xmlserialization grouping

Hi all

How to group values in xml serialization

my query

select xmlserialize(document
             xmlelement("l",
               xmlattributes(locale_code as "id", BASE_FLAG AS "b" , dbms_lob.substr(text) as "d")
             )
             as Nclob indent
           ) as row_data
   from wrk_catalog_rd_l ;

Returns something like this

1 < id l = 0 b = 0d = "abcd" / >
1 < id l = 0 b = 0d = "abcd" / >
2 < id l = 1 b = 1 d = "abcd" / >

but I need something like this...

1 < id l = 0 b = 0d = "abcd" / > < id l = 0 b = 0d = "abcd" / >
2 < id l = 1 b = 1 d = "abcd" / >

your help is appreciated... Thank you...

SQL> set long 5000
SQL>
SQL> select deptno
  2       , xmlserialize(content
  3           xmlagg(
  4             xmlelement("emp",
  5               xmlattributes(empno as "id", ename as "name")
  6             )
  7             order by empno
  8           )
  9           as clob indent
 10         )
 11  from scott.emp
 12  group by deptno ;

DEPTNO XMLSERIALIZE(CONTENTXMLAGG(XML
------ --------------------------------------------------------------------------------
    10 
       
       

    20 
       
       

    30

Also notice the change in the DOCUMENT keyword contained in XMLSerialize. It lets you serialize XML fragments (not not only root).

Tags: Database

Similar Questions

grouping of XML

looking for help generate xml. Thanks to all who can help. im sure I do something wrong with the group. This inner query must also generate in a clob, so that the final result is 1 plug clob so my finished result is a clob.
It works fine when I do by itself
------------
SELECT
XMLELEMENT
(
'OBJECT ',.
XMLATTRIBUTES)
b.OBJECT AS 'NAME '.
), XMLAGG
(
XMLELEMENT
(
"WELL,"
XMLELEMENT
(
'NAME' PROPERTY
),
XMLELEMENT
(
"DESCRIPTION", DESCRIPTION
)
)
)
)
OF mysecondtable b
GROUP BY b.OBJECT
------------
but when I paste this into my other request, that it will fail with this error.
ORA-01427: einreihig subquery returns multiple rows
----
SELECT
xmlserialize
(
content
(
XMLELEMENT
(
"trials."
XMLATTRIBUTES)
SYSTIMESTAMP AS 'DATE'),
XMLELEMENT ("FUNCTIONS",
(select XMLAGG
(
XMLELEMENT
(
"FUNCTION."
XMLELEMENT
(
"U_ID", a.U_ID
) ,
XMLELEMENT
(
'Function_name', a.FUNC_NAME
) ,
XMLELEMENT
(
'PATH', a.PATH
) ,
XMLELEMENT
(
"INCLUDE", a.INCLUDE
) ,
XMLELEMENT
(
'DESC', a.DESC
) ,
XMLELEMENT
(
'EX', a.EX
) ,
XMLELEMENT
(
'DOC', a.DOC
) ,
XMLELEMENT
(
'STATUS', a.STATUS
) ,
XMLELEMENT
(
"PROP."
(
SELECT
XMLELEMENT
(
'OBJECT ',.
XMLATTRIBUTES)
b.OBJECT AS 'NAME '.
),
XMLAGG)
XMLELEMENT
(
"WELL,"
XMLELEMENT
(
'NAME' PROPERTY
),
XMLELEMENT
(
"DESCRIPTION", DESCRIPTION
)
)
)
)
OF mysecondtable b
WHERE b.R_ID = a.U_ID
GROUP BY b.OBJECT
)
)
)
)
OF myfirsttable one
)
)
)
)
as CLOB
) testxml
OF THE DOUBLE

OK, so you must group these 4 rows in a single XML using XMLAgg fragment:

...

XMLELEMENT

(

"PROP."

(

SELECT XMLAGG)

XMLELEMENT

(

'OBJECT ',.

XMLATTRIBUTES)

b.OBJECT AS 'NAME '.

)

...

Get back information XMLSERIALIZE in a variable of the APEX...

((Request Express 4.1.1.00.23 11 g)

So, I have the following code:

with test_table as)

SELECT VM_REPORT_DATE, quantity, point VM_CORE unpivot)

ITEM quantity in (VM_HOSTS_NUM, VM_NUMBER, VM_PHYS_MEM, VM_VIRT_MEM, VM_CPU_COUNT, VM_TOTAL_DISK, VM_PROVISIONED_DISK)

() where VM_DCNAME = "bc_production")

SELECT XMLSERIALIZE (CONTENT XMLELEMENT ("SERIES", xmlAttributes (under the name "option name"),

XMLAGG (XMLElement ("point", xmlAttributes (VM_REPORT_DATE as "name", much like "y")))

()) as the Group test_table NOMINATIVE by point;

Which returns successfully:

NOMINATIVE CASE
< SET name = "VM_CPU_COUNT" > < point name = "2013-10-29" y = '1312' > < / point of > < point name = "2013-10-23" y = "1308" > < / point > < / SERIES >
< SERIES name = "VM_HOSTS_NUM" > < name of the = y '2013-10-29' = '20' > < / point > < point name = "2013-10-23" y = "22" > < / point > < / SERIES >
< SET name = "VM_NUMBER" > < point name = "2013-10-29" y = "617" > < / point of > < point name = "2013-10-23" y = "616" > < / point > < / SERIES >
< SERIES name = "VM_PHYS_MEM" > < name of the = y "2013-10-29" = "4727.59" > < / point > < point name = "2013-10-23" y = "5175.54" > < / point > < / SERIES >
< SERIES name = "VM_PROVISIONED_DISK" > < name of the = y "2013-10-29" = "76307.65" > < / point > < point name = "2013-10-23" y = "75848.3" > < / point > < / SERIES >
< SET name = "VM_TOTAL_DISK" > < = point name y "2013-10-29" = '95955' > < / point > < point name = "2013-10-23" y = "93793.75" > < / point > < / SERIES >
< SERIES name = "VM_VIRT_MEM" > < name of the = y "2013-10-29" = "3751.98" > < / point > < point name = "2013-10-23" y = "3739.98" > < / point > < / SERIES >

It will be the heart you need to define a variable of APEX of these data with DATA <>< / DATA > tags added around it.

What I'm not sure how is back with a variable chart_series_data PLSQL.

chart_series_data: = "< >". Chr (10);

chart_series_data: = chart_series_data | "WHAT I WENT BACK ON IT."

chart_series_data: = chart_series_data | Chr (10) | "< / data > ';

Thank you

SoC

Why not just do it in the query?

with test_table as)

Select vm_report_date, quantity, item

of vm_core

UNPIVOT)

quantity of the item (vm_hosts_num, vm_number, vm_phys_mem, vm_virt_mem, vm_cpu_count, vm_total_disk, vm_provisioned_disk)

) where vm_dcname = 'bc_production. '

)

Select xmlserialize (document

XmlElement ("DATA"

xmlagg)

XmlElement ("SERIES"

xmlattributes (point "name")

xmlagg)

XmlElement ("point"

xmlattributes)

vm_report_date as 'name '.

, quantity as "o".

)

) as XMLDATA

from test_table

Point group;

Instruction XMLSerialize and case

Hi all
I try to use case statement on choose like that

SELECT

xmlserialize (DOCUMENT

XmlRoot (XMLELEMENT (kdpwdocument, XMLATTRIBUTES)

"xxxxxxxx" AS NRDS,

"xxxxxxxx" AS rcvr,

'xxxxxxxx' AS 'xmlns '.

"xxxxxxxx" AS "xmlns: xsi"

"xxxxxxxx" AS "xsi: schemaLocation".

),

CASE WHEN REPO_STATUS = 1 THEN

XMLAGG)

XMLELEMENT ("regio",

XMLELEMENT ("Inf",

XMLELEMENT ("Id",

XmlElement("PmryId",'1111'),

XmlElement("ScndryId",'1111')

)

)

)

)

ON THE OTHER

XMLAGG)

XMLELEMENT ("regio",

XMLELEMENT ("Inf",

XMLELEMENT ("Id",

XmlElement("PmryId",'0000'),

XmlElement("ScndryId",'0000')

)

)

)

)

END

) ,

VERSION "1.0" encoding = "UTF - 8'

() AS CLOB)

REPO

WHERE 1 = 1

;

but I get the error message:
00937 00000 - 'not a single-group function.

No idea how I can change my query for results? When I use the repo_status group, I get two rows, but it's not a good result for me

Solution:

SELECT

xmlserialize (DOCUMENT

XmlRoot (XMLELEMENT (document, XMLATTRIBUTES)

"xxxxxxxx" AS NRDS,

"xxxxxxxx" AS rcvr,

'xxxxxxxx' AS 'xmlns '.

"xxxxxxxx" AS "xmlns: xsi"

"xxxxxxxx" AS "xsi: schemaLocation".

),

XMLAGG)

CASE WHEN repo_status = 1 THEN

XMLELEMENT ("regio",

XMLELEMENT ("Inf",

XMLELEMENT ("Id",

XmlElement("PmryId",'1111'),

XmlElement("ScndryId",'1111')

)

)

)

ON THE OTHER

XMLELEMENT ("regio",

XMLELEMENT ("Inf",

XMLELEMENT ("Id",

XmlElement("PmryId",'0000'),

XmlElement("ScndryId",'0000')

)

)

)

END

) )

VERSION "1.0" encoding = "UTF - 8'

() AS CLOB)

REPO

WHERE 1 = 1

;

RESULT:

"

0000

0000

1111

1111

"

groups nested without group xmlagg function

I make groups nested without group xmlagg function when using the xmlagg inside another function xmlagg function. Find the structure and sample data in the table here.

 CREATE TABLE "TEST_TABLE" 
   ("KEY" NUMBER(20,0), 
    "NAME" VARCHAR2(50 ), 
    "DESCRIPTION" VARCHAR2(100 )
   );

   Insert into TEST_TABLE (KEY,NAME,DESCRIPTION) values (1,'sam','desc1');
   Insert into TEST_TABLE (KEY,NAME,DESCRIPTION) values (2,'max','desc2');
   Insert into TEST_TABLE (KEY,NAME,DESCRIPTION) values (3,'peter',null);
   Insert into TEST_TABLE (KEY,NAME,DESCRIPTION) values (4,'andrew',null);

select 
        XMLSerialize(document
        xmlelement("root",
         xmlagg(
           xmlelement("emp"           
           , xmlforest(Key as "ID")           
           , xmlforest(name as "ename")
           , xmlelement("Descriptions",  
           xmlagg(
              xmlforest(description as "Desc")
              )
            )
           )
          )
       ) as clob indent
       ) as t    
      from test_table;

Then I removed the of the select query above and utilisΘ xmlelement xmlagg function

  select 
        XMLSerialize(document
        xmlelement("root",
         xmlagg(
           xmlelement("emp"           
           , xmlforest(Key as "ID")           
           , xmlforest(name as "ename")
           , xmlelement("Descriptions",             
              xmlforest(description as "Desc")
              )           
           )
          )
       ) as clob indent
       ) as t    
      from test_table;

It works fine, but the created xml with empty elements for Descriptions key 3 and 4 that has null values. I need no need descriptions element in the xml file when it is set to null. Please help me solve this problem.

Expected behavior, it is not a bug.

The real question is why did you put XMLAgg in the first place?
You can expect several DESCRIPTION by employee?

If yes then please provide some examples of data to this situation.
If not then a simple case statement should be enough:

SQL> set long 1000
SQL>
SQL> select XMLSerialize(document
  2          xmlelement("root",
  3           xmlagg(
  4             xmlelement("emp"
  5             , xmlforest(Key as "ID")
  6             , xmlforest(name as "ename")
  7             , case when description is not null then
  8                xmlelement("Descriptions",
  9                  xmlforest(description as "Desc")
 10                )
 11               end
 12             )
 13           )
 14          ) as clob indent
 15         ) as t
 16  from test_table;

T
--------------------------------------------------------------------------------

  
    1
    sam
    
      desc1
    
  
  
    2
    max
    
      desc2
    
  
  
    3
    peter
  
  
    4
    andrew

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xmlserialization grouping

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