When no rows returned in the query loop, replace Null - need help
HelloI have a requirement where I have a request in the loop for and based on the results of the query, I do some operations.
But even if the query does not match, I should get back something like 'No Data'.
My loop is:
FOR V_SL IN)
SELECT ID, CATEGORY, DI_CD, REV_CD, SL_ID
OF SB, SLOT_2001 S2 SLOT_DATA WHERE
PBM BENEFIT_ID = S2. BENEFIT_ID AND
REV_CD = IN_REV_CD AND
(PROC_CD IS NULL OR PROC_CD = IN_PROC_CD)
ORDER OF DIAGCODE, PROCEDURECODE)
LOOP
END LOOP;
I do some operations inside the loop for. I want the loop to run even if the query returns no rows.
Can someone help me out here.
Thank you
Rambeau
Frank. I am really surprised to see this coming from you. A slider to not find all the lines loop does not cause an exception no_data_found.
Tags: Database
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(
A NUMBER,
PLEASE THE NUMBER,
NUMBER OF END,
NUMBER OF TEACHER,
AVERAGE NUMBER,
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)
;
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (1, 0,.1, 159, 159, 1);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (159, 168, 1 2,.1,.2,);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (3,.2,.3, 179, 159, 1);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (4,.1,.2,, 250, 300, 1);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (5,.2,.3, 320, 250, 1);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (6,.3,.4,, 250, 380, 1);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (7,.2,.3, 388, 379, 1);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (8,.3,.4,, 379, 388, 1);
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values (9,.4,.5, 388, 400, 1);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
values (10, 499, 500, 1 1.5,.6,);
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values (11,.5,.6, 420, 448, 1);
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values (12,.6,.7, 520, 530, 1);
insert into TABLE_AA1 (A, START, END, TEACHER, MEDIUM, REGION)
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I have a situation like below
(1) following query will display the calculation for the first 3 lines - works fine
(2) if the user pass parameter to eliminate the A = 2 & R_SQUARE = 0.95 and to calculate for the first 3 lines - works fine
(3) I have a problemn is so user pass the parameter for A = 2
I want to display eliminate an A = 2 & and R_SQUARE = 0.95 in the second query (as a part of the first 3 rows)
(No idea or help is appreciated)
I want the results of the query as below
(1) first query works FineA BEG END PROF AVERAGE REGION RN RN_DESC R_SQUARE R_SQUARE_VAL RANK 1 0 0.1 159 159 1 1 13 0.956274596 2 *2 0.1 0.2 159 168 1 3 0.2 0.3 179 159 1 2 12 0.956274596 2 4 0.1 0.2 250 300 1 3 11 0.956274596 0.956274596 2 5 0.2 0.3 320 250 1 4 10 0.018818382 1 6 0.3 0.4 250 380 1 5 9 0.018818382 1 7 0.2 0.3 388 379 1 6 8 0.018818382 0.018818382 1
SELECT d.*,DENSE_RANK() OVER (/*PARTITION BY r_square_val*10*/ ORDER BY R_SQUARE_VAL) RANK FROM (SELECT c.*, last_value(r_square ignore nulls) over (order by rn_desc) r_square_val FROM (SELECT a.*, REGR_R2 (average, prof) OVER (ORDER BY rn ROWS BETWEEN CASE WHEN MOD (rn, 3) = 0 THEN 3 WHEN rn_desc = 1 THEN MOD (rn, 3) ELSE 0 END PRECEDING AND CURRENT ROW) AS r_square FROM (select b.*, row_number() over (partition by region order by b.a) rn, row_number() over (partition by region order by b.a desc) rn_desc from table_aa1 b /*where b.a != 2*/ ) a) c) d /*where trunc(r_square_val, 2) = 0.01*/ ORDER BY d.region asc ,d.a asc;
(2) request works very wellA BEG END PROF AVERAGE REGION RN RN_DESC R_SQUARE R_SQUARE_VAL RANK ------------------------------------------------------------------------------------------------------- 1 0 0.1 159 159 1 1 14 0.25 3 2 0.1 0.2 159 168 1 2 13 0.25 3 3 0.2 0.3 179 159 1 3 12 0.25 0.25 3 4 0.1 0.2 250 300 1 4 11 0.164520715 1 5 0.2 0.3 320 250 1 5 10 0.164520715 1 6 0.3 0.4 250 380 1 6 9 0.164520715 0.164520715 1 7 0.2 0.3 388 379 1 7 8 0.218256852 2 8 0.3 0.4 379 388 1 8 7 0.218256852 2 9 0.4 0.5 388 400 1 9 6 0.218256852 0.218256852 2 10 1.5 0.6 499 500 1 10 5 0.973538061 4 11 0.5 0.6 420 448 1 11 4 0.973538061 4 12 0.6 0.7 520 530 1 12 3 0.973538061 0.973538061 4 13 0.7 0.8 540 550 1 13 2 1 5 14 0.9 1 560 570 1 14 1 1 1 5
If the user pass parameter to remove the A = 2 and R_SQUARE = 0.95 calculate for the first 3 lines - works fine
SELECT d.*,DENSE_RANK() OVER (/*PARTITION BY r_square_val*10*/ ORDER BY R_SQUARE_VAL) RANK FROM (SELECT c.*, last_value(r_square ignore nulls) over (order by rn_desc) r_square_val FROM (SELECT a.*, REGR_R2 (average, prof) OVER (ORDER BY rn ROWS BETWEEN CASE WHEN MOD (rn, 3) = 0 THEN 3 WHEN rn_desc = 1 THEN MOD (rn, 3) ELSE 0 END PRECEDING AND CURRENT ROW) AS r_square FROM (select b.*, row_number() over (partition by region order by b.a) rn, row_number() over (partition by region order by b.a desc) rn_desc from table_aa1 b where b.a != 2 ) a) c) d where trunc(r_square_val, 2) <= 0.95 ORDER BY d.region asc ,d.a asc;
Published by: user1849 on September 8, 2009 09:02A BEG END PROF AVERAGE REGION RN RN_DESC R_SQUARE R_SQUARE_VAL RANK 1 0 0.1 159 159 1 1 13 0.956274596 2 3 0.2 0.3 179 159 1 2 12 0.956274596 2 4 0.1 0.2 250 300 1 3 11 0.956274596 0.956274596 2 5 0.2 0.3 320 250 1 4 10 0.018818382 1 6 0.3 0.4 250 380 1 5 9 0.018818382 1 7 0.2 0.3 388 379 1 6 8 0.018818382 0.018818382 1
Published by: user1849 on September 8, 2009 09:14
Published by: user1849 on September 8, 2009 09:17You don't think the my last request everything works very well for your needs:
Look carefully
with req_data as ( SELECT d.* , DENSE_RANK() OVER (ORDER BY R_SQUARE_VAL) RANK FROM (SELECT c.* , last_value(r_square ignore nulls) over (order by rn_desc) r_square_val FROM (SELECT a.* , REGR_R2 (average, prof) OVER (ORDER BY rn ROWS BETWEEN CASE WHEN MOD (rn, 3) = 0 THEN 3 WHEN rn_desc = 1 THEN MOD (rn, 3) ELSE 0 END PRECEDING AND CURRENT ROW) AS r_square FROM (select b.* , row_number() over (partition by region order by b.a) rn , row_number() over (partition by region order by b.a desc) rn_desc from table_aa1 b where b.a not in (select d.a from table_aa1 d where d.a in(2,6))) a ) c ) d where trunc(r_square_val, 2) <= 0.49 ) select * from ( select * from req_data union all select m.* , to_number(null) r_square , to_number(null) r_square_val , to_number(null) RANK from ( select b.* , row_number() over (partition by region order by b.a) rn , row_number() over (partition by region order by b.a desc) rn_desc from table_aa1 b ) m where m.a in (2, 6) and exists (select 1 from (select max(r.a) mx , min(r.a) mn from req_data r ) where m.a between mn and mx ) ) x ORDER BY x.region asc , x.a asc;
As a result of output product
5 0.2 0.3 320 250 1 4 9 0.496965785 1 6 0.3 0.4 250 380 1 7 0.2 0.3 388 379 1 5 8 0.496965785 1 8 0.3 0.4 379 388 1 6 7 0.496965785 0.496965785 1
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861173 wrote:
Requirement: need to get the names of the employees who were hired Tuesday it must use the function to_charSelect ename
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