Select the records in which the last character in the string is a letter

Similar Questions

• Select the last character of a string

  Hello
  I want to select the last character of a string address. "For example, as a result of select ' 165 John Ave W '-'W '. I tried to use the RIGHT but it does not work. I am using sqlplus.
  
  SELECT RIGHT(ADDRESS,1) FROM addresses;
  ORA-00904: "RIGHT": invalid identifier
  
  I can't find that any select statement to get the result I want. Ideas?
  
  Thank you!

  You want: SUBSTR (, - 1).

• Find the last character in a string aplhanumreic

  Hi guys first time poster long time hiding in the shadows, I hope someone can help me
  
  I put the stored username and I need to find the last character before the number, for example
  
  ABC123 that I would like to find c
  AB123 I would find b
  
  suggestions as to how I could do this?
  Thanks in advance

  Here's one way:
  
  
  
  
  
  
  
  
  
  
  
  
  

• Select the string table drop-down list box.

  Hi all

  I want to select the combo box list based on a string in the entry, I don't know how to do this. I have a drop-down list box and the value comes from a database, what I want to do is I want to change the value of the selected box based on the existing value in the database drop-down list. for example, A, B, C D I strings in the drop-down list box, and then in my database, I have a field with the string C, I want to change the C to A. I can't enter the value of C in a string format, but I don't know how to be the first position of the drop-down list box in so the order of channels combo box will be C, A, B, d., the value of C

  Thank you

  Then just write a new array of strings, with the elements of the new agenda, to the "[] strings" - property.

  Either you must code something that allows you to create an array of strings with the elements in the order that you want them to be. If there is a reorganization only, you could do something like:

  -Get the array of strings [] from the drop-down list using a property node box.

  -Find the position of the element you want to place first and use "delete from table", which returns the new array and the element removed.

  -Build a new table 1 d of the deleted item and table remaining. Move to the second combobox Strings [] property of a node property.

• any easier way to replace the last character in a string?

  That's what I got:

  select SUBSTR('tjgb005dy_01_31_08',1,LENGTH('tjgb005dy_01_31_08')-1)||'1' from dual;
  
  --
  tjgb005dy_01_31_01

  and I am enough fan of it. It's ugly and it's long.
  so, I wonder if you have better ideas?
  
  Thank you

  Even easier:

  select regexp_replace('tjgb005dy_01_31_08','.$','1') from dual;
  

• Looking for the last element of a string defined in a specific character style

  I should find each space which is the last character of a string in a particular character style. For example, in the "123 456 789" passage (the underlined part here indicating a passage located in a specific character style), my ideal GREP search would produce a match after the number 6.

  How to do this?

  Define your character style in the Format Panel find, use this GREP: \s$

  $ is the match end-of-string location, and when you search for text in a style character style, the end of what this style is applied to is considered the end of the string.

  Peter
  

• How can I prevent Pages 5.6.1 selecting the invisible when I change the text in bold, italic, etc. on a new line

  This is starting to annoy me a lot and I have not found something online that will solve this problem.

  Let's say I'm editing a file.

  

  Now I say "Oh, I need to put a"BOLD"two lines after the second 'Cogito ergo sum'"- so I go to this line and press Cmd + B (shortcut for "BOLD") and in this case:

  
  He selects the invisible! Now, let's say I write about it

  

  It disables the "BOLD"! What is the point of this? This makes me press the shortcut and then I have to press the arrow to the left. That you understand it's frustrating because it's a waste of 4 seconds, every time I want to change the style of the last line. And for someone who publishes an entire document, it is VERY frustrating.

  Can someone help me?
  I hope it's a clear description of the problem

  When you use the attribute text keyboard shortcuts, it's a good idea to show invisible, so that you know where click to place your insertion point - before selecting the keyboard shortcut. If you want to use these shortcuts, you must adapt to the way in which the Pages to do things and not try to make it work like MS Word.

  When you select the paragraph marks, the following keystrokes will remove them, right as well as your sense of humor.

• By selecting the rope between some special characters

  Dear Senior
  Please guide me how to select the string from - channel selection - behind the edge-
  I mean I want to select the channel of the first indent of before the second indent
  example of
  1-OS MARKING-1072
  2 BONE POCKET TIE-1288
  3-OS ATTACH A-1073
  4-OS CUP-1128
  5-OS ATTACH B-1075
  POCKET 6 OS O/L-976
  7 REGULUS SLEEVE O/L-1221
  8-ARMHOLE F/L-804
  9-CARD MAKING-819
  10-BADGE TIE-820
  Result
  BONE MARKING
  OS LOCK TIE
  BONE JOIN
  CUTTING OF THE BONE
  BONE TIE B
  POCKET OS O/L
  REGULUS SLEEVE O/L
  ARM HOLE F/L
  BADGE MANUFACTURING
  BADGE TIE

  Hello

  Use INSTR and SUBSTR, like this:

  WITH     got_pos     AS
  (
       SELECT     str
       ,     INSTR (str, '-', 1, 1) + 1     AS start_pos
       ,     INSTR (str, '-', 1, 2)           AS end_pos
       FROM     table_x
  )
  SELECT     SUBSTR ( str
              , start_pos
              , end_pos - start_pos
              )       AS between_hyphens
  FROM    got_pos
  ;
  

  You can also use regulat expressions, but they will be slower.
  In Oracle 10.1 (and), for example:

  SELECT     REGEXP_REPLACE ( str
                   , '^[^-]*-([^-]*)-.*'
                   , '\1'
                   )     AS between_hyphens
  FROM    table_x
  ;
  

  From Oracle 11.1, you can also use REGEXP_SUBSTR.
  Again, it will be less effective than using SUBSTR and INSTR.

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  What do you do if the string does not contain 2 hyphens? If thiis is a problem, then include examples in your sample data and results.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

• Select from the table where the last character of the string is numeric

  Hello
  I have a table of STREETS with a field called ADDRESS. I want to select all the records in streets where the last character in the address is a number.
  Select ADDRESS of STREETS where regexp_like (substr (address,?,?,), '[0-9]');
  --? means that I don't know what to put here!
  
  I don't know if substr is the best approach to do this, because I want only the last character and the records are of different lengths.
  
  Thank you!

  Hello

  If you want to use regular expressions:

  WHERE     REGEXP_LIKE ( address
                , '[0-9]$'
                )
  

  You can get the same results, no doubt more effectively, without regular expressions:

  WHERE     INSTR ( '0123456789'
             , SUBSTR (address, -1)
             )     > 0
  

• Select the last record of each month

  Hello

  to select the last docnumber and qty of every month

  Structure

  Name Null?    Type

  ------------------------------- -------- ----

  PRODUCTCODE NUMBER

  NUMBER NUMBER

  DATE OF PLANFORMONTH

  NUMBER OF CLEXPECTEDQTY

  NUMBER OF CLCONFIRMQTY

  NUMBER OF CLFGBUFFERQTY

  NUMBER OF CLTOTPRINTBUFFER

  in this select query if I take the sum he required all records where, as I want the last record of each month

  SELECT productcode docnumber MAX (Number), planformonth, SUM (clexpectedqty) clexpectedqty (planformonth) MAX.

  SUM (clconfirmqty) clconfirmqty, SUM (clfgbufferqty) clfgbufferqty, cltotprintbuffer OF FGSALESPLAN of the SUM (cltotprintbuffer)

  GROUP BY productcode, (planformonth)

  Sandy

  Hello

  Thanks its working now the code is written as below:

  SELECT * FROM

  (SELECT

  e.*,

  ROW_NUMBER() OVER (partition by PRODUCTCODE by DOCNUMBER DESC order) r

  Of

  E FGSALESPLAN)

  WHERE r = 1 AND

  entryvalid = 'Y '.

  order by Number

  Sandy

• Select before the last character.

  I have some URLS in a picture like this

  http://test.com/ABC/ghgh.html

  http://test.com/BCD/

  http://test.com/FFF/default.aspx

  http:// test2.com/a

  I want to select all the items before the last.

  But if the last / is it after the .com can get just how it is.

  so before should translate into

  http://test.com/ABC

  http://test.com/BCD

  http://test.com/FFF

  http:// test2.com/a

  create table soqs2)

  URL varchar2 (50)

  );

  insert into soqs2 values ('http://test.com/abc/ghgh.html');

  insert into soqs2 values ('http://test.com/bcd/');

  insert into soqs2 values ('http://test.com/fff/default.aspx');

  insert into soqs2 values ('http:// test2.com/a "");

  SQL and PL/SQL are the same forum...

  Check my last response to your original thread select prior to last character /

• How to select the last 3 records in a table?

  I have a table named HRM_ATTENDANCE
  as follows

  Name         Type         Nullable Default Comments 
  ------------ ------------ -------- ------- -------- 
  LEAVEDATE    DATE                                   
  EMPLOYEECODE VARCHAR2(8)                            
  LEAVETYPE    VARCHAR2(4)                            
  APPROVEDBY   VARCHAR2(8)  Y                         
  FEEDBY       VARCHAR2(8)  Y                         
  FEEDTIME     DATE         Y                         
  REMARKS      VARCHAR2(50) Y 

  the table contains the record of leave of employees as follows

  LEAVEDATE   EMPLOYEECODE LEAVETYPE APPROVEDBY FEEDBY   FEEDTIME    REMARKS
  ----------- ------------ --------- ---------- -------- ----------- --------------------------------------------------
  6/1/2013    00001        CL  
  6/3/2013    00001        EL                                         
  6/5/2013    00001        CPL    
  6/7/2013    00001        SL 
  6/9/2013    00001        CL                                        

  I want to select the last 3 leaves (records) to employeecode "00001" so I don't know the what are the dates of the leave. in easy words I want to choose the folder where leavedate > = 5 June 2013 ", but I don't know any dates."

  Select * from HRM_ATTENDANCE where rownum<=3 order="" by="" leavedate="">

• Select the last 50 closed records

  The research of a statement select simple sql which selects the latest 50 records closed in the database.
  
  I found some help out there who have an example like:
  
  SELECT RecordID, closed_date
  (SELECT RecordID, closed_date, RANK() over (ORDER BY closed_Date DESC) date_rank
  FROM table1)
  WHERE the date_rank < = 50;
  
  Only problem is, this is to select something like 4000 recordings, and many of them are not yet closed.

  I think that you need to retrieve the records that are only closed in the first place.

  Try this,

  SELECT RecordID, closed_date
    FROM (SELECT RecordID,
                 closed_date,
                 ROW_NUMBER () OVER (ORDER BY closed_Date DESC) rn
            FROM table1
           WHERE closed_date < SYSDATE)  --Notice this.
   WHERE rn <= 50;
  

  G.

• Select the last 10 records in a table

  Oracle9i. I am trying to select the last 10 numbers in a table with this command series

  select serial from tab_42 where employeecode='00001'  and rownum<=10 order by serial desc;

  but it's not not selecting the most recent serial number 10. How to do?

  The rownum clause is applied before the order by clause, one must use a subquery...

  select * from (select serial from tab_42 where employeecode='00001' order by serial desc) where rownum<=10;
  

• If the record not found this particular date, then select the last recordings date.

  I have three columns
  Number DP_FND_CODE;
  Date of DP_DATE;
  Number DPPRICE;
  
  I want that if dp_uprice not found this particular date (: dd1) then
  Select maximum Dp_uprice that the date would be less then: dd1
  
  Example: -.

  I run query and :DD1 parameter = 18/10/2010
  
  SELECT dp_fnd_code, dp_date , dp_uprice dpprice 
  FROM dailyprice where dp_date = :dd1
  
  DP_FND_CODE DP_DATE                      DPPRICE
  ----------- ----------------------- ------------
            1 18/10/2010                  109.0344
            2 18/10/2010                   10.1045
            3 18/10/2010                  100.4010
            4 18/10/2010                  102.3276
            6 18/10/2010                   14.6958
            7 18/10/2010                   98.8300
            8 18/10/2010                  102.0900

  It will show that all the Archives: dd1 = 18/10/2010, you can see above the result of the query DP_FND 5 is missing.
  I want to if there is no DPRICE of that particular date (: DD1) then it shows the date of the last DPPRICE.
  Like this

  DP_FND_CODE DP_DATE                      DPPRICE
  ----------- ----------------------- ------------
            1 18/10/2010                  109.0344
            2 18/10/2010                   10.1045
            3 18/10/2010                  100.4010
            4 18/10/2010                  102.3276
            5 16/10/2010                  122.3276          
            6 18/10/2010                   14.6958
            7 18/10/2010                   98.8300
            8 18/10/2010                  102.0900

  so I used this query, but correct nicely.

  SELECT dp_fnd_code, dp_date, 
               case when dp_uprice is null then(
             select max(dp_uprice) dpprice from dailyprice where dp_date < :dd1 group by dp_fnd_code,dp_date
             ) else dp_uprice  end dpprice 
    FROM dailyprice 
    where dp_date = :dd1
    order by dp_fnd_code
    

  Thanks in advance.

  SELECT dp_fnd_code,
         max(dp_date) keep (dense_rank last order by dp_date),
         max(dpprice) keep (dense_rank last order by dp_date)
    FROM dailyprice
    where dp_date <= :dd1
    group by dp_fnd_code
    order by dp_fnd_code;