Using syntax for the 'If' statement in the query?

Similar Questions

• Not finding the correct syntax for the select statement

  Hello
  
  The following statement works very well and gives the expected results:
  

  prompt
  prompt Using WITH t
  prompt
  
  with t as
    (
     select a.proj_id,
            a.proj_start,
            a.proj_end,
            case when (
                       select min(a.proj_start)
                         from v b
                        where (a.proj_start  = b.proj_end)
                          and (a.proj_id    != b.proj_id)
                      )
                      is not null then 0 else 1
            end as flag
       from v a
      order by a.proj_start
    )
  select proj_id,
         proj_start,
         proj_end,
         flag,
         --
         -- the following select statement is what I am having a hard time
         -- "duplicating" without using the WITH clause
         --
         (
          select sum(t2.flag)
            from t t2
           where t2.proj_end <= t.proj_end
         ) s
    from t;

  As an academic exercise, I wanted to rewrite the above statement without using the WITH clause, I tried this (amongst dozens of other tests - I hit a mental block and cannot understand):
  

  prompt
  prompt without with
  prompt
  
  select c.proj_id,
         c.proj_start,
         c.proj_end,
         c.flag,
         --
         -- This is what I've tried as the equivalent statement but, it is
         -- syntactically incorrect.  What's the correct syntax for what this
         -- statement is intended ?
         --
         (
          select sum(t2.flag)
            from c t2
           where t2.proj_end <= c.proj_end
         ) as proj_grp
    from (
          select a.proj_id,
                 a.proj_start,
                 a.proj_end,
                 case when (
                            select min(a.proj_start)
                              from v b
                             where (a.proj_start  = b.proj_end)
                               and (a.proj_id    != b.proj_id)
                           )
                           is not null then 0 else 1
                 end as flag
            from v a
           order by a.proj_start
         ) c;

  Thanks for the help, much appreciated.
  
  John.
  
  PS: The DDL for table v used by the above statements is:
  

  drop table v;
  
  create table v (
  proj_id         number,
  proj_start      date,
  proj_end        date
  );
  
  insert into v values
         ( 1, to_date('01-JAN-2005', 'dd-mon-yyyy'),
              to_date('02-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         ( 2, to_date('02-JAN-2005', 'dd-mon-yyyy'),
              to_date('03-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         ( 3, to_date('03-JAN-2005', 'dd-mon-yyyy'),
              to_date('04-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         ( 4, to_date('04-JAN-2005', 'dd-mon-yyyy'),
              to_date('05-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         ( 5, to_date('06-JAN-2005', 'dd-mon-yyyy'),
              to_date('07-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         ( 6, to_date('16-JAN-2005', 'dd-mon-yyyy'),
              to_date('17-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         ( 7, to_date('17-JAN-2005', 'dd-mon-yyyy'),
              to_date('18-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         ( 8, to_date('18-JAN-2005', 'dd-mon-yyyy'),
              to_date('19-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         ( 9, to_date('19-JAN-2005', 'dd-mon-yyyy'),
              to_date('20-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         (10, to_date('21-JAN-2005', 'dd-mon-yyyy'),
              to_date('22-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         (11, to_date('26-JAN-2005', 'dd-mon-yyyy'),
              to_date('27-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         (12, to_date('27-JAN-2005', 'dd-mon-yyyy'),
              to_date('28-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         (13, to_date('28-JAN-2005', 'dd-mon-yyyy'),
              to_date('29-JAN-2005', 'dd-mon-yyyy'));
  insert into v values
         (14, to_date('29-JAN-2005', 'dd-mon-yyyy'),
              to_date('30-JAN-2005', 'dd-mon-yyyy'));

  select c.proj_id,
         c.proj_start,
         c.proj_end,
         c.flag,
         --
         -- This is what I've tried as the equivalent statement but, it is
         -- syntactically incorrect.  What's the correct syntax for what this
         -- statement is intended ?
         --
         (
          select sum(t2.flag)
            from (select a.proj_id,
                         a.proj_start,
                         a.proj_end,
                         case when (
                            select min(a.proj_start)
                              from v b
                             where (a.proj_start  = b.proj_end)
                               and (a.proj_id    != b.proj_id)
                                   )  is not null then 0 else 1
                         end as flag
                    from v a
                   order by a.proj_start
                 ) t2
           where t2.proj_end <= c.proj_end
         ) as proj_grp
    from (
          select a.proj_id,
                 a.proj_start,
                 a.proj_end,
                 case when (
                            select min(a.proj_start)
                              from v b
                             where (a.proj_start  = b.proj_end)
                               and (a.proj_id    != b.proj_id)
                           )
                           is not null then 0 else 1
                 end as flag
            from v a
           order by a.proj_start
         ) c;
  

• Why always, I received management is not available when you use maps for the iPhone 6 and I live in the Qatar?

  Why I always get direction is not available when you use maps for the iPhone 6 more?

  Currently I live in the Qatar.

  Hi Alison, Sameh

  The reason why you see directions is not available, it's that for cards of Apple, turn-by-turn directions is not a feature that is available in the Qatar. You can search for places and satellite imagery
  Take a look at the link below for more details on what features are available in the Qatar.

  iOS 9 feature availability
  http://www.Apple.com/iOS/feature-availability/

  Nice day

• I m using firefox on mac. I used it for the first time on mac while I had put a lot of "separators" on the bookmarks toolbar... How to remove the xtra those? Small request that it creates big problems...

  Well not much description required in this case. I was using firefox for the first time on a mac and so was trying new things with this version of firefox. Just got stuck with these separators xtra... Can't find a way to get them off of my bookmarks toolbar...

  You can open the Bookmark Manager (Bookmarks > show all bookmarks) and go to the Favorites bar folder in the left pane.
  You can then remove the separators in the right pane.

  • How can I delete a bookmark?

• Can I use java for the development of the playbook?

  Hi I'm new in blackberry development. I've owned playbook and that you want to develop playbook apps, but I can only develop in java. Please, someone tell me what I can use java for the development of the Tablet?

  Bilal

  # You can convert by android android applications, run-time.

  Explore these links

  https://developer.BlackBerry.com/

  https://developer.BlackBerry.com/Java/

• I installed ux 16 driver Windows 7 my pc but nothing displays, no .so tracks what is wrong with it please suggest.or how can I do this by using midi for the first time.

  I installed driver ux 16 in my widows 7 and connected to my pc but nothing displays, no .so tracks what is wrong with it please suggest.or how can I do this by using midi for the first time.

  In the subject line, type a brief description of your problem or your question. A subject line that says only "Hi alll" not will receive the attention of someone who can be familiar with your particular situation.

  Contact the support of Yamaha.

• syntax for the compilation of the pll in oracle11i on windows files

  Hello
  
  What is the syntax for the compilation of files of pll in oracle11i?
  
  When executing pll, I got the below error
  
  E:\oracle\testappl\au\11.5.0\resource > f60gen module = CUSTOM.pll userid = apps/app0305apps output_file = CUSTOM.plx
  module_type = library package = no compile_all = special
  'f60gen' is not recognized as an internal or external command
  operable program or batch file.
  
  
  Thank you
  
  Regarding
  
  Umair

  Umair,

  I changed the fichier_de_sortie so I ran which command that was successful.

  It should work, but you must replace the original file, so enforcement is necessary.

  Means I have to stop application services (forms + Apache).

  Correct (mainly the forms).

  Kind regards
  Hussein

• Using NVL in the query in the query resulting in error

  I always use CF8 and Oracle 11 G back.

  When I use NVL in the query in the query, I got error... I can't use NVL to check the value null? Help, please

  Here are my codes:

  < name cfquery = "GetC2" datasource = "#Trim (application." OracDSN) #">"

  SELECT CamID2, rel2_2, p_ln2, p_fn2, ins, l_year

  OF prt_temp

  WHERE Ins = 'CC '.

  AND l_year = '1481'

  	AND NVL (Child_LN2,' ') <>' '
  	AND NVL (Child_FN2,' ') <>' '

  < / cfquery >

  	< cfif GetC2.Recordcount NEQ 0 >
  	< cfquery name = "CheckRel2C2", dbtype = "QUERY" >
  	SELECT CamID2, rel2_2
  	OF GetC2
  	WHERE NVL (Rel2_2,' ') <>' '
  	AND NVL (p_ln2,' ') = ' '
  	AND NVL (p_fn2,' ') = ' '
  	AND Ins = 'CC '.
  	AND l_year = '1481'
  	< / cfquery >

  < / cfif >

  The error:

  Run database query error.

  Query of queries syntax error.

  Met «NVL (Rel2_2.» Incorrect conditional expression, waiting for an a [as | null | between | in | comparison] condition,.

  NVL is an Oracle function and it is not available in ColdFusion query of query.  If you try to check the values null, use IS NULL or IS NOT NULL.  Then

  WHERE NVL (Rel2_2,' ') <> ' '

  AND NVL (p_ln2,' ') = ' '

  AND NVL (p_fn2,' ') = ' '

  becomes

  WHERE Rel2_2 IS NOT NULL

  AND p_ln2 IS NULL

  AND p_fn2 IS NULL

  -Carl V.

• What is the correct syntax for the use of a variable in an ad-hoc query?

  Hi all
  
  I'm a casual user of the DB and right now need to update the records about 1000 + so that a certain column gets a unique value.
  
  So I thought I'd use a variable for this.
  
  Then, I built this type of SQL statement for only a small subset of records:
  ----------
  variable number recNumber;
  exec: recNumber: = 1;
  UPDATE TABLE_TO_BE_UPD
  SET COL_TO_BE_UPD = COL_TO_BE_UPD + recNumber
  WHERE COL_TO_BE_UPD IN ('VAL_A', 'VAL_B');
  ----------
  
  I get invalid SQL statement error when you try to run above (except for the guest who asks for a value I want to omit).
  
  In any case, I also tried this one:
  ----------
  CREATE SEQUENCE seqCounter;
  UPDATE TABLE_TO_BE_UPD
  SET COL_TO_BE_UPD = COL_TO_BE_UPD + seqCounter.NEXTVAL
  WHERE COL_TO_BE_UPD IN ('VAL_A', 'VAL_B');
  ----------
  
  Of it, I got the error ORA-01722: invalid number... I guess it's because seqCounter is of type number and the COL_TO_BE_UPD is of type character... (?)
  
  Then I want to ask is what is the correct way to define and use a counter variable type to add a number at the end of a string?
  
  Also another question I would ask is that are variables that are used in queries ad hoc, also called "bind variables"?
  
  Thank you muchly

  If you want to add a unique number to a column, then it would be:

  UPDATE TABLE_TO_BE_UPD
  SET COL_TO_BE_UPD = COL_TO_BE_UPD ||to_char(rownum)
  WHERE COL_TO_BE_UPD IN ('VAL_A','VAL_B');
  

• How the group using SQL for the desired output.

  Hi all
  
  I am currently using oracle 10.2.0.4.0
  
  Create a table script:

  CREATE TABLE FORTEST
  ( gpno VARCHAR2(10 BYTE),
    classnumber  VARCHAR2(10 byte),
    age_min NUMBER,
    age_max NUMBER,
    amount NUMBER)

  INSERT statement:

  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 01,0,29,1) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 01,30,35,2) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 01,36,40,3) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 02,0,29,1) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 02,30,35,2) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 02,36,40,5) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 03,0,29,1) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 03,30,35,2) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 03,36,40,3) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G124' , 01,0,29,1) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G124' , 01,30,35,2) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G124' , 01,36,40,3) 

  power required:

  gpno    classnumber    age_min    age_max    amount
  G123    1,3                0        29        1
  G123    1,3                30       35        2
  G123    1,3                36       40        3
  G123    2                  0        29        1
  G123    2                  30       35        2
  G123    2                  36       40        5
  G124    1                  0        29        1
  G124    1                  30       35        2
  G124    1                  36       40        3

  as for gpno g123, classnumber 1 and 3, the rates are the same in all the age_min and age_max they need to be grouped.
  even if gpno 123 classnumber 2 has the same rates as the classesnumber 1 and 3 for the age groups 0 to 29 and 30 to 35,
  rates are different for ages 36 to 40. so it should not be placed together. How can I do this in SQL
  
  any help is appreciated.
  
  Thanks in advance.

  Hello

  Thorny problem!

  Unfortunately, LISTAGG was created to the Oracle 11.2. About half of the complexity here is the aggregation of chain, i.e. forming the list of the classnumbers, as '1.3', using only functions available in Oracle 10.2.

  Here's a solution:

  WITH     got_gpno_classnumber_cnt   AS
  (
       SELECT     gpno, classnumber, age_min, age_max, amount
       ,     COUNT (*) OVER ( PARTITION BY  gpno
                                    ,            classnumber
                        )   AS gpno_classnumber_cnt
       FROM    fortest
  --     WHERE     ...     -- If you need any filtering, this is where it goes
  )
  ,     pairs          AS
  (
       SELECT    a.gpno
       ,       a.classnumber
       ,       MIN (b.classnumber)
                  OVER ( PARTITION BY  a.gpno
                            ,                    a.classnumber
                    )     AS super_classnumber
       FROM       got_gpno_classnumber_cnt  a
       JOIN       got_gpno_classnumber_cnt  b  ON   a.gpno     = b.gpno
                                    AND  a.age_min     = b.age_min
                                  AND  a.age_max     = b.age_max
                                  AND  a.amount     = b.amount
                                  AND  a.gpno_classnumber_cnt
                                          = b.gpno_classnumber_cnt
       GROUP BY  a.gpno
       ,            a.classnumber
       ,       b.classnumber
       HAVING       COUNT (*)     = MIN (a.gpno_classnumber_cnt)
  )
  ,     got_rnk          AS
  (
       SELECT DISTINCT
               gpno, classnumber, super_classnumber
       ,     DENSE_RANK () OVER ( PARTITION BY  gpno
                                 ,                    super_classnumber
                                 ORDER BY          classnumber
                         )         AS rnk
       FROM    pairs
  )
  ,     got_classnumbers     AS
  (
       SELECT     gpno, classnumber, super_classnumber
       ,      SUBSTR ( SYS_CONNECT_BY_PATH (classnumber, ',')
                     , 2
                   )     AS classnumbers
       FROM     got_rnk
       WHERE     CONNECT_BY_ISLEAF = 1
       START WITH     rnk             = 1
       CONNECT BY     rnk             = PRIOR rnk + 1
            AND     gpno             = PRIOR gpno
            AND     super_classnumber  = PRIOR super_classnumber
  )
  SELECT DISTINCT
         g.gpno
  ,       c.classnumbers
  ,       g.age_min
  ,       g.age_max
  ,       g.amount
  FROM       got_gpno_classnumber_cnt  g
  JOIN       got_classnumbers         c  ON   c.gpno        = g.gpno
                               AND  c.classnumber  = g.classnumber
  ORDER BY  g.gpno
  ,            c.classnumbers
  ;
  

  Out (just as you requested):

  GPNO       CLASSNUMBERS       AGE_MIN    AGE_MAX     AMOUNT
  ---------- --------------- ---------- ---------- ----------
  G123       1,3                      0         29          1
  G123       1,3                     30         35          2
  G123       1,3                     36         40          3
  G123       2                        0         29          1
  G123       2                       30         35          2
  G123       2                       36         40          5
  G124       1                        0         29          1
  G124       1                       30         35          2
  G124       1                       36         40          3
  

• Email application password every time I open the e-mail. I have verizon internet but using Mozilla for the e-mail. I was not asked to password until this week.

  None of the explanations in support of Mozilla are useful. I went to tools and looked for the saved passwords and was not listed. I tried the password associated with my Verizon account, but the message keeps appearing. Recently I change my password for Verizon. I tried the old and the new. I always get the message box. Why? How can I get rid of him? It affects my outgoing emails?

  davislawn, were you able to solve your problem?

• Using aliases for the indicators, controls, procedures and calculated channels

  Hello

  I noticed that aliases do not appear in the workspace for the controls and indicators and procedures system Explorer and see calculated. Is there a way for them to appear? I need to use aliases because I like my definition of the system to control several test systems (which have different CAN report names). Otherwise my system definition would break every time I go to another CAN the database. I thought that the inability to address limited to the configurable alias controls add on, but it seems that VeriStand natively cannot address the areas I would like to also well done right click. Any recommendations would be welcome.

  Thank you.

  You are right that you cannot use alias in a file system definition for mapping purposes. It is an area that we hope to improve in the future. The initial design of alias was to serve as a public interface for the workspace, profiles of stimulus and so on. However, it is certainly a use case valid to be used as an interface in a system definition.

  A possible solution would be to create a set of user channels that play the public role of your interface in your system definition. Always use your user channels in all procedures, calculated channels and so on. Map your CAN channels on these channels to the user. Whenever you update YOUR database, you must remap the new CAN channels to the appropriate user channel. You can also automate this activity by importing a file delimited by tabs on the mappings page. The one drawback here is that your target will take a little more time to deal with these mappings.

• has no success of body to toggel Port0 and Port1 aboard MCB2300 using LV for the ARMS?

  I'm trying to toggel the GPIO (Port0, Port1) on the evaluation package of MCB2300 with LPC2378 uController aboard by using LV8.6. These two ports seems to have no programmable features with the help of 2 Ports NV., 3 and Port4 work well. If any body got these two ports in the work, so it will be great if you could post a functional LV or C code here in the forum.

  I will be grateful for any suggestions or advice.

  Greetings

  Hello AMD.

  I posted the solution to this elsewhere (although I admit that it is not easy to find).

  Here you go: http://forums.ni.com/ni/board/message?board.id=420&message.id=1185#M1185

  In this post, I am referring to the evolution of the model for the generic lpc2378 target project.  If you use the target of MCB2300 (as it seems you are), you need to open the project to C:\Program NIUninstaller Instruments\LabVIEW 8.6\Targets\Keil\Embedded\RealView\MCB2300\Template\Project\LabVIEW.uv2

  The side effect of this change is that the LCD on the MCB2300 no longer works (as it activates / deactivates the GPIO slow/legacy records).  So you can either return the above changes or modifies registry addresses in the LCD display driver to point to the fast GPIO registers.

  This problem should be solved in the next version of LabVIEW for ARM.

  Good luck

• CPU use 100% for the NT kernel & system

  On the Task Manager CPU usage is 100% for the NT kernel & system so my PC is going very slowly
  AMD Athlon X 2 7750 2.7 Ghz
  2 Ghz of RAM

  Hello

  See following message if you suspect malware has a role to play.

  CTRL SHIFT ESC or right click on taskbar - task manager.

  Manager of task - performance tab - resource monitor - any info on what might be executed on the
  CPU box (click on the small neighborhood down right).

  What happens in Mode without fail - repeatedly, press F8 as you boot?

  How to troubleshoot a problem by performing a clean boot in Windows Vista
  http://support.Microsoft.com/kb/929135
  How to troubleshoot performance issues in Windows Vista
  http://support.Microsoft.com/kb/950685

  Optimize the performance of Microsoft Windows Vista
  http://support.Microsoft.com/kb/959062
  To see everything that is in charge of startup - wait a few minutes without doing anything - then right click on the task - bar
  The task manager - take a look at stored by - Services - process - it is a quick reference (if you have
  a small box in the lower-left - show for all users can check only).

  How to check and change Vista startup programs
  http://www.Vistax64.com/tutorials/79612-startup-programs-enable-disable.html

  A quick check to see that load method 2 is - using MSCONFIG and then display a list of the people here.
  --------------------------------------------------------------------

  Tools that should help you:

  Process Explorer - free - find out what are the files, registry keys and other objects processes have opened, the dll
  they loaded and much more. This exceptionally effective utility will show you even owned by each process.
  http://TechNet.Microsoft.com/en-us/Sysinternals/bb896653.aspx

  Autoruns - free - see what programs are configured to startup automatically when your system boots and you
  opening of session. Autoruns also shows you the full list of registry and file locations where applications can configure auto-
  start the settings.
  http://TechNet.Microsoft.com/en-us/sysinternals/bb963902.aspx
  Process Monitor - Free - monitor the system files, registry, process, thread and DLL real-time activity.
  http://TechNet.Microsoft.com/en-us/Sysinternals/bb896645.aspx

  There are many excellent free tools from Sysinternals
  http://TechNet.Microsoft.com/en-us/Sysinternals/default.aspx

  WhatsInStartUP - free - this utility displays the list of all applications that are loaded automatically when Windows
  starts. For each request, the following information is displayed: Startup Type (registry/Startup folder).
  The command - line String, product name, file Version, company name, location in the registry or the file system,
  and much more. It allows you to easily disable or remove unwanted programs that runs in your Windows startup.
  http://www.NirSoft.NET/utils/what_run_in_startup.html

  There are many excellent free tools to NirSoft
  http://www.NirSoft.NET/utils/index.html

  Window Watcher - free - do you know what is running on your computer? Maybe not. The window Watcher says it all, reporting of any window created by all running programs, if the window is visible or not.
  http://www.KarenWare.com/PowerTools/ptwinwatch.asp

  Many excellent free tools and an excellent newsletter at Karenware
  http://www.KarenWare.com/

  Hope these helps.

  Rob - bicycle - Mark Twain said it is good.

• Using configuration for the 2nd link of lan to lan vpn

  Hello

  Successfully, I configured a connection of lan to lan vpn between two offices. I try to add another link to a 3rd office to my office at home, but have some difficulty. I have attached my setup and hope someone can help me solve my problem. Right now I have a working vpn to the 172.16.0.0/24 network and putting in place the link to 172.16.3.0/24 so. For the new vpn connection, I can ping the external interfaces, but can't ping anything in-house.

  Thanks for your time and help,

  Jason

  Jason

  There is a major mistake that's easy to fix. You have successfully created a second instance of the encryption card to create a VPN tunnel for the second site. But as currently configured two instances of the encryption card use the same access list:

  1 ipsec-isakmp crypto map clientmap

  match address 100

  5 ipsec-isakmp crypto map clientmap

  match address 100

  But each session/tunnel VPN needs its own access list. So, I suggest that you make the following changes:

  5 ipsec-isakmp crypto map clientmap

  match address 101

  no access list 100

  access-list 100 permit ip 192.168.0.0 0.0.0.255 172.16.0.0 0.0.0.255

  access-list 101 permit ip 192.168.0.0 0.0.0.255 172.16.3.0 0.0.0.255

  This provides a list of separate for each session/tunnel access and should solve this problem. Try it and tell us the result.

  HTH

  Rick