With separate SQL query and the counter is wrong.

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• Help with making SQL query references to column aliases in the Case statement

  I need help with a sql query that I'm trying. I can go about it the wrong way, but I would be grateful if I could get any suggestions on possible solutions. This is my query:
  
  
  SELECT DISTINCT spriden_pidm, spriden_id id, spriden_last_name | ',' | spriden_first_name name,
  
  CASE
  WHEN rcresar_comm_code_01 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_01
  WHEN rcresar_comm_code_02 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_02
  WHEN rcresar_comm_code_03 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_03
  WHEN rcresar_comm_code_04 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_04
  WHEN rcresar_comm_code_05 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_05
  WHEN rcresar_comm_code_06 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_06
  WHEN rcresar_comm_code_07 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_07
  WHEN rcresar_comm_code_08 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_08
  WHEN rcresar_comm_code_09 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_09
  WHEN rcresar_comm_code_10 IN ('268 ', '269', ' 270') THEN rcresar_comm_code_10
  END acg_elig_comm_code
  
  CASE
  WHEN acg_elig_comm_code = ' 268' THEN 'rigorous HS course. "
  WHEN acg_elig_comm_code = '269' THEN ' 2 or several AP or IB"
  WHEN acg_elig_comm_code = '270' THEN 'NOC as possible ".
  END comm_code_description
  
  OF spriden, rcresar, rcrapp1
  
  WHERE (rcresar_comm_code_01 IN ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_02 ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_03 ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_04 ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_05 ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_06 ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_07 ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_08 ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_09 ('268 ', '269', ' 270')
  
  OR rcresar_comm_code_10 ('268 ', '269', ' 270'))
  
  
  Rcresar_aidy_code = & aidy_code
  
  AND rcrapp1_aidy_code = rcresar_aidy_code
  
  AND rcrapp1_curr_rec_ind = 'Y '.
  
  AND rcrapp1_seq_no = rcresar_seq_no
  
  
  AND spriden_pidm = rcresar_pidm
  
  AND rcrapp1_pidm = rcresar_pidm
  
  
  AND spriden_change_ind IS NULL
  
  ORDER BY name
  
  
  The second case statement is where I don't know exactly what it takes to get what I want.
  
  Output should be like:
  spriden_pidm name ID acg_elig_comm_code comm_code_description
  «0000000000', ' 1111111111 ","John Doe","268", «rigorous HS race"»
  
  If I take the second case statement it works great except that I do not have my comm_code description column. My question is how can I use my first statement value box to determine this column? I think that I need a case statement as I have, but I don't know how to reference the value of acg_elig_comm_code. Any help would be greatly appreciated. Thank you.
  
  Published by: blackhole82 on January 20, 2009 09:20

  Hello

  You cannot use the alias column in the query, even where it is set (except in the ORDER BY clause).
  You can set the alias in a subquery and then use it in a great query, like this:

  WITH  sub_q  AS
  (
      SELECT DISTINCT spriden_pidm,spriden_id id, spriden_last_name||', '||spriden_first_name name,
          CASE
              WHEN rcresar_comm_code_01 IN ('268','269','270') THEN rcresar_comm_code_01
              WHEN rcresar_comm_code_02 IN ('268','269','270') THEN rcresar_comm_code_02
              WHEN rcresar_comm_code_03 IN ('268','269','270') THEN rcresar_comm_code_03
              WHEN rcresar_comm_code_04 IN ('268','269','270') THEN rcresar_comm_code_04
              WHEN rcresar_comm_code_05 IN ('268','269','270') THEN rcresar_comm_code_05
              WHEN rcresar_comm_code_06 IN ('268','269','270') THEN rcresar_comm_code_06
              WHEN rcresar_comm_code_07 IN ('268','269','270') THEN rcresar_comm_code_07
              WHEN rcresar_comm_code_08 IN ('268','269','270') THEN rcresar_comm_code_08
              WHEN rcresar_comm_code_09 IN ('268','269','270') THEN rcresar_comm_code_09
              WHEN rcresar_comm_code_10 IN ('268','269','270') THEN rcresar_comm_code_10
          END acg_elig_comm_code   -- Originally posted with , here (error)
      FROM spriden, rcresar, rcrapp1
      WHERE (rcresar_comm_code_01 IN ('268','269','270')
              OR rcresar_comm_code_02 IN ('268','269','270')
              OR rcresar_comm_code_03 IN ('268','269','270')
              OR rcresar_comm_code_04 IN ('268','269','270')
              OR rcresar_comm_code_05 IN ('268','269','270')
              OR rcresar_comm_code_06 IN ('268','269','270')
              OR rcresar_comm_code_07 IN ('268','269','270')
              OR rcresar_comm_code_08 IN ('268','269','270')
              OR rcresar_comm_code_09 IN ('268','269','270')
              OR rcresar_comm_code_10 IN ('268','269','270'))
      AND rcresar_aidy_code = &aidy_code
      AND rcrapp1_aidy_code = rcresar_aidy_code
      AND rcrapp1_curr_rec_ind = 'Y'
      AND rcrapp1_seq_no = rcresar_seq_no
      AND spriden_pidm = rcresar_pidm
      AND rcrapp1_pidm = rcresar_pidm
      AND spriden_change_ind IS NULL
  )
  SELECT    sub_q.*,
            CASE
                WHEN acg_elig_comm_code = '268' THEN 'Rigorous HS course'
                WHEN acg_elig_comm_code = '269' THEN '2 or more AP or IB'
                WHEN acg_elig_comm_code = '270' THEN 'ACG possible'
            END comm_code_description
  FROM      sub_q
  ORDER BY  name
  

  Furthermore, you might think to rearrange your table, so that you do not have 10 columns (rcresar_comm_code_01, rcresar_comm_code_02,...) that essentially do the same thing. The usual way to handle this kind of one-to-many relationship is to have all rcresar_comm_codes in a separate table, one per line, with a pointer to the table where you have them now.

  Published by: Frank Kulash, January 20, 2009 11:35
  Syntax error has been corrected

• In the Photos of El Capitan how to record a double published in a separate with its own name and the ID file file?

  In the Photos of El Capitan how to record a double published in a separate with its own name and the ID file file?

  Only by exporting - with Photos (and iPhoto and Aperture) - you can have several versions of an image by duplicating the image (control - D), but this does not create an image file separated until you export - it creates a separate edit list in the database that applies to the original when you watch or export the photos

  Photos as it were its predecessors is a non-destructive control Digital Asset Manager (DAM) which does not any changes to files in the database but built a list of validation

  LN

• Need help with a SQL query

  Hello

  I have a data in table (raj_table) with columns (char11) raj_id, raj_number (varchar2 (15)), raj_format (NUMBER), Primary_ID (identity with the values of the primary key column)

  Primary_ID raj_id Raj_number Raj_format

  1                            raj                 rajvend                      1

  2                            raj                 rajvend                      1

  3                            raj                 rajvendor1                 2

  4                            raj                 rajvendor1                 2

  5                            raj                 rajvendor1                 2

  6                            raj                 rajvendor2                 3

  I used under SQL to get query output as below, but has not achieved the required result:

  Select client_id vendor_number, vendor_format, primary_id, row_number() on sl_no (client_id partition, primary_id, vendor_format order of client_id primary_id, vendor_format, vendor_number, vendor_number)

  from raj_table by sl_no asc

  SL_NO raj_id raj_number raj_format primary_id

  1                   1                   raj              rajvendor                 1

  1                   2                  raj              rajvendor                 1

  2                   3                   raj              rajvendor1                2

  2                   4                   raj              rajvendor1                2

  2                   5                  raj               rajvendor1                2

  3                   6                    raj              rajvendor2                3

  I need help with a SQL query to get the result as above without using the group by clause. I want to bring together the combination of separate line of the three columns (raj_id, raj_number, raj_format) and add a unique serial number for each online game (SL_NO column below). So, above there are 3 unique set of (raj_id, raj_number, raj_format) I can get in a group by clause, but I can not add prmiary_id, SL_NO values if I group by clause. I used the analytical functions like row_number() but no luck. Need solution for this.

  with t as)

  Select 'raj' raj_id, 'rajvend' raj_number, 1 raj_format, 1 primary_id Union double all the

  Select option 2, 'raj', 'rajvend', 1 double Union all

  Select 3, 'raj', 'rajvendor1', 2 double Union all

  Select 4, 'raj', 'rajvendor1', 2 double Union all

  Select 5, 'raj', 'rajvendor1', 2 double Union all

  Select 6, 'raj', 'rajvendor2', 3 double

  )

  Select dense_rank() over (order of raj_id, raj_number, raj_format) sl_no,

  t.*

  t

  order by primary_id

  /

  PRIMARY_ID RAJ RAJ_NUMBER RAJ_FORMAT SL_NO
  ---------- ---------- --- ---------- ----------
  1 1 raj rajvend 1
  1 2 raj rajvend 1
  2 3 raj rajvendor1 2
  2 4 raj rajvendor1 2
  2 5 raj rajvendor1 2
  3 6 raj rajvendor2 3

  6 selected lines.

  SQL >

  SY.

• SQL query for the mapping of a set of prizes to a group of classrooms

  Hi all
  
  I use Oracle database 11g Release 2.
  
  I have the following data set:
  
  Classrooms
  ClassId ClassName ability group
  ------ ----------------------------------------------      --------------     -----------
  Babbage/software Engg Lab 1 24 1
  Basement 2 - block PG 63 1
  3 1 56 1 class
  Class 4 1 24 10
  Class 5 1 24 11
  Class 6 1 35 12
  7 13 42 1 class
  8 14 42 1 class
  9 15 42 1 class
  10 2 35 1 class
  11 3 35 1 class
  12 4 35 1 classroom
  13 5 35 1 class
  14 6 25 1 class
  15 7 25 1 class
  16 1 24 8 class
  17 9 24 1 class
  18 control Sys Lab 1 24
  19 dig & Embd Sys Lab 20 1
  20 PSD & Comm 20 1 Lab
  21 electromechanical system Lab 28 1
  Farabi 22/Web Tech Lab 1 36
  23 gen purpose Lab 40 1
  Shirazi/24dB Tech Lab 1 36
  ADV 25 elect Lab 30 2
  26 16 42 2 class
  27 17 49 2 class
  28 18 56 2 class
  29 19 42 2 class
  30 20 49 2 class
  Class 31 21 35 3
  32 22 35 3 class
  33 20 3 MDA lab
  
  DegreeBatches
  BatchId BatchName force
  ---------------     ----------------------- --------------
  1 BIT - 11 79
  2 BIT - 12 28
  3 BS (CS)-1 35
  4 BS (CS) 78-2
  5 BE (SE)-1 69
  6. BE (SE) 84-2
  7 BE (SE) 64-3
  8 84 BYTČA-7
  9 43 BYTČA-8
  BEE-1 10, 112
  11 151 BEE-2
  BEE-3 12, 157
  13 BEE-4 157
  
  I want to map a combination of batch of degree for a class rooms group of such distance that they make full use of the maximum capacity of the class rooms within a group (ideally), or as close to this as possible. Can it be done with a SQL query?
  
  Any response will be appreciated.
  
  The SQL Scripts to generate the required tables and populate data is less to:
  CREATE TABLE classrooms (ClassId NUMBER, ClassName VARCHAR2 (50), capacity NUMBER, group NUMBER);
  INSERT INTO the classrooms of the VALUES (1, "Babbage/software Engg Lab', 24, 1");
  INSERT INTO the classrooms of the VALUES (2, 'basement - PG block', 63, 1);
  INSERT INTO the classrooms of the VALUES (3, '1 class room', 56, 1);
  INSERT INTO the classrooms of the VALUES (4, '10 class room', 24, 1);
  INSERT INTO the classrooms of the VALUES (5, '11 class room', 24, 1);
  INSERT INTO the classrooms of the VALUES (6, 'class room 12', 35, 1);
  INSERT INTO the classrooms of the VALUES (7, 'class room 13', 42, 1);
  INSERT INTO the classrooms of the VALUES (8, 'class room 14', 42, 1);
  INSERT INTO the classrooms of the VALUES (9, '15 'class, 42, 1);
  INSERT INTO the classrooms of the VALUES (10, 'class 2', 35, 1);
  INSERT INTO the classrooms of the VALUES (11, 'class room 3', 35, 1);
  INSERT INTO the classrooms of the VALUES (12, 'class room 4', 35, 1);
  INSERT INTO the classrooms of the VALUES (13, 'class room 5', 35, 1);
  INSERT INTO the classrooms of the VALUES (14, 'class room 6', 25, 1);
  INSERT INTO the classrooms of the VALUES (15, '7 class room', 25, 1);
  INSERT INTO the classrooms of the VALUES (16, 'class Room 8', 24, 1);
  INSERT INTO the classrooms of the VALUES (17, 'class room 9', 24, 1);
  INSERT INTO the classrooms of the VALUES (18, 'Control Sys Lab', 24, 1);
  INSERT INTO the classrooms of the VALUES (19, 'Dig & Embd Sys Lab', 20, 1);
  INSERT INTO the classrooms of the VALUES (20, 'DSP & Comm Lab', 20, 1);
  INSERT INTO the classrooms of the VALUES (21, 'system ELECTROMECHANICAL Lab', 28, 1);
  INSERT INTO the classrooms of the VALUES (22, ' Farabi/Web Tech Lab', 36, 1);
  INSERT INTO the classrooms of the VALUES (23, 'Gen purpose Lab', 40, 1);
  INSERT INTO the classrooms of the VALUES (24, ' Shirazi/DB Tech Lab', 36, 1);
  INSERT INTO the classrooms of the VALUES (25, 'Elected Adv Lab', 30, 2);
  INSERT INTO the classrooms of the VALUES (26, 'class room 16', 42, 2);
  INSERT INTO the classrooms of the VALUES (27, 'class room 17', 49, 2);
  INSERT INTO the classrooms of the VALUES (28, '18 'class, 56, 2);
  INSERT INTO the classrooms of the VALUES (29, '19 'class, 42, 2);
  INSERT INTO the classrooms of the VALUES (30, 'class room 20', 49, 2);
  INSERT INTO the classrooms of the VALUES (31, 'class room 21', 35, 3);
  INSERT INTO the classrooms of the VALUES (32, 'room 22', 35, 3);
  INSERT INTO the classrooms of the VALUES (33, 'MDA Lab', 20, 3);
  
  CREATE TABLE DegreeBatches (BatchId NUMBER, BatchName VARCHAR2 (50), membership NUMBER);
  INSERT INTO DegreeBatches VALUES(1,'BIT-11',79);
  INSERT INTO DegreeBatches VALUES(2,'BIT-12',28);
  INSERT INTO DegreeBatches VALUES (3, 'BS (CS) - 1', 35);
  INSERT INTO DegreeBatches VALUES (4, 'BS (CS) - 2', 78);
  INSERT INTO DegreeBatches VALUES (5,'BE (SE) - 1', 69);
  INSERT INTO DegreeBatches VALUES (6,'BE (SE) - 2', 84);
  INSERT INTO DegreeBatches VALUES (7,'BE (SE) - 3', 64);
  INSERT INTO DegreeBatches VALUES(8,'BICSE-7',84);
  INSERT INTO DegreeBatches VALUES(9,'BICSE-8',43);
  INSERT INTO DegreeBatches VALUES(10,'BEE-1',112);
  INSERT INTO DegreeBatches VALUES(11,'BEE-2',151);
  INSERT INTO DegreeBatches VALUES(12,'BEE-3',157);
  INSERT INTO DegreeBatches VALUES(13,'BEE-4',157);
  
  Best regards
  Bilal
  
  Published by: Bilal on December 27, 2012 09:52
  
  Published by: Bilal on December 27, 2012 10:07

  Bilal, thanks for the nice problem! Another possibility to double check is to write a small PL/SQL function that returns 1 if a duplicate id is found, then equate to 0: "NUMBER of RETURN of Duplicate_Token_Found (p_str_main in VARCHAR2, p_str_trial VARCHAR2). It should analyze the second string and could use p_str_main LIKE '%', | l_id | ', %' for each id. In any case, the query complete (without that) is given below:

  Solution with names
  SQL> WITH rsf_itm (con_id, max_weight, nxt_id, lev, tot_weight, tot_profit, path, root_id, lev_1_id) AS (
    2  SELECT c.id,
    3         c.max_weight,
    4         i.id,
    5         0,
    6         i.item_weight,
    7         i.item_profit,
    8         ',' || i.id || ',',
    9         i.id,
   10         0
   11    FROM items i
   12   CROSS JOIN containers c
   13   UNION ALL
   14  SELECT r.con_id,
   15         r.max_weight,
   16         i.id,
   17         r.lev + 1,
   18         r.tot_weight + i.item_weight,
   19         r.tot_profit + i.item_profit,
   20         r.path || i.id || ',',
   21         r.root_id,
   22         CASE WHEN r.lev = 0 THEN i.id ELSE r.nxt_id END
   23    FROM rsf_itm r
   24    JOIN items i
   25      ON i.id > r.nxt_id
   26     AND r.tot_weight + i.item_weight <= r.max_weight
   27   ORDER BY 1, 2
   28  ) SEARCH DEPTH FIRST BY nxt_id SET line_no
   29  , rsf_con (nxt_con_id, nxt_line_no, con_path, itm_path, tot_weight, tot_profit, lev) AS (
   30  SELECT con_id,
   31         line_no,
   32         To_Char(con_id),
   33         ':' || con_id || '-' || (lev + 1) || ':' || path,
   34         tot_weight,
   35         tot_profit,
   36         0
   37    FROM rsf_itm
   38   UNION ALL
   39  SELECT r_i.con_id,
   40         r_i.line_no,
   41         r_c.con_path || ',' || r_i.con_id,
   42         r_c.itm_path ||  ':' || r_i.con_id || '-' || (r_i.lev + 1) || ':' || r_i.path,
   43         r_c.tot_weight + r_i.tot_weight,
   44         r_c.tot_profit + r_i.tot_profit,
   45         r_c.lev + 1
   46    FROM rsf_con r_c
   47    JOIN rsf_itm r_i
   48      ON r_i.con_id > r_c.nxt_con_id
   49   WHERE r_c.itm_path NOT LIKE '%,' || r_i.root_id || ',%'
   50     AND r_c.itm_path NOT LIKE '%,' || r_i.lev_1_id || ',%'
   51     AND r_c.itm_path NOT LIKE '%,' || r_i.nxt_id || ',%'
   52  )
   53  , paths_ranked AS (
   54  SELECT itm_path || ':' itm_path, tot_weight, tot_profit, lev + 1 n_cons,
   55         Rank () OVER (ORDER BY tot_profit DESC) rnk,
   56         Row_Number () OVER (ORDER BY tot_profit DESC) sol_id
   57    FROM rsf_con
   58  ), best_paths AS (
   59  SELECT itm_path, tot_weight, tot_profit, n_cons, sol_id
   60    FROM paths_ranked
   61   WHERE rnk = 1
   62  ), row_gen AS (
   63  SELECT LEVEL lev
   64    FROM DUAL
   65  CONNECT BY LEVEL <= (SELECT Count(*) FROM items)
   66  ), con_v AS (
   67  SELECT  b.itm_path, r.lev con_ind, b.sol_id, b.tot_weight, b.tot_profit,
   68          Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev - 1) + 1,
   69            Instr (b.itm_path, ':', 1, 2*r.lev) - Instr (b.itm_path, ':', 1, 2*r.lev - 1) - 1)
   70             con_nit_id,
   71          Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev) + 1,
   72            Instr (b.itm_path, ':', 1, 2*r.lev + 1) - Instr (b.itm_path, ':', 1, 2*r.lev) - 1)
   73             itm_str
   74    FROM best_paths b
   75    JOIN row_gen r
   76      ON r.lev <= b.n_cons
   77  ), con_split AS (
   78  SELECT itm_path, con_ind, sol_id, tot_weight, tot_profit,
   79         Substr (con_nit_id, 1, Instr (con_nit_id, '-', 1) - 1) con_id,
   80         Substr (con_nit_id, Instr (con_nit_id, '-', 1) + 1) n_items,
   81         itm_str
   82    FROM con_v
   83  ), itm_v AS (
   84  SELECT  c.itm_path, c.con_ind, c.sol_id, c.con_id, c.tot_weight, c.tot_profit,
   85          Substr (c.itm_str, Instr (c.itm_str, ',', 1, r.lev) + 1,
   86            Instr (c.itm_str, ',', 1, r.lev + 1) - Instr (c.itm_str, ',', 1, r.lev) - 1)
   87             itm_id
   88    FROM con_split c
   89    JOIN row_gen r
   90      ON r.lev <= c.n_items
   91  )
   92  SELECT v.sol_id,
   93         v.tot_weight s_wt, v.tot_profit s_pr, c.id c_id, c.name c_name, c.max_weight m_wt,
   94         Sum (i.item_weight) OVER (PARTITION BY v.sol_id, c.id) c_wt,
   95         i.id i_id, i.name i_name, i.item_weight i_wt, i.item_profit i_pr
   96    FROM itm_v v
   97    JOIN containers c
   98      ON c.id = To_Number (v.con_id)
   99    JOIN items i
  100      ON i.id = To_Number (v.itm_id)
  101   ORDER BY sol_id, con_id, itm_id
  102  /
  
      SOL_ID S_WT S_PR  C_ID C_NAME          M_WT C_WT  I_ID I_NAME     I_WT I_PR
  ---------- ---- ---- ----- --------------- ---- ---- ----- ---------- ---- ----
           1  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           2 BIT-11       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     4 BSCS-3       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   85     3 BSCS-2       35   35
                                                           5 BEE-4        50   50
           2  255  255     1 SEECS UG Block   100   95     4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                                                           7 BESE-3       30   30
                           2 IAEC Building     70   70     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
           3  255  255     1 SEECS UG Block   100  100     3 BSCS-2       35   35
                                                           4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   65     1 BIT-10       35   35
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
           4  255  255     1 SEECS UG Block   100  100     3 BSCS-2       35   35
                                                           4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     2 BIT-11       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   85     1 BIT-10       35   35
                                                           5 BEE-4        50   50
           5  255  255     1 SEECS UG Block   100   95     2 BIT-11       40   40
                                                           6 BICSE-7      25   25
                                                           7 BESE-3       30   30
                           2 IAEC Building     70   70     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
           6  255  255     1 SEECS UG Block   100  100     2 BIT-11       40   40
                                                           3 BSCS-2       35   35
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   65     1 BIT-10       35   35
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
           7  255  255     1 SEECS UG Block   100  100     2 BIT-11       40   40
                                                           3 BSCS-2       35   35
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     4 BSCS-3       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   85     1 BIT-10       35   35
                                                           5 BEE-4        50   50
           8  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     2 BIT-11       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   85     3 BSCS-2       35   35
                                                           5 BEE-4        50   50
           9  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   65     3 BSCS-2       35   35
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
          10  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                                                           7 BESE-3       30   30
                           2 IAEC Building     70   65     2 BIT-11       40   40
                                                           6 BICSE-7      25   25
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
          11  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                                                           7 BESE-3       30   30
                           2 IAEC Building     70   65     4 BSCS-3       40   40
                                                           6 BICSE-7      25   25
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
          12  255  255     1 SEECS UG Block   100   95     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     2 BIT-11       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
          13  255  255     1 SEECS UG Block   100   95     1 BIT-10       35   35
                                                           3 BSCS-2       35   35
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   70     4 BSCS-3       40   40
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     2 BIT-11       40   40
                                                           5 BEE-4        50   50
          14  255  255     1 SEECS UG Block   100  100     1 BIT-10       35   35
                                                           2 BIT-11       40   40
                                                           6 BICSE-7      25   25
                           2 IAEC Building     70   65     3 BSCS-2       35   35
                                                           7 BESE-3       30   30
                           3 RIMMS Building    90   90     4 BSCS-3       40   40
                                                           5 BEE-4        50   50
  
  98 rows selected.
  
  Elapsed: 00:00:01.42
  

  Published by: BrendanP on January 20, 2013 11:25
  I found the need to deduplicate regular expression:

  AND RegExp_Instr (r_c.itm_path | r_i.path, ',(\d+),.*?,\1,') = 0)

• Single SQL query for the analysis of the date of customs declaration under the table of Stock codes

  Dear all,

  
  

  Please tell us a single SQL query for the below,
  

  We have a Table of Stock as shown below,

  STOCK_TABLE

   

  ITEM_CODE (item code)

  BAT_NO

  (lot no.)

  TXN_CODE

  (transaction code)

  DOC_NO

  (number)

  BOE_DT

  (date of the customs declaration)

  I1

  B1

  I1

  I2

  I3

  B70

  I4

  B80

  I5

  B90

  T102

  1234

  JULY 2, 2015

  I6

  B100

  We have to find the date of customs declaration (i.e. the date when the items have come under this particular table) for items that are not attached to any document (that is, who have TXN_CODE, DOC_NO and BOE_DT fields with a NULL value).

  For each item in the table of actions, which is not attached to any document, the customs declaration date is calculated as follows.

  1. If (code section, lot number) combination is present under HISTORY_TABLE, the date of customs declaration will receive the UPDT_DT, the transaction code (TXN_CODE) is an IN or transactions (which can be analyzed from the TRANSACTIONS table).

  2. If (code section, lot number) combination is NOT currently at the HISTORY_TABLE (or) the transaction code respective to item - batch number combination code is an operation then customs declaration date will be the date of the document (DOC_DT) that we receive from one of the 3 tables IN_TABLE_HEAD that contains the element of that particular lot.

• If the case 1 and case 2 fails, our customs declaration date will be the last date of document (DOC_DT) that we receive from one of the 3 tables IN_TABLE_HEAD containing that particular item and the BAT_NO in expected results will be that corresponding to this document, as appropriate, to another NULL.

• If the case 1 or case 2 is successful, the value of the last field (in the output expected, shown further below) BATCH_YN will be 'Y', because it fits the lot. Otherwise it will be 'n'.

HISTORY_TABLE

 

ITEM_CODE

BAT_NO

TXN_CODE

DOC_NO

UPDT_DT

I1

B1

T1

1234

JANUARY 3, 2015

I1

B20

T20

4567

MARCH 3, 2015

I1

B30

T30

7890

FEBRUARY 5, 2015

I2

B40

T20

1234

JANUARY 1, 2015

TRANSACTION

 

TXN_CODE	TXN_TYPE
T1	IN
T20

OFF

T30

ALL THE

T50

IN

T80

IN

T90

IN

T60

ALL THE

T70

ALL THE

T40

ALL THE

IN_TABLE_HEAD_1

 

H1_SYS_ID (primary key)

TXN_CODE

DOC_NO

DOC_DATE

H1ID1

T1

1234

JANUARY 1, 2015

H1ID2

T70

1234

FEBRUARY 1, 2015

IN_TABLE_ITEM_1

 

I1_SYS_ID

H1_SYS_ID

(foreign key referencing H1_SYS_ID in IN_TABLE_HEAD_1)

ITEM_CODE

I1ID1

H1ID1

I1

I1ID2

H1ID1

I100

I1ID3

H1ID2

I3

IN_TABLE_BATCH_1

 

B1_SYS_ID

TXN_CODE                DOC_NO (now in IN_TABLE_HEAD_1)

BAT_NO

B1ID1

T1

1234

B1 / can be empty

B1ID2

T70

1234

B70

IN_TABLE_HEAD_2

 

H2_SYS_ID (primary key)

TXN_CODE

DOC_NO

DOC_DATE

H2ID1

T30

4567

FEBRUARY 3, 2015

H2ID2

T60

1234

JANUARY 3, 2015

IN_TABLE_ITEM_2

 

I2_SYS_ID	H2_SYS_ID (foreign key referencing H2_SYS_ID in IN_TABLE_HEAD_2)	ITEM_CODE
I2ID1	H2ID1

I1

I2ID2

H2ID1

I200

I2ID3

H2ID2

I2

IN_TABLE_BATCH_2

 

B2_SYS_ID

I2_SYS_ID

(foreign key referencing I2_SYS_ID in IN_TABLE_ITEM_2)

BAT_NO

B2ID1

I2ID1

B30 / null

B2ID2

I2ID2

B90

B2ID2

I2ID3

B60

IN_TABLE_HEAD_3

 

H3_SYS_ID (primary key)	TXN_CODE	DOC_NO	DOC_DATE
H3ID1

T50

1234

JANUARY 2, 2015

H3ID2

T80

1234

JANUARY 3, 2015

H3ID3

T90

1234

JANUARY 4, 2015

H3ID4

T40

1234

AUGUST 5, 2015

IN_TABLE_ITEM_3

 

I3_SYS_ID

H3_SYS_ID

(foreign key referencing H3_SYS_ID in IN_TABLE_HEAD_3)

ITEM_CODE

BAT_NO

I3ID1

H31D1

I2

B50

I3ID2

H3ID2

I4

B40

I3ID3

H3ID3

I4

I3ID4

H3ID4

I6

There is no IN_TABLE_BATCH_3

Please find below the expected results.

OUTPUT

 

ITEM_CODE

BAT_NO

TXN_CODE

DOC_NO

BOE_DT

BATCH_YN

I1

B1

T1

1234

JANUARY 3, 2015

THERE

I1

B30

T30

7890

FEBRUARY 5, 2015

N

I2

B60

T60

1234

JANUARY 3, 2015

N

I3

B70

T70

1234

FEBRUARY 1, 2015

THERE

I4

T90

1234

JANUARY 4, 2015

N

I6

T40

1234

AUGUST 5, 2015

N

Controls database to create the tables above and insert the records.

CREATE TABLE stock_table()item_code VARCHAR2()80),bat_no VARCHAR2()80),txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), boe_dt DATE );

INSERT EN stock_table

   VALUES ('I1', 'B1', '', '', '');

INSERT EN stock_table

   VALUES ('I1', '', '', '', '');

INSERT IN stock_table

   VALUES ('I2', '', '', '', '');

INSERT EN stock_table

   VALUES ('I3', 'B70', '', '', '');

INSERT EN stock_table

   VALUES ('I4', 'B80', '', '', '');

INSERT EN stock_table

   VALUES ('I5', 'B90', 'T102', '1234', '02-JUL-2015');

INSERT EN stock_table

   VALUES ('I6', 'B100', '', '', '');

SELECT *

FROM stock_table










 

CREATE TABLE history_table()item_code VARCHAR2()80),bat_no VARCHAR2()80),txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), updt_dt DATE );

INSERT IN history_table

   VALUES ('I1', 'B1', 'T1', '1234', '03-JAN-2015');

INSERT IN history_table

   VALUES ('I1', 'B20', 'T20', '4567', '03-MAR-2015');

INSERT IN history_table

   VALUES ('I1', 'B30', 'T30', '7890', '05-FEB-2015');

INSERT IN history_table

   VALUES ('I2', 'B40', 'T20', '1234', '01-JAN-2015');

SELECT *

FROM history_table










 

CREATE TABLE transaction1()txn_code VARCHAR()80),txn_type VARCHAR()80));




INSERT INTO transaction1

   VALUES ('T1', 'IN');




INSERT INTO transaction1

   VALUES ('T20', 'OUT');

INSERT INTO transaction1

   VALUES ('T30', 'ALL');

INSERT INTO transaction1

   VALUES ('T40', 'ALL');

INSERT INTO transaction1

   VALUES ('T50', 'IN');

INSERT INTO transaction1

   VALUES ('T60', 'ALL');

INSERT INTO transaction1

   VALUES ('T70', 'ALL');

INSERT INTO transaction1

   VALUES ('T80', 'IN');

INSERT INTO transaction1

   VALUES ('T90', 'IN');

SELECT *

FROM transaction1










 

CREATE TABLE in_table_head_1()h1_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

CREATE TABLE in_table_head_2()h2_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

CREATE TABLE in_table_head_3()h3_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

 

INSERT IN in_table_head_1

   VALUES ('H1ID1', 'T1', '1234', '01-JAN-2015');

INSERT IN in_table_head_1

   VALUES ('H1ID2', 'T70', '1234', '01-FEB-2015');

INSERT IN in_table_head_2

   VALUES ('H2ID1', 'T30', '4567', '03-FEB-2015');

INSERT IN in_table_head_2

   VALUES ('H2ID2', 'T60', '1234', '03-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID1', 'T50', '1234', '02-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID2', 'T80', '1234', '03-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID3', 'T90', '1234', '05-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID4', 'T40', '1234', '05-AUG-2015');










 

CREATE TABLE in_table_item_1()i1_sys_id VARCHAR2()80) PRIMARY KEY,

h1_sys_id VARCHAR2 (80) REFERENCES in_table_head_1()h1_sys_id),item_code VARCHAR2()80));

CREATE TABLE in_table_item_2()i2_sys_id VARCHAR2()80) PRIMARY KEY,

h2_sys_id VARCHAR2 (80) REFERENCES in_table_head_2()h2_sys_id),item_code VARCHAR2()80));

CREATE TABLE in_table_item_3(i3_sys_id VARCHAR2(80) PRIMARY KEY,

h3_sys_id VARCHAR2 (80) REFERENCES in_table_head_3()h3_sys_id),item_code VARCHAR2()80),

bat_no VARCHAR2 (80));

 

INSERT IN in_table_item_1

   VALUES ('I1ID1', 'H1ID1', 'I1');

INSERT IN in_table_item_1

   VALUES ('I1ID2', 'H1ID1', 'I100');

INSERT IN in_table_item_1

   VALUES ('I1ID3', 'H1ID2', 'I3');

INSERT IN in_table_item_2

   VALUES ('I2ID1', 'H2ID1', 'I1');

INSERT IN in_table_item_2

   VALUES ('I2ID2', 'H2ID1', 'I200');

INSERT IN in_table_item_2

   VALUES ('I2ID3', 'H2ID2', 'I2');

INSERT IN in_table_item_3

   VALUES ('I3ID1', 'H3ID1', 'I2','B50');

INSERT IN in_table_item_3

   VALUES ('I3ID2', 'H3ID2', 'I4','B40');

INSERT IN in_table_item_3

   VALUES ('I3ID3', 'H3ID3', 'I4','');

INSERT IN in_table_item_3

   VALUES ('I3ID4', 'H3ID4', 'I6','');

SELECT *

FROM in_table_item_1

SELECT *

FROM in_table_item_2

SELECT *

FROM in_table_item_3










 

CREATE TABLE in_table_batch_1()b1_sys_id VARCHAR2()80) PRIMARY KEY,

txn_code VARCHAR2 (80), doc_no VARCHAR2 (80), bat_no VARCHAR2 (80));

CREATE TABLE in_table_batch_2()b2_sys_id VARCHAR2()80) PRIMARY KEY,

i2_sys_id VARCHAR2 (80) REFERENCES in_table_item_2()i2_sys_id),bat_no VARCHAR2()80));

 

INSERT IN in_table_batch_1

   VALUES ('B1ID1', 'T1', '1234', 'B1');

INSERT IN in_table_batch_1

   VALUES ('B1ID2', 'T70', '1234', 'B70');

INSERT IN in_table_batch_2

   VALUES ('B2ID1', 'I2ID1', 'B30');

INSERT IN in_table_batch_2

   VALUES ('B2ID2', 'I2ID2', 'B90');

INSERT IN in_table_batch_2

   VALUES ('B2ID3', 'I2ID3', 'B60');

Please advise a solution for the same.

Thank you and best regards,

Séverine Suresh

very forced (question subfactoring used to allow easy testing/verification - could work with these test data only)

with

case_1 as

(select s.item_code,

s.bat_no,

h.txn_code,

h.doc_no,

h.updt_dt boe_dt,

cases where s.bat_no = h.bat_no then 'Y' else ' n end batch_yn.

cases where h.txn_code is not null

and h.doc_no is not null

and h.updt_dt is not null

then 'case 1' '.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, boe_dt

of w_stock_table

where bat_no is null

or txn_code is null

or doc_no is null

or boe_dt is null

) s

left outer join

w_history_table h

On s.item_code = h.item_code

and s.bat_no = h.bat_no

and exists (select null

of w_transaction1

where txn_code = nvl (s.txn_code, h.txn_code)

and txn_type in ('IN', 'ALL')

)

),

case_2 as

(select s.item_code,

NVL (s.bat_no, h.bat_no) bat_no.

NVL (s.txn_code, h.txn_code) txn_code.

NVL (s.doc_no, h.doc_no) doc_no.

NVL (s.boe_dt, h.updt_dt) updt_dt.

cases where s.bat_no = h.bat_no then 'Y' else ' n end batch_yn.

cases where h.txn_code is not null

and h.doc_no is not null

and h.updt_dt is not null

then 'case 2'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, boe_dt

of case_1

where refers_to is null

) s

left outer join

w_history_table h

On s.item_code = h.item_code

and exists (select null

of w_transaction1

where txn_code = nvl (s.txn_code, h.txn_code)

and txn_type in ('IN', 'ALL')

)

and not exists (select null

of case_1

where item_code = h.item_code

and bat_no = h.bat_no

and txn_code = h.txn_code

and doc_no = h.doc_no

and updt_dt = h.updt_dt

)

),

case_31 as

(select s1.item_code,

NVL (S1.bat_no, W1.bat_no) bat_no.

NVL (S1.txn_code, W1.txn_code) txn_code.

NVL (S1.doc_no, W1.doc_no) doc_no.

NVL (S1.updt_dt, W1.doc_dt) updt_dt.

cases where s1.bat_no = w1.bat_no then 'Y' else ' n end batch_yn.

cases where w1.txn_code is not null

and w1.doc_no is not null

and w1.doc_dt is not null

then "case 31'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s1

left outer join

(select i1.item_code, h1.txn_code, h1.doc_no, h1.doc_dt, b1.bat_no

of w_in_table_item_1 i1

inner join

w_in_table_head_1 h1

On i1.h1_sys_id = h1.h1_sys_id

inner join

w_in_table_batch_1 b1

On h1.txn_code = b1.txn_code

and h1.doc_no = b1.doc_no

) w1

On s1.item_code = w1.item_code

),

case_32 as

(select s2.item_code,

NVL (S2.bat_no, W2.bat_no) bat_no.

NVL (S2.txn_code, W2.txn_code) txn_code.

NVL (S2.doc_no, W2.doc_no) doc_no.

NVL (S2.updt_dt, W2.doc_dt) updt_dt.

cases where s2.bat_no = w2.bat_no then 'Y' else ' n end batch_yn.

cases where w2.txn_code is not null

and w2.doc_no is not null

and w2.doc_dt is not null

then "case 32'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s2

left outer join

(select i2.item_code, h2.txn_code, h2.doc_no, h2.doc_dt, b2.bat_no

of w_in_table_item_2 i2

inner join

w_in_table_head_2 h2

On i2.h2_sys_id = h2.h2_sys_id

inner join

w_in_table_batch_2 b2

On i2.i2_sys_id = b2.i2_sys_id

) w2

On s2.item_code = w2.item_code

),

case_33 as

(select s3.item_code,

w3.bat_no,

NVL (S3.txn_code, w3.txn_code) txn_code.

NVL (S3.doc_no, w3.doc_no) doc_no.

NVL (S3.updt_dt, w3.doc_dt) updt_dt.

cases where s3.bat_no = w3.bat_no then 'Y' else ' n end batch_yn.

cases where w3.txn_code is not null

and w3.doc_no is not null

and w3.doc_dt is not null

then "case 33'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s3

left outer join

(select i3.item_code, h3.txn_code, h3.doc_no, h3.doc_dt, i3.bat_no

of w_in_table_item_3 i3

inner join

w_in_table_head_3 h3

On i3.h3_sys_id = h3.h3_sys_id

) w3

On s3.item_code = w3.item_code

)

Select item_code, bat_no, txn_code, doc_no, boe_dt, batch_yn

of case_1

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_2

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn,

ROW_NUMBER() over (partition by item_code of updt_dt desc order) rn

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_31

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_32

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_33

where refers_to is not null

)

)

where rn = 1

ITEM_CODE	BAT_NO	TXN_CODE	DOC_NO	BOE_DT	BATCH_YN
I1	B1	T1	1234	JANUARY 3, 2015	THERE
I1	B30	T30	7890	FEBRUARY 5, 2015	N
I2	B60	T60	1234	JANUARY 3, 2015	N
I3	B70	T70	1234	FEBRUARY 1, 2015	THERE
I4	-	T90	1234	JANUARY 5, 2015	N
I6	-	T40	1234	AUGUST 5, 2015	N

Concerning

Etbin

• Pool pane there problem with long sql query?

  Hello

  I use Jdeveloper 11.1.2.2.0

  In the application I'm developing, there is a long sql query to call (it's a function from a package, which may take a few minutes to run) and I want to display a progress bar for the user.

  The progress bar component is a "progress indicator" and the percentage of achivement is refreshed by a component 'pool' with 1-second interval.

  The two components are connected in a javabean.

  The function with the sql query is the javabean too.

  To run the sql query that is long on background I am calling from a thread, and the pool component get the advancement of the percentage of a pipe filled with the sql function.

  If the function to run is just a long loop of java operations the progress bar works fine, but if I put my long sql query instead, stop listener pool should be performed to stop long, s sql queryo progress are updated only at the end of the long sql query.

  You have any ideas?

  Thank you

  Thanks for your replies. Unfortunately, it was not the solution to my case, sql procedures to block the entire application while ADF awaits them at the end...

  To solve my problem, I finally used a PL SQL Job to call my sql procedure (dbms_job.submit).

  The application is released right after the call and the component of the pool is not more secure!

  Kind regards

  Yann

• Vs. runtime vs. ViewObject ViewObject SQL query in the xml file.

  Hello

  I wonder what is the difference between query SQL in the long term, creating a view object in the duration and the creation of a display with an XML object.

  I'm not trying to have the result set cached just to pick once.

  
  

  My code for a creation of a view in a run-time object:

  HashSet<Integer> allPersonIdThatUserHasAccessTo = new HashSet<Integer>();
              AppModuleImpl am = (AppModuleImpl)ADFUtils.getApplicationModuleForDataControl("AppModuleDataControl");
  
              String sqlStr = "SELECT up.person_id FROM user_person up where up.user_id = " + userId;
              ViewObjectImpl vo = (ViewObjectImpl)am.createViewObjectFromQueryStmt("AllPeopleUserHasAccessToVo", sqlStr);
              vo.executeQuery();
              RowSetIterator rsi = vo.createRowSetIterator(null);
              while (rsi.hasNext()) {
                  Row personRow = rsi.next();
                  Integer personId = ((BigDecimal)personRow.getAttribute(0)).intValue();
                  allPersonIdThatUserHasAccessTo.add(personId);
              }
  
              rsi.closeRowSetIterator();
              vo.remove();
  

  When should I use SQL query, when the view object use at time of execution and time to create the view object to an xml file?

  In general you should not write this code in a managed bean. Access code or in your case creating a VO belongs behind the façade in the module of the application.

  You can create the original Version, but the main difference is that it takes more time. Code everything that the definition of VO created in the data model of the application module would make too and it clears directly after the query only to create the same code again the next time you call the method.

  If the goal is not to keep the data, you can create the hashset class and call executeEmptyRowSet() on the VO (https://blogs.oracle.com/smuenchadf/entry/what_does_executeemptyrowset_d for details). This way you only need a VO that takes a parameter and gets you the same result in less time.

  Timo

• Dynamic SQL query in the DB adapter

  Hello
  I want to use the following custom SQL query in the DB adapter:
  
  SELECT EMP_ID, EMP_NAME, EMP_LOCATION FROM EMP WHERE EMP_ID IN (#iNPUT_PARAMETER)
  
  the problem I'm facing is that I don't know at the time of the development that EMP_ID how much will be passed to the process so that I can not use the input parameter specific number. I cannot use it IN the query within which statement I concatenate all the EMP_ID separated by comma and passed under INPUT_PARAMETER, but when running, he read the full concatenated string as a single string rather than identify them as a list of different: with comma separation. could someone help me in this case
  
  Thank you
  Sunil

  Use the following query with two parameters. Build the string with delimiter when running and pass this string and delimiter to query... (in this example, the input value would be the same for both Delimiter1 and Delimiter2.)

  Select * from EMP WHERE deptno IN (SELECT SUBSTR (STRING_TO_TOKENIZE, DECODE (LEVEL, 1, 1, INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL-1) + 1), INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL)-DECODE (LEVEL, 1, 1, INSTR (STRING_TO_TOKENIZE, SEPARATOR, 1, LEVEL-1) + 1)) FROM (SELECT #StringToTokenizer | #Delimiter1 AS STRING_TO_TOKENIZE, #Delimiter2 AS DELIMITER FROM DUAL) CONNECT BY INSTR (STRING_TO_TOKENIZE SEPARATOR) ((, 1, LEVEL) > 0)

  Thank you
  -Sreeny

• ADF: How to print the query and the query passed into the class executeQueryForCollection methof impl VO parameters.

  Hello

  Kindly let me know how to print the query, and the parameters passed to it? I tried with the params parameter in super.executeQueryForCollection (qc, params, noUserParams); but could not succeed.

  I need save the query and the parameters passed to it. Kindly help.

  Thanks in advance,

  Kalpana.

  Here you go

  Coding with Passion: Oracle ADF - Debug Mode object query with parameters

• HP 15-f305ddx: I haveva hp 15-f305dx with an error code and the password of the bios 58495227

  I have a haveva hp 15-f305dx with an error code and the password of the bios 58495227

  Thank you so much, you're the best

• You are not connected to the internet! You want to work offline or try again? There is also a box with a red x and the message reads unplugged network cable.

  Unplugged network cable?

  Recently I get this message then on the line. You are not connected to the internet! You want to work offline or try again? There is also a box with a red x and the message reads unplugged network cable. It is very aggravating. Can someone tell me how to solve this problem? It might have something to do with my firewall? I recently downloaded mozzilla firefox if I could play words with friends, because IE would not work on the game.

  Hi LouisteanGriffin,

  ·         Did you do changes on the computer before the show?

  Follow these methods.

  Method 1: Follow these steps:

  Step 1: Start the computer in safe mode with network and check if the problem persists.

  A description of the options to start in Windows XP Mode

  http://support.Microsoft.com/kb/315222

  Step 2: If the problem does not persist in SafeMode with network, perform a clean boot to see if there is no conflict of software like clean boot helps you eliminate software conflicts.

  How to configure Windows XP to start in a "clean boot" State

  http://support.Microsoft.com/kb/310353

  Note: After completing the steps in the clean boot troubleshooting, follow the section How to configure Windows to use a Normal startup state of the link to return the computer to a Normal startupmode.

  After the clean boot used to resolve the problem, you can follow these steps to configure Windows XP to start normally.

  (a) click Start, run.

  (b) type msconfigand click OK.

  (c) the System Configuration Utility dialog box appears.

  (d) click the general tab, click Normal startup - load all services and device drivers and then click OK.

  (e) when you are prompted, click on restart to restart the computer.

  Method 2: Temporarily disable the security software.

  Note: Antivirus software can help protect your computer against viruses and other security threats. In most cases, you should not disable your antivirus software. If you do not disable temporarily to install other software, you must reactivate as soon as you are finished. If you are connected to the Internet or a network during the time that your antivirus software is disabled, your computer is vulnerable to attacks.

  Method 3: Follow the steps in the article.

  How to troubleshoot a network home in Windows XP

  Windows wireless and wired network connection problems

  For reference:

  How to reset the Protocol Internet (TCP/IP)

• Having a problem with a redirect virus and the refusal by the system to allow me to download various things, Windows Live Mail in particular.

  I recently tried to remove malware on my Vista based laptop Toshiba.

  
  

  I recently tried to remove malware on my Vista based laptop Toshiba. Malwarebytes helped, but I still have problems with a redirect virus and the refusal by the system to allow me to download various things, Windows Live Mail in particular. I tried to download from a copy of the USB stick to a clean computer, but he still refuses to load telling me to check my internet connection, which is fine for general use. Please help I get crazy and do not forget that I am a pure layman - thank you if you can help - Kidso

  I found that the best place to ask this type of question is here: -.

  http://forums.ComputerActive.co.UK/forumdisplay.php?f=20

  There are some very good people out there who helped me (successfully) on 2 occasions.

  Good luck.

  I'll be interested to know how you go.

• I try to burn a DVD with Windows DVD maker and the tiles are about 3 hours or so in total and I like it's too big - it is possible to use SP, SLP. ED or when burning on a DVD

  • I am trying to burn a DVD with Windows DVD maker and the tiles are about 3 hours or so in total and I thought it's too big – is it possible to use SP, SLP or ED when burning to a DVD problem

  • I am trying to burn a DVD with Windows DVD maker and the tiles are about 3 hours or so in total and I thought it's too big – is it possible to use SP, SLP or ED when burning to a DVD problem

  ==========================================
  The following article shows 150 minutes on a single DVD layer, but
  I'd be surprised if it always worked this way. In any case...
  Perhaps you could use a DVD double layer if your burner will handle it.

  Windows Vista - DVD - video burning - frequently asked questions
  http://Windows.Microsoft.com/en-us/Windows-Vista/DVD-Video-burning-frequently-asked-questions

  Splitting the project between 2 or 3 DVD might be the best option.

  Volunteer - MS - MVP - Digital Media Experience J - Notice_This is not tech support_I'm volunteer - Solutions that work for me may not work for you - * proceed at your own risk *.

• I wipe my keyboard and mouse with a paper towel and the screen flipped sideways, how I recover the right way? /

  I wipe my laptop and keyboard mouse with a paper towel and the screen turned sideways, how I recover the right way?

  Hi ken1957,

  Try pressing Ctrl +or to rotate the screen.