Why do I only a part of the graph of the wave even if I added the whole wave using the shift register?

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• Is there a way to make only a part of the timeline?

  Wel the title says it all I guess: is there a way to make only a part of the timeline?

  Yes. Place a marker and use keyboard shortcuts 'B' to set the inpoint and 'n' to define the out-point on your timeline. Good luck

• How to program the shift register to play only when a new user is detected user?

  Hello

  I'm currently developing a program of position control in labview. The program is quite simple, in which case the user will enter the distance on which he wants the table in the labview program and labview will send the signal to move a motor that will turn a ball screw to move a table horizontally to the targeted position. The criterion is that the profile of the engine depends on the distance to move, if a biphase (acceleration and deceleration) or three phase (acceleration, steady speed, deceleration) to reach the position of the target.

  The problem occurs when the user wants to enter a new entry second position) for the table, as the input by the user is the position that the table should be, but the necessary input to determine what profile the engine follows depends on the distance that the table moves to the target position. Therefore, I need a function to save the entry by the user temporarily and reminds that when a new user input is detected. Hereby, I would be able to use the difference of the input (input [n + 1] [n] input) and animal feed to determine what profile the engine follows and the entry by the user can be kept in the position he wants to the table to get (to compare with encoder).

  I thought to use for shift registers do, but I am not able to perform the deduction ([n + 1] - [n]) only when it detects a new entry. When I try to use registry to offset, it moves to the target location, and we only reached it will go to the original position. For example, when a user entry 90, this means that the table must be moved to the point 90. The shift register is initialized to 0, it will move to the point 90 (90-0 = 90), but arriving at 90, the shift register sends a signal of 90 (90-90 = 0) and the table back to its original position.

  Is it possible that I can delay the reading of the shift register only when a new entry is detected or there at - it another way for me to achieve what I want?

  I tried searching the forum site and neither discussion but could not find similar problems. Thank you for your help in advance.

  As I understand it, the use of shift registers with a structure of the event (to detect a user event when the user enters a new value) should solve the problem. Do not forget to post your request (or a version of it that isolates the issue) when you arrive at the lab, if we can get a clear visual of the issue you are facing.

• problem with the shift register

  for purposes of simplicity, I remove code without problems

  Description:
  1. my state machines, for some reason, a lot of cases.
  2. the order of each case may not change.
  3. the main prupose is to get the difference as on the front panel
  4. prior to entry difference, I first is measured in the case where 2 and TRY using shift register to pass data, ideally at least 5
  5. However, the "previous" value is updated too soon, unlike 'get' is always ZERO.

  for example
  You can see the shift register on the left side has two components, ideally, the 'get' difference should display 2-0 = 2.
  However, given that the second element of the registry team updates too early, my objective cannot reach and meet up with ALWAYS 0

  I think it's my misuse of the shift register for the computer to several cases.

  I pasted this problem for 4 hours... kind of stupid, but could not understand

  in a mulit-case state machine, how to properly passes data to the case (5 in this example) INSTRUCTION to ensure that I get the correct calculation

  GOLD: because I am only looking to the current value and the previous value, are there other ways to get this problem is?

  Thank you

  It is a case where execution highlighting can be helpful. Turn on execution highlighting by clicking the light bulb on the block diagram toolbar. Then, run the VI.  You will see the left side of the team to register the change as the state machine goes through States 3 and 4.  At the time where what happens to 5, all data in the change record is identical.

  One of them might be to use two registers to offset, one for the current value and the other for the previous value.

  Lynn

• initialize the shift register

  Hello

  How to initialize the shift register (inside the second loop for) so that it starts from 0 whenever the program runs. I tried to attach a constant 0 in left shift register, but which resets the registry whenever it passes through the inner loop.

  Thank you

  If you only want to reset once at the beginning and not for each iteration of the loop for external, you must add another register to lag on the outer for loop and wire lag 0 to that registry.

• Increment of the counter without using the shift register

  Is there a way to count = count + 1, with using a node registry or feedback shift?  I have a structure of the event within a while loop (see table).  When the button is touched (kickoff event), a test is carried out.  Based on the test in the case of a string is passed outside of the event to a case statement of success/failure.  The user can run one of these 'events' as many times as he or she wishes.  And in an order any... Test1 (fails)... test 1 (fails)... again... test1 (go) again... test 2 (pass) then test 1 (pass).  When the stop button is reached, I would like to know how many times each pass/fail is produced for each test.  Try to stay away from shift registers, as I have 18 w key so a possible failure for each, so I would need 36 shift registers.

  In my example, the printed final statement would be:

  TEST PASS/fail # x test was performed

  test1 failure 1

  2 in case of failure test1

  Test1 pass 3

  Test2 pass 1

  4 passes test1

  etc.

  Do not see an attachment.

  You can use a shift register to store a table.

  Each button would be mapped to an array index. For each button pushed you the value of the index table, + 1, replace the array element and pass out back for the shift register.

• replacement for the shift register chart

  Hi, I have a problem with my program. When I want to compare graphic legend with my present graphic it just overwirite with my graph.when this I add new data and then run my program it does not work. I tried to use shift regoster but my program eror. where should I put the register shift in my program? Thank you

  The shift register is on the outer loop. There is no need for inside while loops. The shift register should contain a table of two parcels of xy. Replace one of the accrding of two plots to the key using "replace the subset of the table".

  You don't need to a simple shift register, you have far too much code.

  (Please attach the screws with a suitable name. My Downloads folder already contains dozends of files "x.vi no title")

• Change the shift register

  I hope someone can direct me on that. I'm stuck.

  The NTC, I want that it start at zero, enter the nested loop

  and when the case statement is equal to one, add 3000,

  so I have a lag on "undesirable" elements in the 1 d

  table I'm parsing...

  TIA!

  the nested loop shift register is not initialized, it is best to initialize it with a constant 0

  Then, the index entry Array subset function is connected after or before the function incriment? I can't decide...

  in any case, if it is connected before the incremint function then the nested loop iteration 1 will send a 0 at the entrance to the function of the subset of the Array index.

  EWW! , a lot of entries, words of functions in the above paragraph lol , can u get me here?

  now I can just understand the problem what exactly you're talking about. the sequence of events for your code will be like this:

  After the nested loop is complete, the output will be available (1 d the function add array element table) to the structure of the case where you want to add 3000 to the value of the shift register and start the loop nested with initialized again records with value = 3000? Am I wrong?

  If I'm right, you must reset the shift by using a control register, create a local variable to him and place it in the business structure then her manipulate it as shown below:

  

  Since the default data of "N" type digital command value is 0, then initially the shift registers will be initialized with 0 as the guy above

  Thank you

• How can I display only a part of the scale in the waveform graph

  This is the first time I try to use the waveform graph, since now, I used the table of waveform.
  The reason why I moved to the chart, it's that I need cursors.

  I have 2 problem

  the first: in the diagram, the graph moves when I add a new data and the scale of the x-axis stay the same size, in the right size I always saw the new data. How can I do that with waveform graph?

  Second: How do I say Labview to the day I click on the graph, I need that because when move graphic I lose the day, and to make I need to zoom out, I drag the imprecateurs.

  All this must be done programmatically. The LabVIEW graphic accepts tabular data, not only as the table and the graph doesn't have the ability to retain the previous points, like the story of a graph. You will need to retain previous values and then continually update the graph with the old and new values to get a shift register "chart as behavior. Cursors should be written programmatically re of each iteration, since you rewrite the entire graph.

• Why is Captivate is not part of the creative cloud?

  Why is Adobe Captivate is not part of the creative cloud?

  
  It seems this would be a great addition to the workflow requiring a screenshot + edition. As a designer, I often need to integrate videos of screenshot projects such as video trailers, web site or application or product presentations. Unless explained, I don't see why it is not part of the package of cloud...  Now, I have to buy Camtasia or use freeware of shit...

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• How to make duplication of text cut so it shows only a part of the underlying Word

  Hello everyone,

  I'm not really sure how to describe it, but the link is: Design a poster classic serif | Illustrator | LKD creative. I basically want to do this. I tried following the instructions, but it seems that its missing instructions. Is it possible to create in Illustrator CS5? Any information would be appreciated. Thank you.

  bossladyleo,

  You can:

  (1) create any Type in position, with overlaps;

  (2) type > Create outlines, at least for the parts that overlap other parts (in some cases, you can keep everything live Type, but not in the case shown because of the shapes of letters and the mutual overlapping (for example, as of the jumps/Over);)

  (3) select each set of letters to overlap other and oppose > compound path > make;

  (4) object > path > offset from the desired gap round forms of the letter;

  (5) select the compound path which is offset and changes color to white, now you should have at least a partial coverage of the letters below.

  (6) object > compound path > exit, then select Direct and remove the counter paths (the one who did the counters/holes in the letters), now you should have one in addition to covering the letters below.

  (7) to get rid of any bit and remaining pieces, you can change the shape of the paths of offset in cutting, removal of parts to support (for example the parts between the serifs) and the displacement of the anchor (to the outside).

  If you want the result on a colored background, you can:

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• is it possible to only 1 part of the bolded text?

  As the title suggests I can everything do a part of the "BOLD" text but not all this?

  Example:

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  cause when I just highlight the part of May 2009 and try to "BOLD" it change all the text inside the div.

  In code view, place tags around the text you want to bold:

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  Nancy O.
  ALT-Web Design & Publishing
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  www.Alt-Web.com/
  www.Twitter.com/ALTWEB
  www.Alt-Web.blogspot.com

• I backed up my playlists M3U files before setting up a new computer, but even if music files are there, the playlists now show only a part of the music that was originally in the playlists. How can I get my playlists to work properly?

  Sorry in advance for the description potentially lengthy below.

  I have the latest version of iTunes on a Windows 10 computer with a processor i5, 8 GB of RAM and a lot of storage capacity.

  I recently updated my computer to the above specifications and installed a new SSD as my main and kept my old C drive as a new drive E drive.

  I backed up all my iTunes playlists as .m3u files export.

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  The selections are saved correctly I would say. When I opened the files as text files to check .m3u, good song lists are all in tact and the songs that do not appear in iTunes imported playlists are there in the .m3u.

  I tried to re - import playlists, as well as the copy of my music files to my different readers (including the same drive as the .m3u links to and those that they do not). Nothing seems to work. I spent years of compiling playlists are now empty or almost empty, and I can't find a reasonable solution to fix it.

  Must the .m3u files be .xml files? Is this a bug between versions of iTunes?

  Not sure if it's relevant, but my iPod Touch still has playlists on it. I hesitate to plug them in and try to sync because I don't want them crushed.

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  I really want to rebuild my entire library of playlists of text files.

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  "Backup" individual playlists is not necessary and probably will not work in all cases.  All selections are stored in the iTunes (iTunes Library.itl) database and all approaches successful transfer, reproduce or modify your library depends on manipulation of this file correctly.

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  Select the iTunes (the file iTunes Library.itl ) on your E: drive database - if you use default iTunes, this will be in E:\Users\username\Music\iTunes.

• Cancellation of registration user stored in the shift register event generates the error 1 if Subvi runs intermittently

  Hello

  I'm trying to understand the behavior of the attached excerpt from a larger overall vi functional.

  In a State, I'm generating a user event and in a State later unsubscribe from the event and destroy it.

  Now, if I went through the VI together in one step (i.e., step through events? set to FALSE), the VI runs without generating an error. However, if I run the VI by intermittent and output after each execution of the loop, the vi generates error 1. Why is it so? Please notify. Thank you.

  Peter

  Why are you registration and deregistration of events user, but you have no event structure in your VI who use them?

  When you run events, probaby the event you registered disappears when your VI stops running.  If you were able to keep your VI in the foreground running, then the life of the event would persist.

  The event number still exists in the uninitialized shift register, but it does not say more once your high level VI stops and you get the error 1.

  If it was really a global functional VI, you would terminals connected to the connector table in your VI, you would call this as a Subvi as part of a main VI and life event would persist and you wouldn't mistake 1.

• Reset the shift register according to value

  Hey there ' All, I've been thrown in Labview to work, so I made a few minis and other programs on my own. The last one I wrote is a system of notification by e-mail, because it's something I plan use a lot. The idea is, I have a random number generator that collects a number every 100ms using a timed loop. When a number is greater than a certain threshold, say 0.5, an email is sent and a flag is hoisted. From there on, I don't want to send any other emails until the number is BELOW a certain level, say, 0.3. With what I wrote, I get emails to send no problem and I can't stop them sending (using a combination of Boolean indicator and a shift register), but I can't understand how to to reset the indicator to allow emails as soon as I "roll" a number under my lower threshold.

  Is there a way I can achieve this? I would be deeply obliged for any help. I have attached the VI I did below, apologies, if it is messy and so on.

  Use a Select statement after the structure of the case.  If the reset condition is True, then thread a real constant through the register shift.  If the reset condition is False, then just wire the existing through the register shift.