Variable number of rows to 4 separate columns

Similar Questions

• [8i] way to add a specific number of rows based on a column value?

  I know that the version of Oracle is old:
  Oracle8i Enterprise Edition Release 8.1.7.2.0 - Production
  PL/SQL Release 8.1.7.2.0 - Production
  CORE 8.1.7.0.0-Production
  AMT for HP - UX: 8.1.7.2.0 - Production Version
  NLSRTL Version 3.4.1.0.0 - Production
  
  I'm trying to get an old database data in a specific format, and this should be run several times during the next year, until we can phase out the old database. Unfortunately, it is not particularly useful for formatting the data after he is questioned, so if a SQL solution can be found, it would probably be best.
  
  Some examples of data:
  

  CREATE TABLE     testabc
  (     item     CHAR(25)
  ,     qty     NUMBER(13,4)
  );
  
  INSERT INTO     testabc
  VALUES ('Item1',1);
  INSERT INTO     testabc
  VALUES ('Item2',3);
  INSERT INTO     testabc
  VALUES ('Item3',1);
  INSERT INTO     testabc
  VALUES ('Item4',2);

  I want to get these results:

  ITEM                                  QTY
  ------------------------- ---------------
  Item1                               1.000
  Item2                               3.000
  --blank row
  --blank row
  Item3                               1.000
  Item4                               2.000
  --blank row
  
  OR
  
  ITEM                                  QTY
  ------------------------- ---------------
  Item1                               1.000
  Item2                               1.000
  Item2                               1.000
  Item2                               1.000
  Item3                               1.000
  Item4                               1.000
  Item4                               1.000

  Either format would be acceptable. The key is to have the same number of rows for an article as its quantity.
  
  Any help on this would be appreciated. I wasn't sure if maybe that this would require a CONNECT BY statement. With my luck, it requires one of the functions which did not become available until 9i...
  
  I tried this:

  SELECT     CASE
            WHEN     LAG(qty)     OVER(PARTITION BY item ORDER BY item, qty DESC)     = 1
            THEN     item
       END                    AS item
  ,     CASE
            WHEN     LAG(qty)     OVER(PARTITION BY item ORDER BY item, qty DESC)     > 1
            THEN     LAG(qty)     OVER(PARTITION BY item ORDER BY item, qty DESC) - 1
       END                    AS qty
  FROM     testabc
  ;

  but he gave me a bunch of empty lines.
  
  Thank you!

  Hello

  Here's a way to do it in Oracle 8.1

  SELECT       CASE  c.n
            WHEN 1  THEN  t.item
         END          AS item_col
  ,       CASE  c.n
             WHEN 1  THEN  t.qty
         END          AS qty
  FROM       testabc  t
  ,       (
            SELECT     ROWNUM     AS n
            FROM     all_objects
            WHERE     ROWNUM     <= 10     -- If you know an upper bound
         )          c
  WHERE       c.n     <= t.qty
  ORDER BY  t.item
  ,            c.n
  ;
  

  This assumes that this quantity is never more than the number of lines in object (usually at least 5000). If you need more lines, you can cross join object to itself, with the result a limit of 25 million lines or more.
  The WHERE clause in the subquery c is not absolutely necessary, but it will make things faster.

  Published by: Frank Kulash, December 19, 2011 15:33

  The solution above is for the first set of results, with blank lines.
  For the results of the second, with lines no NULL duplicate, just lose the CASE expressions in the FROM clause:

  SELECT       t.item
  ,       t.qty
  FROM       testabc  t
  ,       (
            SELECT     ROWNUM     AS n
            FROM     all_objects
            WHERE     ROWNUM     <= 10     -- If you know an upper bound
         )          c
  WHERE       c.n     <= t.qty
  ORDER BY  t.item
  ,            c.n
  ;
  

• How to reset a number of rows based on a column value?

  OracleBI Discoverer 10g (10.1.2.3)
  Oracle Business Intelligence Discoverer Plus 10g (10.1.2.55.26)
  
  I have a Scout more State showing point receipts, receipt of the dates, and if the reception has been inspected. I've got items that need to be inspected each 5th receipt. There must be a function of hand-dandy, that I can use to do that, right?
  

  Item        Receipt Date      Inspected          
  Bracket     1/1/2009               Y
  Bracket     2/1/2009               N
  Bracket     3/1/2009               N
  Bracket     4/1/2009               Y <--let's assume someone didn't follow the instructions
  Bracket     5/1/2009               N
  Bracket     6/1/2009               N
  Bracket     7/1/2009               N
  Bracket     8/1/2009               N
  Bracket     9/1/2009     

  I'm looking to count receipts and reset the inspection counter = Y
  

  Item        Receipt Date      Inspected     Inspect_Count        
  Bracket     1/1/2009               Y                  0
  Bracket     2/1/2009               N                  1
  Bracket     3/1/2009               N                  2
  Bracket     4/1/2009               Y                  0
  Bracket     5/1/2009               N                  1
  Bracket     6/1/2009               N                  2
  Bracket     7/1/2009               N                  3
  Bracket     8/1/2009               N                  4
  Bracket     9/1/2009                                  5 <-- receiver should inspect on this receipt

  I'm open to other methods if the mine seems to be a failure.
  
  -Tracy

  Hello

  I don't think you can do it is Discoverer more only because you must divide twice once to get all inspected records and still counting the days between them.

  What you can do is in Discoverer Admin add an element to the EUL calculated:

  inspections = COUNT (DECODE (inspected, 'Y', 1)) OVER (ORDER BY reception Date)

  In Discoverer, you can add a calculation:

  Count (inspected) over (PARTITION BY ORDER BY Date of receipt) - 1

  to produce the County to inspect.

  Rod West

• Display the option button if the number of rows in the table is equal to 1

  I'm having issues there buy maybe a simple script out there.

  I have a table which can have up to four lines. If the table contains only one row, an option button can be clicked to change the format/entry of cells in this row. I have to hide this box of a user option, if they added more of a line to the table and make it available again if they reduce the number of lines to one.

  I have everything else works well (radio buttons change line format, add/delete rows in the table using buttons, number of rows in the first column)

  Anyone have any ideas?

  See you soon

  Bobby

  You can place it in the code that adds more lines when running... If you have questions send the fomr to [email protected] so I can check it out...

  Thank you

  Srini

• How to determine the number of rows in the database and save the result to a local variable?

  Hello

  I'm a newbie in the use of TestStand, databases and SQL, and now I've met difficulties. I use TestStand 2014 (32 bit).

  I have a need to know the number of rows in a database and save that number in a local variable. I tried to practice using the database of the Types of step provided with TS. I tried to use the following in a SQL statement:

  Locals.NumberOfRows = ("SELECT COUNT (*) FROM TEST_TABLE")

  It returns an error: specified value is not the expected type. My goal is possible in this way, or I'm doing this completely wrong?

  -RautSa

  Thank you for your response, Norbert. I have a database of who wins new values at random, and sometimes I need the exact number of rows in this table.

  I managed to achieve my goal by using the SQL statement: "SELECT COUNT (*) as Rowcount OF TEST_TABLE", followed by a data GET operation, which records that number of lines in a local variable.

  -RautSa

• Insert in the table in separate columns

  I did the vi in the attachments. This basically vi, calculate a value from the device, this is the channel dashboard. I need more so: when calculating terminate, I need to insert data into a table, but the problem is: the number of lines in the constant table is the number of columns, I need the Temp Org chart. And these values are variable. I need a method to do this automatically. Or, I need a vi to 'build' these columns according to the number of rows in the table of constants.

  If the table of constants (number of lines) and the channel table (number of items) to match the size, where the other constants come when the size has to increase?

  What intrigues me is your use of construction "array index... build array. It's the same as truncate the initial 3-element array, regardless of the number of items is originally in there.

  Here's a quick rewrite that eliminates some of the questionable things. As I mentioned in the first sentence, I don't know really what you want.

• Values of Colum as separate columns

  I have a table that looks like this:
  
  Company (varchar),
  FieldName (varchar)
  Valuex (varchar)
  
  Data can look like this:
  
  Company Fieldname valuex
  ------------- --------------- -----------
  
  John 123 name
  MiddleName 123 C
  LastName 123 Smith
  
  I would like to write a query that comes out like this:
  
  MiddleName t first name last name company
  ------------- ------------ ---------------- ------------
  Smith John 123 C
  
  
  
  It can be? Thanks in advance.

  Hello

  Column definitions must be hard-coded in the application.
  You cannot hardcode anything today and make sure that it reflects accurately data next year.
  but you can write soemthing today who, when it is executed next year, will make the hardcode then.
  This is called dynamic SQL.
  Here's a way to do it in SQL * Plus, with the command of the COIL:

  /*
  How to Pivot a Table with a Dynamic Number of Columns
  
  For example, you want to make a cross-tab output of
  the scott.emp table.
  Each row will represent a department.
  There will be a separate column for each job.
  Each cell will contain the number of employees in
       a specific department having a specific job.
  The exact same solution must work with any number
  of departments and columns.
  (Within reason: there's no guarantee this will work if you
  want 2000 columns.)
  */
  
  PROMPT     ==========  0. Basic Pivot  ==========
  
  SELECT     deptno
  ,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
  ,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
  ,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
  FROM     scott.emp
  WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
  GROUP BY     deptno
  ORDER BY     deptno
  ;
  
  PROMPT     ==========  1. Dynamic Pivot  ==========
  
  --     *****  Start of dynamic_pivot.sql  *****
  
  -- Suppress SQL*Plus features that interfere with raw output
  SET     FEEDBACK     OFF
  SET     PAGESIZE     0
  
  SPOOL     p:\sql\cookbook\dynamic_pivot_subscript.sql
  
  SELECT     DISTINCT
       ',     COUNT (CASE WHEN job = '''
  ||     job
  ||     ''' '     AS txt1
  ,     'THEN 1 END)     AS '
  ||     job
  ||     '_CNT'     AS txt2
  FROM     scott.emp
  ORDER BY     txt1;
  
  SPOOL     OFF
  
  -- Restore SQL*Plus features suppressed earlier
  SET     FEEDBACK     ON
  SET     PAGESIZE     50
  
  SPOOL     p:\sql\cookbook\dynamic_pivot.lst
  
  SELECT     deptno
  @@dynamic_pivot_subscript
  FROM     scott.emp
  GROUP BY     deptno
  ORDER BY     deptno
  ;
  
  SPOOL     OFF
  
  --     *****  End of dynamic_pivot.sql  *****
  
  /*
  EXPLANATION:
  The basic pivot assumes you know the number of distinct jobs,
  and the name of each one.  If you do, then writing a pivot query
  is simply a matter of writing the correct number of ", COUNT ... AS ..."\
  lines, with the name entered in two places on each one.  That is easily
  done by a preliminary query, which uses SPOOL to write a sub-script
  (called dynamic_pivot_subscript.sql in this example).
  
  The main script invokes this sub-script at the proper point.
  In practice, .SQL scripts usually contain one or more complete
  statements, but there's nothing that says they have to.
  This one contains just a fragment from the middle of a SELECT statement.
  
  Before creating the sub-script, remember to turn off SQL*Plus features
  that are designed to help humans read the output (such as headings and
  feedback messages like "7 rows selected.", since we do not want these
  to appear in the sub-script.
  Remember to turn these features on again before running the main query.
  
  */
  

  The first HOLD file that it creates, dynaic_pivot_subscript.sql, looks like this

  ,     COUNT (CASE WHEN job = 'ANALYST'    THEN 1 END)     AS ANALYST_CNT
  ,     COUNT (CASE WHEN job = 'CLERK'      THEN 1 END)     AS CLERK_CNT
  ,     COUNT (CASE WHEN job = 'MANAGER'    THEN 1 END)     AS MANAGER_CNT
  ,     COUNT (CASE WHEN job = 'PRESIDENT'  THEN 1 END)     AS PRESIDENT_CNT
  ,     COUNT (CASE WHEN job = 'SALESMAN'   THEN 1 END)     AS SALESMAN_CNT
  

• number of rows affected by report

  Hi all
  
  I want to show the number of result rows to a query on a report page. my test query returns 52 sets of data (also when I execute the same statement with select count (*)) but the #TOTAL_ROWS variable # said that 11.
  I think it's because I put the value in pagination of row 10...
  
  is there a known issue with this? is #TOTAL_ROWS # only supposed to show the number of lines of recoveries?
  
  Thanks in advance hendrik

  Hendrik,

  This will not work unless you paging system is set (with pagination). You can always count your rows in a separate process and get this value by using the same SQL as in your report.

  Denes Kubicek
  -------------------------------------------------------------------
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• Export of DataPump API - number of rows exported using

  Hello

  I'm working on the procedure to export data in the table before deleting the partition. It will be run by the Scheduler of the data, that's why I want to run the datapump job using the API.

  I wonder, if it is possible to get the number of rows exported. I would compare with the number of rows in a partition before you delete the partition.

  
  

  Thank you

  Krystian

  Hello

  Don't know exactly how you want the number of rows per partition that have been exported, but here are a few ideas:

  1. create a log file by using 'add_file ':

  -Add a log file

  dbms_datapump.add_file (h, ' DEPTJOB.log ', a', NULL,)

  dbms_datapump.Ku$ _file_type_log_file);

  It is also in my example included below.  Here is the content after the DEPTJOB.log workload (situated in Oracle Directory object would be "in my example):

  $ cat /tmp/DEPTJOB.log

  Departure 'SCOTT '. "" DEPTJOB ":

  Object type TABLE_EXPORT/TABLE/TABLE processing

  Processing object type TABLE_EXPORT/TABLE/TABLE_DATA

  . . "exported"SCOTT" DEPT': 'SYS_P1581' 5,929 KB 2 lines

  . . "exported"SCOTT" DEPT': 'SYS_P1582' 5,914 KB 1 lines

  . . "exported"SCOTT" DEPT': 'SYS_P1583' 5,906 KB 1 lines

  Table main 'SCOTT '. "' DEPTJOB ' properly load/unloaded

  ******************************************************************************

  Empty the files together for SCOTT. DEPTJOB is:

  /tmp/Dept.dmp

  Job 'SCOTT '. "" DEPTJOB "managed to 00:00

  You can then review or extract the information from the log file.

  2. save the master table and the query for the busy lines.

  Use the parameter "KEEP_MASTER":

  -Keep the main table to be deleted after employment ends

  dbms_datapump.set_parameter(h,'KEEP_MASTER',1);

  Here's my example, the request to the main table is at the end.

  $ sqlplus scott/tiger @deptapi

  SQL * more: version 12.2.0.0.2 Beta on Fri Jan 22 12:55:52 2016

  Copyright (c) 1982, 2015, Oracle.  All rights reserved.

  Last successful login time: Friday, January 22, 2016 12:55:05-08:00

  Connected to:

  Database Oracle 12 c Enterprise Edition Release 12.2.0.0.2 - 64-bit Beta

  With the options of partitioning, OLAP, advanced analytics and Real Application Testing

  Connected.

  SQL > SET FEEDBACK 1

  SQL > SET 10 NUMLARGEUR

  SQL > SET LINESIZE 2000

  SQL > SET TRIMSPOOL ON

  SQL > SET TAB OFF

  SQL > SET PAGESIZE 100

  SQL > SET SERVEROUTPUT ON

  SQL >

  SQL > Rem save on the old table of scott.dept

  SQL > dept and rename it dept_old.

  Renamed table.

  SQL >

  SQL > Rem re-create it with partitions

  SQL > CREATE TABLE dept (deptno NUMBER varchar (14) dname, loc varchar (13)) PARTITION INTO 3 PARTITIONS HASH (deptno)

  2.

  Table created.

  SQL >

  SQL > Rem fill the dept table

  SQL > insert into dept select * from dept_old;

  4 lines were created.

  SQL >

  SQL > Rem now create datapump job export SCOTT. DEPT. using the API

  SQL > DECLARE

  2: NUMBER;         -Handle Datapump

  3 jobState VARCHAR2 (30);   -To keep track of job status

  4 ind NUMBER;         -Index of the loop

  5 the ku$ _LogEntry;   -For error messages and work in PROGRESS

  6 js ku$ _JobStatus;  -The State of the work of get_status

  7 jd ku$ _JobDesc;    -The get_status job description

  8 m ku$ _Status;     -The status returned by get_status object

  9 sql_stmt VARCHAR2 (1024);

  nom_partition 10-VARCHAR2 (50);

  11 rows_completed NUMBER;

  12

  BEGIN 13

  14-

  15 run the Installer based on the operation to perform.

  16-

  17 h: = dbms_datapump.open ('EXPORT', 'TABLE', NULL, 'DEPTJOB', NULL);

  18 dbms_datapump.add_file (h, 'dept.dmp', 'd', NULL,

  dbms_datapump.Ku$ _file_type_dump_file 19, 1);

  20

  21    --- Add a logfile                                                         

  22 dbms_datapump.add_file (h, ' DEPTJOB.log ', a', NULL,)

  23 dbms_datapump.ku$ _file_type_log_file);

  24

  25 dbms_datapump.metadata_filter (h, 'SCHEMA_EXPR', ' IN ("SCOTT") ");

  26 dbms_datapump.metadata_filter (h, 'NAME_LIST', "'DEPT"');

  27

  28

  29-

  30 start work.

  31-

  32 dbms_datapump.set_parameter (h, 'SILENT', 'banner');

  33

  34 -keep the main table to be deleted after employment ends

  35 dbms_datapump.set_parameter(h,'KEEP_MASTER',1);

  36

  37 dbms_datapump.start_job (h);

  38

  39-

  40 - run to grabbing the output of the job and write in the output log.

  41-

  42 jobState: = "UNDEFINED";

  43 WHILE (jobState! = "COMPLETED") AND (jobState! = "STOPPED")

  44 LOOP

  45 dbms_datapump.get_status (h,

  dbms_datapump.Ku$ _status_job_error 46.

  dbms_datapump.Ku$ _status_wip 47, -1, jobState, m);

  48

  49      --

  50. If we received messages WIP or error for the work, display them.

  51      --

  52 IF (BITAND(sts.mask,dbms_datapump.ku$_status_wip)! = 0)

  53 THEN

  54: = sts.wip;

  55 ON THE OTHER

  56 IF (bitand(sts.mask,dbms_datapump.ku$_status_job_error)! = 0)

  57 THEN

  58: = sts.error;

  59 ON THE OTHER

  the 60: = NULL;

  61 END IF;

  62 END IF;

  63

  64 the IS NOT NULL IF

  65 THEN

  66 ind: = the. FIRST;

  67 then AS ind IS NOT NULL

  68 LOOP

  69 dbms_output.put_line ((ind). LogText);

  70 ind: = the. Next (IND);

  LOOP END 71;

  72 END IF;

  73 END LOOP;

  74

  75-

  76 - release work.

  77-

  78 dbms_datapump.detach (h);

  79

  80-

  81. all exceptions that spread at this point will be captured.

  82 - the details are extracted from get_status and displayed.

  83-

  EXCEPTION OF 84

  85, SO THAN OTHERS THEN

  BEGIN 86

  87 dbms_datapump.get_status (h,

  dbms_datapump.Ku$ _status_job_error, 0-88,.

  89 jobState, sts);

  90 IF (BITAND(sts.mask,dbms_datapump.ku$_status_job_error)! = 0)

  91 THEN

  the 92: = sts.error;

  93 the IS NOT NULL IF

  94 THEN

  95 ind: = the. FIRST;

  96 although ind IS NOT NULL

  LOOP OF 97

  98 dbms_output.put_line ((ind). LogText);

  99 ind: = the. Next (IND);

  100 END LOOP;

  101 END IF;

  102 END IF;

  103

  BEGIN 104

  105 DBMS_DATAPUMP. STOP_JOB (m, 1, 0, 0);

  EXCEPTION OF 106

  107. WHEN OTHER NULL THEN;

  END 108;

  109

  110 EXCEPTION

  111, SO THAN OTHERS THEN

  112 dbms_output.put_line ('ORA-00000: an unexpected exception during ' |)

  113 ' Manager of exceptions. ' ||

  114 ' sqlcode = ' | TO_CHAR (SQLCODE));

  END 115;

  END 116;

  117.

  Departure 'SCOTT '. "" DEPTJOB ":

  Object type TABLE_EXPORT/TABLE/TABLE processing

  Processing object type TABLE_EXPORT/TABLE/TABLE_DATA

  . . "exported"SCOTT" DEPT': 'SYS_P1581' 5,929 KB 2 lines

  . . "exported"SCOTT" DEPT': 'SYS_P1582' 5,914 KB 1 lines

  . . "exported"SCOTT" DEPT': 'SYS_P1583' 5,906 KB 1 lines

  Table main 'SCOTT '. "' DEPTJOB ' properly load/unloaded

  ******************************************************************************

  Empty the files together for SCOTT. DEPTJOB is:

  /tmp/Dept.dmp

  Job 'SCOTT '. "" DEPTJOB "managed to 00:00

  PL/SQL procedure successfully completed.

  SQL >

  SQL > table main query Rem for number of lines completed

  SQL > column nom_partition format a10

  SQL > format 9999 column lines

  SQL > SELECT nom_partition, COMPLETED_ROWS FROM SCOTT . DEPTJOB WHERE BASE_OBJECT_NAME = "DEPT";

  PARTITION_ COMPLETED_ROWS

  ---------- --------------

  SYS_P1581 2

  SYS_P1583 1

  SYS_P1582 1

  3 selected lines.

  SQL >

  SQL > "EXIT";

  3. you might even extract information of the call from the command line:

  $ sqlplus scott/tiger @deptapi.sql | grep 'exported ' | AWK ' {print "Table:" $4, 'charge' $7, $8} '

  Table: 'SCOTT '. "" DEPT ":"SYS_P1581"loaded 2 rows

  Table: 'SCOTT '. "' DEPT ': 'SYS_P1583' loaded 1 lines

  Table: 'SCOTT '. "' DEPT ': 'SYS_P1582' loaded 1 lines

• Invalid reference to the variable 'NUMBER '.

  Hi gurus

  I understand that if someone helps me, I have the following code example.

  Code example

  SET SERVEROUTPUT ON

  DECLARE

  List_of_numbers_t TYPE TABLE IS NUMBER;

  l_numbers list_of_numbers_t: =.

  list_of_numbers_t (1,2,3);

  BEGIN

  DBMS_OUTPUT. Put_line (l_numbers (1).) (COUNT);

  END;

  Error

  Error report:

  ORA-06550: line 7, column 38:

  PLS-00487: Invalid reference to the variable 'NUMBER '.

  ORA-06550: line 7, column 3:

  PL/SQL: Statement ignored

  06550 00000 - "line %s, column % s:\n%s".

  * Cause: Usually a PL/SQL compilation error.

  * Action:

  I want to check the index 1 of my collection, but I get the above error. Can someone help me to remove this error. Thank you

  Concerning

  Matt

  
  

  Hi, Matt,

  Matt. wrote:

  Hi gurus

  I understand that if someone helps me, I have the following code example.

  Code example

  SET SERVEROUTPUT ON

  DECLARE

  List_of_numbers_t TYPE TABLE IS NUMBER;

  l_numbers list_of_numbers_t: =.

  list_of_numbers_t (1,2,3);

  BEGIN

  DBMS_OUTPUT. Put_line (l_numbers (1).) (COUNT);

  END;

  Error

  Error report:

  ORA-06550: line 7, column 38:

  PLS-00487: Invalid reference to the variable 'NUMBER '.

  ORA-06550: line 7, column 3:

  PL/SQL: Statement ignored

  06550 00000 - "line %s, column % s:\n%s".

  * Cause: Usually a PL/SQL compilation error.

  * Action:

  I want to check the index 1 of my collection, but I get the above error. Can someone help me to remove this error. Thank you

  Concerning

  Matt

  The collections have some counts; scalars don't.

  l_numbers is a collection, so you can see the number of items contained in it like this:

  DECLARE

  List_of_numbers_t TYPE TABLE IS NUMBER;

  l_numbers list_of_numbers_t: =.

  list_of_numbers_t (1,2,3);

  BEGIN

  DBMS_OUTPUT. Put_line (l_numbers. (COUNT);

  END;

  /

  l_numbers (1) , however, is just a scalar NUMBER, you can't use COUNT on it

  In other words, l_numbers (1) is the number 1, so we can not say

  DBMS_OUTPUT. Put_line (l_numbers. (COUNT);

  for exactly the same reason that you can't say

  DBMS_OUTPUT. Put_line (1. (COUNT);

• Number of rows in each partition is displayed with a NULL value for a table partitioned in user_tab_partitions. Why?

  I created a table and partitioned on the date of the entry and added a local partitioned index.

  Now, I use a query to extract "num_rows" of user_tab_partitions to know the number of rows in each partition.

  Getting this value as null num_rows, wonder why?

  After looking to explain the Plan after interrogation ("select * from my_table1 where entry_date = 1 January 2015" ;))

  to find out if she actually partitioned table and its data in different partitions, I interpreted in effect because the query plan had a line like Partition_range (Single).

  My Question is:

  (a) is actually partitioned data (have I misinterpreted the Explain plan)

  (b) why is the num_rows null column in the query (Pasted below)

  (c) also in addition what difference it would have been if I had created a Global Index instead of the Local Index in my case?

  The following code Snippet:

  ----------------------------------------------------------------------------------------------

  create the table my_table1
  (
  roll_no number constraint my_table1_pk primary key,
  date of entry_date
  )
  partition of range (entry_date)
  (
  PARTITION data_p1 VALUES LESS THAN (TO_DATE (December 31, 2014 ',' DD-MM-YYYY ""));
  PARTITION data_p2 VALUES LESS THAN (MAXVALUE)
  );

  
  create an index only my_table1_indx on my_table1 (entry_date) local;

  ----------------------------------------------------------------------------------------------

  I now insert two lines:
  insert into my_table1 values (1, to_date ('01-01-2015', ' dd-mm-yyyy'));
  insert into my_table1 values (2, to_date('01-02-2015','dd-mm-yyyy'));

  ----------------------------------------------------------------------------------------------

  These have been inserted successfully, now using the query below shows num_rows column as null. I don't know why?

  SELECT table_name, num_rows, high_value, nom_partition
  Of user_tab_partitions
  where table_name = 'MY_TABLE1 '.
  ORDER BY table_name, nom_partition;

  ----------------------------------------------------------------------------------------------

  
  

  (a) is actually partitioned data (have I misinterpreted the Explain plan)

  Yes, it is partitioned. You can query this particular partition SELECT * FROM my_table1 (data_p1) PARTITION to check that.

  (b) why is the num_rows null column in the query (Pasted below)

  As already mentioned that you have not collected statistics.

  (c) also in addition what difference it would have been if I had created a Global Index instead of the Local Index in my case?

  In fact, you have created two types of indexes without knowing (can be)! One is not partitioned (although this column is not partition key) and another is partitioned (LOCAL). They are MY_TABLE1_PK and MY_TABLE1_INDX. You can check that USER_INDEXES.

  You can read this article to get an early jump on the partitioning of decision. Partition: Partition decisions

• number of rows fetch are not even

  Hi all
  
  
  I'm new to sql/plsql
  
  Oracle version 11R2
  RHL 5.0 OS
  
  
  I'm deleting all rows in the parent table as well as children tables based on some criteria to date.
  
  the parent BE_STATUS table contains a column OOC_DT. based on the OOC_DT I get BE_STATUSin the parent Table rows.
  
  other children tables DOES NOT have OOCDT column but meet BENo. and BEDT WHO are also in PARENT TABLE BESTATUS.
  
  
  So I get all the be_no, * be_dt * of BE_STATUS based on the OOC_DT column as below
  

  select distinct(count(*)) from be_status where ooc_dt between '31-mar-10' AND '24-dec-10';
  
  (COUNT(*))
  ----------
   65074 

  and I create a temporary table based on the above query as
  

  create table temp as select be_no, be_dt from be_status where ooc_dt between '31-mar-10' AND '24-dec-10';
  table created.

  and then I count the number of rows in the temporary table
  

  select distinct(count(*)) from temp;
  (COUNT(*))
  ----------
   65074 

  so there are around 51 children tables that have the BE_NO AND BE_DTcolumn.
  
  If the total number of lines in the temp must be equal to the total of all the lines in each column according to the above criteria.
  
  It's

  select distinct(count(*)) from be_penal  where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
          64 
  
  select distinct(count(*)) from be_fine  where (be_no,be_dt) in (select be_no,be_dt from temp);
  
  (COUNT(*))
  ----------
          62
   
  select distinct(count(*)) from be_cash_lic  where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
          23 
  
  select distinct(count(*)) from c_cl_be  where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
           2 
  select distinct(count(*)) from chex where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
           0 
  select distinct(count(*)) from amend_q where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
           0 
  
  select distinct(count(*)) from be_perm  where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
         889 
  select distinct(count(*)) from exam_instr where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
         690
  
  select distinct(count(*)) from c_rms_mesg  where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
       64982
  
  select distinct(count(*)) from item_duty_fg  where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
      398129 
  
  select distinct(count(*)) from a_item_det  where (be_no,be_dt) in (select be_no,be_dt from temp);
  (COUNT(*))
  ----------
       31453
  select distinct(count(*)) from item_det  where (be_no,be_dt) in (select be_no,be_dt FROM temp);
  (COUNT(*))
  ----------
      622271

  so, as you can see the TEMP TABLE contains only * 65074 *. Therefore the sum of the numbers of all of the above tables should be * 65074 * but only item_det contains
  * 622271 * lines.
  
  
  I have made a mistake in counting the records individually?
  
  waiting for your helpful answer
  
  Thanks and greetings

  Not quite sure, I followed your question, but a glaring fault in your codes...

  between '31-mar-10' AND '24-dec-10';
  

  dates should be treated as dates, not the chains and left us 2 years of numbers of programming standards waaay back in the 90's when everyone fixed these issues in the context of the challenges of the Millennium bug.

  between to_date('31-mar-2010','DD-MON-YYYY') AND to_date('24-dec-2010','DD-MON-YYYY');
  

• How can I get the number of rows in the table using Sunopsis API target in ODI 10 g?

  Hi guys,.
  
  In fact, I want to send an alert message as soon as the interface is run from a package. I've included alert OdiSendMail that sends an email once the interface is running.
  
  Could someone please tell how to get the number of rows inserted into the table the Sunopsis API target.
  
  I tried to use < % = odiRef.getNbRows () % >, but this has not worked for me. Since I am a beginner, could you please help out me
  
  This is my mail to send ODI format
  
  "The population of data managed to < % = odiRef.getSysDate () % >
  
  Total of lines in the target table is: < - need an API code-> "
  
  
  Kind regards
  
  Clinton
  
  Published by: LawrenceClinton on February 25, 2013 20:53

  Hello

  Create the project with details below variable

  Nom_de_variable: Total_Row_Count

  Type of variable: Variable discount

  Definition tab:
  Data type: digital
  Action: No persistent

  Refresh the tab:
  Schema: provide the schema of your repository to work and be

  SELECT log.nb_row
  THE journal of snp_step_log, snp_scen_step step
  WHERE log.nno = step.nno
  AND step.scen_no = (SELECT scen_no FROM snp_scen_step WHERE step_name='<%=odiRef.getPrevStepLog ('STEP_NAME") % > ')
  AND log.sess_no = '< % = odiRef.getSession ("SESS_NO") % >' code at low
  AND step.step_name = ' < % = odiRef.getPrevStepLog ("STEP_NAME") % > '

  Note: add this variable after the stage of interface in your package (after the interface anywhere you can place), you can add this variable before ODISendEmailNotification in your package

  call this varciable * #Total_Row_Count * in the Notification of ODISendEmail

  for example :

  Data has been fulfilled successfully in < % = odiRef.getSysDate () % >
  Total no of lines filled are: * #Total_Row_Count *

  it will work

  cordially,
  Phanikanth

  edited by: Phanikanth on February 28, 2013 01:13

  edited by: Phanikanth on February 28, 2013 01:14

• Count the number of rows returned from each view in USER_VIEWS

  For each USER_VIEWS view, I would return the name, creation date, last modified dateand the number of rows returned by this view.
  
  Here's what I have so far:
  

  col object_name format a20
  select 
  object_name, 
  created, 
  last_ddl_time
  from user_objects
  where object_type = 'VIEW'

  Returns:
  

  OBJECT_NAME          CREATED   LAST_DDL_TIME
  -------------------- --------- -------------
  AISLE_AVG            11-FEB-12 11-FEB-12     
  COURSE_AVG           11-FEB-12 20-FEB-12     
  EXE_12_VIEW          11-FEB-12 21-FEB-12     
  L1_P2                17-FEB-12 17-FEB-12     
  L1_P3                17-FEB-12 17-FEB-12     
  L1_P4                17-FEB-12 17-FEB-12     
  L1_P5A               17-FEB-12 17-FEB-12     
  L1_P5B               17-FEB-12 17-FEB-12     
  LAB3_1A              12-FEB-12 20-FEB-12     
  LAB3_1B              12-FEB-12 20-FEB-12     
  LAB3_2A              12-FEB-12 20-FEB-12     
  LAB3_2B              12-FEB-12 20-FEB-12     
  LAB5_1               19-FEB-12 19-FEB-12     
  LAB5_2               19-FEB-12 19-FEB-12     
  LAB5_3               19-FEB-12 19-FEB-12     
  LAB5_4               19-FEB-12 19-FEB-12     
  LAB5_5               19-FEB-12 19-FEB-12     
  LAB5_TIMES           19-FEB-12 19-FEB-12     
  LAB6_1               19-FEB-12 19-FEB-12     
  LAB7_VIEW            20-FEB-12 20-FEB-12     
  PROGRAMS             11-FEB-12 21-FEB-12     
  STUDENT_GPA          11-FEB-12 21-FEB-12     
  
   22 rows selected 

  How can I add a last column that counts the number of rows returned by this view?
  
  EDIT - here is a dump of my paintings, and here are my views.
  
  Edit2 - this is possible by using the DECODE function, by chance?

  The function...

  CREATE OR REPLACE FUNCTION view_row_count (view_name VARCHAR2)
  RETURN NUMBER
  AS
  retval NUMBER;
  BEGIN
  EXECUTE IMMEDIATE
  'select count(*) from '||view_name INTO retval;
  RETURN retval;
  END view_row_count;
  /
  

  And now the query...

  select
  object_name,
  created,
  last_ddl_time,
  view_row_count(object_name) as view_row_count
  from user_objects
  where object_type = 'VIEW'
  

• Download sql % number of rows on a table

  We have
  
  REMOVE from X WHERE Y = "aaa";
  
  Dbms_output.put_line (number of rows sql %);
  
  The above shows the number of deleted rows.
  
  You want to load the value of rowcount % sql on a table. Using the below
  
  INSERT IN the AUDIT (COUNTY) VALUES (number of rows sql %);
  
  -error.
  
  Please let me know how to load this value in an audit table. Thank you

  Store it in a variable after remove it and insert the contents of the variable by using the insert statement later.

  HTH