What SYS tables (not seen) contains the value NULL spec /not/ column definition?

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  I would like to know which table in the repository contains the value of "Owner operating system".
  
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  The following query should help you:

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  cm mgmt_current_metrics WHERE t.target_type = 'oracle_emd. '
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• Creating a variable that contains the value of the variable system (Long) Date of change

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• Siri in him sending text with the value 'NULL '.

  When I say, "Siri, text my wife, 'X', ' Siri responds correctly,"here is your message to Jill: 'X'. "" "  "Ready to send it?"  I say 'Yes' and sends the message.  As soon as I get a text from my carrier saying the recipient of the message was invalid.  100% of the time, I see that Siri has sent a text with the value NULL.

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• using the value null with a function

  Guys, newbie here

  What is the value NULL in function header? Does this mean that I can pass a value zero?

  FUNCTION tot_sales

  (company_id_in IN company.company_id%TYPE,

  status_in IN order.status_code%TYPE: = NULL)

  RETURN NUMBER

  Hello

  dorianpc wrote:

  Guys, newbie here

  What is the value NULL in function header? Does this mean that I can pass a value zero?

  FUNCTION tot_sales

  (company_id_in IN company.company_id%TYPE,

  status_in IN order.status_code%TYPE: = NULL)

  RETURN NUMBER

  You can always pass NULL for any argument.

  What does this code mean, is that the argument is optional (what, you don't have to spend), and if you do not pass it, status_in will be NULL inside the function.

  So call for your function with 1 argument, like this:

  t: = to_sales (c);

  is equivalent to calling with 2 arguments, like this

  t: = to_sales (c, NULL);

  where the 2nd argument is null.

• Divide the values of a single column into multiple values of columns

  I want that the values of the "col_val" column to divide into several values in the column

  Table1:

  Col_val Col1, Col2

  Code1 POINT 45

  L2 AB 45

  L1 POINT 45 OF

  Code2 CAB 61

  ABC 51 LABORATORY

  SSS LAB 45

  QQQ BED 123

  BBV COT 100

  FFF COT 444

  Output as expected:

  OUT1 out2 out3-out4, out5

  Code1 AB SSS

  L1

  Code2

  ABC

  QQQ

  BBV

  FFF

  Each line must contain the values corresponding to the Col2 values and each column must have the values in Col1, as illustrated above.

  SQL> with t
    2  as
    3  (
    4  select 'Code1' col_val, 'ITEM' col1, 45 col2
    5    from dual
    6  union all
    7  select 'L2' col_val, 'AB' col1, 45 col2
    8    from dual
    9  union all
   10  select 'L1' col_val, 'ITEM' col1, 45 col2
   11    from dual
   12  union all
   13  select 'Code2' col_val, 'CAB' col1, 61 col2
   14    from dual
   15  union all
   16  select 'ABC' col_val, 'LAB' col1, 51 col2
   17    from dual
   18  union all
   19  select 'SSS' col_val, 'LAB' col1, 45 col2
   20    from dual
   21  union all
   22  select 'QQQ' col_val, 'COT' col1, 123 col2
   23    from dual
   24  union all
   25  select 'BBV' col_val, 'COT' col1, 100 col2
   26    from dual
   27  union all
   28  select 'FFF' col_val, 'COT' col1, 444 col2
   29    from dual
   30  )
   31  select max(col1)
   32       , max(col2)
   33       , max(col3)
   34       , max(col4)
   35       , max(col5)
   36    from (
   37            select decode(col1, 'ITEM', col_val) col1
   38                 , decode(col1, 'AB'  , col_val) col2
   39                 , decode(col1, 'LAB' , col_val) col3
   40                 , decode(col1, 'CAB' , col_val) col4
   41                 , decode(col1, 'COT' , col_val) col5
   42                 , t.col2 col_2
   43                 , row_number() over(partition by col2, col1 order by 1) rno
   44              from t
   45         )
   46   group
   47      by col_2, rno
   48   order
   49      by col_2;
  
  MAX(C MAX(C MAX(C MAX(C MAX(C
  ----- ----- ----- ----- -----
  Code1 L2    SSS
  L1
              ABC
                    Code2
                          BBV
                          QQQ
                          FFF
  
  7 rows selected.
  
  SQL>
  

• Calculated field with the currency formatting, and hiding the values null

  I am designing a PDF form for quote and I have a field defined to multiply the amount of an article and the unit price to the total price.  There are 5 lines on each quote, and if users are citing only 1 or 2 items I want the values null in fields unused price extended to be hidden.

  I did it with the following script

  If (event.value == 0) event.value = ";

  But when I enter the quantity and total price of price is displayed as a regular number (100) instead of currency ($100).

  I can format to currency with

  Event.Value = util.printf ("$%.2f", event.value);

  I don't know there's a way to combine to give rise to such a situation then, so if the field is 0, make null and if not then format as currency but I don't know how to do it.

  Any help would be appreciated.

  Andrew

  Newer versions of Acrobat hide zero for fields values using the number format and with a currency symbol. »

  But since you can't control the updating of user systems, you must use a small function documented for formatting numeric fields on the fly.

  With the extended price field set to 'None' format, you can add the following script to the Validation script "Custom" or add it to a custom JavaScript calculation. The "Custom Validation will work with any method of calculation. Note that the form must be cleaned or recalculated to see the result of the validation script change.

  if(Event.Value == 0) {}
  Event.Value = ""; set the field value to null to a value of zero
  AFNumber_Format (2, 0, 0, 0, "", true); number with no currency symbol format
  } else {}
  AFNumber_Format (2, 0, 0, 0, "$", true); for the format of the values non-null for number with the currency symbol
  }

  The positional parameters are the number of decimal places, the Style separator, negative value Style, Style of (unused) currency, currency symbol, the currency symbol Pre-hanging chain.

• Compare the value Null

  Hello
  
  Is it possible to compare a null to null...
  
  Example of
  ---------------------------
  Indicator number;
  
  If null = null then
  flag = 1;
  on the other
  flag = 0;
  end if;
  ---------------------------
  
  Thank you.

  Hello

  Use "is null".

  For example:

  declare
  VARCHAR2 (10) variable;
  Start
  If the variable is null then
  dbms_output.put_line ('variable is null');
  on the other
  dbms_output.put_line ("'variable is non-zero");
  end if;
  end;

  By comparing the value null = null will not work.

• What is the empty string, the value null in the column, or...?

  I use Oracle 11.2, a table tb_class as follows:
  
  TB_CLASS (number (3) id, varchar2 (32) nm, seqNum number (3));
  
  1, 212
  2, "under", 12
  3, 'qq', 12
  
  Select * from TB_CLASS where id = 1 and n = null;... .no selected line
  Select nvl (nm) in the TB_CLASS where id = 1; ... 1 selected line
  
  Any know what's in the column of row id = 1 nm? I thought that it is an empty string, but why it returns no rows in the first query?
  
  Thank you!

  (1) in Oracle there is no difference between NULL and an empty string.

  (2) NULL is never equal to what whatsoever (including another NULL). NULL is never spotty what whatsoever (including another NULL). You must use the IS NULL and IS NOT NULL operators to search for NULL values

  SELECT *
    FROM tb_class
   WHERE nm IS NULL
  

  or

  SELECT *
    FROM tb_class
   WHERE nm IS NOT NULL
  

  Of course, it is also possible that you declare that the NM column contains one or more spaces or it contains one or more non-printable characters and not a NULL value. That's why we asked you what dump (nm) returns

  Justin

• Delete data table Parent and child data automatically delete or the value null in the foreign key of the child table.

  Oracle 10g

  Hi gurus

  I test_mst table that has a primary key test_mst.test_id, I detail table test_dtl which has test_dtl.test_id of foreign key, now I have that I want to use the delete statement in test_mst then it should also remove the constraint of her child or null in test_dtl.test_id, can again do in oracle 10g?

  Thanks in advance

  Hi Mit.

  example of cascade

  create table bill(
    bill_id number not null primary key
  )
  ;
  create table bill_item(
    bill_item_id number not null primary key,
    bill_id number references bill(bill_id) on delete cascade
  )
  ;
  insert into bill values (1)
  ;
  insert into bill_item values (1, 1)
  ;
  delete bill
  ;
  select * from bill_item
  ;
  drop table bill_item purge
  ;
  drop table bill purge
  ;
  
  Table BILL created.
  Table BILL_ITEM created.
  1 row inserted.
  1 row inserted.
  1 row deleted.
  
  no rows selected
  
  Table BILL_ITEM dropped.
  Table BILL dropped.
  

  exemplary null

  create table employer(
    employer_id number not null primary key
  )
  ;
  create table employee(
    employee_id number not null primary key,
    employer_id number references employer(employer_id) on delete set null
  )
  ;
  insert into employer values (1)
  ;
  insert into employee values (1, 1)
  ;
  delete employer
  ;
  select * from employee
  ;
  drop table employee purge
  ;
  drop table employer purge
  ;
  
  Table EMPLOYER created.
  Table EMPLOYEE created.
  1 row inserted.
  1 row inserted.
  1 row deleted.
  
                              EMPLOYEE_ID                             EMPLOYER_ID
  --------------------------------------- ---------------------------------------
                                        1                                       
  
  Table EMPLOYEE dropped.
  Table EMPLOYER dropped.
  

• sum of column that contains the values in the time format

  Hi all
  
  I give you a piece of my code below

  SELECT  dif.EMPLOYEE_NUMBER Employee#, dif.FULL_name EmployeeName,
   TO_CHAR(START_DATE,'dd-Mon-rrrr') DOJ ,dif.DEPT_NAME,POSITION , DATE_ENTRAY AttendanceDate,
  
   to_char(DATE_ENTRAY,'DY') day, TO_CHAR(LNE1,'hh24:mi')TimeIn1 ,TO_CHAR(LNE2,'hh24:mi')TimeOut1,
   
   TO_CHAR(LNE3,'hh24:mi')TimeIn2 ,TO_CHAR(LNE4,'hh24:mi')TimeOut2, TO_CHAR(LNE5,'hh24:mi')TimeIn3 ,
  
   TO_CHAR(LNE6,'hh24:mi')TimeOut3, to_char(decode(LNE8,null ,
  
   decode(LNE7,null, decode(LNE6,null, decode(LNE5,null, decode(LNE4,null, decode(LNE3,null,
  
   decode(LNE2,null,LNE2 ,LNE2 ),LNE3 ),LNE4 ),LNE5 ),LNE6 ),LNE7 ),LNE8 ),'hh24:mi')TimeOuts ,
   
   ACT_HOUR Work_Hrs, 
  
  decode(DLY_ABSENT_TYPE,'Late',DED_ABS ,'Late (Deduction)',DED_ABS,'00:00') Late_Hrs,ACT_OVT Over_Time
   FROM jjj_PUNCH_DATA_EMP_LIST trn , 
   jjj_emp_def dif,jjj_PUNCH_CARD_ELEG ele WHERE trn.EMPLOYEE_NUMBER =dif.EMPLOYEE_NUMBER and   
   ele.EMPLOYEE_NUMBER =trn.EMPLOYEE_NUMBER  and   DATE_ENTRAY between '23-Aug-2009' and  '24-Aug-2009' 
  
  I require to find the sum of column  wrk_hrs
  Act_hour or wrk_hrs belongs to table  jjj_PUNCH_DATA_EMP_LIST trn , and the datatype of act_hour is varchar(10 byte)
  the values of column act_hrs, (i require the sum of this column)
  08:00
  07:22
  06:08

  kindly help
  thanking in advance
  
  concerning
  Oracle user

  Hello

  Thanks for posting the CREATE TABLE and INSERT. That really helps.

  Do you want 19:33 ' as the output? Which makes it look like 19 hours and 33 minutes. Most people would represent 19.33 hours (i.e. 19 more than 1/3 hours) as 19:20 '. Should not the sum of
  ' x: 00 ' and
  'y: 20' be
  "z: 20?

  If you really want 19:33 ', see the solution of Hoek.

  If you really want 19:20 ', then you were on the right track.
  I think that you were trying to do:

  WITH  got_total_hours     AS
  (
       SELECT SUM (   TO_NUMBER (SUBSTR (act_hour, 1, 2))
                  + ( TO_NUMBER (SUBSTR (act_hour, 4, 2))
                    / 60
                    )
                  ) AS total_hours
       from      p
  )
  SELECT        TO_CHAR (FLOOR (total_hours))
         || ':'
         || TO_CHAR ( MOD (total_hours, 1) * 60
                 , 'fm00'
                 )     AS hh_mm
  FROM     got_total_hours
  ;
  

  Looks like you were trying calculate total_hours in a subquery, then use the total_hour alias in a query Super, which is quite accurate. You're just confused on how to write a subquery.
  There are two basic ways to write subqueries:
  

  (1) WITH clause:

  WITH  sub_query  AS
  (
       SELECT  ...
  )
  SELECT  ...
  FROM      sub_query
  ;
  

  (2) online review

  SELECT     ...
  FROM     (     -- Begin sub_query
       SELECT     ...
       )     -- End sub-query
  ;
  

  Looks like you tried a bit of each method.

  In most cases (this included problem) either one will work.
  Other problems are much easier by using a WITH clause and WITH clauses are usually easier to read and understand, I recommend that you always use a WITH clause rather than views online.

  You can also change the Hoek solution to get the result 19:20 ' without a subquery (or without using any expression complicated, more than once, which is the only reason why I have proposed a subquery). Since date arithmetic Oracle comes from the days, not hours, when the solution of Hoek has calculated the number of hours, you'll have to divide by 24 to get the number of days. If you are using TO_CHAR to fit the time, however, the results can be confusing if the total is 24 hours or more. You might be better off using NUMTODSINTERVAL.

• NET right in paywsacv.fmb contains the value after employee termination

  Hello
  
  Published by: user12046014 on April 19, 2011 13:53

  Hmm, that's strange. When you are so close to something, it is easy to slide up on a couple of obvious things. You can simply check:
  (1) this quick formula change was applied and saved
  (2) the formula change was not an update date of turn and these changes apply for the duration of the fast formula
  (3) that this Fast formula is defined as the rapid accumulation of the accumulation Plan form, looking to
  (4) that you have followed by date to a date beyond the date of termination of the employee
  (5) who in FastPath > accrued interest gross payment (the one on the first line of the retail block) is equal to zero

  If the foregoing is true I don't understand how your gross payment is zero. I see that your Fast formula looks like it has some sort of custom logging mechanism. This could be used to write the values of ACP_TERMINATION_DATE and Calculation_Date for us to verify that they are as expected?

• The value of name of column

  Hi gurus

  I'm stuck on 1 Scenario and need your help. I have the following table:

  Create table

  drop table age_rate;

  CREATE TABLE age_rate
  (
  age_0_4 number 4,
  age_5_20 number 4,
  age_21_34 number 4,
  age_35_44 number 4
  );

  -------------------------------

  Insertion

  INSERT INTO age_rate

  SELECT 45, 50, 60, 90 double UNION ALL

  SELECT 45, 50, 60, 88 OF double UNION ALL

  SELECT the 40, 50, 60, 90 double UNION ALL

  SELECT 5, 50, 60 and 88 DOUBLE;

  -------------------------------

  Query on table

  SELECT * from age_rate;

  The query result

  age_0_4 age_5_20 age_21_34 age_35_44

  45                          50                     60                     90

  45                          50                     60                     88

  40                          50                     60                     90

  5                            50                     60                     88

  Power required

  Rate Min_age Max_age

  -The lower is age band 0_4

  45            0           4

  45            0           4

  40            0           4

  5              0           4

  -The lower is age band 5_20

  50            5           20

  50            5           20

  50            5           20

  50            5           20

  -The lower is age band 21_34

  60 21 34

  60 21 34

  60 21 34

  60 21 34

  -The lower is age band 35_44

  90 35 44

  88 35 44

  90 35 44

  88 35 44

  Rules

  -I have all the data in the rows each column online create separate lines and add 2 columns automatically Min_age and Max_age and insert the value on these columns based on the name of the column for example if the column name as age_0_4 then insert 0 in min_age and 4 in max_age means values for Min_age and Max_age extracted from the base of the column name. I don't know if it's possible or not, but I appreciate if someone can give me the solution for this problem... Do you like answers. Thank you

  
  

  Hello

  I'm not 100% sure what you want.  Do you want 16 production lines at a time, which is 4 lines of output for each line that is actually in the table?

  This looks like a job for the UNPIVOT operator:

  SELECTION rate

  min_age

  Case min_age

  WHEN 0 THEN 4

  WHEN 5 THEN 20

  WHEN 21 AND 34

  WHEN 35 THEN 44

  END AS max_age

  Of age_rate

  UNPIVOT (rate

  FOR min_age IN (age_0_4 0)

  age_5_20 AS 5

  age_21_34 AS 21

  age_35_44 AS 35

  )

  )

  ORDER BY min_age

  ;

• Group by to ignore the values null

  Hi all
  Oracle version 10 g 2
  Consider the scenario
  
  Table: point
  Columns: Itm_id, Itm_type, appl_y_n (VALUES VALID 'Y', ' n, NULL)
  
  I HAVE FOLLOWING ITEM TYPES.
  
  TYP1
  TYP2
  TYP3
  
  In this appl_y_n is applicable only to the item type typ1 and it can contain y, n, or null.
  Types of remaining elements of this field may contain any value, including null, but I want to ignore these values.
  

  ITM_ID     ITM_TYPE     APPL_Y_N
  1     TYP1     NULL
  2     TYP1     Y
  3     TYP1     N
  4     TYP2     NULL
  5     TYP2      NULL
  6     TYP3     NULL
  7     TYP3     NULL

  now I need a group of clause which must ignore values null to appl_y_n only for TYP1
  
  on top of the sample output must be
  

  ITM_TYPE     APPL_Y_N     CNT
  TYP1     YES     1
  TYP1     NO     1
  TYP2     NULL     2
  TYP3     NULL     2

  Query, that I use for this:
  
  Select ITEM_TYPE, COUNT (ITM_ID), decode (itm_type, 'TYP1', DECODE(APPL_Y_N,'Y','Yes','N','No')) APPL_Y_N
  of the order of the day
  Item_type group, decode (itm_type, 'TYP1', DECODE(APPL_Y_N,'Y','Yes','N','No'))
  
  But he's considering typ1 as null values.
  
  Please give me a solution that ignores null values
  
  Thanks in advance
  NM

  Hello

  Check the below. It will be useful.

  SQL >
  SQL > WITH t AS)
  2 SELECT 2 ITM_ID, 'TYP1' ITM_TYPE, 'Y' APPL_Y_N FROM dual UNION ALL
  3. SELECT 3 ITM_ID, 'TYP1' ITM_TYPE, "n" APPL_Y_N FROM dual UNION ALL
  4. SELECT 1 ITM_ID, 'TYP1' ITM_TYPE, APPL_Y_N NULL FROM dual UNION ALL
  5. SELECT 4 ITM_ID, "TYP2' ITM_TYPE, APPL_Y_N NULL FROM dual UNION ALL
  6. SELECT 5 ITM_ID, "TYP2' ITM_TYPE, APPL_Y_N NULL FROM dual UNION ALL
  7. SELECT 6 ITM_ID, "TYP3' ITM_TYPE, APPL_Y_N NULL FROM dual UNION ALL
  8. SELECT 7 ITM_ID, "TYP3' ITM_TYPE, APPL_Y_N double NULL)
  9 SELECT itm_type,
  10 DECODE (itm_type, 'TYP1', DECODE (appl_y_n, 'Y', 'Yes', "n","no")) appl_y_n,.
  11 COUNT (itm_id)
  12 FROM t
  13 WHERE NOT (itm_type = 'TYP1' AND APPL_Y_N IS NULL)
  14 group of itm_type,
  15 decode (itm_type, 'TYP1', DECODE (APPL_Y_N, 'Y', 'Yes', "n","no"))
  16 ORDER BY itm_type
  17.

  ITM_TYPE APPL_Y_N COUNT (ITM_ID)
  -------- -------- -------------
  TYP1 NO. 1
  TYP1 Yes 1
  TYP2 2
  TYP3 2

  SQL >

  Rgds
  Ameya