Last day of the month with the last minute of the day
HelloI wonder about how to get the last day of the month with the last minute of this day(23:59). We can use the last_day function (DATE) to get the last date, but reminds me of the time of day when the function has been executed. But I want to have the last minute with my last date of the current month.
Please inform.
Thank you
HP
Hello
Ora_bie wrote:
Hello
I wonder about how to get the last day of the month with the last minute of this day(23:59). We can use the last_day function (DATE) to get the last date, but reminds me of the time of day when the function has been executed. But I want to have the last minute with my last date of the current month.
In fact, it returns at the same time as the argument you pass; But whatever it is, is not what you want.
This will return the last day of the month that contains the DATE 23:59 (or 23:59) dt:
SELECT ADD_MONTHS ( TRUNC (dt, 'MONTH')
, 1
) - (1 / (24 * 60))
FROM dual
;
TRUNC (dt, 'MONTH') is 00:00 on the first day of the month that contains dt.
ADD_MONTHS (TRUNC (dt, 'MONTH'), 1) is from 00:00 the first day of the month following the one containing dt.
ADD_MONTHS (TRUNC (dt, 'MONTH'), 1)-(1 / (24 * 60)) is a minute earlier.
(Since there are 24 hours, each with 60 minutes, every day, 1 / (24 * 60) days is identical to a minute.)
Another (less clear, in my opinion) way to get the same results is:
TRUNC (LAST_DAY (dt)) + (1439/1440) -- 1440 minutes = 1 day
Tags: Database
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I now table to store the daily presence of each employee
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I want to get the number of months used unpaid in the past 6 months (excluding the current).
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The application must check the latest 6 month data and number of months for which there is any unpaid value
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County
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I use oracle 10g
EXAMPLES OF DATA
create the table attendancesheet as
(
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Select 1 as empid, to_date (12 January 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the
Select 1 as empid, to_date (February 12, 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the
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Select 2 as empid, to_date (3 February 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid double
);
Help, please
Hello
So, you want to count the distinct months for 6 months before (not included) the given month; is this fair?
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VARIABLE month VARCHAR2 (2)
Year VARIABLE VARCHAR2 (4)
EXEC: months: = '4';
EXEC: year: "2014"; =
WITH got_end_date AS
(
SELECT TO_DATE (: month |) '/' || : year
, ' MM/YYYY ".
) AS end_date
OF the double
)
SELECT a.empid
, COUNT (DISTINCT
CASE
WHEN a.unpaid > 0
THEN TRUNC (a.payrolldate, 'MONTH')
END
), Cnt
Of attendancesheet one
JOIN e-got_end_date WE a.payrolldate > = ADD_MONTHS (e.end_date-6)
AND a.payrolldate< > >
GROUP BY a.empid
ORDER BY a.empid
;
If you use a WHERE clause to exclude the lines with some outstanding = 0 (or unpaid is NULL), then you would get no output for employees like empid = 2 in this example. A WHERE clause ignores an entire line, so I used an expression BOX just a value.
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SELECT 'WEEK ' || (TO_CHAR (EMP_DATE + 4, 'W')) WEEKS,
FK_EMP_TYPE_ID ,
COUNT (FK_EMP_TYPE_ID) AS EMP_TYPE_COUNT
FROM TBL_EMP
WHERE EMP_DATE BETWEEN TO_DATE ( :P10_START_DATE, 'MM/DD/YYYY')
AND NVL (TO_DATE ( :P10_END_DATE, 'MM/DD/YYYY'), SYSDATE)
GROUP BY 'WEEK ' || (TO_CHAR (EMP_DATE + 4, 'W')), FK_EMP_TYPE_ID
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-P10_START_DATE 10/01/2014
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WEEK 3 200 1
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SELECT FK_EMP_TYPE_ID , COUNT (*)
FROM TBL_EMP
WHERE EMP_DATE BETWEEN TO_DATE ( :P10_START_DATE ' MM/DD/YYYY '( )
AND NVL (TO_DATE ( :P10_END_DATE, 'MM/DD/YYYY'), SYSDATE)
GROUP BY FK_EMP_TYPE_ID
ORDER BY FK_EMP_TYPE_ID ASC;
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FK_EMP_TYPE_ID COUNT(*)
100 2
200 2
300 1
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FK_EMP_TYPE_ID WEEK 1 WEEK 2 WEEK 3 WEEK 4 TOTALS
100 0 0 2 0 2
200 0 1 1 0 2
300 0 0 1 0 1
Hello
Select
Here's one way:
WITH relevant_data AS
(
SELECT fk_emp_type_id
TO_CHAR (emp_date + 4, 'W') AS week_num - see note below
OF tbl_emp
WHERE the emp_date BETWEEN NVL (TO_DATE (: p10_start_date, ' MM/DD/YYYY'))
SYSDATE - TRUNC (SYSDATE) or
)
AND NVL (TO_DATE (: p10_end_date, ' MM/DD/YYYY'))
SYSDATE
)
)
SELECT p
week_1 + week_2 + week_3 + week_4 + week_5 AS totals
OF relevant_data
PIVOT (COUNT (*)
FOR week_num IN ('1' AS week_1
'2' AS week_2
'3' AS week_3
'4' AS week_4
'5' AS week_5
)
) p
ORDER BY fk_emp_type_id
;
Are you sure you want to add 4 days before calculating the week number? If you're wondering the month of October 2014, for example, '1' of the week would include 1-3 October and from 28 to 31 October. (4 days after October 28 is November 1, which is 1 week of November).
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);;
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Required result
========================
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========================
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=======================
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)
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