"WARNING: illegal character in the string literal encoding.

Similar Questions

• How to check an ascii value of the character in the string

  Hi all
  I have a string that contain alphanumeric values.
  I want only numeric values in this string.
  FRO this purpose.
  I created a varry
  

  TYPE tab IS VARRAY(10) OF VARCHAR2(10) ;
     var tab

  ;
  variable var of type varray contain this string
  
  and now I want to check each character in this string at end of validation
  
  How can I check this particular string
  
  can I use loop?

  Hello

  If str is a string, then

  REGEXP_LIKE ( str
              , '^[[:digit:]]+$'
              )
  

  Returns TRUE if and only if str contains digits (0 ith 9) and nothing else.
  Here's a way you can use REGEXP_LIKE in PL/SQL:

  SET     SERVEROUTPUT     ON
  
  DECLARE
      str          VARCHAR2 (10)     := '123.4';
  BEGIN
      IF  REGEXP_LIKE ( str
                    , '^[[:digit:]]+$'
                )
      THEN
       dbms_output.put_line (  str
                      || ' is all digits.'
                      );
      ELSE
       dbms_output.put_line (  str
                      || ' contains something besides digits, or is NULL'
                      );
      END IF;
  END;
  /
  

  Published by: Frank Kulash, December 12, 2011 09:13
  Added PL/SQL example

• Select from the table where the last character of the string is numeric

  Hello
  I have a table of STREETS with a field called ADDRESS. I want to select all the records in streets where the last character in the address is a number.
  Select ADDRESS of STREETS where regexp_like (substr (address,?,?,), '[0-9]');
  --? means that I don't know what to put here!
  
  I don't know if substr is the best approach to do this, because I want only the last character and the records are of different lengths.
  
  Thank you!

  Hello

  If you want to use regular expressions:

  WHERE     REGEXP_LIKE ( address
                , '[0-9]$'
                )
  

  You can get the same results, no doubt more effectively, without regular expressions:

  WHERE     INSTR ( '0123456789'
             , SUBSTR (address, -1)
             )     > 0
  

• Enter the character in the string... ?

  Have a chain called "Boris", so want to enter the number of characters 'a' of the chain.

  any help is appreciated!

  SELECT REGEXP_COUNT('sathyanarayana', 'a') FROM DUAL COUNT;

• Select the records in which the last character in the string is a letter

  Hello
  I have a STREET table with a field NAME where there is a single letter at the end of a few names that shouldn't be there. I want to select all names that are like that. For example: "GREENE * B *", "JOHN BATCH * J."
  
  what I would do with this query, is to fill a field new name2 with the correct version of the name without the last letter. Ex: "GREENE B"-> "GREENE.
  Would that be a RTRIM command?
  
  Thank you!

  update t
     set name= TRIM(SUBSTR(NAME,1,LENGTH(NAME)-2))
  WHERE NAME LIKE '% %'
  AND SUBSTR(REVERSE(NAME),2,1) = ' ' 
  

  but, even once, REVERSE (TRIM (SUBSTR (REVERSE (NAME), 3))) would be much faster then using the length

• Insert the tab character in a string

  I am trying to create a string that will be eventually written to a text file, which must be delimited by tabs. I can't figure out how to insert a tab character in the string. Here is an example:
  
  < cfset headerline 'H' & TAB = & #FORM.order_ID # >
  
  Obviously, "TAB" doesn't work here. Help?
  
  Michelle
  

  michellezee@Comcast. wrote:
  > I am trying to create a string that will be eventually written to a text file
  > who should be delimited by tabs. I can't understand how to insert a tab in the
  > string. Here is an example:
  >
  >
  >
  > Of course, "TAB" doesn't work here. Help?
  >
  > Michelle
  >
  >

  TAB = #chr (9).

  --

  Azadi Saryev
  SABAI - Dee.com
  http://www.SABAI-Dee.com

• replace characters in the string

  Hi all

  Is it possible to index the characters in a string as if it were a table and remove them from the second position and now. I just want with the first letter or number so that I can later concatenate strings to it.

  Thanks for any help!

  -Michael

  Hi Michael,

  Yes. Use the function "Sring subset. At the beginning the value 0 (default value) and the length of 1.

  This will give you the first character in the string.

  Steve

• What is the method of the String class's trim() in special cases?

  You are looking for here ( String (Java Platform SE 7) ), I understand that the method of the String class's trim() 'returns a copy of the string with white spaces of early and omitted end', but I don't understand what the last special case Unicode characters is exactly.

  You are looking for here ( list of characters Unicode - Wikipedia, the free encyclopedia ), I see that U + 0020 is a space character, and I also see the characters that follow the character space (for example, the exclamation point character).

  So, I decided to write a sample of the size of the code to try to reproduce the behavior that I quoted (from the documentation of the API of the trim method) in the comment from several line of this code even example. Here is the code example. :

  public class TrimTester {
  
      public static void main(String[] args) {
         
          /*
           * "Otherwise, let k be the index of the first character in the string whose code
           * is greater than '\u0020', and let m be the index of the last character in the
           * string whose code is greater than '\u0020'. A new String object is created,
           * representing the substring of this string that begins with the character at
           * index k and ends with the character at index m-that is, the result of
           * this.substring(k, m+1)."
           */
          String str = "aa!Hello$bb";
          System.out.println(str.trim());
      }
  }
  

  However, what is printed is "aa." «Hello bb$ "(without the quotes) instead of «!» "Hello$" (without the quotes).

  Any input to help me better understand what's happening would be greatly appreciated!

  Hallo,

  I think that the characters 'a' and 'b' both have greater than '\u0020' code, so your entire string is returned by the trim () - method, then the first character of the string whose code is superior to ' \u0020 has index 0, and the last character whose code is greater than '\u0020' a index 10. All printable characters have codes greater than 0020, try "\r\ntest". After trim(), you get 'test '.

  Regarding

  Rafal Z

• Search and replace the string in a column

  Hello
  
  In the table the data stored with "" (double quotes), I need to remove these quotes please suggest me how to remove
  
  
  Select the address of TECH_SOURCING_EMPLOYEE_DETAILS
  
  "No. 12/32"-> data recorded in this format in the table. I need to remove the double quotes
  
  
  Thank you
  Sudhir

  Hello

  UPDATE to modify existing rows in a table
  REPLACE to delete a given sub - a to a string.

  UPDATE     tech_sourcing_employee_details
  SET     address     = REPLACE (address, '"')
  WHERE     INSTR (address, '"')         > 0          -- Maybe
  ;
  

  This will remove all the quotes of the address.
  If you want to remove the quotes only from the beginning and the end of the string, then use TRIM instead of REPLACE:

  UPDATE     tech_sourcing_employee_details
  SET     address     = TRIM ('"' FROM address)
  WHERE     INSTR (address, '"')         > 0          -- Maybe
  ;
  

  The WHERE clause is only for effectiveness.
  So, whenever the column contains quotes, of the double quotation mark is always the first character in the string, then you can change the WHERE clause to:

  WHERE     address  LIKE '"%'
  {code}                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                        
  

• How to convert a string literal function function valid

  Hello
  
  I have a situation where I need to get the built-in (sysdate/sysdate-1/sysdate-2) as variables. As the variable is taken as a string, it is considered as a string, not a function. Is it possible to convert the string literal in valid function.
  
  Here is an example for better understanding. I used v_var to store the 'sysdate-1 "in the form of string literal. Try to change the value.
  
  
  */*-------------------------------------------------------------------------------------*/*
  declare
  
  v_var varchar2 (20): = ' sysdate-1';
  date of v_var2;
  
  Start
  
  Select v_var in the double v_var2;
  
  dbms_output.put_line ('v_var2: ' | v_var2);
  
  end;
  
  */*-------------------------------------------------------------------------------------*/*
  
  
  Thanks in advance

  Or

  SQL>  var str varchar2(20)
  SQL>  exec :str := 'sysdate - 1'
  PL/SQL procedure successfully completed.
  
  SQL>  select trim(dbms_xmlgen.getxmltype('select ' || :str || ' s from dual').extract('//text()')) str from dual
  /
  STR
  ------------------------
  15.07.09
  1 row selected.
  

• Encoding of the string for HTTP Post

  Hello

  I work with HTTP get and post at the moment, I have a server with a REST of apache based interface. Obtaining and displaying the data are no problem for 'normal' strings and characters, but I can't send characters like German "Umlaut" (Ä Ü Ö) or Japanese or Chinese characters. Coding for the Socket connection is UTF-8 and the command POST also contains a line of Content Type with character set UTF-8. The server expects UTF - 8, so I need my data in this encoding.

  When I send strings of InDesign now, I always get an error 'Bad Request' from my server. Looks like that the strings in ESTK is not UTF-8 - How can I create UTF-8 strings? I can't find methods of encoding conversion...

  Thank you

  Klaus

  OK, it took a while to find that - maybe someone else has the same problem and it is looking for a solution, I'll try to explain:

  I downloaded the source files for tomcat to know how tomcat with my data. I debugged deep into the code until I reached the CotoyeInputStream - here the reading of data from InDesign. And although I understood that the stream is read in the form of bytes and characters are counted. The Umlaute and other special characters are encoded as two bytes, but they are counted as a single character. For every Umlaut transferred the number of bytes is 1 higher than the number of characters.

  And at a time the flow is cut to the number of characters.

  So these are 13 bytes and 12 characters:

  {'name': 'u'}

  The byte stream is cut to 12 - last byte is lost and it will happen in my application server:

  {'name': 'u'}

  Support of closing is absent and that throws the Exception.

  My simple solution/solution: I'm adding several spaces. Tomcat is always cut the last characters, but now there are only spaces to be cut. And with spaces, it worked...

• I have a MacBook Pro.  Is there a way to implement a rarely used keyboard key that - WHENEVER - it is pressed the computer will insert the string, predetermined character at the cursor position?

  I have a MacBook Pro.  Is there a way to implement a rarely used keyboard key that - WHENEVER - it is pressed the computer will insert the string, predetermined character at the cursor position?

  Yes. You can add in system preferences > keyboard > text.

• Find the bold, italic and underline the character of a string

  I have a VI to find bold, italic and underline the sequence of character in a string, but it is very slow.  I want to speed up this VI, an idea?

  Jean-Marc

  You feel the joy of the knots of property, whenever you access one, LV feels the urge to update the control it references.  You can speed things up greatly (factor 4 on my machine) by postponed Panel updates on the VI during the Subvi execution.  I probably shape another factor of two with the code, but this simple correction goes a long way.

• How to encode the string

  Hi I want to send the string encoded on server I do not have now encode this string it please help me.

  Discover your own documentation of the API for URLEncodedPostData.  Who should do it for you.

• Error #2101: The string passed to URLVariables.Decode must be a URL-encoded query string residues

  : Error #2101: the string passed to URLVariables.Decode must be a query string URL-encoded containing name/value pairs. to Error$ /throwError () to flash.net::URLVariables/decode() to flash.net::URLVariables() to::URLLoader/onComplete() _ flash.net stop(); var DepartVars:URLVariables = new URLVariables(); var DepartURL:URLRequest = new URLRequest ("scripts/www.mywebsite.com/depart.php"); DepartURL.method = URLRequestMethod.POST; DepartURL.data = DepartVars; var DepartLoader:URLLoader = new URLLoader; DepartLoader.dataFormat = pouvez; DepartLoader.addEventListener (Event.COMPLETE, completeDepart); depart_btn.addEventListener (MouseEvent.CLICK, DepartUser); Function to execute when you press the start function DepartUser (event: MouseEvent): void {/ / Ready variables here for shipment to PHP DepartVars.post_code = 'Start';}         Send the data to the PHP DepartLoader.load (DepartURL);         welcome_txt. Text = "processing of application...". Good journey. " } / / Close function DepartUser / / / / / function for when the PHP talk back to Flash function completedepart(event:Event):void {if (event.target.data.replyMsg == 'success') {var refreshPage:URLRequest = new URLRequest("javascript:NewWindow=window.location.reload();)} NewWindow.focus (); ("void (0);");             navigateToURL (refreshPage, "_self");         } / / CompleteDepart close function / / / / / View Code for the res button var viewRes:URLRequest = new URLRequest ("view_res.php"); viewRES_btn.addEventListener (MouseEvent.CLICK, viewResClick); function viewResClick(event:MouseEvent):void {navigateToURL (viewRes, "_self") ;} / / / / / / / / Code for the edit profile button var editRes:URLRequest = new URLRequest ("edit_res.php");} editRES_btn.addEventListener (MouseEvent.CLICK, editResClick); function editResClick(event:MouseEvent):void {navigateToURL (editRes, "_self") ;}}}

  you need a function named completeDepart to handle the return of you php script.  for example:

  function completeDepart(e:Event):void {}

  trace (e.Target.Data);

  }