Weeks of the month with Total
Hey,.
I try to display the weeks of the month based on values and a date. I have a select statement that displays vertical to results, but I would like that they horizontally with the listed weeks. Below are the create table and insert instructions to help. Once the start dates and end Dates are entered for one month, then the weeks should display with the counts for each Type Emp values and totals for each Type of Emp showing also. Any help is appreciated. Thanks for taking a peek at my question.
-Toad for Oracle 12.5
CREATE TABLE TBL_EMP
EMP_ID NUMBER NOT NULL,
FK_EMP_TYPE_ID NUMBER ,
EMP_DATE DATE
INSERT INTO TBL_EMP
()EMP_ID FK_EMP_TYPE_ID EMP_DATE( )
(1, 100, TO_DATE('10/14/2014', 'MM/DD/YYYY'));
INSERT INTO TBL_EMP
()EMP_ID FK_EMP_TYPE_ID EMP_DATE( )
(2, 200, TO_DATE('10/12/2014', 'MM/DD/YYYY'));
INSERT INTO TBL_EMP
()EMP_ID FK_EMP_TYPE_ID EMP_DATE( )
(3, 200, TO_DATE('10/8/2014', 'MM/DD/YYYY'));
INSERT INTO TBL_EMP
()EMP_ID FK_EMP_TYPE_ID EMP_DATE( )
(4, 300, TO_DATE('10/15/2014', 'MM/DD/YYYY'));
INSERT INTO TBL_EMP
()EMP_ID FK_EMP_TYPE_ID EMP_DATE( )
(5, 100, TO_DATE('10/12/2014', 'MM/DD/YYYY'));
INSERT INTO TBL_EMP
()EMP_ID FK_EMP_TYPE_ID EMP_DATE( )
(6, 100, TO_DATE('9/9/2014', 'MM/DD/YYYY'));
SELECT * DE TBL_EMP;
-Can I display the vertical weeks but I would like that they horizontal
SELECT 'WEEK ' || (TO_CHAR (EMP_DATE + 4, 'W')) WEEKS,
FK_EMP_TYPE_ID ,
COUNT (FK_EMP_TYPE_ID) AS EMP_TYPE_COUNT
FROM TBL_EMP
WHERE EMP_DATE BETWEEN TO_DATE ( :P10_START_DATE, 'MM/DD/YYYY')
AND NVL (TO_DATE ( :P10_END_DATE, 'MM/DD/YYYY'), SYSDATE)
GROUP BY 'WEEK ' || (TO_CHAR (EMP_DATE + 4, 'W')), FK_EMP_TYPE_ID
ORDER BY WEEKS;
-The values to enter for months
-P10_START_DATE 10/01/2014
-P10_END_DATE 31/10/2014
-Results
WEEK 2 200 1
WEEK 3 100 2
WEEK 3 200 1
WEEK 3 300 1
SELECT FK_EMP_TYPE_ID , COUNT (*)
FROM TBL_EMP
WHERE EMP_DATE BETWEEN TO_DATE ( :P10_START_DATE ' MM/DD/YYYY '( )
AND NVL (TO_DATE ( :P10_END_DATE, 'MM/DD/YYYY'), SYSDATE)
GROUP BY FK_EMP_TYPE_ID
ORDER BY FK_EMP_TYPE_ID ASC;
-Results
FK_EMP_TYPE_ID COUNT(*)
100 2
200 2
300 1
-Results and horizontal display I want
FK_EMP_TYPE_ID WEEK 1 WEEK 2 WEEK 3 WEEK 4 TOTALS
100 0 0 2 0 2
200 0 1 1 0 2
300 0 0 1 0 1
Hello
Select
Here's one way:
WITH relevant_data AS
(
SELECT fk_emp_type_id
TO_CHAR (emp_date + 4, 'W') AS week_num - see note below
OF tbl_emp
WHERE the emp_date BETWEEN NVL (TO_DATE (: p10_start_date, ' MM/DD/YYYY'))
SYSDATE - TRUNC (SYSDATE) or
)
AND NVL (TO_DATE (: p10_end_date, ' MM/DD/YYYY'))
SYSDATE
)
)
SELECT p
week_1 + week_2 + week_3 + week_4 + week_5 AS totals
OF relevant_data
PIVOT (COUNT (*)
FOR week_num IN ('1' AS week_1
'2' AS week_2
'3' AS week_3
'4' AS week_4
'5' AS week_5
)
) p
ORDER BY fk_emp_type_id
;
Are you sure you want to add 4 days before calculating the week number? If you're wondering the month of October 2014, for example, '1' of the week would include 1-3 October and from 28 to 31 October. (4 days after October 28 is November 1, which is 1 week of November).
Tags: Database
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Monday the 1st business day of the month of 15 before and after 15.
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Hello people:
I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.
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Currently, this is the result I get (I'm only including the months of January and December here).
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- DECEMBER 27, 12 2 JANUARY 13
- JANUARY 3, 13 JANUARY 9, 13
- 10 JANUARY 13 JANUARY 16, 13
- 17 JANUARY 13 23 JANUARY 13
- 24 JANUARY 13 30 JANUARY 13
- 31 JANUARY 13 FEBRUARY 6, 13
December:
- NOVEMBER 28, 13 4 DECEMBER 13
- 5 DECEMBER 13 DECEMBER 11, 13
- 12 DECEMBER 13 18 DECEMBER 13
- 19 DECEMBER 13 DECEMBER 25, 13
What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:
January:
- JANUARY 1, 13 2 JANUARY 13
- JANUARY 3, 13 JANUARY 9, 13
- 10 JANUARY 13 JANUARY 16, 13
- 17 JANUARY 13 23 JANUARY 13
- 24 JANUARY 13 30 JANUARY 13
- 31 JANUARY 13 JANUARY 31, 13
February:
- 1ST FEBRUARY 13 FEBRUARY 6, 13
- 7 FEBRUARY 13 FEBRUARY 13, 13
- 14 FEBRUARY 13 FEBRUARY 20, 13
- 21 FEBRUARY 13 FEBRUARY 27, 13
- 28 FEBRUARY 13 FEBRUARY 28, 13
November:
- 31 OCTOBER 13 NOVEMBER 6, 13
- 7 NOVEMBER 13 NOVEMBER 13, 13
- 14 NOVEMBER 13 NOVEMBER 20, 13
- 21 NOVEMBER 13 NOVEMBER 27, 13
- NOVEMBER 28, 13 4 DECEMBER 13
December:
- 1ST DECEMBER 13 DECEMBER 4, 13
- 5 DECEMBER 13 DECEMBER 11, 13
- 12 DECEMBER 13 18 DECEMBER 13
- 19 DECEMBER 13 DECEMBER 25, 13
- 26 DECEMBER 13 DECEMBER 31, 13
Why the "weeks" in November, have all 7 days, while the "weeks" in the first or the last week in the other month usually have less? (For example, February 28 is a 'week' alone.)
The following works for the other months:
WITH all_days AS
(
SELECT DATE "2013-01-01' + LEVEL - AS a_date 1
OF the double
CONNECT BY LEVEL<=>
)
SELECT DISTINCT
More GRAND (TRUNC (a_date + 4, 'IW') - 4)
, TRUNC (a_date, 'MONTH')
) AS week_begin
, The LEAST (TRUNC (a_date + 4, 'IW') + 2
TRUNC (LAST_DAY (a_date))
), Week_end
Of all_days
ORDER BY week_begin
;
Output:
WEEK_BEGIN WEEK_END
----------- -----------
January 1, 2013 January 2, 2013
January 3, 2013 January 9, 2013
January 10, 2013 January 16, 2013
January 17, 2013 January 23, 2013
January 24, 2013 January 30, 2013
January 31, 2013 January 31, 2013
February 1, 2013 February 6, 2013
February 7, 2013 February 13, 2013
February 14, 2013 February 20, 2013
February 21, 2013 February 27, 2013
February 28, 2013 February 28, 2013
...
November 1, 2013 November 6, 2013
November 7, 2013 November 13, 2013
November 14, 2013 November 20, 2013
November 21, 2013 November 27, 2013
November 28, 2013 November 30, 2013
December 1, 2013 December 4, 2013
December 5, 2013 December 11, 2013
December 12, 2013 December 18, 2013
December 19, 2013 December 25, 2013
26 December 2013 31 December 2013
-
How do the 3rd week (business day) of the month in a date range?
Hello
I'm trying to find the 3rd day of the work week of each month in a given range of dates. How is it possible in a SQL query? Thank you in advance.
Hello
Here's one way:
SELECT first_day + BOX
WHEN TO_CHAR (first_day, "DY") IN ("play", "Fri", "SAT")
THEN 4
WHEN TO_CHAR (first_day, "DY") ("SUN")
THEN 3
2 ELSE
END AS workday_3
DE)
SELECT ADD_MONTHS (first_month
, LEVEL - 1
) AS first_day
DE)
SELECT TO_DATE ('Sep 2013', 'My YYYY') AS first_month
, TO_DATE ('Jan 2014', 'Mon YYYY') AS last_month
OF the double
)
CONNECT BY LEVEL<= 1="" +="" months_between="" (last_month,="">
)
ORDER BY workday_3
;
In another thread,.
https://community.Oracle.com/thread/3513808
you said that you had problems using a WITH clause, so I used online views instead of CLAUSES.
With the above parameters, the result is:
WORKDAY_3
---------------
Wed 04-Sep-2013
Set of 3 October 2013
November 5, 2013 Mar
Wednesday, December 4, 2013
Fri January 3, 2014
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