XQuery to compare lists

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• Is there a simple (or easier to understand) solution than this one?

  Good evening
  
  The problem is to identify providers who provide exactly the same set of parts as specified/selected provider. For example, given the following lines:
  

  SUPPLIERNAME                     PARTNAME                              QUOTE
  -------------------------------- -------------------------------- ----------
  NEW YANKEE WORKSHOP, INC.        HAMMER                                 1.89
  NEW YANKEE WORKSHOP, INC.        NAIL                                    .19
  OLD YANKEE WORKSHOP, INC.        HAMMER                                 2.09
  TOOL TIME, INC.                  HAMMER                                 1.99
  TOOL TIME, INC.                  NAIL                                     .2
  MORE TOOLS, INC.                 HAMMER                                 1.99
  MORE TOOLS, INC.                 NAIL                                     .2
  MORE TOOLS, INC.                 PLYERS                                  3.2
  HANDY TOOLS, INC.                HAMMER                                 1.99
  HANDY TOOLS, INC.                PLYERS                                   .2

  NEW YANKEE and TIME TOOL provide the same set of parts. If you choose NEW YANKEE, then the query should return TIME TOOL and vice versa. Since these are the only two suppliers who provide exactly the same pieces, choose another provider must return the empty set.
  
  I came up with the following solution:
  

  select distinct suppliername
    from quote
   where suppliername not in
         (
          --
          -- set of suppliers who supply at least one part not
          -- supplied by the specified supplier
          --
          select suppliername
            from quote
           where partname not in (
                                  select partname
                                    from quote
                                   where suppliername like '&&suppliername%'
                                 )
          union
          --
          -- set of suppliers who do not supply at least one
          -- part supplied by the specified supplier
          --
          select suppliername
            from supplier cross join
                 (
                  select partname
                    from quote
                   where suppliername like '&&suppliername%'
                 )
           where (suppliername, partname) not in (
                                                  select suppliername,
                                                         partname
                                                    from quote
                                                 )
         )
     and suppliername not like '&&suppliername%'
  ;

  that works, but feels a bit convoluted and complicated.
  
  The question is: Y at - it a simpler way to achieve the same result?
  
  Thank you very much for your help, (Note: I used 'as' in the query to save everyone - and myself - having to type the full provider name)
  
  John.
  
  DDL follows: (regardless of using varchar instead of varchar2)
  

  /* ------------------------------------------------------------------ */
  /* table supplier                                                     */
  
  create table supplier
    (
     suppliername         varchar(32)     not null,
     primary key(suppliername)
    );
  
  insert into supplier values
    ('NEW YANKEE WORKSHOP, INC.');
  insert into supplier values
    ('OLD YANKEE WORKSHOP, INC.');
  insert into supplier values
    ('TOOL TIME, INC.');
  insert into supplier values
    ('MORE TOOLS, INC.');
  insert into supplier values
    ('HANDY TOOLS, INC.');
  
  
  /* ------------------------------------------------------------------ */
  /* table quote                                                        */
  
  create table quote
    (
     suppliername         varchar(32)     not null,
     partname             varchar(32)     not null,
     quote                number(8,2)     not null,
     primary key(suppliername, partname),
     foreign key(suppliername) references supplier
    );
  
  insert into quote values
    ('NEW YANKEE WORKSHOP, INC.',         'HAMMER',       '1.89');
  insert into quote values
    ('NEW YANKEE WORKSHOP, INC.',         'NAIL',         '0.19');
  insert into quote values
    ('OLD YANKEE WORKSHOP, INC.',         'HAMMER',       '2.09');
  insert into quote values
    ('TOOL TIME, INC.',                   'HAMMER',       '1.99');
  insert into quote values
    ('TOOL TIME, INC.',                   'NAIL',         '0.20');
  insert into quote values
    ('MORE TOOLS, INC.',                  'HAMMER',       '1.99');
  insert into quote values
    ('MORE TOOLS, INC.',                  'NAIL',         '0.20');
  insert into quote values
    ('MORE TOOLS, INC.',                  'PLYERS',       '3.20');
  insert into quote values
    ('HANDY TOOLS, INC.',                 'HAMMER',       '1.99');
  insert into quote values
    ('HANDY TOOLS, INC.',                 'PLYERS',       '0.20');

  Published by: 440bx - 11 GR 2 on August 3, 2010 19:19 - correction of grammar, replaced 'to' by 'that '.

  Hello

  Here's one way:

  WITH     got_r_num     AS
  (
       SELECT     suppliername
       ,     partname
       ,     ROW_NUMBER () OVER ( PARTITION BY  suppliername
                           ORDER BY        partname
                         )     AS r_num
       FROM     quote
  )
  ,     got_part_list     AS
  (
       SELECT     suppliername
       ,     SYS_CONNECT_BY_PATH (partname, ',')     AS part_list
       FROM     got_r_num
       WHERE     CONNECT_BY_ISLEAF     = 1
       START WITH     r_num     = 1
       CONNECT BY     r_num          = PRIOR r_num + 1
            AND     suppliername     = PRIOR suppliername
  )
  SELECT     m.suppliername
  FROM     got_part_list     t
  JOIN     got_part_list     m     ON     t.part_list      = m.part_list
                      AND     t.suppliername     != m.suppliername
  WHERE     t.suppliername     = '&&suppliername'
  ;
  

  It is perhaps the most intuitive way. The basic procedure is exactly what you could do if you had to fix this problem manually: make a list of all parties and compare lists. The tricky part generates the list.

  In Oracle 11.2 (which I don't have available right now to test), you could simplify this using LISTAGG instead of CONNECT BY.

• Disqualification: Compare the value list in another Table

  I'm relatively new to the Disqualification.

  I use the 11.1.1.7 version.

  I have 2 tables Oracle.  Table1.FieldA does not have a foreign key constraint (but should be) at Table2.FieldB.

  I created a snapshot for Table1 that includes FieldA.

  I created another cliché to Table2 which includes FieldB.

  I am trying to compare the Table1.FieldA with Table2.FieldB value to make sure that there is.

  I can think of a few processors that I could, but they seem to compare a value with another value in the same snapshot (table).

  Any advice would be helpful.

  
  Thank you.

  Ray

  Hello

  Use the search check if you want to just check between the tables. According to the reference database, you need create a list of choices on the table (can be either staged as you, or just a list of external choice provided the lookup columns are indexed). Use Lookup and return if you want to import data in the other table in your process. You can control if you want a 1:1 or from a 1:M relationship, and if you go back several records, you can use split chronogram: table with all the paintings of entry to create an intermediate join process.

  Mike

• How to compare 2 lists of box-multi-select/shuttle APEX (e.g.1:2:3 and 3:1:2) for equality?

  I want to validate 2 selections of list of shuttle for equality. for example

  1:2:5:7:18:3

  and

  1:5:7:2:3:18

  should be treated as equals and therefore valid (i.e. same selections but in different order)

  While

  1:2:5:7:18:3

  and

  1:2:18:9 are not equal and would fail validation.

  If I use the function string_to_table() on the two lists, then I need sort the associative arrays and then compare them for equality.  Any suggestions on the best way to do it?

  Thanks in advance

  PaulP

  Thanks for all help you, but I decided to stay with string_to_table APEX tables and keep things simple.  I decided to return Varchar2 ('TRUE', 'FALSE') instead of boolean (TRUE, FALSE) so I could use the function in a SQL WHERE clause.

  Here's my working solution

  create or replace FUNCTION CheckMultiSelectStringsEqual(
        p_string1    IN VARCHAR2 ,
        p_string2    IN VARCHAR2 ,
        p_separator IN VARCHAR2)
      RETURN varchar2
  ------------------------------------------------------------------------------------------------------------------
  -- This function accepts 2 multi-select/shuttle box strings in the format '1:2:3:5:12:4'
  -- and a string separator i.e.':' and irrespective of the order of individual selections within
  -- the string, returns 'TRUE' if the strings are equal else returns 'FALSE'.
  -----------------------------------------------------------------------------------------------------------------
    IS
      l_table1 apex_application_global.vc_arr2;
      l_table2 apex_application_global.vc_arr2;
      v_return varchar2(8);
    BEGIN
      if p_string1 is null or p_string2 is null or p_separator is null then
        raise_application_error(-20001,'USAGE: CheckMultiSelectStrings() function requires 2 not null strings and a separator character' );
      end if;
      l_table1 := apex_util.string_to_table(p_string1, p_separator);
      l_table2 := apex_util.string_to_table(p_string2, p_separator);
      if l_table1.count() <> l_table2.count() then
          return 'FALSE';
      end if;
      <>
      FOR i IN 1..l_table1.count() LOOP
          FOR j IN 1..l_table2.count() LOOP
             if l_table1(i)=l_table2(j) then
               v_return:='TRUE';
               continue OUTER_LOOP;
             else
               v_return:= 'FALSE';
               continue;
             end if;
          END LOOP; -- FOR j IN 1..l_table2...
          EXIT OUTER_LOOP WHEN v_return = 'FALSE';
      END LOOP; --FOR i IN 1..l_table1.
      RETURN v_return;
    END;
  

  -= == HERE IS THE TEST FOR THE FUNCTION CODE =.

  set serveroutput on
  declare
  v_return varchar2(8);
  begin
  v_return:= CheckMultiSelectStringsEqual('1:2:3:4','2:1:3:4',':');
        if v_return='TRUE' then
            dbms_output.put_line('Strings are equal');
        else
            dbms_output.put_line('Strings are NOT equal');
        end if;
  end;
  

  Hope this helps someone...

  PaulP

• How to compare the variables list

  Hello
  
  
  I have a requirement to compare a value in a list of values (350)
  
  
  for example:
  
  food ('burger', 'cake', 'sandwich'...)
  
  We have best practices to do?
  
  
  Thank you
  Sivakumar

  You paste the example I did for you.

  DVM Code:

  
  
  
  
  
  
  
  
  
  
  
  cake
  THERE
  
  
  Burger
  THERE
  
  
  chips
  THERE
  
  
  

  In your file attribute or xslt, you can call the digital Voltmeter using below function code.

  DVM:lookupValue1M("foods.DVM","food",bpws:getVariableData('inputVariable','payload','/client:process/client:input'),"available")

  In the above example, I kept DVM locally, you can keep it either in project MDS MDS retention is that a best practice the digital Voltmeter can be referenced from more than one composite.

  If you find the above useful, please mark this thread as response and provide marks accordingly.

  (* 7) give points - this is the right label to reward an answering machine (5 - useful; 10 - correct) points for their position if they meet your concerne.*

  Thank you
  Vijay

• Compare 2 lists and running operation less

  Hello
  How to compare 2 lists and perform the operation with these lists less
  
  For ex:

  Declare
   list1 varchar2(100) := '1,2,3,4,5';
   list2 varchar2(100) := '2,3,4,5,6';
  Begin
    select list1 from dual
     minus list2 from dual
  
  end;

  Hello
  Assuming that your version of Oracle support regular expressions, this could be done like this:

  select rtrim(ltrim(regexp_substr('1,2,3,4,5', ',?[0-9]+,?',1, level), ','), ',')
  from dual
  connect by level <= length(translate('1,2,3,4,5',',0123456789', ','))+1
  minus
  select rtrim(ltrim(regexp_substr('2,3,4,5,6', ',?[0-9]+,?',1, level), ','), ',')
  from dual
  connect by level <= length(translate('2,3,4,5,6',',0123456789', ','))+1
  

  Published by: grey_narn on February 10, 2012 12:49 AM

• By comparing the two lists for equality

  I am trying to determine if 2 lists contain the same elements, including the times, but any order. For example:
  
  List 1: A, B, C, D, E
  List 2: A, A, B, C, D
  List 3: A, B, D, A, C
  List 4: A, B, B, C, D
  
  I consider only lists 2 and 3 are equal. I have what I think are the 3 methods of work, but I'd like your opinion on:
  
  (1) are they really correct? Do you see an obvious flaw in the algorithm.
  (2) effectiveness. I've always aspired to look at an algorithm and be able to 'see' the big - O of it.
  (3) other ideas.
  
  Also, I'm a little more confidence in the accuracy of the #1 and #2 (efficiency by derogation) and less confident on #3. I had the idea of #3 the Javadoc on the playlist hashCode(). I don't really know if it's okay.
  

  import java.util.*;
  
  public class ListCompareTest
  {
    public static void main(String[] args)
    {
      List s1 = Arrays.asList(new String[]{"A", "B", "C", "D", "E"});
      List s2 = Arrays.asList(new String[]{"A", "A", "C", "D", "E"});
      List s3 = Arrays.asList(new String[]{"A", "E", "C", "D", "A"});
      
      System.out.println("\nUsing method 1:");
      System.out.println("s1 & s2: " + isEqual(s1, s2));
      System.out.println("s2 & s3: " + isEqual(s2, s3));
      
      System.out.println("\nUsing method 2:");
      System.out.println("s1 & s2: " + isEqual2(s1, s2));
      System.out.println("s2 & s3: " + isEqual2(s2, s3));
  
      System.out.println("\nUsing method 3:");
      System.out.println("s1 & s2: " + isEqual3(s1, s2));
      System.out.println("s2 & s3: " + isEqual3(s2, s3));
    }
    
    public static boolean isEqual(List a, List b)
    {
      if (a.size() != b.size())
      {
        return false;
      }
      
      List copyB = new ArrayList(b);
      
      for (Object obj : a)
      {
        if (! copyB.remove(obj))
        {
          return false;
        }
      }
      
      return true;
    }
    
    public static boolean isEqual2(List a, List b)
    {
      if (a.size() != b.size())
      {
        return false;
      }
      
      List copyA = new ArrayList(a);
      List copyB = new ArrayList(b);
      
      Collections.sort(copyA);
      Collections.sort(copyB);
      
      for (int i = 0; i < copyA.size(); i++)
      {
        if (! copyA.get(i).equals(copyB.get(i)))
        {
          return false;
        }
      }
      
      return true;
    }
    
    public static boolean isEqual3(List a, List b)
    {
      if (a.size() != b.size())
      {
        return false;
      }
      
      List copyA = new ArrayList(a);
      List copyB = new ArrayList(b);
      
      Collections.sort(copyA);
      Collections.sort(copyB);
      
      return copyA.hashCode() == copyB.hashCode();
    }
  }

  Approach 1:
  O(n^2), because you do actually:

  for each element in A {
    for each element in B {
  

  Approach 2:
  Never use (i) get to iterate over a list. An ArrayList is very good (iteration of o (n)), but for a LinkedList is O(n^2). Use an explicit iterator (if necessary) or a foreach loop (where possible). Or, if for some reason you really want to stay with (i) get (and I don't see why you would here), then explicitly declare it as an ArrayList.

  Method 3:
  The hashCode() method will not work. Two unequal lists can easily have the same hash code.

  Unless your lists are very large, or it is very often called, approach 1 is probably good enough, and it is the most simple. In addition, it works in all cases. Will approach 2 evolve better, but only work with classes that implement Comparable (or if you provide a comparator).

• Need the XQuery function that compares two nodes.

  Is there a any function XQuery for the OSB 10 g which compares two nodes with a correct management of redundant namespaces?
  There is a function "" fn:deep - equality "that compares two nodes." But it fails when one node is to have redundant namespaces as an attribute.
  I need a XQuery function that compares two nodes for the same content, same child nodes and their content, the same attributes of the child nodes except the attribute xmlns for one of the node that has redundant namespaces (namespace that are already defined in the parent nodes or any unnecessary space of names).
  
  for example, it should treat following two equal nodes:
  
  < has t '1' = >
  < xmlns:ns1 b = "ns1" >
  2
  < /b >
  < /a >
  
  
  < has t '1' = >
  < b >
  2
  < /b >
  < /a >
  
  
  Above two nodes are the same attributes and content except 1st node attribute xmlns. Wise business scenario it is redundant but not bad, same case can occur and I need to take care of these scenarios.
  Please let me know about a feature or logic to treat this

  in fact the XMLs 2 you posted are different to a '2 '.

  I tried this:

  XQuery version "1.0" encoding "Cp1252";
  (: pragma type = "xs: anyType" ::))

  declare namespace xf = "http://tempuri.org/OSB%20Project%201/compare/";

  declare function:compare() xf
  {element (*)}

  Let $a: = (t = '3')(b xmlns:ns="ns") 2 (/ b) (/a)
  Let $b: = (a t = "3") (b) 2 / (b) (/a)

  return {fn:deep - equal ($a, $b)}
  };

  XF:Compare()

  and it does not work as expected, it is the additional xmlns:ns = 'ns' are ignored...
  I have real

• By comparing the lists

  Hello
  
  I am trying to compare 4 lists (valuelists) and not really found an average effective still.
  My lists are e.g..
  < 4,5,8,6,3,2,7 >
  < 1,2,3,8 >
  < 8,1,2,3 >
  < 3,5,4,9,2,8 >
  
  I keep a list with the values that are in each of the four lists, like:
  
  < 2,3,8 >
  
  At the moment I have create a query with the first list, and then use SQL statements (see the code example) to get my result, but it seems very complicated to me. Is there an easy way in CF?
  
  Thanks for the tips
  

  
  
  SELECT
  mn_team_ID
  Of
  ak_pr_mn
  WHERE
  mn_cat_ID (#categoryIdList #)
  GROUP BY
  mn_team_ID
  HAVING
  Count (mn_cat_id) = #listlen (categoryIdList) #.