GROUP OF + SQL COUNT + SUM
HelloI have a table, it has 2 colunms, (name, number)
name number
B1 7
B1 7
B1 28
B1 28
B1 28
B2 7
B2 28
B3 7
. .
. .
.
.
I want to see below
number
name sum 7sum 28sum
5 2 3 B1
2 1 1 B2
B3...
.
.
.
.
.
Can you help me
THANK YOU VERY MUCH FOR HELP
Like this?
SQL> ed
Wrote file afiedt.buf
1 with t as (select 'B1' as name, 7 as num from dual union all
2 select 'B1', 7 from dual union all
3 select 'B1', 28 from dual union all
4 select 'B1', 28 from dual union all
5 select 'B1', 28 from dual union all
6 select 'B2', 7 from dual union all
7 select 'B2', 28 from dual union all
8 select 'B3', 7 from dual)
9 --
10 -- end of test data - use query below
11 --
12 select name
13 ,count(*)
14 ,sum(decode(num,7,1,0)) as sum7
15 ,sum(decode(num,28,1,0)) as sum28
16 from t
17 group by name
18* order by 1
SQL> /
NA COUNT(*) SUM7 SUM28
-- ---------- ---------- ----------
B1 5 2 3
B2 2 1 1
B3 1 1 0
Tags: Database
Similar Questions
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Hello
I need help to fix this SQL.
Fields in the table are like that.
Basically I want the values of user_id, user_name, last time the logged-in user and total number of times the userID(PK) user_id user_name login_time(timestamp)
the above query is to give the result set with user_id, user_name, last time that the user logged on, but how can I include count (*) Group of user_id in the sql aboveselect distinct user_id , user_name, login_date from USER_LOGIN where login_date in (select max(login_date) from USER_LOGIN group by user_id)
the sql above does not work.select distinct user_id , user_name, login_date, count(*) from USER_LOGIN where login_date in (select max(login_date) from USER_LOGIN group by user_id) group by user_id
can you help me to get the number of records by user_id group.
Thank you
SKHello
Looks like you want something like this:
SELECT user_id , user_name , MAX (login_time) AS last_login_time , COUNT (*) AS total_rows FROM user_login GROUP BY user_id , user_name ;This assumes that user_login is off standard (like him are often seen), such that every row of the same user_id will also have the same user_name.
I hope that this answers your question.
If not, post a small example of data (CREATE TABLE and INSERT statements) and the results desired from these data. -
Group by and count on the same table
Hello
DB version: 11.2.0.3
Tried to SQL:
create table log1 (identification number, status varchar2 (15) date of insert1);
insert into log1 values (1, 'SUCCESS', sysdate-1);
insert into log1 values (2, 'SUCCESS', sysdate-2);
insert into log1 values (3, 'FAIL', sysdate-1);
insert into log1 values (4, 'FAIL', sysdate-2);
insert into log1 values (5, 'FAIL', sysdate-1);
insert into log1 values (6, 'ERROR', sysdate-1);
insert into log1 values (7, 'ERROR', sysdate-1);
insert into log1 values (8, 'ERROR', sysdate-1);
insert into log1 values (9, 'ERROR', sysdate-1);
WITH AS TBL1
(SELECT THE STATE OF 'SUCCESS' OF THE DUAL UNION ALL
SELECT "FAIL" STATUS OF THE DUAL UNION ALL
SELECT 'PENDING' STATUS OF DOUBLE)
SELECT NVL (TBL1. STATUS OF STATE, 'TOTAL'), COUNT (LOG1.ID)
FROM TBL1 JOIN LOG1 FULL EXTERNAL
ON LOG1. STATUS = TBL1. STATUS
GROUP BY ROLLUP (TBL1. STATUS)
STATUS COUNT (LOG1.ID) IN CASE OF FAILURE 3 SUCCESS 2 PENDING 0 TOTAL (*) 4 TOTAL 9 t need only State of SUCCESS, FAILURE, WAITING. and NUMBER of global ID omit the rest of type status as ERROR, etc. EXECUTION in the result set.
I don't need the TOTAL (*) of the above result set. Which is total (Error).
Please tell us how the query above can be changed to produce the result to wait.
Thank you
Hello
So, you want to see all the tbl1 lines, if they have a match in log1, and for the grand total of lines, you must count the log1 lines if they have a match with tbl1. This looks like a job for a FULL OUTER JOIN:
SELECT t.status
EARL of (l.status) AS cnt
OF log1 l
FULL OUTER JOIN tbl1 t WE t.status = l.status
GROUP OF ROLLUP (t.status)
HAVING t.status IS NOT NULL
OR of a GROUP (t.status) = 1
;
-
SQL Count query - Assistance needed
Hello
Hoping someone can point me in the right direction. Here's the query I have so far. What I'm trying to do is to compare and add the names of the skills of individuals. My current query will count them, however, I need to take a step further where if the person has a name of "Spanish" skills can only which is counted and not their names other skills.
Current query:
WITH AS TBL1
(SELECT
TRIM (A.NWIE_ID) AS NWIE_ID,
A.AGENT_NM,
B.BUSINESS
Of
LIGHTHOUSE. IEX_AGENTS A JOIN
LIGHTHOUSE. TBL_GEN_MU_BUSINESS B
ON A.MU_ID = B.MU_ID
WHERE B.BUSINESS IN ('PL_LEGACY'));
TBL2 ACE
(SELECT
TRIM (C.USER_ID) AS USER_ID,
TRUNC (ASOF_DT, 'IW') AS WEEKBEGINNING,
CASE
WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL < = 2) THEN "basic".
WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL < = 7) THEN "moderate."
WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL < = 10) THEN 'complex '.
WHERE (SKILL_NM = "PLSCLegacySpanish") THEN 'Spanish '.
Another null
END AS SKILL_NM
THE LIGHTHOUSE. C CFG_PERSON_SKILL_HIST
)
SELECT
WEEKBEGINNING,
SKILL_NM,
COUNT (DISTINCT NWIE_ID) TOTAL_SKILLED
Of
TBL1,
TBL2
WHERE TBL1. NWIE_ID = TBL2. USER_ID
AND SKILL_NM NOT IN ('NULL %')
SKILL_NM GROUP, WEEKBEGINNING
ORDER OF WEEKBEGINNING, SKILL_NM
Create the Table data:
CREATE TABLE IEX_AGENTS
(
AGENT_NM VARCHAR2 (20).
NWIE_ID CHAR (8),
NUMBER OF MU_ID (5)
)
CREATE TABLE TBL_GEN_MU_BUSINESS
(
BUSINESS VARCHAR2 (100),
NUMBER OF MU_ID (5)
)
CREATE TABLE CFG_PERSON_SKILL_HIST
(
USER_ID VARCHAR2 (8).
DATE OF ASOF_DT,
SKILL_NM VARCHAR2 (64).
NUMBER OF SKILL_LEVEL (10)
)
INSERT INTO IEX_AGENTS (AGENT_NM, NWIE_ID, MU_ID) VALUES ("Marcelle, Athalie", "MARCELA1", 5)
INSERT INTO IEX_AGENTS (AGENT_NM, NWIE_ID, MU_ID) VALUES ('Lister, Laura", 'LISTERL3', 6)
INSERT INTO IEX_AGENTS (AGENT_NM, NWIE_ID, MU_ID) VALUES ("Purvis, Bradley", 'PURVIB1', 4)
INSERT INTO IEX_AGENTS (AGENT_NM, NWIE_ID, MU_ID) VALUES ("Cannon, Mark", "CANNON1", 4)
INSERT INTO TBL_GEN_MU_BUSINESS (BUSINESS, MU_ID) VALUES ('PL_LEGACY', 5)
INSERT INTO TBL_GEN_MU_BUSINESS (BUSINESS, MU_ID) VALUES ('PL_LEGACY', 6)
INSERT INTO TBL_GEN_MU_BUSINESS (BUSINESS, MU_ID) VALUES ('PL_LEGACY', 4)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('PURVIB1', 3/9/2014 12:00 ',' PLSCLegacy', 1).
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('MARCELIA1', 3/9/2014 12:00 ',' PLSCLegacy', 10)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('LISTERL3', 3/9/2014 12:00 ',' PLSCLegacy', 7)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('CANNON1', 3/9/2014 12:00 ',' PLSCLegacy', 7)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('MARCELIA1', 3/9/2014 12:00 ',' PLSCLegacySpanish', 3)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('LISTERL3', 3/9/2014 12:00 ',' PLSCLegacySpanish', 6)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('PURVIB1', 3/9/2014 12:00 ',' PLSCLegacySpanish', 2)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('PURVIB1', 3/19/2014 12:00 ',' PLSCLegacy', 10)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('LISTERL3', 3/19/2014 12:00 ',' PLSCLegacy', 2)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('MARCELIA1', 3/9/2014 12:00 ',' PLSCLegacy', 10)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('CANNON1', 3/19/2014 12:00 ',' PLSCLegacy', 7)
INSERT INTO CFG_PERSON_SKILL_HIST (USER_ID, ASOF_DT, SKILL_NM, SKILL_LEVEL) VALUES ('CANNON1', 3/19/2014 12:00 ',' PLSCLegacySpanish', 7)
Results of the current query:
WEEKBEGINNING SKILL_NM TOTAL_SKILLED 07/03/2014 12:00:00 AM Foundational 1 07/03/2014 12:00:00 AM Complex 1 07/03/2014 12:00:00 AM Moderate 2 07/03/2014 12:00:00 AM Spanish 3 14/03/2014 12:00:00 AM Foundational 1 14/03/2014 12:00:00 AM Complex 2 14/03/2014 12:00:00 AM Moderate 1 14/03/2014 12:00:00 AM Spanish 1 Desired results:
WEEKBEGINNING SKILL_NM TOTAL_SKILLED 07/03/2014 12:00:00 AM Foundational 0 07/03/2014 12:00:00 AM Complex 0 07/03/2014 12:00:00 AM Moderate 1 07/03/2014 12:00:00 AM Spanish 3 14/03/2014 12:00:00 AM Foundational 1 14/03/2014 12:00:00 AM Complex 2 14/03/2014 12:00:00 AM Moderate 0 14/03/2014 12:00:00 AM Spanish 1 WITH ACE TBL1)
SELECT TRIM (A.NWIE_ID) AS NWIE_ID,
A.AGENT_NM,
B.BUSINESS
OF IEX_AGENTS HAS
JOIN THE
TBL_GEN_MU_BUSINESS B
ON A.MU_ID = B.MU_ID
WHERE B.BUSINESS IN ("PL_LEGACY")
),
(ACE TBL2)
SELECT USER_ID, TRIM (C.USER_ID)
TRUNC (ASOF_DT, 'IW') AS WEEKBEGINNING,
CASE
WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL<= 2)="" then="">
WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL<= 7)="" then ="">
WHERE (SKILL_NM = 'PLSCLegacy' AND SKILL_LEVEL<= 10)="" then ="">
WHERE (SKILL_NM = "PLSCLegacySpanish") THEN 'Spanish '.
END AS SKILL_NM
OF CFG_PERSON_SKILL_HIST C
),
(AS TBL3)
SELECT USER_ID,
WEEKBEGINNING,
SKILL_NM,
COUNT)
SKILL_NM SEPARATE CASE
WHEN 'Spanish', 1
END
) HAS_SPANISH OVER (PARTITION BY USER_ID, WEEKBEGINNING)
FOR TBL2
)
SELECT WEEKBEGINNING,
SKILL_NM,
COUNT)
SEPARATE CASE
WHEN HAS_SPANISH = 0 THEN NWIE_ID
WHEN SKILL_NM = "Spanish" THEN NWIE_ID
END
) TOTAL_SKILLED
FROM TBL1;
TBL3
WHERE TBL1. NWIE_ID = TBL3. USER_ID
AND SKILL_NM NOT IN ('NULL %')
SKILL_NM GROUP,
WEEKBEGINNING
ORDER OF WEEKBEGINNING,
SKILL_NM
/
WEEKBEGINNING SKILL_NM TOTAL_SKILLED
---------------------- ------------ -------------
03/03/2014 12:00:00 am founders 0
03/03/2014 moderate from 12:00:00 am 0
03/03/2014 12:00:00 am 2 Spanish
17/03/2014 12:00:00 am complex 1
17/03/2014 12:00:00 am basic 1
17/03/2014 12:00:00 am Spanish 16 selected lines.
SQL >
SY.
-
Need of a just rows in table using SQL counter bearing
Oracle 11 g 2
RHEL 6.4
---------------
Given the following table data:
EMPLOYEE HIRE_DATE TERM_DATE DEPT
------------------ ----------------- ------------------ ---------
John Doe 01/01/13 101
Jane Smith 05/01/13 102
Bob Jones 102 02/04/13, 22/04/13
Jenny Boo 03/12/13 03/31/13 103
Joe Schmoe 24/03/13 102
Bill Max 23/04/13 103
Jill clay 24/04/13 103
Joe Boom 11/05/13 102
I want to return the number of employees who work for each month, as long as they were hired at anytime during the month and what if they ended this month (ie the month worries me). So I would expect
EMPLOYEE OF THE MONTH
Jan 2
3 Feb
5 March
April 6 (Jenny Boo ended)
May 6 (Jenny Boo and Bob Jones have been completed)
I know there are bright people out there who are SQL expert, but I'm not one of them. If there is a way to do this in SQL just I would like to see it.
Hello stew,.
Thanks for your reply. Looking at your SQL, where did you get the column "cnt"? I don't see that in any table, physical or virtual.
It is in the clause "unpivot" of the request he posted.
Create the table "emp1" and the data that Martin condition and then run the query that provided stew.
Works for me:
Select to_char (Lun, ' FMMonth, YYYY') month,
Sum (Sum (TO_NUMBER (CNT))) more employees (command per LUN)
de)
Select trunc (hire_date, 'MM') "1."
trunc (ADD_MONTHS(term_date,1), 'MM') '-1 '.
from emp1
) a
UNPIVOT (LUN for NTC in ("1", "-1"))
LUN group
order by Lun;
Header 1 Header 2 MONTH
EMPLOYEES January 2013 2 February 2013 3 March 2013 5 April 2013 6 May 2013 6 -
How the group using SQL for the desired output.
Hi all
I am currently using oracle 10.2.0.4.0
Create a table script:
INSERT statement:CREATE TABLE FORTEST ( gpno VARCHAR2(10 BYTE), classnumber VARCHAR2(10 byte), age_min NUMBER, age_max NUMBER, amount NUMBER)
power required:insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 01,0,29,1) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 01,30,35,2) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 01,36,40,3) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 02,0,29,1) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 02,30,35,2) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 02,36,40,5) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 03,0,29,1) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 03,30,35,2) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G123' , 03,36,40,3) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G124' , 01,0,29,1) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G124' , 01,30,35,2) insert into fortest (GPNO,classnumber,age_min,age_max,amount) values ('G124' , 01,36,40,3)
as for gpno g123, classnumber 1 and 3, the rates are the same in all the age_min and age_max they need to be grouped.gpno classnumber age_min age_max amount G123 1,3 0 29 1 G123 1,3 30 35 2 G123 1,3 36 40 3 G123 2 0 29 1 G123 2 30 35 2 G123 2 36 40 5 G124 1 0 29 1 G124 1 30 35 2 G124 1 36 40 3
even if gpno 123 classnumber 2 has the same rates as the classesnumber 1 and 3 for the age groups 0 to 29 and 30 to 35,
rates are different for ages 36 to 40. so it should not be placed together. How can I do this in SQL
any help is appreciated.
Thanks in advance.Hello
Thorny problem!
Unfortunately, LISTAGG was created to the Oracle 11.2. About half of the complexity here is the aggregation of chain, i.e. forming the list of the classnumbers, as '1.3', using only functions available in Oracle 10.2.
Here's a solution:
WITH got_gpno_classnumber_cnt AS ( SELECT gpno, classnumber, age_min, age_max, amount , COUNT (*) OVER ( PARTITION BY gpno , classnumber ) AS gpno_classnumber_cnt FROM fortest -- WHERE ... -- If you need any filtering, this is where it goes ) , pairs AS ( SELECT a.gpno , a.classnumber , MIN (b.classnumber) OVER ( PARTITION BY a.gpno , a.classnumber ) AS super_classnumber FROM got_gpno_classnumber_cnt a JOIN got_gpno_classnumber_cnt b ON a.gpno = b.gpno AND a.age_min = b.age_min AND a.age_max = b.age_max AND a.amount = b.amount AND a.gpno_classnumber_cnt = b.gpno_classnumber_cnt GROUP BY a.gpno , a.classnumber , b.classnumber HAVING COUNT (*) = MIN (a.gpno_classnumber_cnt) ) , got_rnk AS ( SELECT DISTINCT gpno, classnumber, super_classnumber , DENSE_RANK () OVER ( PARTITION BY gpno , super_classnumber ORDER BY classnumber ) AS rnk FROM pairs ) , got_classnumbers AS ( SELECT gpno, classnumber, super_classnumber , SUBSTR ( SYS_CONNECT_BY_PATH (classnumber, ',') , 2 ) AS classnumbers FROM got_rnk WHERE CONNECT_BY_ISLEAF = 1 START WITH rnk = 1 CONNECT BY rnk = PRIOR rnk + 1 AND gpno = PRIOR gpno AND super_classnumber = PRIOR super_classnumber ) SELECT DISTINCT g.gpno , c.classnumbers , g.age_min , g.age_max , g.amount FROM got_gpno_classnumber_cnt g JOIN got_classnumbers c ON c.gpno = g.gpno AND c.classnumber = g.classnumber ORDER BY g.gpno , c.classnumbers ;Out (just as you requested):
GPNO CLASSNUMBERS AGE_MIN AGE_MAX AMOUNT ---------- --------------- ---------- ---------- ---------- G123 1,3 0 29 1 G123 1,3 30 35 2 G123 1,3 36 40 3 G123 2 0 29 1 G123 2 30 35 2 G123 2 36 40 5 G124 1 0 29 1 G124 1 30 35 2 G124 1 36 40 3 -
When count sum ID number total < 300
Afternoon Folks,
I was wondering if someone could help me with a query of code?
I'm counting the number of Packs of Service where the total payment of the amount for each separate sp_id is less than 300 pounds and also more than 300 pounds.
This is the code I have so far:
Select the specialty
count (distinct sp_id) "Service Packs",
Sum (payment_total) "Total paid £»,
round (sum (payment_total) / count (distinct sp_id), 0) 'average spend by MS.
of a3_fact_sms_service_inv
where specialized ("podiatry", "Podiatry")
and service_date between '01 Jan 11' and 31 Dec 11'
Specialty group
This is the table that I want it to look
SPECIALTY Service Packs Total paid £ average spend by SP * < 300 * > 300 *.
Podiatry 129 25682,26 199 * 107 * 22 *.
Podiatry 622 206651,08 332 * 403 * 219 *.
I'm currently running application 10 g
Concerning
Farming :)First of all, ' 01 Jan 11' is not a date, but rather a string. Use literals date (or at least to_date):
with t as ( select specialty, sp_id, sum(payment_total) sp_id_total from a3_fact_sms_service_inv where specialty in ('Chiropody','Podiatry') and service_date between date '2011-01-01' and date '2011-12-31' group by specialty, sp_id ) select specialty, count(sp_id) "Service Packs", sum(sp_id_total) "Total Paid £", round(sum(sp_id_total) / count(sp_id)) "Average Spend per SP", count(case when sp_id_total < 300 then 1 end) "Service Packs Less £300", count(case when sp_id_total = 300 then 1 end) "Service Packs Equal £300", count(case when sp_id_total > 300 then 1 end) "Service Packs Greater £300" from t group by specialty /SY.
-
I have a table called consignment with values as follows:
RID THE CTIME USERID
---------- ---------- ----------
1-1-1
1 1 2
1 1 3
1 2 1
1-2-2
1-3-1
1 3 4
1-3-6
1 3 7
2-1-1
2-1-7
RID THE CTIME USERID
---------- ---------- ----------
2 1 5
2-2-2
2-3-1
2 4 5
2-4-7
3-2-4
3-2-6
3-2-7
3-2-8
3-2-9
3 4 1
RID THE CTIME USERID
---------- ---------- ----------
3 4 2
3-4-3
3-1-1
For each DIN, I need to find what USERID check has the largest number of times. Here, for example. to rid = 1, userid = 3 check-in has the most number of times, to rid = 2, userid = 1 has the largest check in number of times and to rid = 3, userid = 2A check-in the large number of times.
How to write such a request? Help, please. I'm new to SQL. I understand GROUP BY, but here it seems that I would need a double collection and I have no idea how do.Hello
842474 wrote:
In this case, to rid = 1, userid = 1 and userid = 3 have the same number of check-ins. NOTE that ctime is not needed for anything whatsoever.OK, so forget the AMOUNT and total_ctime; Use COUNT and cnt:
WITH got_rnk AS ( SELECT rid , userid , COUNT (*) AS cnt , RANK () OVER ( PARTITION BY rid ORDER BY COUNT (*) DESC ) AS rnk FROM checkin GROUP BY rid , userid ) SELECT rid , userid , cnt FROM got_rnk WHERE rnk = 1 ; -
Hello world
I need to display the SPER_STATUS_TEXT count as 0 if there is no data from query below. Could someone help me please
SQL > SELECT a.sper_status_text, COUNT (*)
2 from (SELECT sper.assettxt,
CASE 3
4. WHEN sper.sper_status_text = "assessment" said.
5 THEN
6 'confirmed assessment '.
7. WHEN sper.sper_status_text AS "update - rated %".
8 THEN
9 "update - rated up to."
10. WHEN sper.sper_status_text AS "update - % evaluated.
11. CAN
12 'update - rated down"
13 ELSE
14 "other responses.
15 END
16 sper_status_text
17 zzcus.zzcus_sper_data sper
18 WHERE sper.sper_dates = ' 20100801-20100831'
19 AND sper.customer_id = 'NATFINS. '
20 AND sper.task_inquiry_type = "Vendor Comparison"
21 AND sper.assettxt <>'! MAD
(22) a
23 GROUP BY a.sper_status_text
ORDER 24 (CASE
25. WHEN a.sper_status_text = "Said assessment" THEN 1
26. WHEN a.sper_status_text = "update - evaluated until ' THEN 2
27. WHEN a.sper_status_text = 'Update - rated down' THEN 3
28 4 SOMETHING ELSE
END 29);
Results:
SPER_STATUS_TEXT COUNT (*)
------------------------ ----------
Claims assessment 2
I need to display as below (if there no data I need to display the number as 0)
SPER_STATUS_TEXT COUNT (*)
------------------------ ----------
Claims assessment 2
Updated - evaluated up to 0
Updated - rated low 0
Other answers 0
Please adviceYou can get this. Using the TYPE clause.
SQL> SQL> CREATE TABLE ZZCUS_SPER_DATA1 2 ( 3 SPER_STATUS_TEXT VARCHAR2 (30) 4 ,TASK_INQUIRY_TYPE VARCHAR2 (100) 5 ); Table created. SQL> SQL> INSERT INTO ZZCUS_SPER_DATA1 2 VALUES ( 3 'Data Updated', 'Descriptive Data Challenge - Maturity date / Redemption date'); 1 row created. SQL> SQL> INSERT INTO ZZCUS_SPER_DATA1 2 VALUES ('Data Updated', 'Descriptive Data Challenge - Ticker / Local Code'); 1 row created. SQL> SQL> SELECT * 2 FROM ( SELECT A.SPER_STATUS_TEXT, COUNT (*) CNT 3 FROM (SELECT CASE 4 WHEN SPER.SPER_STATUS_TEXT = 'Data Confirmed' 5 THEN 6 'Data Item Confirmed' 7 WHEN SPER.SPER_STATUS_TEXT LIKE 'Data Updated' 8 THEN 9 'Data Item Updated' 10 ELSE 11 'Other Responses' 12 END 13 SPER_STATUS_TEXT 14 FROM ZZCUS_SPER_DATA1 SPER 15 WHERE 1 = 1 16 AND SPER.TASK_INQUIRY_TYPE LIKE 'Descriptive Data Challenge%') A 17 GROUP BY A.SPER_STATUS_TEXT 18 ORDER BY (CASE 19 WHEN A.SPER_STATUS_TEXT = 'Data Item Confirmed' THEN 1 20 WHEN A.SPER_STATUS_TEXT = 'Data Item Updated' THEN 2 21 WHEN A.SPER_STATUS_TEXT = 'Other Responses' THEN 3 22 ELSE 4 23 END)) 24 MODEL 25 DIMENSION BY (SPER_STATUS_TEXT) 26 MEASURES (CNT) 27 RULES 28 (CNT ['Data Item Confirmed'] = NVL (CNT[CV ()], 0), 29 CNT ['Data Item Updated'] = NVL (CNT[CV ()], 0), 30 CNT ['Other Responses'] = NVL (CNT[CV ()], 0)); SPER_STATUS_TEXT CNT ------------------- ---------- Data Item Updated 2 Other Responses 0 Data Item Confirmed 0 3 rows selected. SQL>G.
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I need help can rewrite this query to get the result I wanted. Any help would be grealy appreciated.
Here, I'm trying to get the total number of master accounts and not master created per month. With the query below, I get the data, but I have to do a lot of coding to display data in a tabular and graphic form on the web.
Select last_day (add_months (trunc (created),-1)) + 1 as count (*) created, master, as the number
of web_users
Last_day (add_months (trunc (created),-1)) + 1, master group;
Now it returns the data
Created Master Number*.
01/01/2004 Y 100
01/01/2004 N 120
01/02/2004 Y 100
01/02/2004 N 120
01/03/2004 Y 100
01/04/2004 Y 100
01/04/2004 N 120
I need data output format. It won't be easy for me view the data on the web
Created Master1 Countnumber1 Master2 Countnumber2 *.
01/01/2004 N Y 100 120
01/02/2004 O N 100, 120
01/03/2004 O N 100, 0
01/04/2004 O N 100, 120SQL> create table web_users (created,master) 2 as 3 select case 4 when level <= 220 then date '2004-01-01' 5 when level <= 440 then date '2004-02-01' 6 when level <= 540 then date '2004-03-01' 7 else date '2004-04-01' 8 end 9 , case 10 when level <= 100 then 'Y' 11 when level <= 220 then 'N' 12 when level <= 320 then 'Y' 13 when level <= 440 then 'N' 14 when level <= 540 then 'Y' 15 when level <= 640 then 'Y' 16 else 'N' 17 end 18 from dual 19 connect by level <= 760 20 / Table created. SQL> select last_day(add_months(trunc(created),-1))+1 as created 2 , master 3 , count(*) as countnumber 4 from web_users 5 group by last_day(add_months(trunc(created),-1))+1 6 , master 7 order by created 8 , master 9 / CREATED M COUNTNUMBER ------------------- - ----------- 01-01-2004 00:00:00 N 120 01-01-2004 00:00:00 Y 100 01-02-2004 00:00:00 N 120 01-02-2004 00:00:00 Y 100 01-03-2004 00:00:00 Y 100 01-04-2004 00:00:00 N 120 01-04-2004 00:00:00 Y 100 7 rows selected. SQL> select trunc(created,'mm') created 2 , 'Y' master1 3 , count(case master when 'Y' then 1 end) countnumber1 4 , 'N' master2 5 , count(case master when 'N' then 1 end) countnumber2 6 from web_users 7 group by trunc(created,'mm') 8 order by created 9 / CREATED M COUNTNUMBER1 M COUNTNUMBER2 ------------------- - ------------ - ------------ 01-01-2004 00:00:00 Y 100 N 120 01-02-2004 00:00:00 Y 100 N 120 01-03-2004 00:00:00 Y 100 N 0 01-04-2004 00:00:00 Y 100 N 120 4 rows selected.Kind regards
Rob. -
Grouping of SQL with a subquery
Hi all
I had to get an output by combining the same field by using 2 different condition. I tried to use the subquery, but the output is not getting properly completed.
example of the query will be something like:
Select count (*), _ (select count (*) from TableX where = 1 condition) from TableX Grouper by FieldA.
The output is considered the first condition + (Count + have 2 folders and subquery (.. .or condition = 1) with also 2 records.)
But the real result for the subquery if I run the query separately is only 1 card. The query has filled the second row with the same performance as a result of the first condition with 2 records to return. Anyway I put a condition to bring together both the condition?
Thank you.Something like that?
select sum(case whenthen 1 else 0 end ) first_count, sum(1) total_count from TableX group by FieldA; Arun-
Not tested
-
Hi all
I think I'm really stupid but I have problems of SQL query.
I have a table with many lines of operations which all refer to different stores, for example:
Store... _Sales_... _Month_
Reading... 200 k... April
Leeds... 50k................ April
Manchester... 70k................ May
Reading... 100 k... May
I need to arrive at the average sales for the month combined as a total. That is the average income of store for a given period is 200 k + 50 k + 70 k + 100 k / * 3 * (because there are only 3 unique shops) - I hope this makes sense!
So, basically, I'm doing both a query of the SUM (and company store) and then out of the average of all the stores together. Is this possible?
Thank youHello
This query returns 140 which seems to be the correct value:
with data as ( select 'Reading' Store , 200 sales from dual union select 'Leeds' , 50 from dual union select 'Manchester' , 70 from dual union select 'Reading' , 100 from dual ) select sum(sales) , count( distinct store ) , sum(sales)/count(distinct store) from dataThere are several options:
1. you can get two IR on one page (using IFRAMEs - search for that word on the Forum)...
2. you create another region with the above query and that position just below the report
3. in the foot of the region call a process of PL/SQL (using AJAX) that calculates the value using the query and print it (via htp.p)Greetings,
Roelhttp://roelhartman.blogspot.com/
http://www.bloggingaboutoracle.org/
http://www.Logica.com/You can assign this answer to your question in marking it as useful or Correct ;-)
-
To be used at the APEX, I am trying to accomplish the following:
Have a read to the user indicating how much of a certain task is available:
IE:
There is 'X' associated tasks 'name of the project.
However, I get an error whenever an attempt to save the code, the code is as follows:
I tried both the single and double quotes.select 'There are ' ||count(distinct pd.fk_tasks_id) ||' tasks for project ' ||pm.name from protrac_master pm, protrac_detail pd where pk_proj_master_id = pk_proj_detail_idHello
Leland says:
... Wouldn't put an alias defeat the whole point of what I was trying to do?Lol why do you think that it would frustrate the object?
select 'There are ' ||count(distinct pd.fk_tasks_id) ||' tasks for project ' ||pm.name AS txt from protrac_master pm, protrac_detail pd where pk_proj_master_id = pk_proj_detail_id GROUP BY pm.nameIn addition, the statement runs a toad.
He would probably run in SQL * more, too, but not in all contexts where you would have to refer to columns.
-
Hi all
I have problems with the upgrade of SQL Server 2008 R2 at SQL2014 with the error "no mapping between account names and security IDS was done" and the reason for the error is SQL server local groups that were created during installation (SQL2008 R2) are not on the local server groups.
Can anyone help identify the good fix for this problem?
SQLServerMSSQLUser$$MSSQLSERVER
SQLServerSQLAgentUser$$MSSQLSERVER
SQLServerReportServerUser$$MSRS10_50.MSSQLSERVER
SQLServerFDHostUser$$MSSQLSERVER
Please let me know if you need any further details.
Thank you
Naz
S/NThis issue is beyond the scope of this site (for consumers) and to be sure, you get the best (and fastest) reply, we have to ask either on Technet (for IT Pro) or MSDN (for developers)* -
Group by and count in every 5 minutes
Dear guy,
I need to recover table data transaction report for the number of transactions sumarizing and the sum of the value in every 5 minutes. Please look below
Last time Type Value --------- ------ ----- 12:01:12 buy 10 12:02:34 pay a 20 12:04:43 topup 10 12:05:55 pay a 30 12:08:34 buy 40 12:11:21 buy 40 12:12:46 topup 5 12:15:50 pay a 30 12:16:23 pay a 25 12:19:40 pay a 15 12:19:50 buy 15 12:19:59 buy 5 -get the number of buy and pay a transaction every 5 minutes and the sum of the value
the result of the will:
Last time transaction number of value --------- ------ ----- ----- 12:00-12:05 pay a 1 20 12:00-12:05 buy 1 10 12:05 to 12:10 pay a 1 30 12:05 to 12:10 buy 1 40 12:10-12:15 pay a 0 0 12:10-12:15 buy 0 0 12:15-12:20 pay a 3 70 12:15-12:20 buy 2 20 Do you have ideas for this?
So thank you and enjoy
Ch
WITH DATA (last time, TYPE, VALUE)
AS (SELECT to_date('12:01:12','hh24:mi:ss'), 'buy', 10 double UNION ALL)
SELECT to_date('12:02:34','hh24:mi:ss'), "billpay", 20 FROM dual UNION ALL
Select to_date('12:04:43','hh24:mi:ss'), 'charging', 10 double UNION ALL
SELECT to_date('12:05:55','hh24:mi:ss'), pay 'a', 30 double UNION ALL
Select to_date('12:08:34','hh24:mi:ss'), 'buy', 40 double UNION ALL
SELECT to_date('12:11:21','hh24:mi:ss'), 'buy', 40 double UNION ALL
Select to_date('12:12:46','hh24:mi:ss'), 'charging', 5 double UNION ALL
SELECT to_date('12:15:50','hh24:mi:ss'), pay 'a', 30 double UNION ALL
SELECT to_date('12:16:23','hh24:mi:ss'), "billpay", 25 FROM dual UNION ALL
Select to_date('12:19:40','hh24:mi:ss'), pay 'a', 15 double UNION ALL
SELECT to_date('12:19:50','hh24:mi:ss'), 'buy', 15 double UNION ALL
SELECT to_date('12:19:59','hh24:mi:ss'), 'buy', 5 FROM dual)
-1/1440 is a minute so 5 / 1440 would be 5 minutes
To_char (SELECT trunc (SYSDATE) + (PIECE * (5 / 1440)), "HH24")
TO_CHAR (trunc (SYSDATE) + ((CHUNK + 1) * (5 / 1440)), "HH24")
TYPE
value
OF (-piece is the number of periods of 5 minutes since midnight)
Floor (to_number (to_char(lasttime,'SSSSS')) SELECT / 300) AS CHUNK
TYPE
value of MySQL
FROM THE DATA
GROUP BY floor (to_number (to_char (last time, 'SSSSS')) / 300)
TYPE)
/
HTH
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