/9/2013 8 5.71 10.00 1 4/10/2013 6 3.71 6.50 1 4/12/2013 10 5.14 9.00 1 4/13/2013 0 5.14 7.20 1 4/14/2013 0 5.14 6.00 1 4/15/2013 10 4.86 5.67 1 4/16/2013 5 4.42 5.17 1 4/17/2013 2 3.85 4.50 1 4/20/2013 3 2.86 4.00 2 4/3/2013 12 null null 2 4/5/2013 15 null null 2 4/6/2013 5 null null 2 4/7/2013 7 5.57 9.75 2 4/9/2013 10 7.00 9.80 2 4/11/2013 5 6.00 8.40 2 4/12/2013 0 3.86 5.40 2 4/13/2013 0 3.14 4.40 2 4/15/2013 6 3.00 4.20 2 4/16/2013 8 2.71 3.80 2 4/17/2013 0 2.71 3.17 2 4/18/2013 10 3.43 4.00 2 4/19/2013 5 4.14 4.83
I tried something like this at first, but becomes "missing keyword" error
Should I have the structure outside the sum function?select t.*/, sum( case when date_val between :day2 - 6 and :day2 then value_num between date_val - 6 and date_val else null end ) as 7Day_avg form t
Any thoughts?
Published by: 1004407 on June 7, 2013 11:06Hello
If you want to calculate the average of the last 7 days, including the current day, then then RANGE should be 6 PRIOR, not 7.
Try this:
WITH got_min_date_val AS
(
SELECT id_key, date_val, value_num
MIN (date_val) compared to (AS min_date_val)
T
WHERE the date_val BETWEEN TO_DATE (April 1, 2013 ', "dd-mm-yyyy")
AND TO_DATE (April 20, 2013 ', "dd-mm-yyyy")
)
SELECT id_key, date_val, value_num
CASE
WHEN date_val > = min_date_val + 6
THEN SUM (value_num) OVER (PARTITION BY id_key
ORDER BY date_val
PRIOR TO TIER 6
)
/ 7
END AS avg_7_day
CASE
WHEN date_val > = min_date_val + 6
THEN AVG (value_num) OVER (PARTITION BY id_key
ORDER BY date_val
PRIOR TO TIER 6
)
END AS avg_7_day_2
OF got_min_date_val
ORDER BY id_key
date_val
;
Output:
ID_KEY DATE_VAL VALUE_NUM AVG_7_DAY AVG_7_DAY_2
---------- --------- ---------- ---------- ------------
1 1 APRIL 13 10
1 2 APRIL 13 15
1 APRIL 3, 13 20
1 5 APRIL 13 0
1 APRIL 8, 13 12 6.71 11.75
1 APRIL 9, 13 8 5.71 10.00
1 APRIL 10 13 6 3.71 6.50
1 12 APRIL 13 10 5.14 9,00
1 13 APRIL 13 0 5,14 7.20
1 14 APRIL 13 0 5,14 6.00
1 15 APRIL 13 10 4.86 5.67
1 16 APRIL 13 5 4.43 5.17
1 APRIL 17, 13 2 3.86 4.50
1 APRIL 20, 13 3 2.86 4.00
2 APRIL 3, 13 12
2 5 APRIL 13 15
2 6 APRIL 13 5
2 7 APRIL 13 7 5.57 9.75
2 9 APRIL 13 10 7,00 9.80
2 11 APRIL 13 5 6.00 8.40
2 12 APRIL 13 0 3.86 5.40
2 13 APRIL 13 0 3.14 4.40
2 15 APRIL 13 6 3.00 4.20
2 16 APRIL 13 8 2.71 3.80
2 17 APRIL 13 0 2.71 3.17
2 18 APRIL 13 10 3.43 4.00
2 APRIL 19, 13 5 4.14 4,83
Post edited by: FrankKulash
Sorry; I wanted to respond to OP, not Greg
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I want to count the number of records of members who register within a date range specified, based on effective and expiration dates and their "elg_code". I posted the SQL code for some examples of data. What I would like to see returned is in three columns of the counties where the eff_date date_exp members fall within the date range specified by the SQL and have an Elg_code of ' ' (space).
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Select count (m1.mbr_name) APR,
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mbr2 M1,
mbr2 m2,
mbr2 m3
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Commit
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CommitThis gives you a report for the current month and the two front. Column header must be adjusted ;-)
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PivotTable ' display the data as "percentage of accuracy
Hello
I would like to know if there is a way to configure the PivotTable ' display the data sub - percentage of ' precision.
ATM, I have reports using SR types where one of those who are much bigger than others... Thus, when its generated report, it returns something like:
TYPE A: 99%
TYPE B: 0%
TYPE C: 0%
TYPE D: 0%
How can I view other correct value types? Something like number of decimals...
PS: as criteria in this report, I changed my data Format 'Number', ' less:-123 "to 15 decimal places.»
Thank you
Ramon902360 wrote:
HelloI would like to know if there is a way to configure the PivotTable ' display the data sub - percentage of ' precision.
ATM, I have reports using SR types where one of those who are much bigger than others... Thus, when its generated report, it returns something like:
TYPE A: 99%
TYPE B: 0%
TYPE C: 0%
TYPE D: 0%How can I view other correct value types? Something like number of decimals...
PS: as criteria in this report, I changed my data Format 'Number', ' less:-123 "to 15 decimal places.»
Thank you
RamonWell Yes. Can do. Read this link:
http://shivabizint.WordPress.com/2008/09/14/changing-the-precession-of-percent-of-columns-in-pivot-table-of-OBIEE/
-
I need a SQL to display the Mon - Sun in a week when enter a date. If I give 24 March 2011 "I want Mon - Sun displayed dates IE from March 21, 2011 to March 27, 2011."
Even if this question is asked a lot times I decided to post this time.
Next time if you could search the forum it will be very much appreciated.
SQL> select * from v$version; BANNER ---------------------------------------------------------------- Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi PL/SQL Release 10.2.0.4.0 - Production CORE 10.2.0.4.0 Production TNS for 64-bit Windows: Version 10.2.0.4.0 - Production NLSRTL Version 10.2.0.4.0 - Production SQL> alter session set nls_Date_Format = 'DD-MON-YYYY'; Session altered. SQL> with t 2 as 3 ( 4 select next_day(to_date('&Enter_Date','dd.mm.yyyy') - 7, 'SUN') start_date from dual 5 ) 6 select start_date + level from t 7 connect by level <= 7 8 / Enter value for enter_date: 24.03.2011 old 4: select next_day(to_date('&Enter_Date','dd.mm.yyyy') - 7, 'SUN') start_date from dual new 4: select next_day(to_date('24.03.2011','dd.mm.yyyy') - 7, 'SUN') start_date from dual START_DATE+ ----------- 21-MAR-2011 22-MAR-2011 23-MAR-2011 24-MAR-2011 25-MAR-2011 26-MAR-2011 27-MAR-2011 7 rows selected.Thank you
REDA
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