When count sum ID number total < 300

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• Count of the number of months with unpaid for the last six months

  Hello

  I now table to store the daily presence of each employee

  ATTENDANCESHEET
  EMPID	PAYROLLDATE	UNPAID
  1	10/01/2013	6
  1	10/02/2013	2
  1	11/01/2013	0
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  11/02/2013

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  I want to get the number of months used unpaid in the past 6 months (excluding the current).

  If the month of payroll, I'm in treatment is 4, 2014, I spend 4 as payrollmonth and 2014 as payroll year

  The application must check the latest 6 month data and number of months for which there is any unpaid value

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  EmpID	County
  1	2
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  I use oracle 10g

  EXAMPLES OF DATA

  create the table attendancesheet as

  (

  Select 1 as empid, to_date (January 10, 2013 ',' DD/MM/YYYY ') as payrolldate, 6 paid by union double all the

  Select 1 as empid, to_date (10 February 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (January 11, 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (February 11, 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (12 January 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (February 12, 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (1 January 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (February 1, 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (January 2, 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (February 2, 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (3 January 2014 ',' DD/MM/YYYY ') as payrolldate, 45 paid by union double all the

  Select 1 as empid, to_date (3 February 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 2 as empid, to_date (3 January 2014 ',' DD/MM/YYYY ') as payrolldate, 0 as default all the double union

  Select 2 as empid, to_date (3 February 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid double

  );

  Help, please

  Hello

  So, you want to count the distinct months for 6 months before (not included) the given month; is this fair?

  Here's one way:

  VARIABLE month VARCHAR2 (2)

  Year VARIABLE VARCHAR2 (4)

  EXEC: months: = '4';

  EXEC: year: "2014"; =

  WITH got_end_date AS

  (

  SELECT TO_DATE (: month |) '/' || : year

  , ' MM/YYYY ".

  ) AS end_date

  OF the double

  )

  SELECT a.empid

  , COUNT (DISTINCT

  CASE

  WHEN a.unpaid > 0

  THEN TRUNC (a.payrolldate, 'MONTH')

  END

  ), Cnt

  Of attendancesheet one

  JOIN e-got_end_date WE a.payrolldate > = ADD_MONTHS (e.end_date-6)

  AND a.payrolldate< >

  GROUP BY a.empid

  ORDER BY a.empid

  ;

  If you use a WHERE clause to exclude the lines with some outstanding = 0 (or unpaid is NULL), then you would get no output for employees like empid = 2 in this example.  A WHERE clause ignores an entire line, so I used an expression BOX just a value.

• How to count the tank &amp; number?

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  11.2.0.1

  I have an EMP table with column EMPID (varchar2 (15))

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  cllaurena

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  Are you after something like this?

  WITH t
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           SELECT '6356' FROM DUAL
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    SELECT CASE
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                 'not_number'
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              typ,
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      FROM t
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              WHEN LENGTH (TRANSLATE (str, '~0123456789', '~')) IS NULL
              THEN
                 'num'
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                 'not_number'
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  TYPE COUNT (*)

  ------------------------------------------

  num                  4

  not_number 5

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• GROUP OF + SQL COUNT + SUM

  Hello
  
  I have a table, it has 2 colunms, (name, number)
  
  name number
  B1 7
  B1 7
  B1 28
  B1 28
  B1 28
  B2 7
  B2 28
  B3 7
  . .
  . .
  .
  .
  
  
  I want to see below
  
  number
  name sum 7sum 28sum
  
  5 2 3 B1
  2 1 1 B2
  B3...
  .
  .
  .
  .
  .
  
  
  Can you help me
  
  THANK YOU VERY MUCH FOR HELP

  Like this?

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select 'B1' as name, 7 as num from dual union all
    2             select 'B1', 7 from dual union all
    3             select 'B1', 28 from dual union all
    4             select 'B1', 28 from dual union all
    5             select 'B1', 28 from dual union all
    6             select 'B2', 7 from dual union all
    7             select 'B2', 28 from dual union all
    8             select 'B3', 7 from dual)
    9  --
   10  -- end of test data - use query below
   11  --
   12  select name
   13        ,count(*)
   14        ,sum(decode(num,7,1,0)) as sum7
   15        ,sum(decode(num,28,1,0)) as sum28
   16  from t
   17  group by name
   18* order by 1
  SQL> /
  
  NA   COUNT(*)       SUM7      SUM28
  -- ---------- ---------- ----------
  B1          5          2          3
  B2          2          1          1
  B3          1          1          0