How to get the Date in month based on week of the month.

Hi gurus,

I have provided.

Quarter (Q) = > 1 (Jan - Mar), 2 (April-June), 3 (July-September), 4 (October-December).

Months (M) = > Jan = 1, Feb = 2, Mar = 3 in the 1st quarter.

ARP = 1, may = 2, Jun = 3 in the 2nd quarter,

Jul = 1, August = 2, Ms = 3 in Q3,

Oct 1 Nov = = 2, Dec = 3 in the 4th quarter

If I give Q = 3, M = 3, W = 1 day = Fri so I get 6-Sep-13

Similarly, if I give Q = 2, M = 1, O = 3, day = game so I get 18 April 13.

Could someone help me higher and higher.

Concerning

Sanjeev

Believing that when you say you want to say that it is 1 - 5 in a month with the 1st day of the month as the beginning of the 1st week of the week. You can try this.

SQL > t
2 as
(3)
4. Select q 3, 3 m, 1 w, 'Ven' d
5 double
6 union
7 all the
8. Select q 2, 1 m, 3 w, d 'game '.
9 double
10)
11. Select q, m, w, d, d_day
12 years of)
13 select y + (level - 1) d_day
14, ceil (extract (day of cast (y + (level - 1) as timestamp)) / 7) week_7_day
15                   , t.*
16 of)
17 select add_months (trunc (sysdate, 'year') (q * 3-3) +(m-1)) y
18                             , t.*
19 t
20                     ) t
21 connect
22 by level<= last_day(y)="" -="" y="" +="">
23 and prior y = y
dbms_random.value (24 and prior) is not null
25         )
where the 26 w = week_7_day
27 and substr (to_char (d_day 'day'), 1, 3) = lower (d);

Q M W D D_DAY
---------- ---------- ---------- --- ---------
2 1 3 Friday 18 April 13
3 3 1 Fri 06-SEP-13

SQL >

Tags: Database

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    24-DEC-12 23-DEC-12                                      1
    24-DEC-12 23-DEC-12                                      1
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    24-DEC-12 23-DEC-12                                      1
    
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    24/12/12 24/12/12                                       0
    24/12/12 24/12/12                                       0
    24/12/12 24/12/12                                       0
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