With the help of the previous line in a formula calculator

Hello.  I use the calculator to create a new string that is a custom filtered version of an existing channel.  Unfortunately, I was not able to identify the entrance of previous line in the channel.  To make things easier, let's say my filter is a simple averager.  This is simple pseudocode for what I want to do:

New_Channel = (Existing_Channel [n] + Existing_Channel [n-1]) / 2

where n is the current line.

It's the calculator formula, with I came:

ch("[1]/New_Channel") = (CHD (' chnRow - 1 ' [1] / Existing_Channel "") + ch("[1]/Existing_Channel")) / 2 + CTNV (chnRow > 1)

Unfortunately, I think that chnRow returns 0.

Of course, I'm a beginner.  I'm open to other approaches to the creation of a new channel with a custom filter.

Thank you!

Hi jbuttron,

What you need to do is to copy the channel and remove the first value of the copied channel then the nth line of the original channel is aligned on the e line (N-1) of the copied string.  You must also add the last value of the string copied at the end of this channel as a new value that both channels end up with the same channel width.  Now you can reference the channels with Ch("[1]/old") and Ch("[1]/new") in the expression of canal's calculator, assuming that the channel names are 'old' and 'new' respectively and both are in the first group.  You need not row variable in the expression now, which is good because there is no way to iterate through a variable row in an expression of canal's calculator.  The iteration of the row is implicit in the reference channel Ch("[1]/new").

Brad Turpin

Tiara Product Support Engineer

National Instruments

Tags: NI Software

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