Using NVL in the query in the query resulting in error

Similar Questions

• Shouldn't be using WITH return the same results as if you would first put the results in a table?

  First of all, here is my version info:

  BANNER

  --------------------------------------------------------------------------------

  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

  PL/SQL Release 11.1.0.7.0 - Production

  CORE Production 11.1.0.7.0

  AMT for HP - UX: 11.1.0.7.0 - Production Version

  NLSRTL Version 11.1.0.7.0 - Production

  I just re-read the documentation of the subquery factoring clause of select again and I saw no restriction that applies.

  Can someone help me understand why I get different results?  I would like to be able to use the statement that creates spades3, but for some reason it does not work.  However, when I break up and store the last subquery TMP in a table (MAT1), I am able to get the expected results in MAT2.

  Sorry if the example seems a bit esoteric.  I tried to put something together to help illustrate another problem, so it was more convenient to use the same instructions to illustrate this problem.

  drop table mat1;
  create table mat1 as
  with skus as (
    select level as sku_id
    from dual
    connect by level <= 1000
    ),
    tran_dates as (
    select to_date('20130731', 'yyyymmdd') + level as tran_date
    from dual
    connect by level <= 31
    ),
    sku_dates as (
    select s.sku_id,
    t.tran_date,
    case when dbms_random.value * 5 < 4
    then 0
    else 1
    end as has_changes,
    round(dbms_random.value * 10000, 2) as unit_cost
    from skus s
    inner join tran_dates t
    on 1 = 1
    )
  select d.sku_id,
    d.tran_date,
    d.unit_cost
    from sku_dates d
    where d.has_changes = 1
  ;
  
  
  drop table mat2;
  create table mat2 as
  select m.sku_id,
    m.tran_date,
    m.unit_cost,
    min(m.tran_date) over (partition by m.sku_id order by m.tran_date rows between 1 following and 1 following) as next_tran_date
    from mat1 m
  ;
  
  
  drop table mat3;
  create table mat3 as
  with skus as (
    select level as sku_id
    from dual
    connect by level <= 1000
    ),
    tran_dates as (
    select to_date('20130731', 'yyyymmdd') + level as tran_date
    from dual
    connect by level <= 31
    ),
    sku_dates as (
    select s.sku_id,
    t.tran_date,
    case when dbms_random.value * 5 < 4
    then 0
    else 1
    end as has_changes,
    round(dbms_random.value * 10000, 2) as unit_cost
    from skus s
    inner join tran_dates t
    on 1 = 1
    ),
    tmp as (
    select d.sku_id,
    d.tran_date,
    d.unit_cost
    from sku_dates d
    where d.has_changes = 1
    )
  select m.sku_id,
    m.tran_date,
    m.unit_cost,
    min(m.tran_date) over (partition by m.sku_id order by m.tran_date rows between 1 following and 1 following) as next_tran_date
    from tmp m
  ;
  
  
  select count(*) from mat2;
  select count(*) from mat3;
  
  
    from tmp m
  ;
  

  select count(*) from mat2;
  select count(*) from mat3;
  

  Select count (*) from mat2;

  COUNT (*)

  ----------

  31000

  Executed in 0,046 seconds

  Select count (*) in spades3;

  COUNT (*)

  ----------

  0

  Executed by 0,031 seconds

  Hello

  Khaled says:

  The problem is with

  -case when dbms_random.value * 5<>

  You can change this

  dbms_random. Value (1,100) * 5<>

  and test

  I don't know that I agree 100% with your police department, work there.

  dbms_random. Value, no arguments, returns a random number between 0 (inclusive) and 1 (exclusive), so

  dbms_random. Value * 5< 4 ="" will="" be="" true="" about="" 80%="" of="" the="">

  dbms_randon. Value (1, 100) returns a random number between 1 (included) and 100 (exclusive), so

  dbms_random. Value (1, 100) * 5< 4="" will="" be="" true="" exactly="" 0%="" of="" the="" time,="" which="" is="" not="" what="" op="" wants="" at="">

  The problem here apparently revolves around the optimizer not really call dbms_random over and over again in sku_dates of the subquery.  Add ROWNUM in the subquery seems to force Oracle to assess dbms_random.value immediately.  I don't really understand myself, but adding 1 element in the SELECT of the sku_dates subquery clause could solve the problem:

  create table spades3 as

  with references like)

  Select the level as sku_id

  of the double

  connect by level<=>

  ),

  tran_dates like)

  Select the level + to_date ('20130731', 'YYYYMMDD') as tran_date

  of the double

  connect by level<=>

  ),

  sku_dates like)

  Select s.sku_id,

  t.tran_date,

  -case when dbms_random.value * 5<>

  then 0

  1 other

  end as has_changes,

  Round (dbms_random.value * 10000, 2) as unit_cost

  ROWNUM AS r-<=== new="" column="" added="" here="" new="" column="" added="">

  s SKUs

  inner join tran_dates t

  1 = 1

  ),

  tmp as)

  Select d.sku_id,

  d.tran_date,

  d.unit_cost

  of sku_dates d

  where d.has_changes = 1

  )

  Select m.sku_id,

  m.tran_date,

  m.unit_cost,

  min (m.tran_date) over (partition by order of m.sku_id by m.tran_date rows between 1 next and 1 suite) as next_tran_date

  of tmp m

  ;

  You do not have to refer to this column anywhere; just having him in the subquery is enough.

  If someone can't understand why, I know it.

• Bad query results grouping

  Hello
  
  I have 3 tables (cars, colors and Cars_Colors). Cars_Colors is a junction table to list all of the possible combinations of cars and their colors. Using joins, produce the following results to my query:
  
  CAR_NUM, COLOR_NUM
  CAR1, Color1
  CAR1, Color2
  Car2, Color1
  Car3, Color1
  RAC4, Color1
  RAC4, Color2
  RAC4, couleur3
  Car5, couleur3
  
  Query works fine, my problem is to get results to display how I want that they. I want to display the results in a single < table >, with separate for each separate car, where the < tr > shows the car in the first < td > and all the colors associated with this car in a second < td > < b >. Colors must be separated by commas. For example:
  
  CAR1 | Color1, Color2
  Car2. Color2
  Car3 | Color1
  RAC4 | Color1, Color2, couleur3
  Car5 | Couleur3
  
  Now, I could make it work by questioning first for separate cars in the Cars_Colors table, and then loop through each result of the car and make a second request on colors associated with the current car. But is probably not the most effective method.
  
  I would like to use a query to produce the result set, I have listed at the top... with all combinations of colors/car, then use Coldfusion to display output... without having to run another query each time through the loop. I tried to use valuelist(), but couldn't make it work properly. I also tried < cfoutput group queries > and < cfloop >. I have the closer to the time, just can't get the commas work properly. I don't know how to avoid that the comma at the end of the colors, for example:
  
  CAR1 | Color1, Color2
  
  Someone at - there a better way? I appreciate all help. Thank you!

  
  SELECT in... where... ORDER BY car_num, color_num
  

  query = "myQuery" group = "car_num">
  
  
  #car #-#ListChangeDelims (tempColors, ",") #.
  
  

  HTH,
  CR

• Increase the search results to be more than 500

  We have a requirement of use to increace the search results for any type of technique to over 500 (now the set limit). Is it possible none in the system?

  This limit is in place for performance reasons and cannot be rid of basic research.   However, usually when users want more than 500 results is because they are tasks considered compared to standard search/navigation tasks.   For tasks in report, we published reports ready.  Ready reports offers the same features that the search you can adjust the limit of 500 and run saved contextual criteria.   Alternatively, you can calm the concern for the performance by implementing enforcement reports, ready to use a reporting database if necessary.

  Reports of loan is extremely simple to install.  You can learn more on this topic by watching the video of presentation on the collaboration site.  You can also read the guide that is located in the pack of extensibility.

• Understand the VMmark results

  Hi all!

  I successfully ran a VMmark full test and is seeking more information about the results and how to improve them.

  The numbers generated are very vague and the doc that I have does not say much about how the numbers are calculated.  I'm looking for some kind of computation that VMmark uses to get the final result.  I guess that's something like Ops ARE/s/total transactions... etc...

  I have a quad core server CPU with 16 GB of Ram.  I am using a back-end SAN and I try to really test the back-end SAN vs the other components of this.

  If anyone has any advice they would be appreciated!

  Thank you in advance!

  ESX4 using esxcfg-module

• How to get the sql query result?

  Hello

  Currently I use LV2012 to connect to an Oracle database server. After the Oracle Express and Oracle ODBC driver facilities/settings made.

  I managed to use the SQL command to query the data through my command prompt window.

  Now the problem is, how to do the same task in Labview using database connectivity tools?

  I have build a VI to query as being attached, but I have no idea of what range to use to get the result of the query.

  Please help me ~ ~

  Here is a piece of code that I use to test the SQL commands, you can use the part that retrieves the results of sql.

  It is also possible to get the rear column headers, but it's for the next lesson!

  ;-)

• Need help to build the query/pl-sql block to get the query result and the name of column from DB table in the form of key-value pairs.

  Hi Experts,

  I have a DB table has columns of more than 50.

  I question this table, it should only return one line at any time. as sqldeveloper below image.

  

  here, I need to build block pl/sql-query, Discover the column in the table as a key and query result as values.

  Eg:     Key                         -  Value

  TASK_EVENT_ID - 1765

  EVENT_TYPE - ASR_UPDATE

  ... etc until all of the columns in my table.

  Experts please comment on that point, appreciate your help on this.

  Thank you

  -Vincent.

  Here is an approach using DBMS_SQL to iterate over the columns of key / value to assign... (Little code snipped for brevity)

  create or replace procedure (task_expired)

  v_store_id in full,

  v_task_action_id in full,

  v_job_id in full

  )

  as

  -[SNIP code...]

  v_sql VARCHAR2 (4000): = ' select * from my_table where PK = 123';  -Your SQL here!

  v_v_val VARCHAR2 (4000);

  v_n_val NUMBER;

  v_d_val DATE;

  v_ret NUMBER;

  c NUMBER;

  d NUMBER;

  col_cnt INTEGER.

  f BOOLEAN;

  rec_tab DBMS_SQL. DESC_TAB;

  col_num NUMBER;

  vAsString VARCHAR2 (4000);

  BEGIN

  -[SNIP code...]

  Message_properties. CORRELATION: = "EDF_EVENT";

  MSG: = SYS. AQ$ _JMS_BYTES_MESSAGE. Construct();

  Msg.set_string_property ('queueName', ' shipping/csi_cth');

  Msg.set_string_property ('MODE', 'CR8');

  c: = DBMS_SQL. OPEN_CURSOR;

  DBMS_SQL. PARSE (c, v_sql, DBMS_SQL. NATIVE);

  d: = DBMS_SQL. Execute (c);

  DBMS_SQL. DESCRIBE_COLUMNS (c, col_cnt, rec_tab);

  1.col_cnt J

  LOOP

  CASE rec_tab (j) .col_type

  WHEN 2 THEN

  DBMS_SQL. DEFINE_COLUMN (c, j, v_n_val);      -Number

  WHEN 12 CAN

  DBMS_SQL. DEFINE_COLUMN (c, j, v_d_val);      -Date

  ON THE OTHER

  DBMS_SQL. DEFINE_COLUMN (c, j, v_v_val, 2000);   -Else treat as varchar2

  END CASE;

  END LOOP;

  LOOP

  v_ret: = DBMS_SQL. FETCH_ROWS (c);

  WHEN OUTPUT v_ret = 0;

  1.col_cnt J

  LOOP

  -Fetch each column to the correct data type based on coltype

  CASE rec_tab (j) .col_type

  WHEN 2 THEN

  DBMS_SQL. COLUMN_VALUE (c, j, v_n_val);

  vAsString: = to_char (v_n_val);

  WHEN 12 CAN

  DBMS_SQL. COLUMN_VALUE (c, j, v_d_val);

  vAsString: = to_char (v_d_val, ' DD/MM/YYYY HH24:MI:SS');

  ON THE OTHER

  DBMS_SQL. COLUMN_VALUE (c, j, v_v_val);

  vAsString: = v_v_val;

  END CASE;

  Msg.set_string_property (rec_tab (j) .col_name, vAsString);

  END LOOP;

  END LOOP;

  DBMS_SQL. CLOSE_CURSOR (c);

  DBMS_AQ. ENQUEUE (queue_name-online 'cbus.aqjms_common',

  Enqueue_options => Enqueue_options,

  Message_properties => Message_properties,

  Payload-online msg,

  Msgid => Message_handle);

  dbms_output.put_line ('00 Msgid =' |) Message_handle);

  dbms_output.put_line('===Done=');

  -[SNIP code...]

  END;

  /

• How to get SQL Developer 4.1 to display the query result?

  SQL DEV 4.0.3.16.84 execution of a SELECT statement is stored in a .sql file causes the window of the query result of pop-up indicating the result of a SELECT statement.  SQL DEV 4.1 is not to do so.

  Oops on my part; my SQL formatting has been the root cause.  I got used to insert split without any character of comment lines in front of them.  For example:

  ==================================================

  Select funny business;

  The foregoing indicates the behavior described.

  --==================================================

  Select funny business;

  With the dash double comment shows, the SQL works very well.

  This is different than previous versions of SQL Developer, but is probably better functionality.  I'll try to mark it as answered, but anyone with the admin should certainly do so if I can't.

• Need help to understand the query result

  Hi gurus

  I was reading one of the question here in this forum and its link is below:

  Query required for scenario

  I had some confusion related to this code and don't understand the logic of the out put, see query below:

  Query

  with sub_services as

  (

  Select su_seq 12323, 'HLR1' so_id, 1 seq Union double all the

  Select su_seq 12323, "HLR2' so_id, seq 2 Union double all the

  Select su_seq 12323, "A09" so_id, seq 3 of all the double union

  Select su_seq 12333, "MO1" so_id, seq 4 Union double all the

  Select su_seq 12333, "MO2' so_id, seq 5 Union double all the

  Select su_seq 12333, "A09" so_id, 6 seq in union double all the

  Select su_seq 12333, 'M0CR' so_id, seq 7 Union double all the

  Select su_seq 12999, "LOL1' so_id, seq 8 Union double all the

  Select su_seq 12999, "LOL2' so_id, seq 9 double

  )

  Select *.

  of sub_services b

  where exists (select 1 from sub_services

  where su_seq = b.su_seq

  and so_id = 'A09.

  )

  order by 2;

  The query result

  12323 A09 3

  12333 6 A09

  12323 HLR1 1

  12323 HLR2 2

  12333 M0CR 7

  12333 4 MO1

  12333 5 MO2

  According to my understanding, the above query should return records in red only because of her is below command

  It exists (select 1 from sub_services

  where su_seq = b.su_seq

  and so_id = 'A09.

  but don't know why he's back 7 files, can someone help me understand the result...

  It is query is functionally identical to the PL/SQL block, but much more effective.

  declare

  number of l_res;

  Start

  for line (select *)

  sub_services) loop

  Start

  Select 1 from l_res

  of sub_services

  where su_seq = row.su_seq and

  so_id = "A09" and

  rownum = 1;

  exception when

  NO_DATA_FOUND then

  null;

  end;

  end loop;

  end;

  Essentially every row in the outer query are tested against him exists query.  Given the correlation between two requests is based only on su_seq each line with a su_seq value returned by him is returned in the output.

  Another way to think he uses instead a join condition.  This query is equivalent to the query to exist

  Select the main

  of main sub_services

  Join select (separate su_seq

  of sub_services

  where so_id = "A09") cond

  We main.su_seq = cond.su_seq;

  John

• Ask help - please help me get the expected defined in a query result

  Dear all,

  Help with your suggestions and advice. Please see the bottom of the screenshots for the planned result sets.

  create table shift_dt 
  (name varchar2(20),
  shift_start date,
  shift_end date);
  
  insert into shift_dt values ('Brian',to_date('01-01-2015 09:10:00','dd-mm-yyyy hh24:mi:ss'), to_date('01-01-2015 22:10:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('02-01-2015 09:10:00','dd-mm-yyyy hh24:mi:ss'), to_date('04-01-2015 00:00:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('04-01-2015 00:00:00','dd-mm-yyyy hh24:mi:ss'), to_date('05-01-2015 15:20:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('06-01-2015 10:00:00','dd-mm-yyyy hh24:mi:ss'), to_date('06-01-2015 23:20:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('07-01-2015 11:00:00','dd-mm-yyyy hh24:mi:ss'), to_date('09-01-2015 00:00:00','dd-mm-yyyy hh24:mi:ss'));
  insert into shift_dt values ('Brian',to_date('09-01-2015 00:00:00','dd-mm-yyyy hh24:mi:ss'), to_date('10-01-2015 22:00:00','dd-mm-yyyy hh24:mi:ss'));
  
  select * from shift_dt;
  
  
  

  Select * from shift_dt;

  

  Expected result set: -.

  

  I compare date of shift_end with the next date of shift_start of the day. If the dates made 12 am (IE 00:00:00), then I ignore and display the next shift end date available as displayed in the screen game result. Please see the screen set outcome turned for more details.

  Please help get the results you want in the SQL query

  Kind regards

  Souls

  Hello

  Here's one way:

  WITH got_new_grp AS

  (

  SELECT name, shift_start, shift_end

  CASE

  WHEN shift_start = TRUNC (shift_start)

  AND shift_start = LAG (shift_end) OVER (ORDER BY shift_start)

  THEN 0

  1. OTHER

  END AS new_grp

  OF shift_dt

  )

  got_grp AS

  (

  SELECT name, shift_start, shift_end

  SUM (new_grp) OVER (ORDER BY shift_start) AS grp

  OF got_new_grp

  )

  SELECT MIN (name) DUNGEON (DENSE_RANK FIRST ORDER BY shift_start)

  As a name

  MIN (shift_start) AS shift_start

  MAX (shift_end) AS shift_end

  OF got_grp

  GROUP BY grp

  ORDER BY shift_start

  ;

  Output (from the full sample data):

  NAME SHIFT_START SHIFT_END

  -------------------- ---------------- ----------------

  01/01/2015 Brian 09:10 01/01/2015 22:10

  Brian 02/01/2015 09:10 01/05/2015 15:20

  Brian 06/01/2015 10:00 01/06/2015 23:20

  Brian 07/01/2015 11:00 10/01/2015 22:00

  Brian 01/02/2015 15:00 02/02/2015 00:00

  Brian 02/02/2015 11:00 02/02/2015 17:00

  Brian 03/02/2015 00:00 03/02/2015 08:00

  Brian 02/05/2015 15:30 06/02/2015 07:30

  Brian 07/02/2015 23:30 10/02/2015 00:30

  I guess that shift_start is unique.

  It's finally a GROUP BY problem: we want to show the first shift_start and the last shfit_end of a group of 1 or more lines.  The tricky part is to identify the groups.  If I understand the problem, line X is grouped with the previous line X-1 if shift_start on the X line is midnight and is equal to shift_end on line X-1.  The above query uses the LAG analytic to see if each line begins a new group or not and the analytic function SUM to see how many groups have already begun (and therefore, which group each line entry belongs.)

  I still don't understand why you 'Corrected name of Anne in Brian' and not vice versa.  I guess the name to display in each group is the name of the first row in the Group (i.e. the line with the shift_start earlier).

• ORA-06504: PL/SQL: return variables of the game results or the query types do not match

  Hello!

  I have a simple object type and a proecdure in which I am trying to use it to insert into another table

  -object

  CREATE ORREPLACETYPEmt_mtg ASOBJECT

  (

  ACOL NUMBER ,

  BCOL NVARCHAR2 (100)

  );

  CREATE ORREPLACETYPEREF_MTG ASTABLEOFMt_MTG ;

  -same structure as the use of sampletbl target table in the cursor query

  create table tbl_MT_MTG

  (

  ACOL NUMBER ,

  BCOL NVARCHAR2 (100)

  );

  -procedure

  CREATE ORREPLACEINTERIORTEST_PROCEDURE1

  AS

  ref_cur sys_refcursor ;

  REFR ref_mtg ;

  BEGIN

  OPEN ref_cur FOR

  Select acol,

  BCOL

  DE sampletbl où rownum<10;

  Fetch ref_cur in bulk collectintorefr;

  Insert intotbl_MT_MTG(acol,bcol)selectacol,bcol fromtable(refr);

  commit;

  CLOSE Ref_cur;

  END;

  /

  When I run this procedure fails with

  ORA-06504: PL/SQL: return variables of the game results or the query types do not match

  ORA-06512: at "TEST_PROCEDURE1", line 10

  ORA-06512: at line 2

  Any help on this please...

  Thanks to an OLD POST below

  so perfect helped me! Thank you

  Tubby

  After 5 years of more :-)

  How to store refcursor in collection How to store refcursor in collection

• Query results pane should display the entire XML following the execution of the query

  Hi, I'm trying to get the xml output results returned in sqldeveloper returned in full.

  they are truncated to.

  I tried the trick / * xml * / but that is implemented in the form xml cdata codes and other structures of nickname.

  Select xmlserialize (DOCUMENT

  XMLELEMENT ("root",

  XMLAttributes ('http://www.millicom.com' as 'xmlns'),

  XMLAGG)

  XMLELEMENT ("line",

  XMLFOREST (U.username,

  U.user_id,

  U.PASSWORD,

  U.ACCOUNT_STATUS,

  U.LOCK_DATE,

  U.EXPIRY_DATE,

  U.DEFAULT_TABLESPACE,

  U.TEMPORARY_TABLESPACE,

  U.CREATED,

  U.PROFILE,

  U.INITIAL_RSRC_CONSUMER_GROUP,

  U.EXTERNAL_NAME,

  U.PASSWORD_VERSIONS,

  U.EDITIONS_ENABLED,

  U.AUTHENTICATION_TYPE)))

  AS CLOB DASH)

  from dba_users U

  CROSS JOIN (select 1 of the double connect by level < = 10);

  Thanks for any help you can offer.

  
  

  JM

  Hi jm,

  In the line of query results, did scroll all the way to the right, then click twice on the «...» "at the end of the line to open the cell editor?

  So again, who does not show all the XML, it may be a problem with the version of the ojdb6.jar in use (11.2.0.3 client or later is required), or whether or not the JDBC OCI/thickness is used.  Read the following discussion: retrieve XMLTYPE based on very slow saved schema

  Kind regards

  Gary

  SQL development team

• new to 4.02, no grid or column names in the query results

  It is a bit strange, I have SQL Developer 4.02 just installed, and I don't see grid or column names in the query results.  Don't see anything useful in tools > Preferences, what don't get me?

  The worksheet gives you a couple of different ways to run a query...

  1. instruction execute sheet icon toolbar (large green arrow, or Ctrl + Enter).

  This produces a results tab of the query with the data displayed in a grid.

  2. worksheet icon toolbar Execute the Script (the small tip of the green arrow on lined paper, or F5).

  This produces a tab out of the Script with the data displayed on the printer.

  If execution of the statement to Execute the Script, using some SQL * most orders will remove the column headers:

  1. set the position

  2. set the pagesize 0 (or 1 or 2).

  Pagesize and linesize default is - 1.  By default, the spreadsheet is free for formatting output script as he wishes.  If you have not changed these settings in the spreadsheet, then see if you point to a startup script in Tools > Preferences > Database > name of the connection startup script file

  Kind regards

  Gary

  SQL DeveloperTeam

• Help on the game of query results

  Hi gurus,

  Have this survey for my requirement of dataset sql.

  Sample, it's that I have to pick up the nonfunctional currency transactions.

  Lets say for a given month, data that are present are for CurrencyA and CurrencyB for a particular account.

  Account1 has a transaction does not work CurrencyA and CurrenyB then Account2 has only transaction to CurrencyB.

  My current query result is that the 3 first lines, what I need is the 4th should also appear and be included.

  CurrencyA - amount - account1

  CurrencyB - amount - account1

  CurrencyB - amount - Account2

  CurrencyA - < '0' / or null >-Account2

  I think that my request is based on the currency < x > I have, so it should be for each account, he has all the lines for each currency.

  If please notify and let me know your thoughts.

  Kind regards

  Hello

  It looks like you want an outer join partitioned.

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002

• The SQL query result

  Hello

  Here's my data in the table for itm_id = 1000

  ITM_ID	ADD_ATR	DEL_ATR
  1000	a: b:c:d
  1000		d
  1000	d
  1000	e:f:g
  1000		e:f:g

  My required return is (a: b:c:d) d = a: b: c + d = a: = a +(e:f:g) b:c:d: b:c:d:e:f:g-(e:f:g) = a: b: c; d

  Output ITM_ID

  1000A: b:c:d

  can we get the output using the sql query above?

  I had tried with union but could not able to get the required result.

  Please let me know if there is no possible solution

  Thank you

  David

  I have the impression that you are looking to treat each character in 'RTA' as an individual item and then add or delete depending on whether they are an ADD_ATR or DEL_ATR.

  So something like...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select 1000 as itm_id, ' a: b/c: some like add_atr, null as del_atr of all the double union)
  2 select 1000, null, would be "union double all the"
  3 select 1000, 'd', null of union double all the
  4 select 1000, 'e:f:g', null of union double all the
  5 select 1000, null, "e:f:g" of all the double union
  6 select 1234, null, "x: y: z" of all the double union
  7 select 1234, 'u: v: w', null of union double all the
  8 select 1234, null, 'u' of all the double union
  9 select 1234, "x: y", null of union double all the
  10. Select 1234, "x: z", null of union double all the
  11. Select 1234, 'p', the double null
  12            )
  13-
  14. end of test data
  15-
  16. Select itm_id
  17, cast (listagg(atr,':') within the Group (order by atr) as varchar2 (40)) output
  18 of)
  19 select itm_id
  20, atr
  21, sum (add_del)
  22 of)
  23 select itm_id
  24, coalesce(add_atr,del_atr) as full_atr
  25, decode (add_atr, null,-1, 1) as add_del
  26, regexp_substr (coalesce(add_atr,del_atr),'[^:] +', 1, level) RTA
  27, flat surface that l
  28 t
  29 to connect by level<= (length(coalesce(add_atr,del_atr)="">
  30 and itm_id = prior itm_id
  31 and coalesce(add_atr,del_atr) = prior coalesce(add_atr,del_atr)
  sys_guid() 32 and prior is not null
  33             )
  34 group by itm_id, atr
  35 having sum (add_del) > 0
  36       )
  37 * group by itm_id
  SQL > /.

  ITM_ID OUTPUT
  ---------- ----------------------------------------
  1000A: b:c:d
  1234 p:v:w:x

  that just shows how stupidly data is as it should be divided every thing in the different elements so that you can then group to determine how many of each, you have (and whether to add or subtract) and then re - combine results again in a combined string.