[8i] need help for updating/fixing work table

I work in an old database:
Oracle8i Enterprise Edition Release 8.1.7.2.0 - Production
PL/SQL Release 8.1.7.2.0 - Production
CORE 8.1.7.0.0-Production
AMT for HP - UX: 8.1.7.2.0 - Production Version
NLSRTL Version 3.4.1.0.0 - Production

I'm trying to fix a work schedule, and I'm not exactly sure how do. I am accustomed to querying data, do not make changes to the data...

Some examples of data:
CREATE TABLE     test_cal
(     clndr_dt     DATE     NOT NULL
,     work_day     NUMBER(3)
,     clndr_days     NUMBER(6)
,     work_days     NUMBER(5)
);

INSERT INTO     test_cal
VALUES     (TO_DATE('12/30/2010','mm/dd/yyyy'), 254, 11322, 7885);
INSERT INTO     test_cal
VALUES     (TO_DATE('12/31/2010','mm/dd/yyyy'), 255, 11323, 7886);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/01/2011','mm/dd/yyyy'), 0, NULL, NULL);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/02/2011','mm/dd/yyyy'), 0, NULL, NULL);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/03/2011','mm/dd/yyyy'), 1, NULL, NULL);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/04/2011','mm/dd/yyyy'), 2, NULL, NULL);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/05/2011','mm/dd/yyyy'), 3, NULL, NULL);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/06/2011','mm/dd/yyyy'), 4, NULL, NULL);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/07/2011','mm/dd/yyyy'), 5, NULL, NULL);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/08/2011','mm/dd/yyyy'), 0, NULL, NULL);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/09/2011','mm/dd/yyyy'), 0, 11332, 7895);
INSERT INTO     test_cal
VALUES     (TO_DATE('01/10/2011','mm/dd/yyyy'), 6, 11333, 7896);
Note: 2010-12-31 is the last time that I am 100% sure that the data in the table are good. After that, clndr_days and work_days are absent or at least in the case of work_days, are not correct No.

It is a question of both parties, since I need to set the clndr_days and the work_days. (You can fix probably both with a single statement, but I broke it into two to start, to simplify it for me).

I show only 12 days in my sample data, but really, the table stretches in a number of years and pass another 5 years.

PART 1: determination of clndr_days

I've implemented this request:
SELECT     clndr_dt
,     work_day
,     work_days
,     clndr_days
,     min_clndr_day + r_num     AS clndr_days_test
FROM     (
     SELECT     t.*
     ,     MIN(clndr_days)     OVER(ORDER BY clndr_dt)     AS min_clndr_day
     ,     ROW_NUMBER() OVER(ORDER BY clndr_dt)-1     AS r_num
     FROM     test_cal t
     WHERE     clndr_dt     >= TO_DATE('12/31/2010','mm/dd/yyyy')
     )
;
Who gives the right clndr_days (like clndr_days_test), but I don't know how to get that in the table.

It does not work:
UPDATE     test_cal
SET     clndr_days     =     (
                    SELECT     min_clndr_day + r_num
                    FROM     (
                         SELECT     t.*
                         ,     MIN(clndr_days)     OVER(ORDER BY clndr_dt)     AS min_clndr_day
                         ,     ROW_NUMBER() OVER(ORDER BY clndr_dt)-1     AS r_num
                         FROM     test_cal t
                         WHERE     clndr_dt     >= TO_DATE('12/31/2010','mm/dd/yyyy')
                         ) c
                    WHERE     c.clndr_dt     = ???  -- how do I make this equal whatever the clndr_dt is for the record I'm updating?
                    )
WHERE     clndr_dt     >      TO_DATE('12/31/2010','mm/dd/yyyy')
and I don't know how to operate...


PART 2: Fixing work_days

Then, I can't set up a query for work_days.

That's what I have so far, but it does not work quite right, and then it must also be as well an UPDATE statement:
SELECT     clndr_dt
,     work_day
,     work_days
,     clndr_days
,     min_work_day + r_num     AS work_days_test --this isn't right, when work_day is 0 work_days_test should be the previous work_day not the minimum work_day
FROM     (
     SELECT     t.*
     ,     MIN(work_days)     OVER ( ORDER BY clndr_dt)     AS min_work_day
     ,     CASE
               WHEN     work_day     <> 0
               THEN     ROW_NUMBER()     OVER ( PARTITION BY     CASE
                                                  WHEN     work_day <> 0
                                                  THEN     1
                                                  ELSE     2
                                             END
                                     ORDER BY     clndr_dt
                                   )
               ELSE     0
          END               AS r_num
     FROM     test_cal t
     WHERE     clndr_dt     >= TO_DATE('12/31/2010','mm/dd/yyyy')
     )
;
(When I tried to use LAG, that did not work either, because you can have more than 1 non consecutive working day and so it only works for the first day of non-working to have the correct work_days, and then it is to be wrong again)

That's what I want my table to look like in the end:
CLNDR_DT                   WORK_DAY       WORK_DAYS CLNDR_DAYS_TEST
------------------- --------------- --------------- ---------------
12-31-2010 00:00:00         255.000       7,886.000    11,323.000
01-01-2011 00:00:00            .000       7,886.000    11,324.000
01-02-2011 00:00:00            .000       7,886.000    11,325.000
01-03-2011 00:00:00           1.000       7,887.000    11,326.000
01-04-2011 00:00:00           2.000       7,888.000    11,327.000
01-05-2011 00:00:00           3.000       7,889.000    11,328.000
01-06-2011 00:00:00           4.000       7,890.000    11,329.000
01-07-2011 00:00:00           5.000       7,891.000    11,330.000
01-08-2011 00:00:00            .000       7,891.000    11,331.000
01-09-2011 00:00:00            .000       7,891.000    11,332.000
01-10-2011 00:00:00           6.000       7,892.000    11,333.000
(Sorry for all the additional decimals)

Published by: user11033437 on January 11, 2012 13:40

Hello

Thanks for posting the CREATE TABLE and instructions INSERT, the desired output that is very clear, and your attempts; It's all very useful. It would also be useful to explain how you get the desired based on the sample results. There's always a chance, a person could get by chance good results for the wrong reasons with the small set of sample data, but allows you to get complete wrong results with your data would cause.
It seems that clndr_days is the total number of days elapsed since some point of conventional departure (perhaps when the company started), and that work_days is the total number of days of work to a starting point. It seems that work_day is 0 when the day is not a working day, and otherwise, the total number of working days so far in the calendar year. Is this fair?

You said the data after December 31, 2010 is not reliable. Did you mean that two columns (clndr_days and work_days) are not reliable, but the rest of the data is reliable? In other words, are you sure there is only one line a day even after that 2010 and the work_day column is accurate? If so, you can do this:

UPDATE       test_cal     m
SET       (clndr_days, work_days) =
(
     SELECT     MIN (clndr_days) + COUNT (*) - 1          -- clndr_days
     ,     MIN (work_days)  + COUNT ( CASE
                                           WHEN  work_day > 0
                                AND   clndr_dt > TO_DATE ('12/31/2010', 'MM/DD/YYYY')
                                THEN  1
                            END
                             )               -- work_days
     FROM     test_cal
     WHERE     clndr_dt     BETWEEN     TO_DATE ('12/31/2010', 'MM/DD/YYYY')
                    AND     m.clndr_dt
)
WHERE     clndr_dt     > TO_DATE ('12/31/2010', 'MM/DD/YYYY')
;

You are right: it is possible to set the two columns at the same time.

It's a shame that you are using Oracle 8.1. The command MERGE, which was new in Oracle 9.1, is much clearer and more effective. If you could use MERGE, you can essentially use the code you have posted in the middle of a MERGE statement.

Education of UPDATE above assumes that, for the incorrect days, clndr_days and work_days will be never less than the last exact value. If this is not the case, the solution is a bit more complicated. You can avoid this problem and to make the statement faster too, by simply hard-code the last exact value of clndr_days and work_days in the UPDATE statement, where I used min. (this looks like a situation where the efficientcy is not a big problem, however. "You'll probably never make this exact UPDATED once again, so if it runs in 1 second or 10 minutes maybe not much of importance.)

Sorry, I don't have an Oracle 8 database to test this. It works in Oracle 9.2, and I do not think that it uses all the features that are not available to the point 8.1.

Tags: Database

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    AFFIRM_CODE COMPANY_CODE INTERNAL_ORDER_CODE INTERNAL_ORDER_DESC ENIGMA_ACTIVITY             SUB_ACTIVITY_CODE IN_AFF_IND ORDER_TYPE EXTERNAL_ORDER COUNTRY        
EU          6067AT       AT10                 000000402004       NEXIUMGERDMANAGEMENTPROJECT     Z435           NULL        ZZ29       NIS-GOLD        AT             
EU          6068AT       AT11                 000000402005       NEXIUMGERDMANAGEMENTPROJECT     Z435           NULL        ZZ29       NIS-GOLD        AT            

    Sorry, my bad. Without database at hand, I'll try 'baby steps' (borrowed from Frank) so you don't confuse it with errors that I might add (happens far too often already, but at least you won't "swallow" as forum members think is one of the main goals of this fighter - help her learn - providing not only the proverbial fish.)
    Search the Forum - your problem is one of its best sellers. Watching {message identifier: = 10694602} ("split string into" was the key word used in research) you can try something as

    select table_row,
       level clob_row,
       regexp_substr(char_data,'[^' || chr(13) || chr(10) || ']+',1,level) the_line
  from (select to_char(queue_seqnum)||':'||to_char(line_seqnum) table_row,
               char_data
          from order_details
       )
 connect by regexp_substr(char_data,'[^' || chr(13) || chr(10) || ']+',1,level) is not null
        and prior char_data = char_data
        and prior table_row = table_row
        and prior sys_guid() is not null

    to get all the s the_lineall CLOB and after that the use of the example even to get your columns of each the_line.

    Concerning

    Etbin

    Edited by: Etbin on 3.2.2013 09:01

    .. .but I m connected to do things according to the instructions, I can't do something.

    Used to happen to me too and I did as told to the but only after explaining any disadvantages, I was aware of in time. The last sentence is usually: "O.K. now be just and Don't come back with that kind of thing when it turns out that this isn't the right thing."
    rp0428 post - something to remember.

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